Well done Sir. It would be appreciated.if you could develop the concept of Capability Curve and how to draw one. I really liked your explanation. Thanks
Sir, you presentation is very good & you explain everything thing in most easier & interesting way. Thank you. It will be helpful if you upload some more videos regarding protection of busbar, transmission line & different protection schemes of transformer, generator & motor. Apart from this I am interested to see videos from you covering topic of impedance, reactance & mho relay i.e different distance protection relay & their zones of operation.
Very nice & well explained ..it very helpful to understand. I have some question regarding alternator in power plant What happened when we increase or decrease power factor ? What changes happen when we put load on it?
Great Explanation! I think you have done the explanation considering the load as inductive, in case of capacitive load can you please show in detail in a similar way? Hoping to get a feedback
Sir pls make a video on how reactive power is controlled in Alternator by AVR and how it changes by varying the AVR volt.and does it causes any change in load angle...as we are varing the excitation volt....
Excitation is inversely proportional to load angle by P= EV/X Sin del Reason : Assuming governor position as constant, the power angle sinusoidal curve peak i.e. (EV/X) changes with change in excitation voltage, so to keep MW constant load angle also changes.
Did you find why do we multiply with V/X? Every other steps are well explained. But the instructor skips explaining why he multiplies V/X with the equation.
Yes, it comes from Ohm's law. Considering resistance near zero we have S = V²/X, hence when you multiply voltage phasors (E and V) by V/X you move them from the voltage plane to the power plane (S = P + jQ).
Excellent Explanation. Thank you.
Very nice explanation... boss.. really nice
Well done Sir. It would be appreciated.if you could develop the concept of Capability Curve and how to draw one. I really liked your explanation. Thanks
Sir, you presentation is very good & you explain everything thing in most easier & interesting way. Thank you. It will be helpful if you upload some more videos regarding protection of busbar, transmission line & different protection schemes of transformer, generator & motor. Apart from this I am interested to see videos from you covering topic of impedance, reactance & mho relay i.e different distance protection relay & their zones of operation.
Very nice & well explained ..it very helpful to understand.
I have some question regarding alternator in power plant
What happened when we increase or decrease power factor ?
What changes happen when we put load on it?
good
Great Explanation! I think you have done the explanation considering the load as inductive, in case of capacitive load can you please show in detail in a similar way? Hoping to get a feedback
Muhammad Ahsan Zamee
Just take a minus sign in denominator of the eqn
P/(V^2/x - Q)
Thank You very much! Wish you more success ahead!
Very good
thank u sir.....
please explain about auto reclosure scheme.....
superb
Sir, kindly give lecture about generator out of step protection
@electrocean 200% = 2 pu ,not 0.2pu
Sir pls make a video on how reactive power is controlled in Alternator by AVR and how it changes by varying the AVR volt.and does it causes any change in load angle...as we are varing the excitation volt....
Excitation is inversely proportional to load angle by P= EV/X Sin del
Reason : Assuming governor position as constant, the power angle sinusoidal curve peak i.e. (EV/X) changes with change in excitation voltage, so to keep MW constant load angle also changes.
Where to get X pu?
Wouldn't a 200% sync reactance be 2 in per unit, not 0.2?
Casey Martin yes typo error..thanx
Again multiply by 'V/X'? What is actually V/X? Is it current as in ohm's law like, I=V/Z(X or R)
Did you find why do we multiply with V/X? Every other steps are well explained. But the instructor skips explaining why he multiplies V/X with the equation.
Yes, it comes from Ohm's law. Considering resistance near zero we have S = V²/X, hence when you multiply voltage phasors (E and V) by V/X you move them from the voltage plane to the power plane (S = P + jQ).
uh ok, thank you
Boss..can I have your email...would like to exchange technical enquiries.