I missed a question about it in Uworld for USMLE step 1, and their explanation could not help me understand the concept, and you did. Thank you so very much!
I couldn't understand clearly in my class and was very tensed about it cause my exam is on thrusday.But your explanation gave me relief.very effective video......
radioimmunoassay can be employed for the detection of insulin in blood plasma for this 125I labelled insulin is mixed and allowed to bind with a known concentration of anti insulin antibody. A known volume of patient blood plasma is then added to the conjugate and allowed to compete with the antigen binding site of antibody. the bound antigen is then separated from the unbound ones and radioactivity of free antigen is then measured by Gama counter . following are some the statement made about this essay . 1 the ratio of radioactive count for the unbound antigen to the bound one is more at the end of reaction. 2.the ratio of radioactive count for unbound antigen to the bound one is less at the end of the reaction. 3 the diabetic patient, the radioactive count for free antigen is less than that for a normal individual 4 A diabetic patient the radioactive count for the free antigen is more than that for the normal individual which of which of the above statement are true?....... Plz sir ans this question in some short explanation plzzzzzzzz
Thanx for giving positive response..you can either paytm us on 8830061003 or google pay on same number (UPI ID - saj.99999@oksbi) Your small help can make big diffrence.. Allah hafiz
sir , how this antibody is coated to the microtiter plate..?? and how does isotops are tag to particular antigen ??... plz ans i couldn't find from ne other book also
For coating , coating buffers like bicarbonate of pH 9 are used... for making particular molecular radiolabelled... radioactive nutrients are supplied to the producer cells
@Sajid Shaikh is there a way to determine unlabeled antigen or ligand concentration if there were only two solutions? In other words, the first scenario is only adding a known concentration of labeled antigen to some concentration of antibodies. The radioactivity is measured of bound antibody-antigen molecules after removing free antigen. Then, the experiment is repeated with an unknown amount of unlabeled ligand that is added after adding the same known amount of labeled antigen. Ki = kd = 7.4*10^-6 M and concentration of known labeled antigen = 7.4*10^-6 M. What is concentration of unlabeled antigen added in the repeat experiment? Also, radioactivity of bound antibody in the first experiment = 63000 cpm and radioactivity of bound antibody after removing free labeled and unlabeled antigen = 49000 cpm (counts per minute). I am not sure what Ki in this instance means, i.e. Ki = [Ag][Ab]/[AgAb] ? and kd = [Ag*][Ab]/[Ag*Ab]? (where Ag* = radiolabeled antigen) in which case [Ab] would cancel leaving [Ag]/[AbAg] = [Ag*]/[Ag*Ab]. However, I am not sure that is correct. At any rate, I am not sure how to use the information given in this problem. Please anyone let me know if you "see the light" on how to use this information to find concentration of unlabeled antigen [Ag]. Thanks.
Great explanation. One question though, Why is unlabeled antigen able to displace labeled Ag bound to Ab.... As in why is the unlabeled antigen winning the competition?
I'm assuming you know the concentration of the radio labeled antigens? Just saying if you take a blood serum sample how will you determine comparison antigen level without knowing the tagged antigens
Sajid, is seriously, your explanation and visual methods was SO AMAZING, thanks a lot!!!!
I have seen many videos on this topic but no one explained like this! this is such a nice explanation!!😊
I missed a question about it in Uworld for USMLE step 1, and their explanation could not help me understand the concept, and you did. Thank you so very much!
Omg YOU EXPLAINED THIS SO WELL. I get it now.
Very clear explanation! Thank you!
Most welcome
I couldn't understand clearly in my class and was very tensed about it cause my exam is on thrusday.But your explanation gave me relief.very effective video......
Thank you, this helped a lot! Excellent work! I'm studying in german, but I could still understand everything very well (:
Most wecome brother
Way to represent is excellent, covered all the major points in short video, Thankyou so much
most welcome
I'm very happy now, all my doubts on RIA are cleared, thank u so much sir..😊
Finally I understand actually what is this. Even in my university I didn't understand this
Thanks a lot. This has helped a lot with my physiology course
Best video on CZcams that cleared all concepts waoooo... Urdu version b bnaya kren plz apni videos k 😊
Your videos now helping in my csir net jrf preparation
Thank you ☺☺
Most welcome
Thank you so much ,saved at least an 2to 3 hours of time and energy....
