A Sudoku Genius Recommended A Puzzle...
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- čas přidán 3. 06. 2024
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** TODAY'S PUZZLE **
It's rare a sudoku is so good that it causes one of the giants of the sudoku world to recommend it but that's what happened today. Jay Dyer thought this puzzle was very interesting and SHE IS RIGHT! Featuring a brand new twist on the Circle ruleset, ThePedallingPianist's Circular Unreasoning is absolutely wonderful.
Play the puzzle at the following link:
sudokupad.app/4mtPGFb6dm
Rules:
Normal sudoku rules apply. Digits along an arrow must sum to the digit in that arrow's circle. A digit in a circle shows how many circles DO NOT contain that digit. Additionally, a digit on an arrow shows how many arrows DO NOT contain that digit.
The Maths Advent Calendar mentioned by Simon in the video introduction can be found here:
www.mathekalender.de/wp/
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▶ Contents Of This Video ◀
0:00 Theme Music & Puzzle Introduction
1:22 The Maths Advent Calendar
2:52 Thanks For Watching Our Chants of Sennaar 2nd Stream
3:37 New Fog-Of-War Kickstarter NEW PUZZLE UNLOCKED
4:38 Happy Birthdays
6:44 Rules
9:00 Start of Solve: Let's Get Cracking
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Thank you, this was a wonderful surprise! A recommendation from Jay Dyer is high praise indeed!
Alannah and Orla spent a bit longer in hospital than hoped, but they are now both very happy and healthy at home. Thankfully they don't mind me fitting in a bit of puzzle construction between nappy changes and feeds!
I owe huge credit to Marty Sears and ViKingPrime for not only testing but also inspiring this puzzle. Circular Reasoning, which you did indeed solve on this channel, was a Marty puzzle, and ViKingPrime introduced me to the idea of anti-circles. He is an exceptional constructor and lovely human, and really must be featured more often on the channel! Expect a recommendation or two in your inbox very soon...
Funnily enough, Circular Unreasoning was one of my least favourite puzzles to set, because although the maths in the break-in was really satisfying to find, that was only the first 10% of the construction process. The next 89% was just a grind trying to find a nice layout of the arrows that was unique and humanly solvable, so I'm glad the hard work paid off and the puzzle has been received so well!
The final 1% was publishing it to Logic Masters Germany then immediately realising that I could swap two arrows in columns 1 and 2 in order to achieve a second 3 in the corner, so I hurriedly deactivated the puzzle and fixed my appalling oversight.
Also, I can confirm that your theory about what happens to the people who spend too much time with me in real life is scarily accurate...
"Alannah and Orla spent a bit longer in hospital than hoped, but they are now both very happy and healthy at home."
That sentence had a worrying start but a wonderful ending. So glad to hear it.
This was a beautiful puzzle, and I hope that your daughter will grow up to share your enthusiasm for puzzles!
You can either be first or be best, and regardless of where the idea comes from, I think we can all agree - you executed on the idea in the best way possible. Amazing work, truly.
This was a beautiful puzzle. Never seen anything so intricate in an approachable manner. I probably would never attempt to solve it but just seeing the degree of reasoning was not terribly outlandish that anyone with a love for logic puzzles could easily approach and appreciate it. Well done!
That was one of my all-time favourite puzzles. Just the right difficulty for me and some fantastic logic. Thanks ThePeddlingPianist - brilliant puzzle.
I always find it fascinating that Simon manages to read the most confusing and weird ruleset, go "Huh?" and then 10 seconds later start to flawlessly solve that puzzle as if it were the most normal ruleset ever.
The ruleset's consequences turned out a lot simpler than I thought they would be.
The column logic was so helpful, but even more so if he would have continued with 3's! Once 3's were eliminated from rows 6 and 9 you can fill in the rest a bit quicker
hard to understand why he didnt continue it. would have made it simpler
It's always a real bummer when he announces the next step, everyone sees it and then he wanders off aimlessly in another direction😅
(Or when he's doing sudoku and suddenly stops while staring at a pencilmark next to it's big digit, then says "I'm stuck" and fills the digit in by another constraint ten - thirty minutes later)
This puzzle is bananas. I love it. PedallingPianist has once again proven himself to be one of the true greats of puzzle construction.
