Ohms Law: R=V/I. Most LED's are rated for 20 mA, you could go a bit higher without killing it, but at 5V a 220 ohm resistor should be bright enough, or as you said 330 ohms for 9V.
To keep it lighting without holding it.... Get a battery connector. Join it to the battery and keep the black wire on negative (-) and red on positive (+). To do it with less wires and more easily, this is what you require: LED (light emitting diode) - 1 Jumper wires (female wires) - 2 (wires that have the point on both sides) Resistor 220 ohms - 1 (it can be squiggly/wavy, as long as it can pass electricity safely, it’s fine. You can use some different ohms too) Breadboard (obviously) - 1 9V Battery - 1 Batter connector - 1 First, connect the battery to battery connector. Take the LED and place if on F - 16, 17. Anode (longer side, positive+) on the right side 17 and Cathode (smaller side, negative-) on the left side 16. Take the resistor. Make sure that it is placed carefully, only a bit curved from both sides (i-i something like this). Place one side on E, 17 and the other side on C, 17. Now, take the jumper wires (colour doesn’t matter). Take one jumper wire and place its one side right ahead of Cathode (E, 16) and the other on the negative side (-) right ahead of A, 16 (it wouldn’t be exactly in the same position, a little bit up). Take the second jumper wire, place its one side ahead of A 17, and the other on positive (+). Make sure the second wire is in Resistor’s line (vertically I). Finally, take the battery which is connected to the battery connector. Place the black wire on negative (-) and the red wire on positive (+). It’ll now glow. Also, this is very simple it’s just explained in detail. This takes like 2-3 minutes but some people still don’t understand. That’s why I had to exaggerate a simple LED lighting so much.
First, you actually need a male jumper cable, not the female one. Second, if you're running the led using two double A 1.5v batteries, and the LED is rated for 3 - 3.2 volts, you don't need a resistor, but you can use one if you want it to stay much longer.
Hey bro I'm and robotics student and I've done these things previously I wanna give a tip you can also connect the positive terminal Directly to save jumper wires if you are lighting up only one led and you can also use 1.5 V battery if you haven't a resistor Thank you for reading this😊
If you want to know what resistors to use, you just need to know how much current your components are rated for, then use Ohms Law. Resistor value = Voltage/Current. So if an LED is rated for 20 mA, and you are using a 9V battery, it will be R = 9/0.02 = 450 ohms. It's usually okay to overshoot or undershoot a little, better to overshoot than to risk drawing too much current and possibly burning a component.
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How many ohms is the resiator? I use ~330 ohms for bright and 1k ohms for darker
Ohms Law: R=V/I. Most LED's are rated for 20 mA, you could go a bit higher without killing it, but at 5V a 220 ohm resistor should be bright enough, or as you said 330 ohms for 9V.
To keep it lighting without holding it.... Get a battery connector. Join it to the battery and keep the black wire on negative (-) and red on positive (+).
To do it with less wires and more easily, this is what you require:
LED (light emitting diode) - 1
Jumper wires (female wires) - 2 (wires that have the point on both sides)
Resistor 220 ohms - 1 (it can be squiggly/wavy, as long as it can pass electricity safely, it’s fine. You can use some different ohms too)
Breadboard (obviously) - 1
9V Battery - 1
Batter connector - 1
First, connect the battery to battery connector. Take the LED and place if on F - 16, 17. Anode (longer side, positive+) on the right side 17 and Cathode (smaller side, negative-) on the left side 16. Take the resistor. Make sure that it is placed carefully, only a bit curved from both sides (i-i something like this). Place one side on E, 17 and the other side on C, 17. Now, take the jumper wires (colour doesn’t matter). Take one jumper wire and place its one side right ahead of Cathode (E, 16) and the other on the negative side (-) right ahead of A, 16 (it wouldn’t be exactly in the same position, a little bit up). Take the second jumper wire, place its one side ahead of A 17, and the other on positive (+). Make sure the second wire is in Resistor’s line (vertically I). Finally, take the battery which is connected to the battery connector. Place the black wire on negative (-) and the red wire on positive (+). It’ll now glow.
Also, this is very simple it’s just explained in detail. This takes like 2-3 minutes but some people still don’t understand. That’s why I had to exaggerate a simple LED lighting so much.
First, you actually need a male jumper cable, not the female one.
Second, if you're running the led using two double A 1.5v batteries, and the LED is rated for 3 - 3.2 volts, you don't need a resistor, but you can use one if you want it to stay much longer.
No comments? Let me fix that
Hey bro I'm and robotics student and I've done these things previously
I wanna give a tip you can also connect the positive terminal Directly to save jumper wires if you are lighting up only one led and you can also use 1.5 V battery if you haven't a resistor
Thank you for reading this😊
Thankyou for all of your support 🎉❤ please like and subscribe👍🎉
Really helpful
Yes
Thank
you
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Nice. Take nite the edge parts. On some breadboards arent xonnected the whole way. If the coloured lines have a gap its not connected.
Thank you it's working
Sir plz iss topic me aek working model Bana dijeye na sir please (To investigate the resistance pattern in the circuit of Sequential glow of LED)
Alternatively connect the pins to different numbered rows then you can connect the resistor negative and LED positive to the power rails.
You may use battery snap ,right?
Hlo pls ap required material bta dijiy na please
1. Bread board
2. Jumper wires
3. Resistor
4. Battery
You need a 9v battery mount. It will make your life easier.
*editing tips
Don't make the music volume too loud.
Yeah this bread board also good
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Very nice 👍
Thank you 👍
Which components required for this
really helpful
Glad to hear that
What type of wiring us thid
its normal jumper wires used in this. Video
Can you do three LEDs?
Which type of resistor u have used
330ohm resistor
It worked😊😊😊
Great!
Project name?
Nice😊
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Battery u r using
Plzz tell that name…
It's Hi-watt 9v battery
Price in India?
Is it connected in series or parallel
The resistor? The resistor is connected in series with the LED, otherwise the LED would draw too much current and burn.
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Welcome
Battery me direct laga ke led glow ho jati
If you do like that the lED will burst
💔💔💔
The verticals are not connected how did you make a line 😂
Excatly
Sorry if you didn't like this video,,, I will make sure that my next video would be exicting
How much ohm resistor?
I got it in my science lab
@@smartytricks1483 ok
Guys use 330 ohm resistor
Yes
If you want to know what resistors to use, you just need to know how much current your components are rated for, then use Ohms Law.
Resistor value = Voltage/Current. So if an LED is rated for 20 mA, and you are using a 9V battery, it will be R = 9/0.02 = 450 ohms. It's usually okay to overshoot or undershoot a little, better to overshoot than to risk drawing too much current and possibly burning a component.
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