Q2B=6.32cm; Q4C=8.89cm; Q2Q4=12.7cm; BC=12.7cm Q2B is turning uniformly clockwise at a speed of 1 rad/sec. Find: A. The Velocity of C when theta is equal to 15 degrees B. The position and velocity of that point H on the center line of BC (Produced if necessary) which has the least velocity, when theta is equal to 15 degrees C. The velocity of C and of the same point H when Theta is equal to 60 degrees and the value (or values) of theta when velocity of C is 0 Draw the graphical method of the velocity Draw the required of C
wonderful explanation sir......
ek no video banayela public ko aur chaiye
Helpful ❤
Behtarin... 👍👍
Good sir👊👊 i thanks a lot of you...
Thanks man..ur 17 min make me good feel..
great,very clear explanation sir
awesome teaching sir 💛
Plz make video of acceleration and instantaneous velocity method
Wonderful. excellent.❤️❤️❤️❤️❤️
Excellent 👌👌
Very very thanks sir for making such a concept clear vedio.
Sir ap bahot achaa smghate ho tq sir👍
Super explanation sir
Wonderful explanation on copy sir
Thanks sir great explanation
wow that good explaining sir
Your video were so helpful sir thank you very much ...anti clockwise ke problem's bhi kijiye sir
Please share videos with your friends and for more videos visit my channel GTU MIMP.... Thanks
A very big thanks sir
Tq fr ur valuable teaching sir!😍
Thanks sir you are so helpful
Wow nice learning sir.
Thank you
Good explanation
Plz make video on tom icr method to draw velocity digram
Apka bahut bahut dhanyabad
very good keep it up
Very helpful
#ThankS #Broiii
Sir,GREAT EXPLANATION! I just have one doubt,how did you choose the directions for V(cd) and V(cb)?
Please reply soon sir to this.
THANK YOU!
It's acc to the direction of the speed or angular velocity.
i.e they both act in the same direction.
Super 😎
In 8:49 why do we want to divide by 2?????rply pls
That's the scale dude
@@manaskulkarni3117 which type of scale
@@draconisgaming1 ,🤣🤣
Wo sirne starting me 2 se divide galat kar diya tha.
It is as
First take --1cm=0.2m/sec.
Then for 0.8377m/sec. Scale will be
0.8377/0.2=4.189
Excellent
You are amazing sir... Good work keep on.
thank you!
Nice sir tnx
why divide by 2? or should we divide by 2.5?
Thank You!
Very helpfull
Thank you sir.
Easy to understand but quite lengthy video.
Thank you so much sir ❤️
How many Mark ask for semester exams sir...
Thank you so much🤗
I have a cat this morning. Thanks
Thank you sir...
Agar Questionsme counterclockwise diya hoga toh reverse janeka na qudrant me
Nycc
Sir can u make sum on slider crank velocity
Thanks
Thank you sir
Make video on icr
Scale kese select kare ?
Thank you
thanks
Why divided by 2 ,8:48
@8:17 sir why divided 2 ?
Its according to the scale bro
If rmp is not given?
Tq
But aese our problem ke video banae ne
didnt get how scale is calculate why its taken as 6cm = 150mm ?
Why are we using 6cm.to reo 150mm sir? This is confusing why and why not 4cm rep 150mm or 2cm rep 150mm or 12cm rep 150mm sir?
Answer quick pls sir
Hello bro.. y u divided with 2 ???????????????
Please why did you divide 0.8377 by 2. 0.8377/2 ???
why you draw ab perpendicular to AB in downward not in upward
why dd u draw 6 cm AD?
If theta is 90 degree how will be triangle.
13:43 mai perpendicular line upar kyo li ?
velocity is always perpendicular to the link
How velocity diagram draw.. From of space diagram.. How draw first a,d point and second point
Why we are take 6 CM ?
i love u sir
Sir pls so word bar bar repeat mt kijiyega video me
Kaun kaun Paper se 15 minute pehle dekh raha hai
Hindi sir hindi me bataye ....upar se gaya sab
Q2B=6.32cm; Q4C=8.89cm; Q2Q4=12.7cm; BC=12.7cm Q2B is turning uniformly clockwise at a speed of 1 rad/sec.
Find:
A. The Velocity of C when theta is equal to 15 degrees
B. The position and velocity of that point H on the center line of BC (Produced if necessary) which has the least velocity, when theta is equal to 15 degrees
C. The velocity of C and of the same point H when Theta is equal to 60 degrees and the value (or values) of theta when velocity of C is 0
Draw the graphical method of the velocity
Draw the required of C
notice please
Good explanation
Thanks
Thanks
Thanks