What is Euler's formula actually saying? | Ep. 4 Lockdown live math

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  • čas přidán 14. 06. 2024
  • What does it mean to compute e^{pi i}?
    Full playlist: • Lockdown math
    Home page: www.3blue1brown.com
    Brought to you by you: 3b1b.co/ldm-thanks
    Beautiful pictorial summary by @ThuyNganVu:
    / 1258220129327800320
    / 1258220541686628353
    Not on the "homework" to show that exp(x + y) = exp(x) * exp(y). This gets a little more intricate if you start asking seriously about whether the series really converge, what they converge to, and how exactly you define a product with infinitely many terms. For anyone curious about the technical details, what you would want to show is that the Cauchy Product of the series for exp(x) and exp(y) converges to the product of the values exp(x) and exp(y) for any particular x and y. That requires the Merten's Theorem.
    Thanks to these viewers for their contributions to translations
    Hebrew: Omer Tuchfeld
    ------------------
    Video Timeline (Thanks to user "Just TIEriffic")
    0:00:00 Welcome
    0:00:20 Ending Animation Preview
    0:01:15 Reminders from previous lecture
    0:03:30 Q1: Prompt (Relationship with e^iθ=…)
    0:05:40 Q1: Results
    0:07:15 WTF, Whats The Function
    0:10:00 Exploring exp(x)
    0:11:45 Exploring exp(x) in Python
    0:14:45 Important exp(x) property
    0:15:55 Q2: Prompt (Given f(a+b) = f(a)f(b)…)
    0:17:30 Ask: Which is more interesting, special cases or the general case
    0:20:00 Q2: Results
    0:23:50 Will a zero break Q2?
    0:25:40 The e^x convention
    0:27:10 Q3: Prompt (i^2 = -1, i^n = -1)
    0:27:45 Ask: Zero does not break Q2
    0:30:20 Q3: Results
    0:31:05 Comparison to Rotation
    0:33:00 Visualizing this relationship
    0:36:50 The special case of π
    0:39:20 Periodic nature of this relationship
    0:39:40 Q4: Prompt (e^3i)
    0:41:35 Q4: Results
    0:43:55 Explaining the celebrity equation
    0:45:55 Homework / Things to think about
    0:49:15 Ask: Zero does break Q2.
    0:50:30 Closing Remarks
    ------------------
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Komentáře • 1,8K

  • @3blue1brown
    @3blue1brown  Před 4 lety +928

    Summary of the confusion on problem 2. TL;DR, given the spirit of the question it should have also specified that f(x) > 0 for all x, and I'm clearly prone to deep confusion while trying to juggle the many balls of live broadcasting.
    The question asks about a function f satisfying f(a + b) = f(a)f(b). The relevant part of the question was whether f(-1) must be 1 / f(1).
    - It was originally graded in a way to suggest that this _does_ indeed need to be true.
    - While "explaining" it, I realized that the explanation required that f(0) = 1, and questioned whether this is necessarily true. I even said, "oh, you could just scale it". This thought of scaling is not correct, since (c*f(a))(c*f(b)) = c^2 f(a + b), so the lhs and rhs doesn't scale the same way.
    - At 27:48, Sam points out that the constant function f(x) = 0 doesn't work, which I misread as asking about whether f(x) = 0 for some x (sorry Sam!).
    - Crispin points out that f(0) must be 1 because f(x) = f(x + 0) = f(x)*f(0). This is true, as long as f(x) does not equal 0 everywhere, but at that point, I was still weirdly blind to that edge case and enthusiastically accepted this as a reason that the question was originally graded correctly.
    - At 49:07, more of the discussion that has been happening on twitter is brought to screen, where Eric correctly points out that Crispin's proof doesn't work for the constant function f(x) = 0, which Sam had said all along much earlier and I misread.
    Thanks for the good discussion, and the tolerance of some live befuddlement.

    • @oximas
      @oximas Před 4 lety +11

      I have a nice question does all functions that satisfy f(a+b) =f(a)f(b) produces values that are bigger than or equal to zero or can a function with such property have a negative output?

    • @theloganator13
      @theloganator13 Před 4 lety +77

      ​@@oximas Let's assume there is a continuous (you can draw it without lifting your pencil) function f(x) such that f(a+b) = f(a)f(b), and that at some place this function is negative, say f(c) < 0.
      In the spirit of this post, we can see that f(c+0) = f(c) = f(c)f(0), so f(0) = 1.
      We know that f(0) = 1 and f(c) < 0, which means that there must be a number d between c and 0 such that f(d) = 0.
      This means that f(1+d) = f(1)f(d) = 0. But also f(2+d) = 0. And f(3+d). In fact, we would find that no matter what number x is input to the function, f(x) = 0.
      But this contradicts our assumption that f(c) < 0. The contradiction means that the original assumption must be wrong, so there cannot be a continuous function f(x) such that f(a+b) = f(a)f(b) and f(c) < 0 for any number c.
      Using this same argument, we can show that the only continuous function such that f(a+b) = f(a)f(b) that can take the value 0 is the function f(x) = 0.

