Tension force in strings (Easy method + Numerical) - two mass in an elevator | Newton's laws

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  • čas přidán 28. 11. 2017
  • Without using any tension formula, we will learn how to calculate the tension in a string using Newton's laws of motion. We will also solve problems elevator problems in finding tension in strings in two masses hanging.

Komentáře • 80

  • @digiworldkids
    @digiworldkids Před 4 lety +113

    You sound like Chatur Ramlingan 😂 thanks tho

  • @arulvel96
    @arulvel96 Před rokem +4

    ily, without you i cant got off with my doubts.
    at first i was wonderring why a body has two tension forces, but now i cam to know there is an tension forces by the body to the string and other by the string to the body

  • @itzzprimis9027
    @itzzprimis9027 Před 2 lety +1

    Thank you, it was well explained :)

  • @randomstranger62786
    @randomstranger62786 Před 3 lety +1

    That's what I was looking for. Thanks...

  • @tetoeco
    @tetoeco Před 3 lety

    Thank you, very clear.

  • @antonberezhnoy4835
    @antonberezhnoy4835 Před 2 lety

    Thank you, super useful information)

  • @BrajeshKumar-um9qd
    @BrajeshKumar-um9qd Před 3 lety

    Thanks BRO for this video:)

  • @FACTRASH
    @FACTRASH Před 4 lety

    Thanks really !

  • @binte-huwwa8770
    @binte-huwwa8770 Před 2 lety +1

    Thank you so much sir , you are a great person

  • @paulring9246
    @paulring9246 Před 4 měsíci

    This was so good

  • @brotoroto6086
    @brotoroto6086 Před 2 lety

    Hello i wanted to ask a question, is there a way where i can send the question to you, it's okay if you dont want to

  • @shikharbhai3397
    @shikharbhai3397 Před 2 lety

    op bro love from india

  • @swatidangi8313
    @swatidangi8313 Před 11 měsíci

    You are amazing

  • @jyotipravasahoo4281
    @jyotipravasahoo4281 Před 2 lety

    Thank you..

  • @kalpanapathak2769
    @kalpanapathak2769 Před rokem +1

    At 7:07...sir i didnt understand..why u added g and 9/2...plz reply sir🙏🙏🙏🙏

  • @allrounders3672
    @allrounders3672 Před 3 lety

    Thx bro

  • @harshathakare458
    @harshathakare458 Před 10 měsíci +1

    Thankyou sir...can u give me clarification on why its not (m1+m2) g down there....that Fake contradiction always 😢 makes me underconfident to solve que.

  • @cocococo1026
    @cocococo1026 Před 3 lety

    Thankyou:)

  • @Spinelli__
    @Spinelli__ Před 4 lety +4

    At 7:00, why did you not also write the tension force acting downwards from the ceiling? Just prior to that, you explained how the tension force from the ceiling can result in the ceiling collapsing if the ceiling is not strong enough (in extreme cases of course) but then you never wrote down this force so it seems contradictory and confusing. You wrote all the other up & down tension forces so why are you "allowed" to not include this one? This just makes it more confusing. How come 1 of the 4 tension forces does not have to be taken into account?

    • @ibetudkmahnameb4114
      @ibetudkmahnameb4114 Před 2 lety +1

      Dude-
      This was the exact same question I asked my physics teacher, i was like "why do we only include the forces acting on the block in an fbd and not the ones the block applies in the opposite directions and then make equations out of them? " He didn't even have a reasonable answer and then when I tried asking one more time, he just got mad at me. I still don't have the answer. But hey, it's been a year since u commented so did u get the answer?

    • @Mahesh_Shenoy
      @Mahesh_Shenoy  Před 2 lety +2

      @@ibetudkmahnameb4114 There is a downward tension force acting on the ceiling, but ceiling is NOT my object of interest. Since my objects of interests are the two masses, we only consider the forces acting on them.
      But, if we considered the ceiling as the object of interest, then we could consider the T2 tension force acting downward!

    • @barneycasting8331
      @barneycasting8331 Před 7 měsíci

      @@ibetudkmahnameb4114 Allah be merciful on your idiotic brain! You have to first define which system you are considering forces and draw the FBD FOR THAT SYSTEM and then draw forces on THAT SYSTEM. Allah be merciful on this idiot.

  • @AGR_GAMERS
    @AGR_GAMERS Před rokem +1

    Thanks

  • @mitochondria336
    @mitochondria336 Před 3 měsíci

    nice

  • @karishma8969
    @karishma8969 Před rokem +1

    But why do we put the g\2

  • @Kayl63
    @Kayl63 Před 3 lety +3

    Whats the formula for tension if the rope has a mass?

    • @AngusMcAlister14
      @AngusMcAlister14 Před 3 lety

      there’s no specific formula for tension; you’re meant to find it by looking at your diagram.

  • @AbhishekKumar-ko1kk
    @AbhishekKumar-ko1kk Před 3 lety

    Msttt

  • @arulvel96
    @arulvel96 Před rokem

    sir, if we are drawing a freebody diagram for a body with mass m1, then which tension do we need to consider (tension by body to string) or (tension by string to body) ?