I finally understood this technique, you made it very clear. thank you so much !!!
best explanation 😎👍👍and helpful for clearing the concept thoroughly 🤠🙏🙏
Sirjee u are genius the way u teach excellent after watching ur videos all doubts are crystal clear God bless u brother
Crystal clear explanation. Tysm!!
Wow !.. finally got it , amazing skills to aproach the topic 👏👏
Excellent explanation n clear understanding pictures tq so much sir
Excellent..
A thorough efforts in making us understand the core concept..
Thanku sir
Most welcome Pritpal .. would you like to help us by donating small amount to our channel? This will motivate us to make more free videos.
Wooooow super and clearly explanation 😎👍👌👏👏
You're amazing
I'm not speak your language but I understand your explanation because you are excellent ✔
Thanks sajid Bhai.....It really helped me during exam....
Most welcome akshay
*slowly claps* Well presented. Thank you, Sir. You are a legend.
Thank you very much for your explanation 🙂🤝
Thank you so much ! Your explanation on this topic is phenomenal.
Good job...perfect explanation...keep up the good work!! 👍
Excellent..precise and short explanation
Got it sir... plz explain about microparticle enzyme immune assay
You Sir are amazing.... Very wonderful explanation...
You are the better than everyone else 😍😍😍😍😍 shomu is also not that clear but hats off to u man
Learn immunology (live, online personal/group couching ) contact : saj.99999@gmail.com
Simpel clear and video wasn't too long, thank you!
Better than shomu's biology video.
U r right 👍
Sir u r simple and awesome teacher.....thank u for helping us.....🙏🙏🙏
Most welcome dayana
The part From 7:40 is where the problem has been solved and it's all clear now eventhough the accent is a little hard to understand .. thank u sir!!
Most welcome.. it hard to talk english for me
Very easy plus clearly explained.. thankyou so much sir
may GOD bless u...pls make more videos
This was very helpful and easy to understand. Thank you.
Perfect explanation! Thank you!
Most welcome mena.. would you like to help us by donating small amount to our channel? This will motivate us to make more free videos.
@@sajidmicrobiology Yes!
Thanx mena.. you can paytm us on 8830061003. Your small help can make big diffrence.
Incredible explanation, thank u 🙏🏻 😊
Most welcome razan .. would you like to help us by donating small amount to our channel? This will motivate us to make more free videos.
Why the labeled antigen is removed ? Is it have low affinity as compared to unknown antigen??
Very clear concept. 😊
Sir it was just amazing
Please keep on making such amazing vedios
Thanx sir ... u explained it in very easy way
Most welcome Shivani Duggal
Very good explanation thank you❤
Thanks bro you made me understand it so easy...jazakallah
Amazing explanation
i have watched many videos on youtube but no one can teach like you. thank u sir for well detailed explanation.
awessssommmme explanation and verrrry nic sir God bless u
Very nicely explained.. thank u so much🙂
wow i just loved it.
Very informative and your way of teaching is excellent 👍
Thanx.. whr r u from ?
@@sajidmicrobiology lahore
Ok
@@sajidmicrobiology sir how can we measure the radioactivity?
With the help of scintillation counter
thank you sajid . it is really amazing video .pls do more videos
Most welcome Sure...
thank you
Thanks a lot. Really well explained
Most welcome
ASSALAMUALAIKUM দাদা , খুব ভালো বোঝালেন , খুব ভালো লাগল
Great explanation
Thank you so much ✨
Thanks sajith
Love you this explains
Nice and amazing explanation... Thank you sir...
Sajid both ur name and video are great
Imran Malla Thanx ☺
Are u from Kashmir i think so
Maharashtra
you're a Lifesaver!
radioimmunoassay can be employed for the detection of insulin in blood plasma for this 125I labelled insulin is mixed and allowed to bind with a known concentration of anti insulin antibody. A known volume of patient blood plasma is then added to the conjugate and allowed to compete with the antigen binding site of antibody. the bound antigen is then separated from the unbound ones and radioactivity of free antigen is then measured by Gama counter .
following are some the statement made about this essay .
1 the ratio of radioactive count for the unbound antigen to the bound one is more at the end of reaction.