    • @theloganator13
      @theloganator13 Před 4 lety +60

      @3Blue1Brown Thank you so much for taking the time to walk through not only the correct answer, but also your own confusion. So often students (and many teachers) see teachers as infallible sages. It's very encouraging to see teachers demonstrating to students the process of admitting their errors but then persisting towards reaching the correct solution. Keep up the great work!

    • @tomekczajka
      @tomekczajka Před 4 lety +24

      @@oximas For real-valued functions negative values are not possible, because f(x) = (f(x/2))^2 >= 0.
      If complex values are allowed then you can get negative values, for instance...
      f(x) = e^(ix)
      Then f(pi) is negative.

    • @oximas
      @oximas Před 4 lety +6

      ​@@tomekczajka ohh i get it so all "real" functions (aka ones that don't contain imaginary values) only give nonnegative values, that's interesting.
      thanks for the help

  • @VadimKudim
    @VadimKudim Před 2 lety +318

    As a non-native English speaker, I'm really grateful that someone finally explained what WTF means.

    • @orang1921
      @orang1921 Před 10 měsíci +118

      i keep asking my friends what "idk" and "idc" means but they just respond that they don't know and don't care :(

    • @boonga585
      @boonga585 Před 10 měsíci

      @@orang1921this deserves more credit

    • @nikos4677
      @nikos4677 Před 10 měsíci +20

      ​@@orang1921lol nice joke

    • @cmgeolo
      @cmgeolo Před 7 měsíci

      😮

    • @aliatack19
      @aliatack19 Před 7 měsíci +3

      @@orang1921 I don't know you and I don't care to know you

  • @microhoarray
    @microhoarray Před 4 lety +917

    When he wrote Wtf = Whats the function
    I waited for him to laugh (cause i did) bu he didn’t. This guy is good on camera

    • @indianjitsingh8838
      @indianjitsingh8838 Před 4 lety +34

      That made me giggle too much

    • @knightwik
      @knightwik Před 4 lety +12

      @@indianjitsingh8838 my nigga!

    • @andreykol13
      @andreykol13 Před 4 lety +1

      Dr Peyam reference (i guess)

    • @sahilsagwekar
      @sahilsagwekar Před 4 lety +1

      I'm glad that he didn't say anything about it. I was watching this

    • @StarNumbers
      @StarNumbers Před 4 lety +5

      Maybe didn't spend much time in the bar

  • @hal6yon
    @hal6yon Před 4 lety +340

    37:22 Grant: π² is same as g
    Me: satisfied engineer noises

    • @JNCressey
      @JNCressey Před 4 lety +74

      mathematician: π² = g
      engineer: 3² = 10

    • @JM-us3fr
      @JM-us3fr Před 3 lety +6

      Heresy!

    • @alonsovm2880
      @alonsovm2880 Před 3 lety +9

      @@JM-us3fr g = 10

    • @ammyvl1
      @ammyvl1 Před 3 lety +14

      @@JNCressey Cosmologist: e² = 1+- 10^4

    • @ganondorfchampin
      @ganondorfchampin Před 3 lety +5

      @@JNCressey Mathematicians don't believe in g, surely you mean a physicist.

  • @peeyushkelkar
    @peeyushkelkar Před 4 lety +226

    Grant: *drinks water
    Me: Write that down!

  • @stewartmoore5158
    @stewartmoore5158 Před 4 lety +987

    Genuine question: Why aren't we taught this concept intuitively at institutions we literally pay thousands for each year? Why is it that we have to come to a free source to learn these things deeply?

    • @ccgarciab
      @ccgarciab Před 4 lety +140

      Pedagogy is a field that deserves to be studied and improved in it's own right. Unfortunately some institutions just look for teachers with dexterity in the branch of knowledge being taught but not in the knowledge of how to teach.

    • @jeffjiang5272
      @jeffjiang5272 Před 4 lety +57

      Schools have to make it "hard" to distinguish "good" students

    • @amatya.rakshasa
      @amatya.rakshasa Před 4 lety +107

      Being a great teacher and being a great mathematician are different skills and hard to find in the same person. Also, being a great teacher is not particularly valued by society so great communicators who deeply understand a subject frequently find other jobs. Ideally a University should hire mathematicians to do research and not force them to teach and hire teachers to teach.. but that would be too expensive. High schools only hire teachers but there aren't enough talented individuals in the world who deeply understand math, love teaching, and love students. Grant is like the LeBron James of math education and by definition every highschool in the world cant have their own LeBron James.

