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Statics: Lesson 50 - Trusses, How to Find a Zero Force Member, Method of Joints
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- čas přidán 18. 06. 2020
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You don't know how good a teacher is until you lose'em
Like your's 🙂
Exactly.
My current teacher (in a related course that uses all this stuff but higher level) is pretty nice, but the stuff is just tough.
And this stuff... I can sit there for 6 hours not knowing something going across all sorts of resources, then sit here and in 5 minutes learn a crap ton on these videos.
I started watching this channel almost 2 years ago and am still dumbfounded by how well it works.
Too bad yours made you cook meth 💔
Had him as a professor, he was great!
school would have been easier
The fact that he solves the problem with us is what is so helpful to me. My professors use old solutions that sometimes have errors and they just say "this equals so and so" expecting me to know how they arrived at their answer. Dr. Hanson, thank you for TEACHING us your ways. I would be so lost without this channel.
I love this class because you actually teach us the tricks and that’s all i needed
Where you from
@@Forever-fun creep
"let's just do a couple of joints, and we're gonna be there!" - That's priceless! :D I wish my lecturers had been able to explain how to find a zero force member as well as you have. Many thanks!
DR. Hanson, thank you for solving a mammoth Trusses and Zero Force Member problem in mechanics. The explanation for this example is outstanding.
i love the way you simplify school,you make it easier....none gets bored with the way you teach
Learning statics is literally the only reason why I went to university, and here I am back to watching CZcams videos to learn its anyway! Subbed. This is so much more useful than mindlessly memorizing trigonometric identities and functions just so you can write a series of equations to prove that the sky is blue.
I really enjoyed this this playlist , all the lessons were fun & engaging , thank you
Great video Jeff, I was so confused about zero force members and you did a great job explaining and solving the problem! Keep it up!
Wonderful statics lessons!! really taking the time to explain the problems along with a good sense of humor :))
You have helped me so much with these videos professor! Thank you so much!!! :)
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thank you for explaining the steps and showing how they apply properly. this theory will help me in my quiz. tho i like my professor as a person....he doesn't teach very clear....this helped a lot!
Thank you so much!
You helped us a lot.Thank you professor Jeff Hanson
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Studying for my PE, this is great.
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xD Very helpful for the near future! Structural analysis feels like statics all over again but on steroids.
thanks
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thank you professor , this vid was really helpful with visualizing zero force members i was struggling at ❤❤
I have a very nice professor, however we have never gone over how to visually identify zero force members. This is amazing stuff.
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good one
this guy just rescued before the engineering statics quiz
Increíble señor es un master d l. Carpintería no hay quien le pueda ganar
He used to have this wooden truss system model or something. Anyone know which video he uses it in? or perhaps where to buy something like that? I'd like to have some models to play with so I don't have to imagine everythng in my head :-)
Can you take sum of moments when solving by method of joints? Or can you only use sum of forces in the x-y direction at the joint in question?
Me about 10 hours before an exam:
maybe this truss thing is interesting
Lmao I got a statics exam in 2 hours and am totally banking on this guys lectures to carry me through it.
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@@sebastiancurry3714 not great got a 65
@@dirtmoto2780 its all good bro, thats not even that bad. If you would of started studying sooner, like a week or even more instead of 2 hours before you would of got an A most likely, keep grinding bro!
Yes sir! I really slacked during this summer semester, but I am ready to kick some ass in the fall!
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thank you
What about Ax when calculating forces in joint A?
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Thanks 😊 our teacher❤❤
This was an amazing video, thank you, I wish my professor was as good at teaching as you are.
For KJ and IJ you have it = 23.57kN C, but then on the FBD for joint J the arrows are in T. Just a little confused.
Can anyone confirm this alternative way of solving for KD and KJ: @12:20, we could instead rotate the axis so that x and y align with KD on the y-axis and KJ on the x-axis, and then solve from that?
I think typically we can't do that cause KD and KJ aren’t perpendicular
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How do we determine the direction of the forces please
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Sir I have a doubt. KL and KJ are colinear and why they have different and opposite loads. Please.
Why didn't we incorporate Ax when finding the sum of forces in Fx for AB?
i had the same question, but i doubt itll be sorted by the time i have my exam tomorrow, hah.
Had the same query. Likely because its a symmetric truss and we have the roller on one side (where reaction would only by along y-axis), and there are no external forces in x direction. Therefore on the pinned connection, the reaction along the x-direction would be zero.
How do we know whether kj is acting inwards or outwards??
Wow, 20mins for that scary truss!
It would've took me all the time of the exam😂😂😂
what happens when there's loading on the top?
I can't believe he actually solved this entire problem.
4:44 is actually crazy. He asked a question, looked at me to answer, and I answered "LB for starters!" He was like yea ok LB. What an incredible teacher to be able to read his students without even talking to them. insane
Thank you sir for this lecture 13:10
If i calculate Moment in G, I have 10KN*8m + 20KN*6m + 10KN*4m - Ay*12m, where Ay=15KN. Although it makes sense to have both Ay and Gy be 20KN each, the formula gives a different result. What am I missing?
May i ask sir, Why didnt you used joint D instead of J?
Sir at point A why it only has vertical reaction and not horizontal(Ax) it is not roller support
Can I get a PDF past questions for the mechanic mathematics..?
excuse me sir Jeff how did you get the KJ and the KD i dont quite get it what you input in your calculator
They're simultaneous equations. Scientific calculators can solve them.
God bless u
hyee. sorry, but may i ask is there no reaction force (ax) at joint a ? why is that ?
I finally found out which members are zero force in my example, I struggle with finding them...
Zero force members are simply forces that has no reaction to equate the joint to zero force in any direction.
in the system eq i get KJ 22.37 and KD -14.14
i dont know how to get the kj and kd, help please
How to use calculator when finding KD and KJ value? Send helpppp
can someone solve for KJ and KD without using the system calculator thing he is talking about (manually). im trying to find ways but im hitting a roadblock. help
Big man
Very trussworthy info.
Why at the end you did not count the force in the Y direction going down that is equal to 20 KN and will make JD be 13.3 KN? Please let me know if it was just a little mistake or I am missing something.
Idk if you still need this but if we do the FBD at joint D and do the sum of the forces in the y direction it would be
[DJ - 20 - 7.46sin63.4 - 7.46sin63.4 = 0]
Therefore DJ = 33.341
It looks like you forgot to add the 20KN force
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Thank you!
I hope I finally find my answer. I am confused I have read almost the whole day. Adult education is indeed hard.
when solving this particular example why didn’t we find the x component at joint A?
Because there are no applied forces that have an X component to them, so he found the Reaction at A in the X to also be zero (There's nothing to react to).
I See his calc for JD, but by analysis, why isnt it a ZFM?
I found it!
How do you know the angles?🤔
Truss me, this video is useful
19:50 you don't need to subtract 20 kN force?
If I understand it, 20kN is not acting on joint J but on joint D so it's not considered there.
How did he solve for KJ and KD when both equations had 2 unknowns?
Simultaneous linear equations although u would've prolly known by now
why isnt force dj =20kn?
those roller pin combos always threw me cause I thought there had to be a force or a leg would kick out, then I remembered for that to happen a member needs to break and im supposed to prevent that.
i love you
7:44 how did you know it was 45?
I used Jeff's videos while in my statics class, and here i am again studying for my FE. Still one of the best Professors on CZcams.