Trigonometry Top-10 सवाल🔥 एक सवाल पक्का Gagan Pratap Sir

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[@MathsConceptKing_]

Trigonometry ke top 10 sawal kaise lage mere bhai😊😊😊 videos ko jyada se jyada share kare , dosto se subscribe bhi karwaye ☺️☺️
Aur kis chapter ke top 10 questions solve karna chahte hai ??? Comments me batao🙂

[@MausamRaj-kz3tt]

Bahut hi laa jabab question the guru jii

[@officialchoudhary__mahakal9700]

Algebra ke guru ji

[@tarungupta2429]

Bhut badhiya solution karwaya sir apne sir please number system ke har ek topic ke bhi top 10 questions Kara do

[@Omkar-MEA]

Mixture allegation ~~ multiplying factor wala

[@Pacific_phoenix]

Guruji har chapter k hi kra dijiye concept k sath. Bhot productive h accha revision ho rha hai.

[@twinaspirants]

SecA+tan³A.CosecA= SecA(1+tan²A)= Sec³A
▶️tan²A=3+Q²
▶️1+tan²A=4+Q²
▶️Sec²A=4+Q²
▶️SecA= (4+Q²)½
▶️Sec³A= (4+Q²)³/²
Option D ✅

[@himanshubajaj4605]

Bahi aapne ye type kaise kiya hai ?

[@poojachauhan6294]

D

[@chandrakantchouksey9896]

Bahut sahi bro

[@jaishreeram3753]

Opt d

[@shubhampawar4304]

Thanks brother 😊

[@Bolt-ek7nm]

Q11 option d (4+q2)3/2
sec +tan3a coseca
1/c + sin3/cos3 *1/sin3
1/c + sin2a/cos3a
On solving = sec3a
And put Value from below
Tan2a +1= 3+Q2 +1
Sec2a = 4+q2
(sec2a)3/2 or sec3a = (4+q2)3/2 ans

[@riyansh_0019]

*_"अतीत पर रोने से बेहतर है नए भविष्य का निर्माण कीजिए.,क्योंकि अतीत एक सबक है भविष्य नहीं..😊......!_*
जय हिन्द गुरुदेव,,❤️🔥🇮🇳

[@DeepakKumar-kc7nx]

Seca+tan^3a.coseca
Seca+sin^3a/cos^3a.coseca
Seca+tan^2a.seca
Seca(1+tan^2a)
Sec^3a
(√1+tan^2a)^3
(4+Q^2)^3/2

[@user-sb1bl5mz3y]

11.Ans-D (4+Q^2)3/2

[@rolexsir..8052]

1/c3=sec3
Sec2-1 =tan2
Put in eq and solve it
option d is coreect

[@bhupendrajoshi5618]

(d) (4+Q^2)^3/2

[@SSCASPIRANT7187]

Q.11- 42:10 Ans. (D)❤ chlo ab to sir ke ashirbad se CGL nikal jayga

[@DeepakTiwariThenewAmbitionstar]

ANS. (D) (4+Q^2)^3/2 JAI JAI SHIYA RAM SIR JI

[@anarghashome87]

Option D is the absolute answer. As we see from the given expression, it could be reduced to sec a(1+tan²a), or (1+tan²a)½(1+tan²a)= (1+tan²a)^1.5. Thus, the answer is, (1+3+a²)^1.5= (4+a²)^1.5.

[@ShashiPrakash-er4jx]

Mind blowing question❤❤

[@RimjhimSingh-xt8bg]

Main jb. Kam time m questions ko slove lar leti huu to apnne ap pe gurv hone lagta hhh......because of sir

[@Income_Tax_Officer_1718]

Jai shree Ram sir ji ❤❤❤

[@ankitgoswami2358]

D

[@onlineknowledgepoint9519]

Question no. 11 , Ans - D

[@ankit_ku_singh]

Seca +tan3a. Coseca
=Seca(1+tan2a)
=Seca.sec2a
=Sec3a
=(4+Q2)3/2

[@Shiva---1729---]

Putting Q=0
Tana=√3
A=60⁰
Now sec60⁰+tan³60.cosec60⁰
=1/2+3√3×2/√3 =8
Satisfying option 4. At Q=0✅✅✅

[@Sachinsirop21]

Pahle math se dar lagta tha per aab sab se jayada interest hi math me ho Gaya

[@allexams7611]

Batch liya bhai aapne

[@RjsportsAdda]

Super Sir

[@nitish6239]

Nice class sir ji ...
by the way answer is option D: Thank you.

