UPSC CSAT - Basic Concept Of Divisibility Rule | UPSC 2024 | Short Tricks | OnlyIAS CSAT

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[@rushikeshdhoran2280]

Happy that I found a teacher who focus on fundamentals and teaches with clarity.

[@Iamneerajsingh]

54:18 593+4A5 =107B which gives us B=8 and as 9+A =7 so A= 8 as well therefore, A-B = 0.
54:40 47A5654B divisible by 88 therefore divisible by co prime factors 11 and 8 considering divisibility of 8, last three digits must be divisible by 8 so,
54B /8 gives us B=4.
Considering the divisibility of 11 which is alternate digits sum and subtraction either be 0 or a multiple of 11 so,
(4+A+6+4) - (7+5+5+4)
14+A- 21 gives us A= 7 therefore,
A+B or 7+4 = 11.

[@mahimamohapatra777OAS]

Thank you for ur description

[@Sukh737-s1i]

Pls explain practice question 3

[@jalilulrahmansaddiqi]

@@Sukh737-s1i 981+369-37+25P (VALUE OF P IS 6) =944+113 now add 944+113 = 1057 . 1057 is divisible by 7 so value of P here is 6 .

[@RadhaKaushik-sw9ib]

I couldn't understand the 2nd😢

[@user-mp7jf4um9n]

बहुत ही आसान मैथड से अपने समझाया है सर, thankyou so much और मैं प्रैक्टिस करूंगी जैसा अपने सिखाया है।

[@iiHavingFun]

you are better than other educators for upsc csat. Thank you so much.

[@meerachodhri1259]

Bhaut sandar,easy way mei samjhaya sir aapne..you are all rounder..❤

[@anandbharti2537]

Man is rocking every field

[@harishbhatt4314]

What an amazing lecture sir......thanku so much ❤❤❤
Jug jug jiyo Sir 🙏🙏

[@sagargaming3424]

One of the best lecture I have ever seen in you tube tutorial

[@tulsimittal2614]

Radhe Radhe sir
Awesome lecture sir, thank you so much

[@manojk2923]

Very useful session sir, thank you ❤

[@Panditsohan]

Very quality lecture by rishab sir thankyou sirs

[@misshustler021]

Great explanation Sir
You made every concept easy
Thank you for wonderful sessions 🌷❤️

[@kajaltiwari1679]

Thank you so much sir 🎉🎉🎉🎉. Bachpan se jo maths ke liye dar tha ab lag raha finally hat jayega . Really the methodology were quite easy . ❤❤❤

[@riyasharma6887]

Nice explanation
Thank you so much sir 🙏🙏🙏

[@pkkumar5487]

Superb

[@ambikayadav7852]

Super lecture sir❤

[@amartripathi6985]

Thank u so much dear sir......

[@MahibaChavda-wb7ry]

Thank you so much Sir 😊🙏

[@RohitYadav-sd1ou]

Thanks sir

[@winamp297]

Hello sir ,Myself Dr Karan,I m a pediatrician by profession..I m extremely thankful to u because these videos helped me a lot in this yr prelims exam...I ll remain in debt for ur contribution...Thank you sir❤

[@rishavsharma1459]

Thank you so much Dr Karan....
Wishing you the Best for your preparation 👍

[@twinklekhan2003]

Thank you sir....

[@priyarai2374]

Thank you so much🙏🙏😊

[@vineetchauhan9775]

Thank u sir

[@Geetagujjar]

U r awesomest🎉

[@riyagupta1637]

thank you so much sir for this awesome lecture

[@harshrathore9407]

YOU ARE RIGHT SIR PRACTICE MAKES A MAN / WOMAN PERFECT

[@richachauhan3319]

Si please make these videos daily...so that we can complete CSAT in one go as a complete subject.