What I really love about this puzzle, and what adds to its approachability (?), is that you can solve it in so many different ways based on the core concept. And they are all equally beautiful. You can count low digits on arrows, like Simon did 1s and 2s. Or high digits, placing some 6-circles before you know anything else basically. Or map out the colors of the circles, and the low digits that don't go on their arrows. Just an astonishing creation!
Another much deserved feature for The PedallingPianist. As I commented on LMD, this is my favourite of his puzzles. The core deduction of what the circles and arrows must contain is so clean and beautiful. And the way the puzzle flows allowing them to be slowly located one by one is satisfying and miraculous.
Simon's solve path was a bit different to mine... I used the idea that he started off using when he initially coloured all the arrows, but carried on down that route of focusing on locating the three 4s, two 3s and one 2 that don't appear on an arrow. Finding some of them helped me get started, but actually SImon's eventual method was probably easier and cleaner. Another joyous bit of solving from Simon.
Thanks Stu for taking the time to slog it out and find a workable arrangement of arrows which didn't need any other clues to disambiguate anything, It was totally worth the effort! The original draft that had an extra disambiguator clue was still very fun, but your perfectionist urge to get rid of that clue, and success in doing so, took this puzzle into the realm of a memorable classic.
When I created Circular Reasoning 2 months ago I never could have predicted that it would inspire other puzzles as fantastic as this, but I'm very happy it has.
Also, anti-circles is a brilliant idea by ViKingPrime, and I will no doubt be exploring them myself in the not too distant future.
I look forward to the beautiful fallout of a Marty Sears v. ThePedallingPianist sudoku arms race. The two of you trying to top each other is going to make for some incredible puzzles.
I did something similar to your initial method I think, with an idea that Simon came upon about halfway through the video. I did colour blue and orange, but I coloured the low digits not on arrows as green instead, because I thought they would be important in particular. You can use the 9 arrow to identify that the 3 other arrows in columns 1-3 are all distinct, so one each of 6, 7, and 8. Then in columns 4-6, notice that the only low digits not on arrows are all in column 6. Therefore, the arrows are all missing a different digit (the digits off arrows in c6), and are also all distinct. We've now accounted for the 9 arrow, and two each of the 6, 7, and 8 arrows. Hence columns 7-9 must contain two 6 arrows and a 7 arrow. Presuming you've already found most of the 1's, you can identify which of those arrows must be the one different from both of the other two, and you have the digits in those circles.
15:20 Simon: I'm now wondering whether the idea of this puzzle ... is to color everything.
Simon's dictionary: wonder: see hope.
my solve for this went completely differently than simons. after the math on the numbers letting us know the circles are all 6-9 and the arrows are all 1-4, you can look at the arrows in the first 3 cols similar to how simon did it at 33:25 except that the arrow in row 9 is also different from the other 3 by the same reasoning (every cell on an arrow sees a different low digit in box 7 and so have to sum to a different total), hence using up the only 9 in a circle. all other circles need a 1 on the arrow, which gives us most of the 1s, in particular the one in r8c6. looking at the arrows in cols 456, we see that there are 4 in each of col 45 so they add to 10, plus the 1 in col 6, means the circles add to 21. 21 being odd needs an odd number of odd numbers in the sum, i.e. 1 or 3 7s. we can't have 3 7s since we need 2 3s on the arrows, so we have 1 7 and the other 2 circles add to 14, and so are a 68 pair. that's our 2nd 8, so we cant have any in the last 3 cols. we need 2 6s and 1 7 in the last 3 cols, and since col 8 has one of each, r5c7 must be a 6. with that and most of the 1's placed, we can fill in most of the arrows/circles.
This was one of those puzzles that my brain just grasped quickly and I went with it. Finished in just under 20m. Started with counting 10 arrows and immediately noticing they are all 6789. My thought process: There can't be 10 arrows with a 1, so one is a 234 = 9 -> With a 9 in a circle, it has to be the only one -> I then realized the "counter digit" logic that there were four 6s...one 9 -> I did a quick aide memoir as well to see the 123, 124, 134, 234 makeup of the arrows. Fully pencil marked the circles and arrows. Added blue/orange, but never really used that. My brain then went to "all 9 boxes need a 1, so the 9 arrow can't be in boxes 2, 3, 5, 6, 8 (the full arrow there), or 9. That's when I realized there were six columns with four arrow cells, one more with 3, one more with 2, and one more with 1. And I was just very quickly able to fill in the arrow digits/circles. Noticing things like "if there's a 3 on the arrow, it can't be 7" or "if there's a 4, it can't be a 6", etc. helped a little along the way. Once the arrows were done, the remaining "classic" sudoku was easy. The two 3s in the corner was a great touch!