    • @hexa3389
      @hexa3389 Před 4 lety +48

      @@jeffjiang5272 I disagree. Those "good" students usually can't care less about what the teacher is saying as they are probably way ahead of the class. Or atleast that's how it is in high school. The way they teach math is bad because math teachers dont design the curriculum but education specialists who barely know any math.

    • @alekisighl7599
      @alekisighl7599 Před 4 lety +48

      Because of time.... I can't believe people don't understand this simple thing... This video takes an hour to deeply and beautifully explain the Euler's formula which is one part of complex numbers...
      While school teachers get about 30 minutes a class to do so

  • @davidgustavsson4000
    @davidgustavsson4000 Před 4 lety +469

    The memory rule I learned for the digits of e is
    {Everyone knows how it starts}{Ibsen's birth year}{Again}{The angles of a right isosceles triangle}
    2.7 1828 1828 459045

    • @stearin1978
      @stearin1978 Před 4 lety +19

      Leo Tolstoy birth year... etc.

    • @xyz39808
      @xyz39808 Před 4 lety +85

      how did I go this long without noticing that there's two 1828s in there

    • @davidgustavsson4000
      @davidgustavsson4000 Před 4 lety +26

      @@xyz39808 you could have gotten four extra digits for free.

    • @Jehannum2000
      @Jehannum2000 Před 4 lety +21

      @@xyz39808 When I first came across e I assumed the 1828 was recurring.

    • @davidgustavsson4000
      @davidgustavsson4000 Před 4 lety +59

      @@Jehannum2000 762 digits into pi, there are six nines in a row, which is an excellent point to stop memorizing and just say "et cetera".

  • @OAmus
    @OAmus Před 4 lety +535

    PLEASE KEEP THESE LECTURES COMING! They're wonderful and are demistifying a lot for me - way past highschool :)

    • @rockefellersavage4122
      @rockefellersavage4122 Před 3 lety +2

      13:15 is where I left off

    • @TechToppers
      @TechToppers Před 3 lety +1

      It's over. At least for now...

    • @ca-ke9493
      @ca-ke9493 Před 3 lety +3

      In all my years of highschool and engineering undergrad, the taylor series of e^x being the way to understand exp(x) was never emphasized like in the way here. Euler's formula was just the way to convert between polar and real/Im form of imaginary numbers and do some convenient maths that was noted down and refered to in a formula sheet. Closest was a professor explaining that defining trait of e^x is the function where its differential was the same as its integral, was the same as the value of e^x.

    • @ruutjormun2262
      @ruutjormun2262 Před 3 lety +1

      @@ca-ke9493 now that one threw me off in integration. every damn time a question asking integral of e^x, id be relieved, and id put e^x. so many missed marks

    • @ishworshrestha3559
      @ishworshrestha3559 Před 3 lety

      Ok

  • @Harsh-Words
    @Harsh-Words Před 4 lety +758

    I think " Maths for the Curious " is a better title for this series than 'Highschool maths'.
    As I don't know if this lecture would specifically help in highschool exams etc.
    But I think it is for anyone who is curious and wants to learn math with a little more intuition and creativity.
    For example: I work in theoretical physics, and have already learnt lots of Maths. Still going back and understanding math fundamentals in this beautiful way accentuates my understanding.
    Which is why I believe that " Maths for the Curious " is a better title, age no bar.

    • @3blue1brown
      @3blue1brown  Před 4 lety +252

      Interesting perspective! And probably true :)

    • @Harsh-Words
      @Harsh-Words Před 4 lety +60

      @@3blue1brown Hey, Thanx for the reply! Would love it if something similar was implemented in the next lecture onwards. While highschool maths reminds most people of dull problems and unnecessary competition, this on the other hand is truly magical.
      Love this series and infact for that matter all your material is brilliant, especially the " essence of " series. Keep up the great work!

    • @jennacook2505
      @jennacook2505 Před 4 lety +4

      +

    • @dramwertz4833
      @dramwertz4833 Před 4 lety +9

      I am also in High School and i agree. I for example wont have complex numbers in school before uni. Atm tho i think the lessons are in a perfect difficulty. Its quite challenging but if one invests a few hrs most should be able to manage iy

    • @fmjs5146
      @fmjs5146 Před 4 lety +11

      I think it depends where you go to high school. This is in the syllabus of high schoolers in certain parts of Europe and Asia 😅
      But regardless of what's in school syllabus, I feel that an appreciation of math like this is all the more important for people in their early to mid teens. So reaching out to high schoolers is a great thing.