[@prateekyadav5349]

Like for Gagan sir ❤❤❤❤

[@matabhai2]

Sir Mera Selection Hone ke baad Main apne Salary ka 25 ℅ Aapko Donate karunga / Yearly❤

[@skmishra6701]

Achcha joke tha bhai

[@4everyone75]

Brother selection only maths se nhi hoga

[@radheshyamkumaryadav3581]

D will be the ans using value putting concept
Put a=60 degree

[@pridishgupta3796]

Behtareen sir

[@Ckyadav-ahir]

Let, Q=0,
Then, a=60°
2+3√3•2÷√3
=8
So, option d is correct 💯
😊

[@SONU...RAJPOOT]

Kon kon sir ko dil se pasand karta hai ❤❤

[@Shanu0184]

Tere andar bhi kaun kaun wala bhut ghus gaya k

[@Anuragsingh-fh5yz]

Tumera bhi fefda dhadakta hh kya..❤❤

[@rkfullfun]

hmare pass dil hi nahi h😂😂tut chuka h😂😂

[@Satendra_Kumar18-10]

Hum toh gurde se pasand karte hain dil toh kisi or ko de diya hai n isliye

[@AKsharma-np6qb]

Option - (D)

[@ravisahani3587]

Easy concept ❤❤❤

[@Nb_783]

Truly amazing class ❤ we need more classes like this 😊😊😊😊 always thank ful of you sir😊😊😊🎉❤❤😂😂😂

[@theearthclasses24]

Tan²a= 3+Q².............................. seca+tan³a×coseca= 1/ cos³a = sec³a
1+tan²a = 1+3 + Q²
Sec² = 4 + Q²
Sec = ( 4+Q²)1/2
Sec³a = (4+Q²)3/4

[@educationtutorial5860]

3/4 😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂pagal

[@hpdongre]

Q. No. 11 answer - d - (4+Q²)³/²

[@vishalsinghsingh8361]

Put q=0. a=60⁰ ( 2+3root3×2/root 3=8 that is in option D

[@HIMANSHUKUMAR-dz6zy]

Ans : option D

[@SonuSingh-vr9wm]

By value putting
a=60° and Q=0
Correct ans. Option D

[@ArjunYadav-rv5pn]

Super sir ❤❤

[@Kashmir-kf3xo]

option D(4+Q²)³/²

[@bijoydas7171]

Option -d : (4+Q²)³/²

[@ndaaspirant9473]

Superb session sir maja aa gya. But end me majboor hokar swal ko solve karna pada (4+Q^2)^3/2 d option answer hoga

[@AJEETKUMAR-py3ex]

Ye series daily chalao sir jee
Very helpful series

[@rajankashyap3452]

First try to make tan²a into sec²a then then on solving we tan²a.seca hence the answer is option (d)

[@Bhaktidarshan909]

(D). (4+Q^2)^3/2

[@Arjun-cx7kt]

Bahut majedar hey sir questions

[@Niru719]

Thanks a lot guru ji & lot of love❤
Ans d

[@smitasarkar9864]

Option -d (4+Q^2)^3/2

[@Mohit-bc3jb]

Ans d hoga after solving given equation we get - sec^3 , we can find out its value using tan^2 =3+Q^2

[@SabitaKumari-pl9od]

Majedaar sir ji 🥰🥰

[@rajnishraj2317]

Wonderful session sir❤❤

[@MathsConceptKing_]

Keep watching

[@Ranjeetkumari911]

Concept lajwab tha sir ji.....❤❤❤❤❤

[@dheerajmahor2836]

Ans D - (4+Q^2)3/2

[@Gauravchaturvediji]

Tnq gurudev 😊

[@diksha565]

Thanks so much sir ❤❤

[@lalitkumarsahu942]

SecA+ tan ^2A*CosecA=Sec^3A.
tan^2A=3+Q^2.
Sec^2-1=3+Q^2.
Sec^2A=4+Q^2.
SecA=(4+Q^2)^1/2.
Sec^3A= (4+Q^2)^3/2.
Correct answer is :-. D.
Thank you so much sir ji 🙏❤️

[@tkseries6643]

Ans. D (4+Q^2)^3/2

[@PavanKumar-sv1zw]

Amazing sir ji

[@MathsConceptKing_]

Keep watching

[@nikitadas5589]

Option . D

[@hrgaming8403]

answer option D (4+Q^2)^3/2

[@poojaparihar3294]

Wonderful session ❤

[@MathsConceptKing_]

Glad you enjoyed it!