[@sushamabansod1468]

Thank you 😊 sir

[@user-up3qq4mh2k]

Thank you dear sir nice to all the classes

[@ranjanasoni3386]

Thank you soo much sir 🙏

[@aditilata7033]

Thank you so much

[@Akashpatelup32]

1:06:35 STEP - I: Three digit number blocks are formed from right to left.⇒ 369, 25P, 981, 037
STEP - II: Not Adding and subtracting the numbers formed alternatively⇒ 369 - 25P + 981 - 37 ⇒ 369 - 250 - P + 981 - 37⇒ 1063 - P
STEP - III: The result obtained in STEP - II should be divisible by 7
⇒ 1063 - P = 151X 7 + 6 - P
For 3798125P369 to be divisible by 7,
6 - P = 0⇒ P = 6

[@anannyamondal1519]

Thank you 😊

[@Anshu_thakur_jii_7810]

Thank you so much sir 🙏🙏😊😊😊🙏🙏🙏😊😊🙏

[@pratikshyaLickeyv16]

Thank you sir

[@tahminafiroz3342]

Being a Neet aspirant I am watching this for clearing my concepts 😂.... Thanks to sir my all concepts have been cleared regarding divisibility rules ❤

[@UjjwalSinghPatle]

😅😅😅

[@OmprakashKumar-ug8gw]

Thank you sir for your session

[@AkashKumar-zv4pb]

Please continue this series

[@Theradhalife]

Present sir ...

[@CSEEXAM2024]

Dear sir Remainder theorem par bhi video banaiye

[@kanchankhandare3251]

Practice questions -
1) option A (0)
2) option A (11)
3) option B (6)
Thank you very much for the session, sir.

[@mindreader2675]

how to do last question ?

[@krushnapatel8899]

1313-25p@@mindreader2675

[@sejalvaishya669]

How

[@mdmadanimak7863]

Lsat one I got option d

[@zethbells1458]

Can u explain last one 😢

[@Geetagujjar]

U kill every subject ❤

[@chandanparidwal3029]

good morning dear sir ❤

[@Royal_IAS]

Day-789
Consistent efforts makes you prosperous ❤

[@PriyankaVerma2001-mhi]

❤❤

[@harshamishra9568]

Good morning sir🙏

[@charakIAS]

49:11 itna karne se acha a+c ki value 4 hai tho...do hi possibility hai either (1,3 and 2,2) 0 ya 2. Zero option mai nhi hai tho answer 2 hi hoga

[@basantisahoo4925]

If 0 in the unit place it can bivisible by both 5,2 ?

[@jalilulrahmansaddiqi]

THANKS ALOT SIR. FEAR OF CSAT + ECONOMY ELIMINATED

[@Muskan-qu5ni]

2. Practice ques answer is A (11)

[@Miscellaneous987]

Practice question ke pdf provide kr dijiye for practice

[@Anisha_mahato]

Good morning

[@Muskan-qu5ni]

1. Practice ques answer is A(0)

[@rasmitanayak4519]

Sir please make video for 2025 preliminary..
Q1- 0 .
Q2- 11

[@priyarai2374]

Que-3 answer(6)

[@priyarai2374]

2-answer-11

[@nidhiyadav-mi4qp]

54:24
Question number 1.593+4A5=107B value of A-B=0
Question number 2.47A5654B÷88,then value of A+B=11
Thank you sir

[@shanidubey5719]

how you solved it

[@shanidubey5719]

thanks sir but i could solve the que. by options not by directly 1=0 q 2= 11 ,Q3 =6

[@shivanigautam3]

Sir CSAT ka math ka pura syllabus ka portion de dijiye

[@user-xd5vj1un7p]

hw 2:A option

[@rts8639]

31:37 ek odd and ek even hona chahiye
54:12 add krne s hi nikl kya A-B = 0
54:31 A+B = 11
1:04:44 P = 6

[@hardwgirl2201]

Kaise P=6 please explain

[@rts8639]

​@@hardwgirl2201m yahi try krta hu
37 981 25P 369
= 369+981 = 1350
= 250+p ( P unit no h ) + 37 = 287 + P
= 1350- (287 + P )
= 1063-P
Ek aaisa value put krna h ishme jisse minus krne pe ye 7 se divisible ho ske to option daal k check kr skti hai
P= 6 ( aaiga )
= ( 1063-6 ) / 7 = 151 aaiga
Answer = 6

[@hardwgirl2201]

Thank you so much

[@Yogitaghangas]

1)a
2)a

[@manishmahto4763]

Sir ap bahut smart hoo gaye purane video mai sakti Kapoor lag rahe they new mai sarukhkan hoo gaye

[@PriyankaVerma2001-mhi]

Unique compliment 😂

[@apoorvashrivastava8019]

where are that digits and pages questions?