  • @itays7774
    @itays7774 Před 4 lety +315

    I remember a couple years ago, during a particularly boring physics lesson, I messed around with my calculator and typed the sum over the factorials to see what i would get. To my surprise, i found out that the answer was 2.718... so i thought to myself "wait, it can't be", i took the ln of it and sure enough it was 1. I was blown away, and i thought i found a secret way to calculate e. Later I took calc 1 and discovered that i discovered nothing new, but still, that feeling when I accidentally stumbled upon this formula for e was really something else, and throughout the last 2 years of my bachelor's math degree, I only ever felt that way once again, the feeling of pride that i discovered something new and beautiful.

    • @macronencer
      @macronencer Před 4 lety +34

      Oh yes, I love epiphanies like this! Aren't they great? I think when you've stumbled upon something in this way you simply can't ever forget it. If only we could learn everything through personal discovery, we'd probably retain it all a lot better.

    • @vivekpanchagnula815
      @vivekpanchagnula815 Před 4 lety +14

      @Rayan I remember finding the same thing but by counting tiles when i was younger. I realized I could find the next square and made a formula for (x+1)^2 until i realized that there was an (a+b)^2 formula, which was equivalent.

    • @tyrannicalthesaurus4672
      @tyrannicalthesaurus4672 Před 4 lety +10

      For me, my search for the function equal to the sum of the factorials lead me down the rabbithole of calc. Little did I know that there was no elementary function describing the sum of factorials. It all stemmed from me discovering a neat formula, that the sum of the first n natural numbers is n(n+1)/2. That was really the start of my journey.

    • @ganondorfchampin
      @ganondorfchampin Před 3 lety +10

      Mine was finding a formula for calculating pi based on the limit of regular polygons.

    • @jimannothe
      @jimannothe Před 2 lety +2

      What was it he second time?

  • @raedinsmore7732
    @raedinsmore7732 Před 3 lety +48

    His excitement is contagious. And seeing him get flustered because he was live and didn't want to say the wrong thing makes me feel better about how I freeze up or get flustered. We're all human!

  • @chandrikadevib1100
    @chandrikadevib1100 Před 4 lety +20

    What I admire about you, is how you try to teach from a perspective of someone who doesn't know it. Most often, teachers forget how they felt while learning it and it becomes harder for them to explain than it was to learn.

  • @JustTIEriffic
    @JustTIEriffic Před 4 lety +243

    Video Timeline
    0:00:00 Welcome
    0:00:20 Ending Animation Preview
    0:01:15 Reminders from previous lecture
    0:03:30 Q1: Prompt (Relationship with e^iθ=…)
    0:05:40 Q1: Results
    0:07:15 WTF, Whats The Function
    0:10:00 Exploring exp(x)
    0:11:45 Exploring exp(x) in Python
    0:14:45 Important exp(x) property
    0:15:55 Q2: Prompt (Given f(a+b) = f(a)f(b)…)
    0:17:30 Ask: Which is more interesting, special cases or the general case
    0:20:00 Q2: Results
    0:23:50 Will a zero break Q2?
    0:25:40 The e^x convention
    0:27:10 Q3: Prompt (i^2 = -1, i^n = -1)
    0:27:45 Ask: Zero does not break Q2
    0:30:20 Q3: Results
    0:31:05 Comparison to Rotation
    0:33:00 Visualizing this relationship
    0:36:50 The special case of π
    0:39:20 Periodic nature of this relationship
    0:39:40 Q4: Prompt (e^3i)
    0:41:35 Q4: Results
    0:43:55 Explaining the celebrity equation
    0:45:55 Homework / Things to think about
    0:49:15 Ask: Zero does break Q2.
    0:50:30 Closing Remarks
    Water drinks at 0:17:10 & 0:27:45 & 0:40:05
    Edits: Moved water drinks to the bottom, spelling errors, these timestamps should be for after the video is trimmed at "Welcome!"

    • @jadenchen8921
      @jadenchen8921 Před 4 lety +12

      My favorite is 0:07:15

    • @mazajee
      @mazajee Před 4 lety +5

      doing gods work

    • @JustTIEriffic
      @JustTIEriffic Před 4 lety

      Had a problem where last video's comment became unpinned after updating timestamps for trimmed video. These timestamps are for the trimmed video (assumed it was trimmed at 5:10) if you wish to use it before the video is trimmed, add 5 minutes and 10 seconds to the displayed timestamp.

    • @coolguy284_2
      @coolguy284_2 Před 4 lety +3

      I lolled at the WTF = what's the function part. I guess he's really prepared, with 69 and WTF.

    • @thguzzo17
      @thguzzo17 Před 4 lety

      Great

  • @3blue1brown
    @3blue1brown  Před 4 lety +164

    For those of you who haven't seen it, Mathologer has a wonderful video on Euler's formula: czcams.com/video/-dhHrg-KbJ0/video.html
    A worthy question is to ask what the connection is between the limit he writes and the polynomial here. Perhaps good fodder for the next lecture :)

    • @ayyoubfatene3768
      @ayyoubfatene3768 Před 4 lety

      Please can you tell me which tool is used to make such a great video ?!

