Jason Joseph another way to word this scenario is that the object is slowing down as it comes back toward the point of origin. So the y-axis value of distance has to be decreasing and since it’s slowing down (decelerating) the curve starts out steep and get less steep. Note this is consistent with the concept that slope of the tangent line to the curve (the instantaneous velocity) starts out with a large value and decreases as the graph increases in time. The velocity graph has to be below the time axis since the object is moving toward and since the velocity is decreasing at a constant rate the velocity numbers start out larger and get closer to zero as time increases giving a straight positively sloped line below the time axis. Since the slope of the velocity graph is positive this puts the horizontal line for the acceleration graph above the time axis with a y-intercept equal to the velocity graph’s slope. Hope this helps!
The term "deceleration" should be avoided in physics. Objects can accelerate in a negative direction, but they do not "decelerate". It is important to standardize language in science. Just like how "g" is 9.81 m/s^2 everywhere on Earth in the scientific community.
I don't agree that g is 9.81 m/s^2. This is just a standard value to use when it isn't specified. The g-value varies with geographical location, and could be as low as 9.76 N/kg atop an equatorial mountain, and as high as 9.83 N/kg at the north pole.
@@carultch Thank you for making that distinction. You said it better than I did. I guess what I said applies to lower level undergrad physics classes, at least the classes I took.
@@Brickswol It applies to just about any problem you'd solve in an academic class, unless the global variation of g is the main focus of the problem. That was a worked example in the text of the textbook for my undergrad class to teach the nuances of gravitation, but we didn't have any homework or exam problems where you needed to know that. This is why precious metals are measured with balances instead of scales, so people don't game the system by buying them at the equator and selling them up north.
The last scenario is a combination of constant deceleration away and then constant acceleration toward. So the x vs. t graph looks like a smooth hill. The v vs. t graph is a straight negatively sloped line that starts above the t axis and then passes through zero velocity and then below the t axis. Two additional points with the v vs. t graph: 1. The straight negatively sloped line passes through zero where the x vs. t graph is at its peak. 2. The slope of this line is -9.81 m/s^2. The a vs. t graph would be a straight horizontal line beneath the t axis and has a y-intercept of -9.81 m/s^2. Let me know if you have any other questions.
Michael Flood Hi, what does it mean when you say “graphic representation of motion in one direction”? Would like to understand it further to be able to make a graph. Thank you
Thank you both so much, i was able to figure it out. Was trying to refresh my memory to be able to help my nephew solve his assignments that time. But a year after, i have forgotten everything about it again haha
The last scenario is a combination of constant deceleration away and then constant acceleration toward. So the x vs. t graph looks like a smooth hill. The v vs. t graph is a straight negatively sloped line that starts above the t axis and then passes through zero velocity and then below the t axis. Two additional points with the v vs. t graph: 1. The straight negatively sloped line passes through zero where the x vs. t graph is at its peak. 2. The slope of this line is -9.81 m/s^2. The a vs. t graph would be a straight horizontal line beneath the t axis and has a y-intercept of -9.81 m/s^2. Let me know if you have any other questions.
At 7.07, is the object moving in the opposite direction? Is they what u mean by towards Cher? Like it’s been travelling to the right and their graph shows that it has reversed its direction?
Clear Concept this acceleration vs time graph is a derivative of the velocity time graph above it. You can see that the rate of change of velocity (the slope) is constant therefore the acceleration is constant producing a horizontal line. You can also see that the slope of the velocity graph is positive therefore the acceleration graph must be above the time axis. Hope this helps.
Michael Flood Hi, what does it mean when you say “graphic representation of motion in one direction”? Would like to understand it further to be able to make a graph. Thank you
suggar:v In lay man's terms slope is how steep a line on a graph is. Mathematically it's the change in y divided by the change in x of the line. A horizontal line would have zero slope since it has no change in y value.
oh that's mental....we don't use the word toward in the uk. It makes no sense to say toward or even towards - without the destination it is moving towards...i.e ground or sky.
Never heard anyone say that in the US either except for the guy in the video. It makes no sense to say toward without including the destination it’s moving towards. No one says “watch out, the car is coming towards”, they’d say “watch out, the car is coming towards us”. The guy in the video is just silly as hell lol.
I am back almost 3 years later for a refresher. Still the best video on this subject. Thank you!
I agree.. so good!
this helped me a lot! especially the part where you explained why the curve is curved upwards!
