thank you! My brain hurts from trying to assume so many rules with no prior knowledge. You make the rules seem so simple I can finally get through my hw like a checklist.
Hi, thank you so much for such a valuable video. The explanations are clear and understandable to me. R and S configuration isn't sinister-looking for me anymore)
sorry why for problem 2 do you have the second priority carbon in the ring connected to OO and C. I know its a double bond but I figured you'd just count 2 O's but you also count an extra C? Is this always the case? thank you for your advice!!
Thank you very much for this video. Could you please make a video about how to study organic chemistry and what are the easier and more informative resources for it ? (Especially for pharmacy students)
That's a great suggestion! My best advice would be to do lots of practice problems, using your textbook or old exams if your prof gives you access to them. And study with friends because it will give you different perspectives on how to approach the problems :)
Hi, I have a question! In the "double swap" exercise the initial configuration of the molecule is S (Cl -> F -> et) but at the end, when we put the Hydrogen to the back we have the R configuration. Why do we obtain the opposite configuration even if we did 2 swaps? I can't really get it 😢
Through Fischer project can every rs problems be possibley solved? I solve actually transfering the compound to Fischer but i don't know,is every rs problems possible or not through Fischer..
One question In the aminoacid cysteine we have 4 different Atoms attached to the stereogenic carbon 1. N (NH3) 2. C(A) (CH2 - SH) 3. C(B) (COOH) 4. H Apparently at first glance we see that N > C(A) = C(B) > H. So we have for sure that nitrogen is in first priority while hydrogen is in fourth Secondly we are gonna compare Carbons A and B and we see that Carbon A is attached to 2 hydrogens and one sulfur (a.n = 18) On the other hand we see that Carbon B has one double bond and one single bond with oxygen. You write that to assign a priority to an atom that is part of multiple bond, treat a multiply bonded atom as an equivalent number of signly bonded atoms. CO2 ---> CO3 But if we do that in the Carbon B we will have a greater atomic number than 18. Therefore the configuration of cysteine will be S and not R. What am i doing wrong then??
CZcams recommended me your video and now I am totally sure this is going to save my next Organic Chemistry exam. Thank you sm!!
thank you! My brain hurts from trying to assume so many rules with no prior knowledge. You make the rules seem so simple I can finally get through my hw like a checklist.
Best explanation I have found so far. Was really struggling with putting the lowest priority group in the back, now it seems easy!
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Hi, thank you so much for such a valuable video. The explanations are clear and understandable to me. R and S configuration isn't sinister-looking for me anymore)
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Thank you so much for these helpful videos !
BEST VIDEO IN CZcams!!!
How is Chiral Carbon at left side is R??? This is S
Why did u not count HHH instead of CHHH???
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sorry why for problem 2 do you have the second priority carbon in the ring connected to OO and C. I know its a double bond but I figured you'd just count 2 O's but you also count an extra C? Is this always the case? thank you for your advice!!
Thank you very much for this video. Could you please make a video about how to study organic chemistry and what are the easier and more informative resources for it ? (Especially for pharmacy students)
That's a great suggestion! My best advice would be to do lots of practice problems, using your textbook or old exams if your prof gives you access to them. And study with friends because it will give you different perspectives on how to approach the problems :)
@@ConfidentChemistry Thank you again .
8:20 Please I don't know how or why CHH tops CHHH
I thought CHHH has a higher atomic number than CHH
Help me out please
Pls make more videos in organic chemistry...
Hi, I have a question! In the "double swap" exercise the initial configuration of the molecule is S (Cl -> F -> et) but at the end, when we put the Hydrogen to the back we have the R configuration. Why do we obtain the opposite configuration even if we did 2 swaps? I can't really get it 😢
Through Fischer project can every rs problems be possibley solved? I solve actually transfering the compound to Fischer but i don't know,is every rs problems possible or not through Fischer..
How can I access your slides
It was noice.
One question
In the aminoacid cysteine we have 4 different Atoms attached to the stereogenic carbon
1. N (NH3)
2. C(A) (CH2 - SH)
3. C(B) (COOH)
4. H
Apparently at first glance we see that N > C(A) = C(B) > H. So we have for sure that nitrogen is in first priority while hydrogen is in fourth
Secondly we are gonna compare Carbons A and B and we see that Carbon A is attached to 2 hydrogens and one sulfur (a.n = 18)
On the other hand we see that Carbon B has one double bond and one single bond with oxygen.
You write that to assign a priority to an atom that is part of multiple bond, treat a multiply bonded atom as an equivalent number of signly bonded atoms.
CO2 ---> CO3
But if we do that in the Carbon B we will have a greater atomic number than 18. Therefore the configuration of cysteine will be S and not R.
What am i doing wrong then??
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