    • @judsongordy8872
      @judsongordy8872 Před 4 lety +6

      Sam was saying that f(x)=0 satisfies f(a)f(b)=f(a+b), but does not satisfy condition 3, and therefore, only answer 1 and 2 are necessarily correct.

    • @karkaroff1617
      @karkaroff1617 Před 4 lety +3

      23:48 f(0) must be 1, because f(n) = f(n+0) = f(n)f(0) = f(n).1 = f(n)
      edit: just when f(n) =/= 0.

    • @judsongordy8872
      @judsongordy8872 Před 4 lety +2

      @@karkaroff1617 If f(n)=0 then we have 0*f(0)=0. And f(0) could 1 or 0 or any other constant. Therefore, if f(n)=0, then equation 3 isn't satisfied. The problem should have stated that f(n) is not 0.

    • @EebstertheGreat
      @EebstertheGreat Před 4 lety +3

      One topic I had always wondered about was a more direct (but challenging) way of defining a^x (a,x∈R, a>0) in terms of Cauchy sequences (a^qₙ) where rational every qₙ is rational and qₙ→x. It would require proving that every such sequence was Cauchy, so by completeness they converge to some real y, and in particular that they converge to the same y. Then (using whatever is your favorite definition of e), exp(x) = e^x, and log(x) = exp⁻¹(x).
      This makes it a direct extension of exponentiation with rational exponents, which are essentially defined by the requirements that a^x * a^y=a^(x+y) and a^1 = a, along with the convention that a^x > 0. It feels a little more motivated than the backdoor method of, for instance, defining log(x) in terms of an antiderivative, then defining and extending its inverse, and finally proving that the resulting function corresponds with the usual definition for rational arguments. Since it is continuous by construction, these two approaches are equivalent, but it feels kind of . . . slippery.

  • @nobodysfool2232
    @nobodysfool2232 Před 3 lety +19

    I’m a middle-aged financial engineer and learn from your lectures- and I was definitely paying attention to math classes in high school. Watching your videos and the beautiful new perspective you cast on sometimes elementary topics is like re-watching a classic movie or re-reading a classic novel and getting whole new appreciation for the material as if you were reading it for the very first time.

  • @WriteWordsMakeMagic
    @WriteWordsMakeMagic Před měsícem +1

    I love how you just deadpan the WTF acronym

  • @bayleev7494
    @bayleev7494 Před 4 lety +46

    In the proof of the necessity that f(0) = 1, the hole in the logic was after the step f(0)f(x) = f(x). This results in f(0) = 1 if and only if f(x) is not zero (so that we don't have to divide by 0). This means that, while true that f(x) = 0 is an exception, it's also the only exception.
    Also at 24:03, where you say that you could scale the function to get a different result for f(0), that wouldn't work because it would no longer satisfy f(x+y)=f(x)f(y). Multiplying the two outputs would result in your scaling factor squared on the right hand side, while the left hand side would only have a single scaling factor.
    With that said, I really enjoyed this lecture! Can't wait for the next one :)

    • @rossigu3006
      @rossigu3006 Před 4 lety +1

      This is what I'm looking for. Nicely done

  • @capilover1023
    @capilover1023 Před 4 lety +621

    Grant: "so you see this weird formula, I think the healthy question to ask is WTF..."
    Me: :)
    Grant: "... - whats the function?"
    Me: :O

  • @itchy7879
    @itchy7879 Před 4 lety +6

    These are really fascinating - I'm a curious high school student and I'm loving seeing these things I just learned in a new way. Thanks for being awesome :)
    I had actually never seen the Euler Formula, but the connection to the unit circle makes it easier to digest

  • @George_Varvoutis
    @George_Varvoutis Před 4 lety +4

    This is some serious educational content, your professionalism and passion to share math knowledge is astonishing. Keep up the good work!

  • @capilover1023
    @capilover1023 Před 4 lety +226

    I don't know why, but this lecture seemed too short to me, even though it was only 10 minutes shorter than the previous ones. Apparently, I've become addicted to your awesome videos, Grant! Well done!

    • @randomguy263
      @randomguy263 Před 4 lety +2

      Well, really a lot of the pther lectures were about 70 minutes, but, yeah, this lecture felt very shirt.

    • @hexa3389
      @hexa3389 Před 4 lety +1

      Me too. It felt like half of the regular ones.

    • @spb1179
      @spb1179 Před 4 lety +1

      Lol my watch time this last week has been like 60% 3b1b and that says a lot because I’m predominantly watching yt

    • @Ultiminati
      @Ultiminati Před 4 lety

      It's first 5 or 10 minutes were afk, it is a short one

  • @elfuego7572
    @elfuego7572 Před 4 lety +252

    I laughed so hard when he said WTF "What's the function ofc" !

