Math Olympiad | Can you solve this ? | Simplify Square Root Problem

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  • čas přidán 24. 08. 2024
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Komentáře • 28

  • @user-hd9do6tc8k
    @user-hd9do6tc8k Před měsícem +3

    Умножить числитель и знаменатель дроби на 2, в знаменателе будет формула квадрат разности корня из 5 и корня из трех. А дальше только упростить! 😊

  • @paulortega5317
    @paulortega5317 Před měsícem +1

    let x = the answer. u = x/4. Then u^2 = 4+sqrt(15) and 1/u^2 = 4-sqrt(15). u^2+1/u^2 = 8 and then u+1/u=sqrt(10). u^2+1=u*sqrt(10). 5+sqrt(15)=u*sqrt(10). u=(5+sqrt(15))/sqrt(10). u=sqrt(2)*(sqrt(5) + sqrt(3))/2. x = 4u = 2*sqrt(2)*(sqrt(5) + sqrt(3)).

  • @kenrutherford7607
    @kenrutherford7607 Před měsícem +1

    splendid!!!!

  • @muratyasaryldz8168
    @muratyasaryldz8168 Před měsícem

    Çok güzel bir paylaşım.Muzik ve matematik öyle muhteşem bilim ki konuşmaları anlamasam da ne yaptığınızı anliyorum.Cok teşekkürler

  • @gnanadesikansenthilnathan6750

    Clear. Splendid and excellent.

  • @betto63mx92
    @betto63mx92 Před 11 dny

    Para no obtener un resultado como el que esperaba, propongo esta alternativa mas directa y con un resultado como el que tampoco me convence .
    .
    A partir de
    Sq(64 + 16 sq15)
    Sq( 16 ( 4 + sq15 ))
    4sq( 4 + sq15)

  • @key_board_x
    @key_board_x Před 2 dny

    = √[16 / (4 - √15)]
    = √[16.(4 + √15) / {(4 - √15).(4 + √15)} ]
    = √[16.(4 + √15) / {16 - 15} ]
    = √[16.(4 + √15)]
    = 4√(4 + √15) → you need to find a number x sush as x² = 4 + √15
    Suppose that: x = √a + √b
    x = √a + √b
    x² = (√a + √b)²
    x² = (√a)² + 2.(√a).(√b) + (√b)²
    x² = a + 2.√(ab) + b
    x² = (a + b) + 2.√(ab) → by identification to (4 + √15)
    a + b = 4
    2.√(ab) = √15
    √(ab) = (1/2).√15
    √(ab) = √[(1/4) * 15]
    ab = (1/4) * 15
    ab = 15/4
    Resume
    a + b = 4 ← this is the sum S
    ab = 15/4 ← this is the product P
    a & b are the solution of the equation:
    x² - Sx + P = 0
    x² - 4x + (15/4) = 0
    Δ = (- 4)² - [4 * (15/4)] = 16 - 15 = 1
    x = (4 ± 1)/2
    x = 5/2 ← this is a
    x = 3/2 ← this is b
    We can see that:
    [ √(3/2) + √(5/2) ]² = (3/2) + 2√[(3/2) * (5/2)] + (5/2)
    [ √(3/2) + √(5/2) ]² = (8/2) + 2√(15/4)
    [ √(3/2) + √(5/2) ]² = 4 + √15
    Restart:
    = 4√(4 + √15)
    = 4√[ √(3/2) + √(5/2) ]²
    = 4.[√(3/2) + √(5/2)]
    = 4√(3/2) + 4√(5/2)
    = √(48/2) + √(80/2)
    = √24 + √40
    = 2√6 + 2√10
    = 2.(√6 + √10)

  • @user-ee7nw2rx9s
    @user-ee7nw2rx9s Před měsícem

    Умножить на 2
    Sqrt (32/(8-2sqrt 15))
    Таким образом
    32=2*4^2
    8-2sqrt 15=(sqrt 5-sqrt 3)^2
    Извлечение квадратного корня
    4 *sqr2 /(sqrt 5-sqrt 3)
    Избавиться от иррациональности в знаменателе
    4 sqrt 2*(sqrt 5+sqrt3) /2=2 sqrt 10+2sqrt6
    2 минуты, а не 8 как на видео

  • @arturchirki
    @arturchirki Před měsícem +3

    Бессмысленная задача, и никакой красоты в решении и ответа.Задача смотрится проще, чем ответ.

