You will learn a lot from this JEE Advanced 2009 Problem | Aman Sir Maths

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  • čas přidán 5. 02. 2023
  • In today's video, we will be solving a challenging JEE Advanced Question.
    this question was asked in JEE Advanced 2009.
    This is a very important question because you will learn a lot from this JEE advanced question, and it will be an excellent question to boost your JEE Advanced preparation.
    How will you solve this Series Problem?
    Give it a thought and apply concepts that you learned to solve this Problem.
    If you are unable to solve it, let's check out how Aman sir will make this JEE Advanced Problem very easy to solve.
    Check out the complete video to know the solution to the Inequality Problem.
    You will learn a lot from this JEE Advanced 2009 Problem | Aman Sir Maths | BHANNAT MATHS
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Komentáře • 527

  • @kushagramishra1729
    @kushagramishra1729 Před rokem +481

    Sir I solved this by converting all terms to sin and then made a quadratic.

  • @JeeNeetMemes
    @JeeNeetMemes Před rokem +192

    The easiest approach in this question is to divide the whole equation by cos4x and converting all terms to tanx and then solving the equation

  • @dineshnahar8557
    @dineshnahar8557 Před rokem +9

    Too easy question I solved it in class 10

  • @LalanKumar-ny4kc
    @LalanKumar-ny4kc Před rokem +3

    Almost an oral question for those who knows titu's lemma 💀

  • @vertechua

    Class 10 ka hoke bas ek bhi question ho jaata hai JEE ADV. ka to rahat milti h 😂

  • @deeppandey5654
    @deeppandey5654 Před rokem +4

    Iam in 10nth and yet solved it , it means it is easy question..

  • @udaymaheshwari1702
    @udaymaheshwari1702 Před rokem +18

    another method: consider x=(sin a) power 2 and y=(cos a) power 2 and solve by ellipse and line's intersection point

  • @ramumaurya4172
    @ramumaurya4172 Před rokem +2

    Cs lemma se direct ho jayega gurudev

  • @fitguy6995

    mera to( A) aa raha h to sir pura no mil jayega

  • @parthmadaan3399
    @parthmadaan3399 Před rokem +5

    Sir I have done this problem 3rd time and sir jab bhi karta hu maza aata h

  • @anirudhathakur7350
    @anirudhathakur7350 Před rokem +24

    Super easy...

  • @AimzIIT
    @AimzIIT Před rokem +12

    Sir it can be easily solved by Titu's Lemma we know (x1)²/A+(x2)²/B >=[x1+x2]²/A+B

  • @parthdanve6511
    @parthdanve6511 Před rokem +2

    Easiest method is to take cos^4x common to make tan^4x on LHS and send to other side as sec^4x. Then write sec^4x as (tan^2x+1)^2. We get biquadratic in tanx or quadratic in tan^2x using this method. After that just substitute values and check for tan^2x. Do the same method for the equation options and substitute correct value of tan^2x to check whether its true

  • @cuteff8811
    @cuteff8811 Před rokem +8

    Full respect

  • @shreyasidubey7042
    @shreyasidubey7042 Před rokem +3

    Sir ,I have done it by using simple quadratic equation

  • @wantedgamer2235
    @wantedgamer2235 Před rokem +1

    Sir Apne Dil Jeet Liya ❤️❤️🙏🙏

  • @ranistanly5340
    @ranistanly5340 Před rokem +3

    We can write 1/5 as 1/5*(sin²x+cos²x)² youll get a perfect square on putting it to left hand side

  • @sdass500
    @sdass500 Před rokem +5

    Sir great respect🙏🏻🙏🏻👑

  • @ritamroy5758
    @ritamroy5758 Před rokem +5

    Sir u upload good vdos. I appreciate u. But this vdo is already uploaded in Math Booster channel.

  • @div_07
    @div_07 Před rokem +10

    Can easily be solved by substituting cos²x with 1-sin²x.