I'm generally slow at sudoku solving, but I definitely found this. I looked at boxes first, and there weren't enough with four arrow cells, so I turned to columns next. Sure enough, six with all four, then columns with three, two, and one. It was a really good start!
I was so worried about that example 2 at the beginning. Simon seemed to be completely ignoring its existence and I had visions of it getting mixed into the puzzle.
at 36:46 there is an easier way to solve the puzzle. The same way Simon got the 1's and 2s, you can now ask which colums do not have a 3 on an arrow. The answer is columns 6 and 9. Therefore any other 3s in the puzzle must be on an arrow. Therefore R8C7 must be a 3. You then get a 4 is R8C4, a 3 in R2C4, a 4 in R2C3. You can then compare arrows and circles to figure the rest of the solution.
Lovely puzzle! I had a different strategy. I placed the 9 in the circle as Simon did. Then I observed that the three circles on the left side have different combinations of digits, so they are one complete set of (6,7,8).
Next, looking at the three circles in the middle, their arrows are all in two columns, and they have two 4s. They're also a set of (6,7,8). That means the three circles to the right must be (6,6,7), and the circle in box 6 contains a 6.
This was also my approach and that 6 in Box 6 was my first digit. 😃
I took the same approach!
I'm a bit confused that Simon gave up on following the low digits after the 2s. In column 6&9 there were no options for a 3 on an arrow and by sodoku one of the four arrows in column 1 to 3 can't have a 3 on it. Therefore column 7 must have a 3 on the third blue cell.
Great little puzzle. Very interested that my first digit was one you didn't get until 44:46.
Solution spoilers below:
Once I worked out there were six 4s on arrow cells, I saw that there were six columns with four arrow cells on them. That meant I could eliminate 4s from the arrow cells in the remaining columns (columns 6, 7 and 9). Once that's done, the 4 in Row 8 is given.
44:27 i bursted out laughing at the fact he stated "got to be more diligent with shading in my 3s and 4s" and still puts in 3 in the row with a 3
Solved it in 16:09, and I completely forgot about the last rule and did not use it at all 😅 the max the circles can add up to is 9x1+8x2+7x3+6x4 given the inverse circles rule, which totals 70 (actually that is the only configuration for the circle cells given that they are all 3 cell arrows). The min the arrow cells can add up to is also 70. So all the arrow cells are 1234, and it just flowed from there. Now I'm wondering if I missed something in my logic 😅😅
I did it the same way, I don't think there's any logical flaw. I think the last rule is innecesary lol
How did you get a minimum of 70 for 30 digits?
By my count, one of the 8s could have been a 125 instead of a 134
You can split the arrows into 6 sets of 4 digits for 60, and the last 6 digits you have are a set of 3 a set of 2 and a single digit, min = 6 + 3 + 1, so total is 60+10 = 70 as the min. @@petergerlagh9858
@@petergerlagh9858there are 4 arrow cells in columns 1 to 5 and 8, so each of those add up to 10 at a min, which totals 60. Then you add the remaining cells: 1 from column 6, 1+2+3=6 in column 7, and 1+2=3 from column 9, for a min total of 70. So all the arrow cells have to be minimized (:
I wonder if there’s a constructor named ‘scrambled brains’, or if that’s a name just for the audience. I feel like I have scrambled brains! Just when you get your head around a new rule set, someone inverses the rule set!
I thought that there was a slightly simpler path. After the Aide Memoire, the number of 6,7,8 and 9 circles was known - and the sum of all circles is 70. It was also clear that there are only 4 digits on the arrows - 1, 2, 3, and 4. Pencil marking these, the minimum total (going by the columns) is 70! That immediately allows us to say that this is the configuration we need! So, in columns 1, 2, 3, 4, 5 and 8 - we have all 1,2,3,4. In column 6, we have only a 1, in colmn 7, it is a 1,2,3 and column 9, it is 1 and 2.