  • @gamewarrior348
    @gamewarrior348 Před 4 lety +6

    Grant, I just want to say how much joy these bring me every Tuesday and Friday. Is it possible/feasible for you to keep doing this in the long term? Or at least longer than quarantine may last, as it is helping to give a much better understanding of the math concepts that end up getting used in my classes.

  • @onlycheeseextracheese8718

    I'm a mechanical engineering graduate who's in the midst of studying for my math subject GRE in the hopes of pursuing academia and go back to grad school for pure mathematics. Your videos have not only helped me throughout the last year with grasping abstract ideas conceptually, but you've also helped me gain a whole new appreciation for mathematics as a whole. Thank you sir. You are a treasure to this world.

  • @gladiusilluminatus3720
    @gladiusilluminatus3720 Před 4 lety +39

    I just want to say that this series is absolutely awesome. I never thought of myself as a math person much less a math nerd and yet I just sat here for hours and have learned and understood so many things I never grasped before so Thank you! I really wish for this to become a regular thing even after the world returns to "normal". Would I not already be a Patreon this series would have definitely earned it. As a student of I often struggle to understand math and as of now firmly belong in the category of didn't understand it but just went along with it as well as I could but you are really changing my perspective on maths and are showing me that instead of frustrating it can be fun and interesting.
    EDIT:
    Okay it seems I accidentally canceled my Patreon subscription last time I cleared up my payments! This grave mistake has been remedied. So in a way this video DID earn my subscription (again).

  • @spb1179
    @spb1179 Před 4 lety +26

    Grant I really hope that there are a good 20-30 more of these lectures in the future, they are so much more insightful that high school math and they have really given me an interest in diving into more complex math, keep up the good work and please don’t stop these lectures once we end lockdown

  • @g.wilcken7992
    @g.wilcken7992 Před 3 lety +5

    The animation of the vector interpretation of the terms of the power series... such beauty. Absolutely beautiful.

  • @The300Trolls
    @The300Trolls Před 4 lety +5

    You tricked me into listening to a full math lecture by explaining it in an interesting way.

  • @CraigNull
    @CraigNull Před 4 lety +59

    Fun observation: when you plug in a positive integer N into Maclaurin series form of exp(x) the individual terms are increasing until you get to the Nth term, the N+1th term equals the Nth term (using indexing that calls x^k/k! the k+1th term), and the culmulative sum of the terms passes the halfway point exp(N)/2 of the total sum between the adding on of the Nth and the N+1th terms. You can ask, if you summed up to the Nth term, what fraction of the N+1th term do you need to add on to get to exactly exp(N)/2. The answer appears to be very close to one-third in the limit of large N, but not quite. It's also close to the square of the Euler-Mascheroni constant.

  • @williammclaughlin2247
    @williammclaughlin2247 Před 4 lety +70

    I’ve just finished year 11 in the UK (16 years old) and I’ve never come across these topics before but they are incredibly well explained and very interesting. I’m happy to be enjoying maths more than I usually would and learn some topics which I’m sure I will come across next year in A-Levels.

    • @AdityaKumar-ij5ok
      @AdityaKumar-ij5ok Před 4 lety

      William McLaughlin hey i am interested what your maths syllabus include cause these topics are actually in my normal math syllabus in India although no Euler formula is shown, it's a plus to know in competitive exams

    • @ASLUHLUHCE
      @ASLUHLUHCE Před 4 lety

      And do further maths. Normal maths has no linear algebra, no complex numbers

    • @pizzahut3001
      @pizzahut3001 Před 4 lety +1

      Wish I had seen these videos during my education, you have a massive advantage!

    • @user-rv9vk8by5i
      @user-rv9vk8by5i Před 3 lety

      ​@@AdityaKumar-ij5ok Another UK student here, just finished with year 11
      And I can confirm, the topics are massively disappointing. At the end of the year we did like, 1 lesson on vectors, and that was just how to add them. And in one of the exams we did, the only question about vectors was the very last question.
      It's mostly just relatively basic geometric proofs, quadratics, and.. that's pretty much it, actually.
      That is for the higher tier test, by the way - the foundation test is mostly comprised of addition, multiplication, ratios, etc
      Just like the original comment, I'm also going to take A-Level maths, and _hopefully_ it'll be at least half as interesting as these videos.

  • @LydellAaron
    @LydellAaron Před 3 lety

    Fantastic job--I mean the whole experience you created for us. The experience, and your energy made for an engaging live stream in mathematics. What I like most, that I didn't get in high school or college, is the ability to pause, rewind, re-listen and absorb--I always felt rushed. Thank you.