[@dominicbhai-gaming8847]

Good evening sir
Answer 1. 0 , 3. 7
2nd answer is not solved sir please help to find answer 🙏🙏🙏

[@learnwithexperts4164]

Qs.1 - 0,
qs 2- 11,
Qs 3- 6

[@deshrajpandey6940]

1:07:02 PQ(2021)
3798125P369 ÷ 7 , R = 0
On solving with triplet method we get 1313 - 25P , that is divisible by 7 Now putting available value of P from options only P = 1 satisfy the condition that is 1288÷7 leaving R = 0 . Hence answer is option A

[@pallavipatil607]

Ans is 6 not 0

[@-vk-sarforajAhmed]

Mine also 1 but ans is 6 but puting 6 the no get not divide

[@deshrajpandey6940]

@@-vk-sarforajAhmed Exactly

[@2003xxx]

6 aaega aryabhatta

[@KalyanKariniPandey]

0, 11, 6 thanks sir

[@nishakrsupdates3347]

First zero and 2nd 11

[@CHANDAN_1008]

XYZXYZ wala mast majak tha😂😂🤣🤣😁😁😃😃.......TITAN 1.0

[@AakrietiVats]

1.0
2.14
3 doubt
Homeworks given by you

[@harshrathore9407]

HW
Q1. 0
Q2. 11
Q3. 6

[@shreenivaschoraghe5134]

HW 1 ANS is Option 0
HW 3 ANs is Option 9

[@KanakRaj-fn7fc]

Streak 2

[@shanidubey5719]

HW = ANS WOULD BE 1 SIR I THINK PLZ TELL

[@aviralgupta5923]

One more session

[@rajuprasadverma951]

MCQ 1 a option is right sir
MCQ 2 a option is right sir
PYQ 2021 d option is right sir

[@aditilata7033]

Last question...P - 6

[@gurucharanbag3332]

P. Q 2021=6

[@user-xd5vj1un7p]

HW 1: A

[@MonikaChauhan-iq6gl]

Homework 3- option B

[@zethbells1458]

Last 6 kaise aaya do explain miss😢

[@tejaswinishah9586]

Practice question
1)a.0
2)a.11

[@shrutisharma1280]

Practice question
1. 0
2. 11
Pyq 2021 - Answer 6
Thankyou Sir

[@awanishsharma7157]

Last 6 hoga na?

[@shrutisharma1280]

@@awanishsharma7157 No how it can be 6.

[@jitu-nf4dd]

6 hi hoga

[@shrutisharma1280]

​@@jitu-nf4dd yeah it's 6 actually I did mistake in calculation when I rechecked than I made correction.

[@riyasharma6887]

Shruti pls tell me solution of 2nd question

[@gurucharanbag3332]

P. Q=(a) 11,
P. Q =0

[@rajnikantbharti5488]

1st , answer 0

[@rajangupta19675]

Sir how to find co prime numbers for say 68.

[@priyaanka5792]

17 * 4

[@IASaimerPinky]

P= 6

[@golperpheriwala]

Last question's answer is 6

[@anjaliyadav4837]

Ans 1-A(0) , 2-A(11) ,3- B (6)

[@priyanka.jangra2021]

54:15 zero

[@nidhiyadav-mi4qp]

Sir pyq 2021 divisibility rule triplets se nh kr pai, options se solve krne pr answer 6 hai.
369+981
25P+ 37 subtraction ke baad nh aaya.
Thank you sir

[@priyaanka5792]

Same problem. But got the answer through options.

[@principarashar6232]

Thank you!
Practice questions
Q1 ans. - A (0)
Q2 ans. -A (11)
Q3 ans. - C (7)

[@sarufayaz3279]

Can u explain 2nd

[@ManishaGupta-tq6bj]

1.0
2.11
3.6

[@Geetagujjar]

Last question answer is P=6

[@NarendraSingh-hn3bj]

Repeat krne ka means ye h ki concept clear ni hua sir

[@nitikabhambhu]

Sir ab smj aya csat ke number kha cut hote hain😅

[@sakshiawasthi7356]

1. Answer- A (0)
2. Answer - A (11)
3. Answer - B (6)

[@priyarai2374]

1-Answer is 0

[@khushigupta2881]

SIR PLEASE FINISH THIS SERIES BEFORE CSAT 2024

[@zethbells1458]

Aapka kaise aaya can j explain mera 9 aaya tha

[@cricketkedewane8362]

Homework answers are
1)0
2)11
3)6
Tysm RISHAV SIR 😊❤

[@somyapandey0912]

1.Ans = 0
2.Ans = 11
3.Ans = 6