[@Rahul_roy_abhi]

Q11-ans option d from value putting if a=60°

[@swetatiwari873]

D. (4+Q²)3/2

[@AdarshYadav-cu8rj]

42:03 (d) (4+Q^2)^3/2

[@BASNTIMEENA2006]

Kese aaya

[@Rockstarabhifactz]

Option D is the Right Answer ❤️❤️🙏🙏

[@rajeshdas867]

(4+Q^2) ^3/2

[@diliptejra6167]

Sir bahut shandar

[@amankeshav6652]

d option (4+Q^2)^3/2

[@mansi5719]

Q.11...Ans-D (4+Q^2)^3/2.

[@statuscreater......]

Ans (d).I have solved it by using value putting.😊

[@PRIYANKATIWARI-nu5rm]

Ans .option (d)( 4+Q^2)^3/2

[@lakshaypandit39]

Let ,Tan A = tan 60 = √3
3 = 3 + Q²
Q² = 0
SecA + Tan³A.CosecA =
2 + 3√3× 2/√3 = 8
Ans (d) (4+Q²) = 8 ⚜️

[@golupatel8822]

ans. - D

[@rahulkrishna640]

Q11--option D

[@stayaway258]

Ans - D

[@Deepanshu-4]

Sir Homework question's answer-------option (D) is right answer (4+Q^2)^3/2

[@MathsConceptKing_]

Right answer

[@Deepanshu-4]

@@MathsConceptKing_ 2024 me rank nikalkar aapse Milne aaunga sir 🙏🥰

[@abhijeetkumawat8502]

Let Q=0 then a=60
2+3√3*2/√3=8
Byoption d is ans

[@shikshapathshalawithmasti5470]

Great sir ji

[@Pacific_phoenix]

d) (4+Q^2)^3/2

[@SSC_CGL_02]

D
Es question को पहले long method se करता था but जब से आपका पहले के video me इस question ka solution dekha hai tab se short me hi ho जाता hai
Thank you sir ❤

[@LezZzeR---]

शब्द कम पड़ जाते है...
आपके मेहनत के बदले शुक्रिया बोलने के लिए।❤❤❤

[@MathsConceptKing_]

So nice of you ❤❤

[@lovemeena4817]

(4+Q^2)^3/2 option D

[@user-ik9tz2qc9i]

Question 11-- option d

[@Manjeet_vardi_lover]

11th and 12th me chije yahi thi lekin use ham ek page me solve karte the aur time bhi jyada lagta tha lekin aaj sir ka video dekhane ke bad seconds me solve kar denge ❤❤love you sir maths founder Gagan Pratap sir thank you sir ❤❤❤❤

[@MathsConceptKing_]

Welcome ❤

[@Satyam-pl2fe]

Speechless...
Ans option D

[@user-zx6md9tt1w]

D >ans

[@shantanu_nath]

Ans : Option D

[@kushyadav203]

एक पुल की मेहराब वृत्त की चाप के आकार की है। यदि पुल की चौड़ाई 40 m है और इसके मध्य भाग की ऊँचाई 8 m है, तो पुल की वक्रता त्रिज्या क्या है ? Please solve this question ❓

[@AbhishekKumar-wj1ve]

Let radies is R
Then remaining part is R-8
R^2=20^2+(R-8)^2

[@_Satish__yadav]

Sir, after reading math from you, I am solving the questions very soon, thank you so much sir.❤

[@MathsConceptKing_]

Most welcome

[@MathsConceptKing_]

Most welcome

[@manojbhobhriya932]

Nice session sir thank you so much

[@MathsConceptKing_]

Always welcome

[@AnkitSingh-it2wt]

Thnq so much sir💖💖

[@MathsConceptKing_]

Most welcome

[@DefencewithOPSIR]

option D correct answer of question no, 11 (4+Q^2)^3/2

[@shivamkumarsingh420]

Gjb 👍🏼

[@neetukumari2986]

Option --- ddd ((4+Q²) ³/²)

[@Anuragmeena-ly1mi]

thank you so much sir for this session

[@MathsConceptKing_]

Always welcome

[@studyadda5080]

Option D { Sec³A=( 4+Q²)³/2}

[@RahulRaj-tj2cp]

Ans :- D

[@shivanigoyal3944]

11. Option D without pen paper

[@rahulvishwakarma207]

Q11 -ansD

[@ashvanigupta1502]

Options..(d)

[@NikitaSharma-rn1cf]

Ques 11-Option d

[@himanshubajaj4605]

Mst jabardast ❤❤

[@GargiJadaun-sq4gr]

Ques 11. Option D

[@rohan98M]

D (4+Q^2)^3/2