Statics: Lesson 42 - Intro to Centroid by Calculus Method, Flip the Strip Method
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This man is carrying my statics grade
just wish id found him earlier
Same fr
fr, all Statics doctors in my college pale in comparison to him.
Protect this man at all costs!
Extremely concise and approachable lessons. Many of my professors could take a page out of your book. Thanks for the knowledge!
Hanson > my statics professor on tenure
this guy gave me a better understanding of statics in 5 minutes than my statics prof did in 4 weeks
You explain the calculus very well. For a subject which usually throws people off, that explanation was crystal clear
how can he make such a complicated topic seem so easy, magic man
This guy just took 15 minutes to teach me what my calc professor couldn't in 2 hours
Thank you so much sir! I learned clearly the concept here in statics. I'm hoping for your another lessons all about strength of materials since I am taking up this in my course this school yr!
DR. Hanson, thank you for a fantastic introduction to Centroid by the Method of Calculus. Calculus is important for all upper level courses.
couldn't be more grateful for these videos ! Thank you so much.
Thank you so much sir! Easier for me to understand ✨ can't wait to see your another lesson!!!
The 2 dislikes are my calc professors cuz hes doing their job better
I saw so many videos about centroids, also went back to my calculus and statics notes and could not understand them! But you've explained it so well, sir. Thank you so much!
Such a perfect example! Thank you!!! Love all your videosss!!
This method is way more understandable
thank you
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Spectacular!
fantastic video this is quite easy to understand for such a hard topic
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Good lesson!
So why didn't you say H-y for the height of the strip while getting the x-value of the centriod
thank u sir
THE BEST
nice
sometimes I just come here to hear this man talking even though I don't have that on my exam
From Philippines.
For arc lenth
We take dy/dx of y equation then put value in and get DL a tiny lenth
DL square = dx sq + dy sq
Then we integrate using x bar y bar formula
But in area y equation is itself area Don't take derivative then put x bar y bar
Put direct value of y as area
And dont forget y is always half when you finding y bar how know I put equation in my calculate and seen graph it shows hole area
Hello guys, why do we integrate only h/b, leaving off dX? Can anyone clear it pleaseeee
hi please thanks for the course i`m done and i`m gonna write exams tomorrow
God bless you so much
One more thing
If you integrat y equation you will get area in numbers like 42ft square
When you integrated dA in terms of x, you didn't subtract the height (left it as h/b * x). But you subtracted the height when you integrated dA in terms of y (b - b/h * y). Why is this the case?
Because the triangle sits on the x-axis.
In terms of x, the strip gets longer with an increasing x: h/b*x
In terms of y, the strip gets shorter with an increasing x: b - h/b*x
number
1
how am I understanding it here but not in class?
goat
Lesa Amipale yama ❤ CEE 2219 yapa UNZA tiwa lila
>>>>Anna Howard
Sir, you explain very fast, for example, we know the equation of y=mx+b, but you don't explain especially how to get y=(h/b)x step by step, you just skipped and only indicated h over b and that's it, students need more details of concepts to get the points.
M is for mountain 😂
I was at problem 54 was doing ok but not satisfied I came back to problem 1 which is arc lenth (1, 1)
I want share it with ur students coz what ever I learned it becoz of you if am wrong plz someone correct me ok then arc length (1,1) with y^2=x^3
^ is power
Equation for centroid is x bar = intigraation of tiny x × tiny L
Who we can find tiny L at point where curve is straight
We can find it by ( chang in y ÷change in x
We have equation y^2= x^3
If we put 1 value of x then value of y is 1/2
dividing both we will get .5 which is change mean tiny L or delta L
Put this value in to x bar equation on top I wrote
We will get .5 x bar which is close to book answer .54 but correct why ?
Second
We have equation y^2 = x^3
If we take derivative of y we will get tiny L or delta L =1.5 under root x
If we put this value of dL in x bar equation then answer is .6 which also close to .54 but not correct
Why?
Third and correct ans
dL squar = dx square +dy square
Square root both side
Divide and multiply inside root by dx to eliminate dx
Root of 1 + (dy/dx )^2 left
Take derivative of dy put in
Get dL and put x bar equation answer is right
We can Get dL value from all three methods but why only square roots one is come with correct ans which .54