My tuition teacher recommended this 2 me coz he can't teach as perfectly as u do . 🤣🤣
Stfu
@@thatonedude5794 lmao chill
Thank you so much for explaining everything so simply, this helped me to fix some of my misconceptions and prepare for my AP1 quiz.
Glad it helped!
I’m so grateful I found your video!! Everything was well explained:)
I didn't understand the graph of Constant deceleration away.I didn't get the idea behind the graph
only helpful motion graph video on youtube.
2 years later can confirm
Unbelievable
@@AvaneeshKalyan Can confirm even even now
@@davidlee9456 Can confirm even now
Now too
The most helpful utube video till today!
Did u understand it???
@@maham5893 i cant understand it
3:12 I thought one could acquire the change in velocity be looking at the area under the acceleration graph.
You are correct. I also confirmed with our calc teacher.
i have a test today and watching this is a last minute thing. thank u for this
Thanks this explains everything
Thanks this explains everything!
Thank you, but at the end of the commentary, the explanation is not complete??
Love🎂😭
Lsteue🚒♊🎃♊
Hy8rsidk🎄🏳️🌈🇦🇱🌹gjdkfeh ♊🚒
Bro. 😭😭😭
We can find the velocity from the acceleration graph by finding the area under the curve
Thank you excellent teaching
For the Object moving at a constant deceleration toward, i don't get the graphs for that.
Jason Joseph another way to word this scenario is that the object is slowing down as it comes back toward the point of origin. So the y-axis value of distance has to be decreasing and since it’s slowing down (decelerating) the curve starts out steep and get less steep. Note this is consistent with the concept that slope of the tangent line to the curve (the instantaneous velocity) starts out with a large value and decreases as the graph increases in time. The velocity graph has to be below the time axis since the object is moving toward and since the velocity is decreasing at a constant rate the velocity numbers start out larger and get closer to zero as time increases giving a straight positively sloped line below the time axis. Since the slope of the velocity graph is positive this puts the horizontal line for the acceleration graph above the time axis with a y-intercept equal to the velocity graph’s slope. Hope this helps!
For increasing acceleration then, will the displacement vs time graph be a cubic function??
If the acceleration function is a linear function, then yes :)
Excellent video!.
super helpful! I actually understand
The term "deceleration" should be avoided in physics. Objects can accelerate in a negative direction, but they do not "decelerate". It is important to standardize language in science. Just like how "g" is 9.81 m/s^2 everywhere on Earth in the scientific community.
Ye ig, retardation d be better to say
I don't agree that g is 9.81 m/s^2. This is just a standard value to use when it isn't specified. The g-value varies with geographical location, and could be as low as 9.76 N/kg atop an equatorial mountain, and as high as 9.83 N/kg at the north pole.
@@carultch Thank you for making that distinction. You said it better than I did.
I guess what I said applies to lower level undergrad physics classes, at least the classes I took.
@@Brickswol It applies to just about any problem you'd solve in an academic class, unless the global variation of g is the main focus of the problem. That was a worked example in the text of the textbook for my undergrad class to teach the nuances of gravitation, but we didn't have any homework or exam problems where you needed to know that.
This is why precious metals are measured with balances instead of scales, so people don't game the system by buying them at the equator and selling them up north.
Sir it is very important and helpfull for me
Sir the video terminates a little bit earlier please explain those two last graphs to me 🥺 about object thrown upwards and returns to the thrower 🥺
See comments below where those are explained.
You are great sir
What are the last 2 graphs supposed to look like??
The last scenario is a combination of constant deceleration away and then constant acceleration toward. So the x vs. t graph looks like a smooth hill. The v vs. t graph is a straight negatively sloped line that starts above the t axis and then passes through zero velocity and then below the t axis. Two additional points with the v vs. t graph: 1. The straight negatively sloped line passes through zero where the x vs. t graph is at its peak. 2. The slope of this line is -9.81 m/s^2. The a vs. t graph would be a straight horizontal line beneath the t axis and has a y-intercept of -9.81 m/s^2. Let me know if you have any other questions.
Thanks!
were r u ?
thank u thank u thank u
thank you!
Amazing
THIS VIDEO SAVED MEEEE
I have my final exam tomorrow and im just watching this to review. SO NERVOUS
😵
this is great
Thank you for teaching! This is really helpful!
