Finding pH and pOH using MOLARITY of a solution | Chemistry with Cat

Finding pH and pOH using MOLARITY of a solution | Chemistry with Cat
When we're given pH or pOH in a question, we can easily calculate the concentration of hydrogen ions or hydroxide ions, and then with that we can calculate the molarity of a solution! This is classic chemistry test and exam gold, so make sure you can do that AND relate pH and pOH. Remember pH + pOH = 14!
Practice problems and answers can be found on the Chemistry with Cat Instagram: / chemwithcat
Cat has a BMSc and MSc. SHE HAS BEEN IN YOUR SHOES AND STRUGGLED ON THOSE EXAMS! She currently tutors university and high school chemistry, and she's here to help YOU! She creates quick videos that teach you everything you need to know to not only pass chemistry but ace it!
Science is fun! Subscribe to this channel for more lessons! / @chemistrywithcat
For individual tutoring contact Cat at: [e-mail]
Intro and Outro Music composed and recorded for this channel by my very talented brother: Andrew Valle
#pHandpOH #molarityfrompOH #molarityfrompH

[@viplavsinghal2005]

Also I might be wrong but when you did -log[.0725] in the last problem, you should have gotten 1.1397 instead of .1397 which would change the final answer.

[@gloryifeany7840]

You really explained this basic concepts very well.i would rate you 100%.

[@torresthemonster]

If I had you as my teacher, I wouldn’t miss one day and get 100 on every exam.

[@fatmanlover962]

real

[@fatmanlover962]

we can only dream

[@journeywithrahat]

She speaks so calm

[@sachitsharma1661]

Suddenly i realized i love chemistry

[@rainsmush]

This helped me sooo much THANKS CAT!!
love how its simple clear and to the point thankyou!!!
"new sub":)
pls keep making videos and you are wayy to underrated

[@maxzytaruk8558]

this was so incredibly well explained! Thanks! :)

[@Jamalashwah]

Hello
The last question:
c=n/v
c= 0,029 mol / 0,4 L
c= 0,0725 mol/L
pOH = -log (0,0725 M)
pOH= 1,139
14 - 1,139
pH = 12,86
THX YOU

[@user-dk5zs7dq7g]

You are the best and thank you very much

[@dkstudio702]

if she was my high school teacher my attendance is 100%

[@greatorg9498]

YOU ARE MARVELOUS and so nice how you explain in order, step by step...
Thank you so much for your video !

[@gavinkinch1911]

Wish u were my chem teacher

[@i.2.igamer920]

nice thats helps a lot

[@axeldaliramirezgonzalez1830]

Thank you , that was a very useful explanation that saves me from reading 20 pages :)

[@valeriaa4428]

Thanks :)

[@vivekj-ki5cq]

im a grduate in chemistry and i donno why am i watching this but that feels good... and btw great explaination

[@vijayadithya492]

Very great explanation. My concepts are clear. thank you madam. Big Fan.

[@mahreentoor4086]

Informative

[@16_biplabkumarpradhan66]

Well explain mam

[@rabishkumar1592]

In last question
POH=1.139
PH=12.86

[@victorngare4304]

True

[@robinbaral5018]

Shouldn't there be two minuses in SO4? 1:37

[@aryanshinde-student19777]

Yes

[@faithmentee1867]

Thanks

[@EngineeringMathematics1729]

Tq🤗

[@user-sl4gt4bo9n]

i love this

[@MechanicalGuy]

Beautiful 😍😍😍😌

[@CC-rh1in]

what if we need the pH of Ca(OH)2?

[@viplavsinghal2005]

So for example lets say the molarity of Ca(OH)2 is .01M. We would first do -log [.02] because there are 2 OH ions, We get around 1.70. Then we would just do 14-1.70 resulting in an answer of 12.30. Sig figs might be off

[@naveelarani7153]

Thanks from Pakistan

[@nZkKanra]

is she recording with a landline phone lmao

[@KUROSAKIKUN-dn6gv]

Bro😂😂😂

[@AmirKhan-ed2qe]

🙏

[@user-er3es1xs5c]

❤👍

[@AliHassan-hb1bn]

You should show without using a calculator.

[@chandraguerrero3361]

I’m watching this video because I don’t fully understand the basics. So I really wish you would have written the “base 10” model 🥴 …. Because that’s where you lost me 😔

[@maxzytaruk8558]

oh that just means "multiplied by ten to the power of -POH" as in [OH-] = 10 ^-POH. I hope that helped, I know I'm a year late to your comment though haha

[@schmvsmsi3920]

damn

[@AmirKhan-ed2qe]

hello mam

[@edrianejay7126]

Do you also teach in onlyfans?

[@SahilKumar-px4hu]

BEAUTY WITHOUT BRAIN IS NOT A MYTH WOW, 😂😂😂😂