Solving from that, we can place about 15 to 20 digits on the arrows, and 4 of the arrow sums quite easily. (Easy for me - would have been super easy for Mark / Simon). Then, from there on - with the support of the information in the aide memoire (counts of totals, and the supporting combinations), I could finally solve the sudoku - again fairly easily.
A really brilliant puzzle. It was very helpful to recognize quickly, that there are only 1-4 on the arrows.
Rules: 07:18
Let's Get Cracking: 09:01
Simon's time: 40m23s
Puzzle Solved: 49:24
What about this video's Top Tier Simarkisms?!
Three In the Corner: 5x (40:48, 43:00, 45:36, 45:45)
Bobbins: 2x (21:03, 40:28)
Maverick: 1x (08:11)
And how about this video's Simarkisms?!
Ah: 12x (03:17, 11:41, 15:53, 18:51, 20:14, 20:14, 20:18, 37:08, 37:08, 41:29, 44:50, 49:05)
Beautiful: 6x (04:02, 04:47, 15:11, 21:36, 33:39, 38:24)
Hang On: 6x (11:48, 19:27, 19:27, 25:34, 30:53, 41:29)
By Sudoku: 5x (22:07, 36:49, 39:51, 40:19, 47:29)
Weird: 5x (04:39, 11:00, 11:00, 18:45, 21:36)
Bother: 4x (41:41, 41:41, 41:41, 41:41)
Brilliant: 4x (03:11, 06:34, 47:47, 47:49)
Sorry: 2x (20:18, 48:26)
In the Spotlight: 2x (43:03, 45:43)
Surely: 2x (15:40, 47:54)
Obviously: 2x (04:05, 41:12)
What Does This Mean?: 2x (27:26, 40:01)
Cake!: 2x (05:00, 05:04)
Goodness: 1x (09:06)
Clever: 1x (27:35)
Lovely: 1x (04:57)
Elegant: 1x (33:13)
Going Mad: 1x (26:19)
Bonkers: 1x (15:08)
Magnificent: 1x (49:31)
In Fact: 1x (12:37)
Whoopsie: 1x (46:56)
Progress: 1x (03:02)
That's Huge: 1x (36:31)
Have a Think: 1x (33:03)
Triangular Number: 1x (10:13)
Most popular number(>9), digit and colour this video:
Ten (11 mentions)
Two (73 mentions)
Green (25 mentions)
Antithesis Battles:
Low (10) - High (8)
Even (2) - Odd (0)
Column (42) - Row (10)
FAQ:
Q1: You missed something!
A1: That could very well be the case! Human speech can be hard to understand for computers like me! Point out the ones that I missed and maybe I'll learn!
Q2: Can you do this for another channel?
A2: I've been thinking about that and wrote some code to make that possible. Let me know which channel you think would be a good fit!
ur a life saver
Thank you for making these lists! They contain the polite ways to express dismay without using expletives - good to write down and remember! 😄
I was watching you shade relating different numbers (something I'm loathe to do myself)... when I saw it (the 4 green circles) which led me to finish the puzzle. When I came back to finish the video, I sat waiting for your epiphany, and you did not disappoint. Thank you for the videos; getting help when I'm all out of ideas really makes the puzzles fun to do.
31:35 for me. Wow. Usually I never comment, but this puzzle was just astonishing. Such a simple configuration on the usual ruleset, I didn’t think much of it but it turned out perfectly!
What I really liked about this puzzle was how original the logic was. Kudos to the setter.
This was a great one!! I had a little bit of a hard time flipping the numbers tho, making me initially go down a wrong path.
And WOW we solved this differently. I didn't do the 678 coloring.
Surprising to see you "miss" the path. Following were the 6 arrow sums could be:
One in the 4 arrows in the left boxes.
One in the 3 arrows in the middle boxes, cuz 4 was on two arrows in c4 and c5
And two in the right boxes, which forces one in r5c7, and the puzzle opens from there
So fun and interesting. I watched the first bit of the video to see how to understand the rules, then paused for a long while and got quite a bit of the way through. But then, Simon, I just paused my solve to come back to the video because I love to watch you solve these. Thanks so much.
Wanted to wish you a wonderful , happy Thanksgiving!! Thankful for you, who you are and what you mean to this community!!