Michael Flood Hi, what does it mean when you say “graphic representation of motion in one direction”? Would like to understand it further to be able to make a graph. Thank you
A year late lmao, but he means how the graph is showing the motion of the object
An object moving in a straight line is said to be in a motion in 1 dimension .that dimension is length
Thank you both so much, i was able to figure it out. Was trying to refresh my memory to be able to help my nephew solve his assignments that time. But a year after, i have forgotten everything about it again haha
I'm an Alight Motion editor and I believe this could help
Good video. Thank you so much.
Is there a part 2? you did not complete the last two graphs
See comments below
Bruh left us hanging so bad
Simon Funk see reply to comments below for the end.
why's the last graphs shown??
The last scenario is a combination of constant deceleration away and then constant acceleration toward. So the x vs. t graph looks like a smooth hill. The v vs. t graph is a straight negatively sloped line that starts above the t axis and then passes through zero velocity and then below the t axis. Two additional points with the v vs. t graph: 1. The straight negatively sloped line passes through zero where the x vs. t graph is at its peak. 2. The slope of this line is -9.81 m/s^2. The a vs. t graph would be a straight horizontal line beneath the t axis and has a y-intercept of -9.81 m/s^2. Let me know if you have any other questions.
Thanks
@@Joy-ee3ie EXPLAIN
At 7.07, is the object moving in the opposite direction? Is they what u mean by towards Cher? Like it’s been travelling to the right and their graph shows that it has reversed its direction?
Yes that’s correct. It’s moving back towards its point of origin.
@@blueraidersscience ok thanks 🙏😊 the video was absolutely helpful! Impressive teaching!
Is there a playlist so I can watch all??
Yes. This link is the playlists for the physics videos arranged by topic: czcams.com/channels/KuVS68plwkJyUKvAbSLWkg.htmlplaylists?view_as=subscriber
Thank you
Thank You
thanksss
this really helped
Can i get explanation about scientific notation and so on in telegram
could you please tell me what software you used to do this. I would love to use this in my classroom
I simply used ScreencastOMatic and Smart Notebook to record this lesson on the Smartboard.
sir can you please explain the graph at 14:22
Clear Concept this acceleration vs time graph is a derivative of the velocity time graph above it. You can see that the rate of change of velocity (the slope) is constant therefore the acceleration is constant producing a horizontal line. You can also see that the slope of the velocity graph is positive therefore the acceleration graph must be above the time axis. Hope this helps.
Michael Flood thanks a lot !
Michael Flood Hi, what does it mean when you say “graphic representation of motion in one direction”? Would like to understand it further to be able to make a graph. Thank you
Thanku.. 😊
Where is the graph for the last two?
Rayyan Saboor see comments below. They are explained.
What is slope?
suggar:v In lay man's terms slope is how steep a line on a graph is. Mathematically it's the change in y divided by the change in x of the line. A horizontal line would have zero slope since it has no change in y value.
I dont get it
Thanx man
thanks bruuvv!!!!!!!!!!!!!!!!!!!!!!!!!!!!
good
can understand
😍😍😍😍 🥰 thanks alot that what I want it
what will the a-t graph loo like for the last one
See comments below. It’s explained below.
Sharmila74 see comments below. It’s explained below.
Tyy sir, worried teacher here because this is not even thought in college
then why the hell am I learning this in 7th grade
Then Why the hell am I learning in class 6?
@@rabzy9591 then why the hell am I learning in class 6?
God bless
does towards me negative??
Bangtan_Animegirl towards means in the process of coming back to the starting point as opposed to moving away from the starting point.
Thank you so much
What about the end???
See comments below where I explain the end.
@@blueraidersscience thank u bro
Question activity 3.8 ansewrs
Tnk u so much sir
Superb thanks!!! 👍👍
Thank you so much :)
oh that's mental....we don't use the word toward in the uk. It makes no sense to say toward or even towards - without the destination it is moving towards...i.e ground or sky.
The position where x = 0 is the point used as reference for away or toward.
Never heard anyone say that in the US either except for the guy in the video. It makes no sense to say toward without including the destination it’s moving towards. No one says “watch out, the car is coming towards”, they’d say “watch out, the car is coming towards us”. The guy in the video is just silly as hell lol.
thank very welll
@@melisapham6627 ...no
anybody watching now
7:16
nice
thx
I don't get it
Anyone gonna talk about how the video just cuts off LMFAO
Easy Tiger...this is addressed in the comments below...
Nq
The concept didn't get clear
too long and slow
i this
Thanks a lot sir
Jesus is the Son of God. Believe in his death and resurrection then confess his lordship over your life. Love yall♥️😊
Wtf
Nice try dude..
Thank you