i have a question, maybe its a silly question. if the circuit is monitoring its own power. lets say the voltage reference is a equal divider (5v in, 2.5v ref). if the voltage decreases, the reference voltage will also decrease. eg, 3v in means 1.5v ref as far as i understand this video, the reference voltage calculation is based on a stable input voltage
The reference voltage depends on the In voltage as you said, but it isn't a division by 2, the reference voltage must be a lower voltage than the in one, like Vin= 3V Vref = 2V, for a lineal operation of the comparator . If you do a circuit with a Vin = 2V and Vref= 5V (for example), your comparator will work in no-lineal way, it will gives you in Output voltage the alimentation, Vcc+ or Vcc- depending were is the realimentation . I wish I answer your question, my english is not good at all :D.
Oh sorry I don't understad your qstion, yes, it will decrease in this case , bc he power the in voltage with 5V and then he divided the voltaje with 2 resistors with te same value and takes half voltage of the power(Vin).
Excellent explanation but I prefer you writing on paper, for the life of me I don't know why we are pushing our kids to write everything on a PC and then complain about their illegible hand writing :)
This new format is okay, but I prefer the more fluid, more human experience of your hand-written presentations. Call me strange (or overly observant), but I find the lag and jitter of the input device you’re using when screen writing is distracting. Maybe consider a tablet instead of a mouse?In any case, I always look forward to your presentations and appreciate the lengths you go to for the benefit of the community. Thanks, Offset!
Funny, I've been doing circuit design for 40+ years and just learned about this technique a month ago. Thanks for the video.
Very good. You're a good teacher.
Excellent!!!
👍
i have a question, maybe its a silly question.
if the circuit is monitoring its own power. lets say the voltage reference is a equal divider (5v in, 2.5v ref).
if the voltage decreases, the reference voltage will also decrease. eg, 3v in means 1.5v ref
as far as i understand this video, the reference voltage calculation is based on a stable input voltage
The reference voltage depends on the In voltage as you said, but it isn't a division by 2, the reference voltage must be a lower voltage than the in one, like Vin= 3V Vref = 2V, for a lineal operation of the comparator . If you do a circuit with a Vin = 2V and Vref= 5V (for example), your comparator will work in no-lineal way, it will gives you in Output voltage the alimentation, Vcc+ or Vcc- depending were is the realimentation . I wish I answer your question, my english is not good at all :D.
Oh sorry I don't understad your qstion, yes, it will decrease in this case , bc he power the in voltage with 5V and then he divided the voltaje with 2 resistors with te same value and takes half voltage of the power(Vin).
so my question is how do i monitor its own voltage as any reference voltage will change accordingly
what is the Voh and Vol? How do i choose their values?
Excellent explanation but I prefer you writing on paper, for the life of me I don't know why we are pushing our kids to write everything on a PC and then complain about their illegible hand writing :)
Thanks for the feedback. So far, the paper and pencil voters are ahead!
I AGREE,I THINK IT IS BECAUSE THEY USE COMPUTORS TO WRITE THINGS.
This new format is okay, but I prefer the more fluid, more human experience of your hand-written presentations. Call me strange (or overly observant), but I find the lag and jitter of the input device you’re using when screen writing is distracting. Maybe consider a tablet instead of a mouse?In any case, I always look forward to your presentations and appreciate the lengths you go to for the benefit of the community. Thanks, Offset!
PLEASE WRITE THINGS DOWNS WE TO DEPENDENT ON COMPUTORS TODAY.