Another great video. looking forward to your next one. To make it easier for people watching i would of made p=0.0172 10x-6 That way when you do the 6mm2 10x-6 you can just cancel out both 10x-6's 0.0172 x 100 / 6 = .0.2866666667 ohms. 0.29 ohms
Oh the memories are flooding back Joe! From 1976 to be precise when i did Electrical Principles at college. Gamma A over L rings a bell, conductivity maybe? Just gonna do some googling.... Another super vid mate 👍
Great video, from the OSG 6mm gives us a resistance of 3.08 and I’ve seen you’ve answered this for impurities but 3.08 is a lot different to 17.2. Have I read this wrong? Many thanks
Great question, the OSG uses slightly higher figures for resistivity values, I'm not sure why, I think it may be due to allowable impurities in the copper and manufacturing tolerances. Pure copper has a resistivity of 17.2. Its one of those things where whichever value I use someone will ask why I didn't use the other. Thanks for asking and stay tuned for more! 👍
I see where u got the 17.2 which is in the c&g text book as 0.0172 microohm meters but all the numbers in the osg are in milli ohm meters and also have different values for line conductor and earth.
The formula in this calculation allows you to change the cross-sectional area. The OSG saves you a step in the calculation by giving different resistivity values for different CSAs. 👍
@@JoeRobinsonTraining just a quick question mate, what if i had 2 conductors 6mm line and 2.5mm cpc and I have the resistance r1+r2 e.g 0.29 i've transposed the formula to L=RxA/P to find the length but as i have 2 areas do i just take 2.5mm away from the 6mm? cheers
Hi, sorry, I've only just seen this. That's a little bit trickier as the two different conductor sizes provide a different proportion of the total resistance. Really good question actually, I'll need a bit of thought to explain that one. 🤔
Another great video. looking forward to your next one.
To make it easier for people watching i would of made p=0.0172 10x-6
That way when you do the 6mm2 10x-6 you can just cancel out both 10x-6's
0.0172 x 100 / 6 = .0.2866666667 ohms. 0.29 ohms
Wicked vids and wicked channel don't let anyone tell you otherwise.
Thanks very much for the kind comment and support!
Great video joe, it’s great to be back to see these and seeing you LIVE, keep up the good work
Fantastic video
Thanks George.
Great vid Joe! One of your best yet!
Thanks Will, stay tuned for more,
Amazing vid
Thanks Sam, stay tuned for more.
Super stuff!👍
The topic is very informative. Thanks Sir Joe. Great job!
My pleasure! 😊
Brilliant training material 👍
Thanks for the kind comment Matt.
Great video joe 👍🏻
Thanks Matt!
Brilliant video, learning to use my new calculator too :-)Thanks!
Nice vid
Thanks for the support Michael.
Oh the memories are flooding back Joe! From 1976 to be precise when i did Electrical Principles at college. Gamma A over L rings a bell, conductivity maybe? Just gonna do some googling.... Another super vid mate 👍
Thanks for the feedback, I think sigma A over L gives you conductivity where sigma is conductance in Siemens. Happy to be corrected though! 😊
Very well explained joe! Big fan!
Ah, thanks that's kind, I'm glad it was helpful. 😊
Thumbs up as always!
Thanks for the support Craig!
We should be thanking you for all the content yourself, Gaz and Matt produce for us to watch and learn.
Great video Joe, how did you get the calculator on the screen like that is there specific software that you use for it?
Thanks 😊
My pleasure! 😊
Great video, from the OSG 6mm gives us a resistance of 3.08 and I’ve seen you’ve answered this for impurities but 3.08 is a lot different to 17.2. Have I read this wrong? Many thanks
Greatly appreciated😉
Why are you using the resistivity value of 17.2 when in the osg it says its 3.08 for 6mm?
Great question, the OSG uses slightly higher figures for resistivity values, I'm not sure why, I think it may be due to allowable impurities in the copper and manufacturing tolerances. Pure copper has a resistivity of 17.2. Its one of those things where whichever value I use someone will ask why I didn't use the other. Thanks for asking and stay tuned for more! 👍
@@JoeRobinsonTraining Hi Joe, using the OSG figure of 3.08 for 6mm gives a massively different answer, 0.051. Am I missing something here?
I see where u got the 17.2 which is in the c&g text book as 0.0172 microohm meters but all the numbers in the osg are in milli ohm meters and also have different values for line conductor and earth.
The formula in this calculation allows you to change the cross-sectional area. The OSG saves you a step in the calculation by giving different resistivity values for different CSAs. 👍
thanks for the video mate i appreciate it
My pleasure, glad it helped. 👍
@@JoeRobinsonTraining just a quick question mate, what if i had 2 conductors 6mm line and 2.5mm cpc and I have the resistance r1+r2 e.g 0.29 i've transposed the formula to L=RxA/P to find the length but as i have 2 areas do i just take 2.5mm away from the 6mm? cheers
Hi, sorry, I've only just seen this. That's a little bit trickier as the two different conductor sizes provide a different proportion of the total resistance. Really good question actually, I'll need a bit of thought to explain that one. 🤔
@@JoeRobinsonTraining let me know if you crack it mate👍🏼
👍👍
Thanks Connor
No problem joe always interesting 😁
Where did you get the 10 to the -6 from, I have no idea.
Converting from millionths of ohms to ohms (minus 6 zeros, sort of) and converting thousanths of metres to metres (minus 3 zeros, sort of)
or u could look in the on site guide...might not be as accurate..
For sure. 👍
What voltage did the tester put through the Conductor please?
It was just on the low ohms or continuity setting. 👍
Brilliant video, learning to use my new calculator too :-)Thanks!