Since the compound is having only one chiral center, switching of only two groups will give an optical isomer which is an enantiomeric pair therefore it is a mirror image. In solid wedge and dashed line they may not appear as mirror images but just by rotation we can confirm that they are mirror images. Thank you.
Normally structures are drawn such that lowest priority group is shown to attached by either wedge or dash. But if that group present in plane, still we can rotate the structure such that the groups in plane become attached by wedge and dash and those groups out of the plane are then come within the plane. We have to carefully imagine the structure and can convert it to the required orientation.
Even any group other than hydrogen with least priority is there in structure, then generally it is placed in vertical line at bottom while giving R,S configuration.
Nearly 6 hours of uni lectures on this and you explained it better in 12 minutes,, thank you so much
Can i know which country you belong to?
U explained very well... crystal clear...thank you so much
Sir you have explained very well.
Really appreciating.
Last example is quite helpful ❤️. Thank You
Thank you so much sir... your explanation cleared all my doubts
Glad to hear that. You are most welcome.
sir video is very nice .it is very easy to understand .please upload videos on stereoisomers
Sir u make this topic very easy for us thanku so much sir🙏🙏🙏
It's my pleasure. Thank you
thanks you so much for this short and crisp video sir
ur voice is so clear that the concept is so esasier to understand
Sir you have given this lecture mashaallah so well that thank you sir for clearing all our concepts
I am not only inspired in chemistry but also a new way to speak English.
very nicely explained, thankyou very much
best👏👏👏
Outstanding explanation 👍🥰🥰
Helped Very Much! Thank You Sir
Thanks a lot sir for clearing my doubt
Thank u so much sir....Your vedio has helped me for understanding this concept very well😍😍😍
Glad to hear that, thanks for watching.
Sir, in example 3,can we use parallel transition instead of retromethod?
Outstanding explation
Thank you very much sir
❤️❤️❤️❤️❤️❤️❤️❤️❤️
Big fan professor
Awesome Interpretation ❤
Thanks a lot!
Superb I understand well 👍
thank u bhaiya very nice lecture
Besttttt ❤
Tnk u so much
Welcome. Thanks for watching
Amazing explanation 👏tq sir
Thank you ❤️, however I have not understood the parallel transition in example one. Why is it that position 4 is interchanged with 3 and not 2?
Thanx alot sir! #respect✌🏻
Most welcome
Thank you so much 🙏🏼
😊
Thanks a lot Sir!
Thank you sir🙏
12 golden mins!
❤
Crystal clear
Last two structures are not mirror images to each other. They may called as isomers but not mirror images
Since the compound is having only one chiral center, switching of only two groups will give an optical isomer which is an enantiomeric pair therefore it is a mirror image. In solid wedge and dashed line they may not appear as mirror images but just by rotation we can confirm that they are mirror images. Thank you.
Thanku sir
Thanks sir
very clear sr...if in dash wedge lowest priority group present in plane what we need to do?
Normally structures are drawn such that lowest priority group is shown to attached by either wedge or dash. But if that group present in plane, still we can rotate the structure such that the groups in plane become attached by wedge and dash and those groups out of the plane are then come within the plane. We have to carefully imagine the structure and can convert it to the required orientation.
tq for very valuble and instant reply sr
Sir video on E Z nomenclature
Definitely, we will upload very soon. Thank you.
Plz sir give lecture video on E And Z configuration
What are the iupac names of each compound?
But sir last mein original ki bhi R nhi hogi,? ... Plz 🙏 clear my doubt sir... It's a humble request
Sir like h2 ki jagah some other group present hai.. Then in tht condition also least priority compound ko niche rkhenge?
Even any group other than hydrogen with least priority is there in structure, then generally it is placed in vertical line at bottom while giving R,S configuration.
Thankyou sir 😊
In example 3 the two structures are not mirror images
That what I was thinking💭