Thank you, David, and Happy Thankgiving to you and yours, too. I think that there are several folks who help set the tone of positivity and genuine appreciation here, and you are one of the top ones!@@davidrattner9
took me a while to wrap my head around the rule set, but once i did, it was awesome!! absolutely loved this puzzle. the pedalling pianist have outdone themselves this time 😮
19:49 For me, very satisfying puzzle, especially the column logic later on (Notably I highlighted the columns with 234 fully on arrows rather than going digit by digit)
Weirdly, my route was very different from Simon’s. After proving (more simply) that the arrows only had 6789 and 1234, I started isolating 4s, then 3s, 2s, and 1s. The high digits fell into place from those.
Absolutely loved this, When you face a new ruleset and then can then work out the logic and then use a full colour palette I smile from ear to ear 😊 and am happy for the rest of the day
70:32 for me. So much joy! Thanks to ThePedallingPianist!
I worked out a bunch of logic, including Simon’s deduction at 33:44 right away, but none of it was immediately actionable.
The actionable logic, as Simon got right after giving up on high/low coloring, is how many columns/rows have 1,2,3, or 4 ON AN ARROW. the column logic is easier to see than the row logic.
10-1 =9 means all columns (& rows) have a 1 on an arrow.
10-2 =8 means 8 c&r have a 2 on an arrow.
10-3 =7 means 7 c&r have a 3 on an arrow.
10-4 =6 means 6 c&r have a 4 on an arrow.
Then one can work out which 1 circle ⭕️ has the 9, & start eliminating 6,7,8 from other circles until four 6s, three 7s, & two 8s are located.
Then the rest is sudoku (until I realized I got one of the 6s wrong & had to redo half the work I’d just done 😜)
Finished in just over 40 min, what with the redo. I make a lot of swapping errors (if a cell can be 5 or 8 & I rule out 5 there’s a ~20% chance I’ll put in a 5 instead of 8, which means I spend a lot of time double checking.)
Brilliant puzzle. Was stuck for 20 min because I forgot that there was only 4 6s, 3 7s and 2 8s. Coloring the puzzle helped a lot
Let's get cracking indeed, just about to watch solve.. This puzzle has physically hurt my brain already.
🙃😂😂
This really is an excellent puzzle, one of the best you've showcased all year.
Great puzzle! By the way: I‘ve been doing the Berlin Math Advent Calender since 2008 now, (I think ;-), and I highly recommend it!
My time today was 28:19, solver number 2612. The trick with 1/9, 2/8, 3/7, and 4/6 took a moment to discover, and I really appreciated the cleverness of that trick!
I liked it. After getting the ones, I found 6 unique groups of 234 (in boxes and columns) and concluded the three cells that didn't belong had to be 2 2s and a 3 . . . and everything kind of fell into place.
Beautiful puzzle. Lots of fun. Solved it in 32:14.
After figuring out the combined content of the circles and arrows, I also looked at their sum, which is 70 (4*6+3*7+2*8+1*9). Six columns (1,2,3,4,5,8) has all four low digit on arrows, column 6 has 1, column 7 has 3, column 9 has 2, so their minimum sum is 60+1+6+3=70, so r8c6=1, the arrow cells in column 7 have 1-2-3 and in column 9 they have 1-2.
Great solve and very fun puzzle! I took a slightly different route and therefore it took me over 50 minutes, but I think Simon’s solve path was the best and smoothest way to approach it.
I'd watched Mark's GAS video and was thinking I should probably go to bed, but I wanted at least to see the introduction, announcements, and birthday shoutouts from Simon first. And then I got hooked on the puzzle. I quickly figured out the initial idea, how many arrows have each total and what the composition of the 9 arrow must be, during the introductory part. I hadn't thought of counting up all the 1s in the puzzle, though. I quite enjoyed watching this one! 😺
Very nice puzzle! This may be my alltime favourite so far, because of its beautiful solving path, and just the right difficulty for me - challenging, but still doable.
I added the arrow cells in columns 123 resulting in 30, minus the 9, so the 3 circles in box 147 must add to 21, without using 9 and not being 777 it must be 678. I added the arrow cells in columns 45 resulting in 20, plus the 1 in col 6 is 21, which results in the 3 remaining circles in box 258 not being 777, so they must be 678. This meant that there are remaing two 6s and one 7 in the circles in boxes 369.
Wow just finished it, one of my favorite puzzles ever. Great job to the setter!!!