  • @TheViolaBuddy
    @TheViolaBuddy Před 4 lety +13

    That's actually a really interesting point of view that I haven't seen before, that writing e^i is arguably an abuse of notation for exp(i), and in general the fact that e^x and exp(x) are two different functions that just happen to have the same value everywhere that e^x is defined, e^x meaning "multiply e by itself x times" and exp(x) meaning "do this infinite sum on x." The strict e^x would be undefined on imaginary numbers, but because it's equal to exp(x) whenever it does exist, we just write e^ix to mean exp(ix) without much confusion once you understand the convention.
    It's pretty similar to the relationship between factorial and the gamma function, which you actually allude to here. x! and Gamma(x+1) are two different functions that just happen to have the same value everywhere that x! is defined (though there is the +1 that makes it annoying). In a strict sense, (1/2)! is undefined; how could you take every integer starting from 1/2 and going down to 1 and multiply them all together? But because Gamma(x), defined by a funny integral, is the same as the factorial where they do exist (offset by 1), we often will write (1/2)! to actually mean Gamma(3/2), and there isn't really any confusion there.

  • @JaredHaertel
    @JaredHaertel Před 4 lety +174

    The proof f(x + 0) = f(x) * f(0) => f(0) = 1 only needs the condition f(x) does not equal 0 to be valid. Whether or not f(-1) = 1 / f(1) should count as a valid answer is up for debate.

    • @rhitamdutta1996
      @rhitamdutta1996 Před 4 lety +18

      Yeah, so if for f(a+b)=f(a)*f(b) you put a and b as 0, you get two solutions for f(0), ie, 0 and 1. Whichever you take is up to you. Usually, in math questions like this, the question usually has the assumption that f(0) is not equal to zero. Funny how that was the first thing that popped into my mind, from years of solving objective questions.

    • @chaosredefined3834
      @chaosredefined3834 Před 4 lety +7

      There are also undefined values. Technically, the following can work:
      f(x) = 0 if x >= 0
      f(x) = undefined if x < 0
      If undefined * 0 = 0 is a valid output (e.g. f(-1)*f(2)=f(1)). Because it also ends up giving undefined * 0 = undefined (e.g. f(-2)*f(1)=f(-1))

    • @esquilax5563
      @esquilax5563 Před 4 lety +21

      @@chaosredefined3834 he said that the given property holds for all real numbers, which implies that the function is defined for all real numbers

    • @wewladstbh
      @wewladstbh Před 4 lety +7

      @@rhitamdutta1996 homomorphism moment

    • @jons2cool1
      @jons2cool1 Před 4 lety +2

      Rhitam Dutta In all of the math classes I’ve taken any number to the power of 0 has been 1. Does the possibility of 0 come from that it can be any function that has this property? What’s an example. The last question f(-1)= 1/f(1); I reasoned that a^(-1)=1/a. Assuming f(x) to be a^(x) based on the fact that this function has the given property. Is this correct reasoning?

  • @RobertLeyland
    @RobertLeyland Před 4 lety +9

    Thanks for doing this.
    Today I was unable to attend live, but I’d pause and figure out some of the answers at each step. I truly appreciate the simplicity of the expansion series, and the resulting connection to the rotation.
    As others have mentioned, I do wish this is how the teachers had explained this in math class.

  • @kxfin
    @kxfin Před 2 lety +2

    I always struggled with the intuition of this connection in my university math lectures. Nobody was able to communicate the absolute beauty of this formula the way you just did. Bravo

  • @blownuppumpkin95
    @blownuppumpkin95 Před 4 lety +1

    Man your lessons are incredibly good. It's people like you who change the world. Looking forward for other videos !

  • @shawon265
    @shawon265 Před 4 lety +41

    Hey Grant,
    I signed up for twitter just to answer that f(a+b)=f(a)f(b) question. But couldn't properly figure out how twitter works :|
    However, f(0) could either be 0 or 1. Here's the proof.
    If a=b=0, f(0+0)=f(0)*f(0)
    => f(0)=f(0)²
    => f(0) = 0 or 1
    if f(0)=0, f(x+0)=f(x)*f(0)=0
    So, f(x)=0 is a valid solution.
    And f(0)=1 gives the exponential solution.

    • @wewladstbh
      @wewladstbh Před 4 lety +5

      f(x) = 0 is a really boring solution though, "yeah lets have the kernel be the reals LOL what a trolllllllllllllllll"

    • @3blue1brown
      @3blue1brown  Před 4 lety +14

      Perfect, thanks!

    • @samuelheidenreich373
      @samuelheidenreich373 Před 4 lety +9

      Really nice proof. For those confused on the jump from step f(0)=f(0)^2 to f(0) = 0 or 1, you can substitute f(0) = x, and now x = x^2, and x^2 - x = 0, which is a quadratic with solutions 0 and 1.
      And just to emphasize that this proof means that either f(x) must be the constant function f(x)=0, or f(0) must =1.
      EDIT:
      I just realized that if there is any c such that f(c)=0, then f(x)=0 is true for all x, since there is a number a where x = a + c.
      f(x) = f(a+c)
      f(a+c)=f(a)*f(c)
      f(x)=0
      So to sum it all up, if there is any number c such that f(c)=0, then f(0)=0 and f(x)=0 for all x. Otherwise, f(0)=1 and f(x) is never 0.