    • @Mahesh_Shenoy
      @Mahesh_Shenoy  Před rokem

      Since we are interested in the 'body' and not the string, which one do you think it is?

    • @arulvel96
      @arulvel96 Před rokem

      @@Mahesh_Shenoy body to string am I right?

    • @Mahesh_Shenoy
      @Mahesh_Shenoy  Před rokem +1

      ​@@arulvel96 If you consider the tension force applied BY the body TO the string, we are making string as our object of interest, right?

    • @arulvel96
      @arulvel96 Před rokem

      @@Mahesh_Shenoy oh ok i got it, if we take the tension of body to string then it means the force by body to string (force on string).
      so we need to calculate all forces on body which means i have to take force exerted by the string to the body

  • @tanishmalvi4398
    @tanishmalvi4398 Před 2 lety +1

    Chatur Ramlingam is on fire🔥
    😂

  • @Pastramityrant
    @Pastramityrant Před 3 lety

    Music in background?

  • @yifanxu8051
    @yifanxu8051 Před rokem

    why is g+g/2 instead of g-g/2? They are in oppo direction aren’t they?

  • @HadithWeekly
    @HadithWeekly Před 2 lety +1

    1:57 he flipped us all

  • @badreddine7187
    @badreddine7187 Před rokem +2

    Pls why you add g/2

    • @jenifervinsi
      @jenifervinsi Před 2 měsíci

      It is the acceleration of the elevator. You should think that the elevator goes upwards with acceleration g/2

  • @arulvel96
    @arulvel96 Před rokem

    sir, can we also say that the direction of tension is same as the direction of pulling

  • @joyce7259
    @joyce7259 Před 3 lety

    What if it is downward? Will it still be +g/2?

    • @timnoskill
      @timnoskill Před 3 lety

      if the elevator is going downwards, it will be -g/2 i believe

    • @stritax9478
      @stritax9478 Před rokem

      @@timnoskill yes

  • @anjaligarg8709
    @anjaligarg8709 Před rokem +1

    Shouldn't the tension forces in each part of the string cancel out since each part experienced tension both upwards and downwards, and thus the resultant tension on the string should be zero?

    • @Mahesh_Shenoy
      @Mahesh_Shenoy  Před rokem

      They do cancel out. That's why the string pieces feel no net force and, hence, no net acceleration!
      The forces are balanced.
      And the magnitude of one of these forces is what we call tension!

    • @anjaligarg8709
      @anjaligarg8709 Před rokem

      @@Mahesh_Shenoy So why do we say that the tension is T throughout the string? Shouldn't we talk in terms of the net force on the string?

    • @Mahesh_Shenoy
      @Mahesh_Shenoy  Před rokem

      @@anjaligarg8709 since we consider massless strings, the net force on it is always zero :)
      Yet, the string will exert pulling forces on its ends, right? So, I think that's what we try to communicate!

    • @anjaligarg8709
      @anjaligarg8709 Před rokem +1

      @@Mahesh_Shenoy So if I have two blocks tied by a string such that the string is not lying loose between them, I say there is a tension T throughout the string. By saying so, I am emphasizing the fact that the string is pulling both the blocks with a force equal to T, and not that the net force experienced by the string is T, am I right?

    • @Mahesh_Shenoy
      @Mahesh_Shenoy  Před rokem

      @@anjaligarg8709 Yes, absolutely!
      Even though the block and the string are accelerating, the net force on the string is zero! Because of its zero mass!

  • @harshitvardy1822
    @harshitvardy1822 Před 3 lety +2

    Aren't you the Khan Academy guy? And I don't mean Sal Khan but the Indian teacher who teaches physics and chemistry Indian syllabus

    • @Mahesh_Shenoy
      @Mahesh_Shenoy  Před 3 lety +1

      Yes, I am the non Sal, Khan Academy guy.

    • @harshitvardy1822
      @harshitvardy1822 Před 3 lety +1

      @@Mahesh_Shenoy You are amazing, sir. Your videos are of extreme help and importance to me..

  • @chiviza
    @chiviza Před 7 měsíci

    why is t1 not pointing downwards too?

    • @jenifervinsi
      @jenifervinsi Před 2 měsíci

      Because it is the opposite force of that block's weight (mg)

  • @pablosantana3173
    @pablosantana3173 Před 2 lety

    Why wouldn't the force be the same throughout the string if it had mass?

    • @Mahesh_Shenoy
      @Mahesh_Shenoy  Před 2 lety

      The pieces of string on the top would have to carry the weight of the entire piece of string below it!

  • @Akshay-np1rb
    @Akshay-np1rb Před 2 lety

    I'm seeing 2 hours before test... 😂

  • @souravxboss2004
    @souravxboss2004 Před 2 lety

    Sir please help

  • @contactkuls1
    @contactkuls1 Před 3 lety +2

    u sound exactly like the guy from khan academy

  • @snehajhalani3797
    @snehajhalani3797 Před 4 lety +4

    Ilove my india