    • @mauriziograndi1750
      @mauriziograndi1750 Před 27 dny

      You right here we see taking pleasure in writing plenty of small steps.
      I believe the shorter is the smartest.

  • @lifewatery7472
    @lifewatery7472 Před měsícem +2

    √[16/(4-√15)]
    =√[32/(8-2√15)]
    =√{32/[(√5)²-2√5•√3+(√3)²]}
    =√[32/(√5-√3)²]
    =4√2/(√5-√3)
    =4√2(√5+√3)/[(√5-√3)•(√5+√3)]
    =4√2(√5+√3)/2
    =2√2(√5+√3)

    • @lifewatery7472
      @lifewatery7472 Před měsícem +1

      √[16/(4-√15)]
      =4√[2/(8-2√15)]
      =4√2/√{[(√5)²-2√5•√3+(√3)²]}
      =4√2/√(√5-√3)²
      =4√2/(√5-√3)
      =4√2(√5+√3)/[(√5-√3)•(√5+√3)]
      =4√2(√5+√3)/2
      =2√2(√5+√3)

  • @user-ud3cg2vp5s
    @user-ud3cg2vp5s Před měsícem

    Thank u ❤

  • @aeroeng22
    @aeroeng22 Před 25 dny

    that's funny, Harris begging for your hard earned cash at the beginning of this video, in an ad. I wouldn't show her the restroom if her hair was on fire.

  • @user-gr3ut4gk9w
    @user-gr3ut4gk9w Před 18 dny

    Как же бесят переписывания по 100 раз одно и тоже

  • @mathshindustani6216
    @mathshindustani6216 Před 6 dny

    There is easier way to solve this bro
    U made it lengthy
    But nice try

  • @reinhardtristaneugen9113
    @reinhardtristaneugen9113 Před měsícem

    also ich habe da 11 vor dem Komma, aber weil das natürlich zum Quadrat 121 ergibt, musste ich weiterrechnen, und kam auf 11,09.
    Wie ich darauf kam?
    Ich zog die Wurzel von 15 im Kopf, was mich zu 3,87 führte und subtrahierte und das brachte mich zu 13 / 100, wobei man ja dividiert, indem man mit dem Kehrwert multipliziert, sodass ich 1600 durch 13 hatte und das führt zu 123 und eben zu 11.09, so man die Wurzel zieht.
    Le p'tit Daniel

  • @user-ge2on1sl6v
    @user-ge2on1sl6v Před 23 dny

    الجاواب النهائي مش مختصر نهائيا

  • @OscarTejada2014
    @OscarTejada2014 Před 22 dny +5

    7 minutes of my life just to see it wasn’t solved at all… go out and have a social life

    • @krzysztofzajac4446
      @krzysztofzajac4446 Před 16 dny +2

      what does your social life consist of? watching films on youtube? go out and have a real social life...

    • @anonymousperson4466
      @anonymousperson4466 Před 13 dny

      ​@@krzysztofzajac4446atleast not solving a square root to get another

    • @grqb_tg2478
      @grqb_tg2478 Před 2 dny

      En Perú, ese ejercicio se hace en 1 minuto y en 4 o 5 líneas ... Hicieron un procedimiento demasiado largo y tedioso.

  • @doctobi9437
    @doctobi9437 Před 23 dny

    Notnonly in your last Line but for example: SquareRoot of 4 could also be -2...so you lost some solutions...sorry

    • @dashinglover9629
      @dashinglover9629 Před 21 dnem +1

      Square root is always positive

    • @doctobi9437
      @doctobi9437 Před 21 dnem

      thank you. I went wrong because x^2=4 has two solutions -2 and +2

    • @shehzar_hn2680
      @shehzar_hn2680 Před 18 dny

      ​@@doctobi9437There is difference between x2 =4 has to solution...Here we remove power
      But when √4 only positive value comes out ...With mod