2.the ratio of radioactive count for unbound antigen to the bound one is less at the end of the reaction.
3 the diabetic patient, the radioactive count for free antigen is less than that for a normal individual
4 A diabetic patient the radioactive count for the free antigen is more than that for the normal individual
which of which of the above statement are true?....... Plz sir ans this question in some short explanation plzzzzzzzz
Option 1 and 4 seem to be correct ...
Thank u sir
Great explanation it helped me a lot.
Very nice explanation sir...but what is the washing agent we have to use in this process?
thank you Sajid- great explanation :)
May Allah bless you brother. very comprhensive
Thanks for appreciation..
Would you like to encourage our team by donating small amount (Rs. 5 to 100)?
@@sajidmicrobiology how can I donate?
Thanx for giving positive response..you can either paytm us on 8830061003 or google pay on same number (UPI ID - saj.99999@oksbi)
Your small help can make big diffrence..
Allah hafiz
THANK YOU!! Well explained!!
superb no wordzzzz
Thanx anisha... whr r u from ?
Nyc explanation sir
Amazing
Thank you so much
That's a great help, thank you.
Most welcome
Very well explained, thank you.
Simply explained.
Thank yu so much for this awesome video
Great explanation!
Realy thankful video......thank you sir
Excellent explanation sir 🤩
Awesome explanation!
Thanx... where r u from?
Thank you! Well explained
Most welcome
thank you! very well explained
It was just amaze👍plz upload video section of molecular biology 😓
Sure ...rashmi negi
Thank u sir!😄
Very good teaching🙂👌
Very good explanation
Thanx tanisha
sir , how this antibody is coated to the microtiter plate..?? and how does isotops are tag to particular antigen ??... plz ans i couldn't find from ne other book also
For coating , coating buffers like bicarbonate of pH 9 are used... for making particular molecular radiolabelled... radioactive nutrients are supplied to the producer cells
THANK YOU!
Whr r u from?
@@sajidmicrobiology ukraine, your video really helped me to prepare for a presentation about RIA( immunology at the university)
Glad to know
@Sajid Shaikh
is there a way to determine unlabeled antigen or ligand concentration if there were only two solutions? In other words, the first scenario is only adding a known concentration of labeled antigen to some concentration of antibodies. The radioactivity is measured of bound antibody-antigen molecules after removing free antigen. Then, the experiment is repeated with an unknown amount of unlabeled ligand that is added after adding the same known amount of labeled antigen. Ki = kd = 7.4*10^-6 M and concentration of known labeled antigen = 7.4*10^-6 M. What is concentration of unlabeled antigen added in the repeat experiment? Also, radioactivity of bound antibody in the first experiment = 63000 cpm and radioactivity of bound antibody after removing free labeled and unlabeled antigen = 49000 cpm (counts per minute).
I am not sure what Ki in this instance means, i.e. Ki = [Ag][Ab]/[AgAb] ? and kd = [Ag*][Ab]/[Ag*Ab]? (where Ag* = radiolabeled antigen) in which case [Ab] would cancel leaving [Ag]/[AbAg] = [Ag*]/[Ag*Ab]. However, I am not sure that is correct.
At any rate, I am not sure how to use the information given in this problem. Please anyone let me know if you "see the light" on how to use this information to find concentration of unlabeled antigen [Ag].
Thanks.
Great explanation. One question though, Why is unlabeled antigen able to displace labeled Ag bound to Ab.... As in why is the unlabeled antigen winning the competition?
Yes... it's due to competition... like substrate of enzyme and inhibitor
@@sajidmicrobiology
Ohh so it's basically due to high concentration of unlabelled Ag vs labelled one... Thanks
Wonderful explanation😊😘👍
I'm assuming you know the concentration of the radio labeled antigens? Just saying if you take a blood serum sample how will you determine comparison antigen level without knowing the tagged antigens
Tq so much I'm clearly understand now
Nice explanation. Sir please make a video on RFLP (POLYMORPHISM OF RESTRICTION FRAGMENT)
Sure Raghuveer
That was excellent! Thank you.
Thank you. It really helps.
Just awesome 💯
Excellent video... 👏👏👏👏
You r a life saver
Contact for Personal or group immunology crash course (online)
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Nice explanation and make a video on fermentation cultures
Thank you very very much
Very good video.. thank you😊