I tackled this from the circle/large number side first, after labelling/colouring the low digits in box 7, you can see that the circles in boxes 1,4,7 (and left one in box 8) have different combinations, so use up the only 9 and one each of 678, then note the circles in boxes 258 all have their "missing" digits in column 6, so must be different and a set of 678, using up the second/last 8, and in column 8 now have a 67 pair, leaving the last circle in box 6 to be a six, which then flows back
59:51 - I absolutely loved that.
Instead of looking at 6, 7 & 8 colouring 3s & 4s is much easier.
Wow, I really liked this one. Loved the whole geometry and the solve went very smoothly for me.
I like this one! I got it in only 00:40:14!
I think some of my hangup was on the fact that I had two circled 6's and knew I needed two more. It took a while to realize that out of the four possible circles left, I had a binary pair (if one was, the other couldn't be), meaning the 6 in column 4 was important. It wasn't in box 8 because that box's column was full. Then it couldn't be in box 2, because that would prevent two different circles from containing the last 6 I needed. That meant I needed a 6 in the circle in box 5! The rest fell into place from there as I had pencil marked well.
It was really nice that I didn't actually do anything wrong and have to back up.
Thank you Simon, for the birthday wishes! This was a total surprise! (this is Kyle) We were playing board games when this video launched and my brother insisted on us listening to this while we played and I was initially annoyed to listen and concentrate on a board game at the same time, but I think my brain sparked when my passive hearing heard you say "Kyle is turning 40 today" Then I Understood!
The double 3 in the corner gave me a weird idea...
can't wait for an exagonal grid (or septagonal or something) with loads of 3 in the corners :D (three 3 in the exagonal grid, more in a different shape)
You could've put 3s in for so long. It was driving me crazy
35:36 for me. I was so immersed in it, that it felt like an hour long solve. Very fun, very interesting concept.
Loved the break in which took me a while to figure.
Beautiful puzzle! Took me a while (01:12:26 with some interruptions), definitely missed a few tricks but I loved how it all fell in place in the end. And with doble 3s in the corners!
Managed to color a few more cells which made this puzzle so much easier.
The best description I can give to the puzzle is "Neat". The logic flows so smoothly. Sometimes, the moment U see a puzzle, U can understand how it'll work though might be hard to make one understand. The 6789 & 1234 were so beautifully limited on the circles & arrows respectively to the no. of their 10 complement, it was a marvel. My time - 21:41(Coloring 67s & 34s helps a lot).
I thought this one would be really hard for me reading the rules, but a surprisingly smooth solve in 48 minutes, which is very good for me. So glad I discovered this thing called funtastic sudoku puzzles
Very approachable once you have your head wrapped around the rule set. Quickly locked in what the arrows had to be then used sudoku with the low digits and high(5-9)-low shading to progress. (28:58 for me)
Really exited about this one. I have quickly come up with the idea of digits on arrows. And placed several 1 and 4. Then by means of colouring 23 took some time to locate similar 78s and by their number deduct which is the 7 and which is 8. Would really save a lot of time, if continued the logic on the number of 2s on arrows in order to place them.
It's obvious why this was recommended. I attacked this almost identically, including giving the 67s and their matching 34s the same colour. It was quite a mechanical solve, rather than logical (other than the initial step of deducing how the arrows were made up), but it was quite magical seeing it come together. I guess the relative lack of logic might explain the title.
I just finished yesterdays puzzles and took a 5 minute break... new puzzles like clockwork!
This was a joy to solve, it took some time to figure out which arrows could be which and it wasnt until I reminded myself that of the 4 different combinations, any 3 will always have 1 digit in common. So once I started colouring the cells it was a breeze (24:12 for me)
PedallingPianist is a magician, really enjoyed watching that solve.
After screwing up my coloring 2 times I finally got it solved in 89 minutes. Really nice puzzle.
OMG that spoiler:
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second three in the corner tho!! loved it. such a delightful concept for a sudoku
34:09, figured out what the arrows had to be, took a bit of time and logic to figure which arrow was which. It was certainly fun.
As per given rules, on arrows digits are
2+3+4 = 9 once
1+3+4 = 8 twice
1+2+4 = 7 thrice
1+2+3 = 6 four times
Total circles (1+2+3+4 =10)
It took me 33:29.
