Physics 47 Inductance (12 of 20) The R-L Circuit Analyzed
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- čas přidán 6. 12. 2014
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In this video I will analyze the R-L circuit with a switch and battery.
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Your explanations are as insightful as they are crystal clear. Many thanks for taking the time to share your understanding of these electronic principles.
Really awesome.I had never seen anyone explaining the subject like you.Appreciate this.
Goodness me this is a fantastic video. Thanks for actually taking the time to traverse the entire landscape of this.
Such great content! Thank you for making this available to us and for taking the time to review this material so thoroughly.
This is fantastic! This makes it much easier to understand the derivations of inductance formulas in our Physics textbooks. Thank you, professor! :)
Glad it was helpful!
thank you very much!!! I was searching for derivation of this formula but I didn't find it. But I find it in this video i. I'm so happy now. Thank you!!!
Thank you so much for your clear, thorough, and detailed descriptions. This video really helped me a lot
Glad you found it helfpul. 🙂
you helping me get through physics 3.. thank you so much
Great explanation.Guru of teaching.Thanks
Michel van Biezen You are awesome! Your lectures are on POINT! huge help! thanks!!!
This is exactly what i was looking for! Thanks for solving this integral :)
Glad it helped. 🙂
Wow, great explanation. I wish my physics professor was as clear and concise as you!! :)
Our instructors never have enough time to explain as well as this gentleman can.
He is the quintessential teacher, Professor MICHEL van BIEZEN come out LIVE from those PROBLE SOLVER BOOKS published by SCHAUM Books/McGraw Hill.
Thank you so much! This is an amazing explanation. I did have one question though. Did you use Kirchhoff's loop rule or Faraday's to get the RL circuit equation? I was watching other lectures as well, but some of them are saying that they did the closed loop integral of E dotted with dL across each part of the RL circuit, and since there is no electric field across an inductor, there is no potential drop, but the total voltage must equal -L(dI/dt).
thank you for the amazing explanation.
Thanks u so much. Your lecture is so awesome!!!
Great teaching and thanks.
You are a beast! Thank you so much.
oh, amazing! i didn't realise you could derive the formula by hand! that's really surprising.
Greatly appreciate this. Thanks so very much for making this easy to understand.
You are welcome.
Professor, so the time at the end above small e is simply E divided by L, correct or no.
This man makes me get away with losing my focus during lectures
Not sure if that is a good thing..... 🙂
Sir, what is happening in the circuit in this case? I mean, which events happening in this circuit while current is increasing? We can know the current-time graph is what you drew on board with solving diff. eq., but it is a real system and laws of Physics is valid here. and some events happens and due to this events current-time graph become like this. How can we explain why this circuits acts like so? What is happening there? please tell me the real physical reasons of being of the current-time graph like so...
You saved my life ;-)
Great sir
Why is the time constant L/R as opposed to LR like an resistor-capacitor circuit?
Since an inductor opposes a CHANGE in the current, a smaller resistor will result in a final larger current and thus a larger change. Placing a smaller R in the denominator will cause a larger current change and a larger time constant.
He is the quintessential teacher = Professor MICHEL van BIEZEN comes out ALIVE from those PROBLEM SOLVER BOOKS published by SCHAUM Books/McGraw Hill.
Thanks for your funny comment. 😄
he was smiling at 0:00
Very good lecture Sir. Thanks 🙏🙏🙏🙏🙏🙏
Most welcome
Thanks fr the video.A concern with me is;why is l/R a function of time.i'll appreciate your response
The current is not a constant. The current start at 0 when the circuit is open. After the circuit has been closed for a while the current is V/R. The inductor prevents the current from changing instantaneously. Thus there is a gradual change of the current.
@@MichelvanBiezen when we are solving for current as a function of time we take (L/R) as a function of time in order to get integrating factor
Why do we take L/R as a function of time
jazakAllah
❤❤❤❤❤❤ thankes
Thank you
Simply 63.2% of whats available each time constant
That is one way to look at it. 👍
Adorable
this explanation is vague you don't explain why the inductance works how it works
That is not the purpose of this video. (see the other videos we have on indductors). This video explains how the current changes over time after the switch closes.