After finding the 1s and the 9 I didn't look for the 2s next but the 4s instead. This eventually lead to finding some 6s and having the 7s/8s not yet disambiguated. Then I had to do some coloring to disambiguate them.
It took me a very long time, and I broke the puzzle near the end and had to restart. Identifying what had to be in the circles and on the lines was straightforward. I colored one of the straight lines in the left band, and colored a good chunk of the left band -- four colors for the digits 1234. The line of every circle in the left band (and R9C4) omitted a different digit, so the circles had to be four different digits. One of them *had* to be *the* 9.
Later on in the solve I began coloring 34s (having wiped the first coloring) but shortly changed to letters, with C & D representing 3 & 4, 1+2+C=F, 1+2+D=G, and 1+C+D=8.
My second attempt, I did everything the same through finding the 9, then immediately went to the letters. I successfully solved the puzzle this time.
22:20 I used 1s to determine the 9 after coloring the low digits in the left band. After that, I knew that one of the two 8s was in the left band. 2s in the middle band showed that one 8 was there as well. (One can see around this point in the video where the 9 has to be.)
23:10 If you're me, you don't resolve the final X-wing in 1s until much later.
26:20 Columns 4 and 5 contain three arrows but only two 2s. Therefore one of them doesn't have a 2 and therefore connects to one of the two 8s. The other is in the left band.
22:46 finish. I saved all of the fives for last, being the invisible middle child. A very interesting switch up on the rules. Excellent!
I got the composition the circles quickly, but was then bamboozled by working out the precise distribution. It never occurred to me that all the 1s had to be on arrows. I wish had a brain like Simon's.
That was an exceptionally satisfying puzzle to solve!
Managed to get to the 20:20 position without Simon's help, but needed his next insight to progress further, after which it all fell out nicely under my own steam. Nice puzzle!
Although now that I watch the rest of the video, my next step was actually different to his. I reasoned that the four arrows in columns 1-3 couldn't contain more than n of any digit X, and that told me that each arrow in columns 4-9 had to have all the other Xs.
I always watch CTC in the evening, but I’m extra grateful for today’s episode, which can hopeful help soothe after the upsetting exit polls of the Dutch election that just released.
It's good to see the Netherlands potentially following in Argentina's wake! 🎉
I heard about that. Hope it get's sorted out before too much harm is done. Sending thought's and prayers from Norway!
The rules seemed intimidating at first glance, but actually figured out composition of circles and arrows in few seconds, but then i got stuck for a while. after initially doing similar thing with 1's and 2's as simon i discovered that there were 6 columns where 4 was forced on arrow, making R8C7 a 3 and thanks to that it was easy to rush to the finish.
Beutiful puzzle and I'm proud of myself for being able to solve this one myself
Finished in 46:19. Fun puzzle with an interesting concept though that was used up pretty quickly. Basically, I figured out how many 6789 there were in each circle and what digits had to be on the arrows in the first couple of minutes. But most of rest of the time was spent trying to figure out which 67s and 34s had to be where.
Still, fun!
Your reaction to this ruleset was the best xD
This puzzle was insane. It took me 3 full days to sove it while lying in bed with tonsillitis, because I didn't spot that all the 1s had to be on a line straight away. 10/10 puzzle.
Once you are done with the 1s, you actually need to think about 4s. There are six 4s on arrows, so there need to be three 4s _not_ on arrows. And there are only three columns available for them (6, 7, and 9). So, after analysis, you need to put a 4 in column 6 of box 5. This starts to give you the 6-circles, and you are on your way.
Very nice simple one anti circle-digit one.
Almost got fooled by which was 7 vs 8 ....where more was 7 not 8. Nice half letter/digit solve
The first thing i noticed in the puzzle, after the counts for 6789 circles, was the circles in the left 3 boxes and the 9 circle needing to be different. That lead to a slightly different solve path. Also, I found that r9c6 was green which made r2c6 red and together the two reds included a 3 and 4. I thought that was a beautiful but if logic there.
I did this one late at night in bed and fell asleep midway through. My time says 02:30:49 but I'm not sure about the actual time.
Once Simon concluded that the circles must be 6666777889, That implies that the 9 arrow must be 234 : if that wasn't the case, *all* arrows contain a 1 and that is impossible, since then the anti-rule says that one arrow doesn't contain a one. And there are similar conclusions with the twos : *two* arrows must not contain a two, so they are the two eight arrows, which then must be 134.
You'd have done well to ask what low number can go in the non orange, non arrowed cells. They act like (normal) circles!
Whoa, another rule with circles! Nice one Simon 🐶
Haven't watched the video yet, because I don't want to be disappointed, but please PLEASE let the title of that puzzle be "Kama Sutra"
Now...to watch!!
14:09 for me. Fantastic puzzle!!
Which would be worse, cycling round the pedalling pianist or meeting Martin at a party? Hung Jury! 😁
An easier way to do this is to realize that 9 + 8 + 8 + 7 + 7 + 7 + 6 + 6 + 6 + 6 = 70, and c1/2/3/4/5/8 all are minimal 10s (adding to 60) and r2 has to be a 1/2 pair, r8 has to be a 1/2/3 triple, and r6 being a 1 adds up to 60 + 3 + 6 + 1 = 70
Loved it, 33min. I did it rather quickly (for me). I did the arrow maths, found the 1s and then started coloring the circles. I could be faster if I found the 2s before coloring, but that's life...
Nice puzzle. Nice solve. I did the low digits differently, though and that worked nicely too
So I went to 4s after 1s because I could locate enough places where 4s were on definitely on arrows and deleted 4s from the other arrow cells. I ended up colouring 2/3 v 7/8.
I had done the breakin a bit differently, by coloring cells on all the arrows in cols 1,2,3. The four arrows each had one color different which proved their circles were all different. Hence we have our one 9 and all other circles are 678 and sure to have 1s on them. By sudoku then you can get the 1s (minus xwing) as Simon got. Course now I'm stuck, giving up and seeing what Simon does.
fun! although confused by the ruleset at first, it became a lot more clear after i counted the number of arrows/circles! i got the solution in 27m59s.
23:57 for me - I spent about 5-10 minutes trying to understand the rule before I started, so my real time is around 30 minutes. This was one of those puzzles where I'm looking at it in disbelief, and then it hits me.
You can even solve that puzzle without using the last rule. Have missed the arrow constraint somehow. 57:06. You can see in the left three boxes (1,4,7) thet there must be an arrow without a 1. But figuring out that the 8 arrows have no 5 isn't that easy 😂
I still cant figure this out. How did you arrive at that conclusion?
My solve is the uncolored cells in c:679 form a swordfish on 4s thus giving you a 6 in the circle in box 9 and leading on
oooof. that one was a bit of a slog. took me a solid 80 minutes, had the entire grid down to colored pairs before i thought to count to solve what was what. Then watching Simon after, he made that look so easy, and had them figured out so much more beautifully. nice solve.
Fantastic puzzle. After initial staring not too hard, even two 3s in the corner
42:15 just a small thing. The 34 green pairs force box 7 circle to be yellow (or 8?)
Love the content as usual. Cracking stuff. My fiance is just beginning his own journey into variant sudoku and is loving it! How woukd I go about asking for a birthday shout out in future? Is there a spot to email or just here in comments?
I think the solution path Simon used was unnecessarily complicated. I found it much easier todo some math that indicated boxes 1/4/7 have a 6/7/8 circle triple as do boxes 2/5/8.
That leaves the circle in box 6 needing to be a 6 and it's about 80% just sudoku from there.
Box 4 got neglected both when it came to place the 1 early on and then the 2. That 2 has to go in row 5 was clear just from the coloring and didn't need all that complicated reasoning
4×1236, 3×1247, 2×1348, 1×2349, okay, that much was obvious. Now to figure out how to work out which arrow is which. Made a bit of a bluster at the start by miscalculating the b9 arrow rather than r9 arrow as a possible 9 arrow.
It's actually pretty fun to do that step, hope you attempt it.
Did in 41:06, after a bit of a bluster at the start. Think I might have figured this in a slightly different way than Simon. I figured out the first column of boxes needed to contain one of each of the 6, 7, 8, and 9 arrows, and that the second column of boxes could only be one of each of 6, 7, and 8 arrows, leaving the last column of boxes two 6 arrows and a 7 arrow. I figured out by using the high digits before the low digits.
I'm, after watching Simon, convinced that we took two entirely different approaches to solve this puzzle, which makes me wonder which of our methods was more intended.
I used colors for 678 and letters for 234… by chance I found myself singing “that’s B in the corner” 🎉🎉 86:19