    • @matanshtepel1230
      @matanshtepel1230 Před 4 lety

      Yes :) when doing this and getting the less boring answer we must assume that f(any real)=0 is not the case (such as for the exp(x) function.

  • @xicodomingues
    @xicodomingues Před 4 lety +20

    I have a bachelors in math and I think this is the first time I actually fully understood the e^(pi*i) = -1. Thank you!

  • @clamr6122
    @clamr6122 Před 2 lety +3

    It's like someone built the perfect teacher in a lab. Thank you so much.

  • @josephfrancis4326
    @josephfrancis4326 Před 4 lety +4

    Thank you so much! It took a while, but at 37:21, the idea of how rotation connects with the definition of i and the complex plane just finally clicked, seeing the exp(i*theta). Your animations are wildly helpful!

  • @illustriouschin
    @illustriouschin Před 4 lety +35

    The question song at the beginning is nice.

    • @swaree
      @swaree Před 4 lety +9

      Vincent Rubinetti --- Grant's New Etude

    • @NovaWarrior77
      @NovaWarrior77 Před 4 lety +5

      @@swaree you people make the world great.

  • @moskthinks9801
    @moskthinks9801 Před 4 lety +4

    Solutions to this lesson's homework.
    1. To show that the terms of exp(x)*exp(y) have
    the form x^k*y^m/(k!*m!), one can write the expression as
    (1+x+x^2/2+...+x^k/k!+...)(1+y+y^2/2+...+y^m/m!+...)
    By expansion, we can choose one term from the first bracket
    and another from the second bracket, and the power of x and y
    would be unique, so the term is just x^k/k!*y^m/m! or x^k*y^m/(k!*m!)
    2. To show that exp(x+y) have terms of the form 1/n!*(n choose k) x^k*y^(n-k)
    Just write exp(x+y)=sum_{n=0}^{infty} (x+y)^n/n!
    Use (x+y)^n = sum_{k=0}^{n} (n choose k) x^k*y^(n-k)
    Again, the powers of x and y are always unique. Hence, the coefficient of x^k*y^(n-k) is
    (n choose k)/n! (remember division by n! from the exp function). Thus, proven.
    3. To show that (1) and (2) imply that exp(x)*exp(y)=exp(x+y), see (2).
    Let n-k=m. We can always pick n=m+k such that we have powers x^k*y^m in the expansion.
    Additionally, we have the coefficient is (n choose k)/n!=((n!)/(k!*(n-k)!))/(n!)
    =1/(k!*m!), which is the same as 1. Hence, each term of exp(x+y) corresponds with a term
    of exp(x)exp(y). Thus, they are equal.
    4. For real numbers, this is evidently okay.
    For complex numbers, we can easily justify that (1) and (2) work because of commutativity, associativity, and distributivity,
    because then we can do the algebra quite well like with the real numbers.
    As of matrices, we can define power of matrices and division by scalars, and so exp(A) is defined, given A is a square matrix.
    However, the property exp(X+Y)=exp(X)exp(Y) holds usually when XY=YX (they commute), such that the binomial theorem can hold
    (terms in the binomial expansion are stuff like XY and YX, which we could add together if they commuted, but that's not always the case for matrices)
    Consequently, exp((a+b)X)=exp(aX)exp(bX), where X is a square matrix, and a and b are scalars.
    Moreover, exp(X)exp(-X)=I, where I is the identity matrix that behaves like 1 in sense of multiplication (behaves like exp(0)).
    So yes, we can extend the definition for many different objects if we need to, like complex numbers and matrices, and these can benefit us in
    electric engineering or differential equations.
    Great homework, great lesson 3b1b! See you in the next lecture!

  • @thomase5374
    @thomase5374 Před 2 lety +1

    Hi! Please do more of these with homework! I'm currently trying to teach myself math as a hobby and practice sets would be a fantastic resource. I've loved this lockdown live math series and more would be amazing even as covid etc. finally clears up

  • @cathyfalk6839
    @cathyfalk6839 Před 3 lety

    As a calculus teacher, your graphics with the unit circle were outstanding and very insightful. I will definitely use that when I teach this topic this spring!

  • @poojaupadhyay3326
    @poojaupadhyay3326 Před 4 lety +152

    Hey Grant, please make WTF T-shirts !

    • @hexa3389
      @hexa3389 Před 4 lety +12

      Yes please. I won't buy one cause I'd be bullied to death at school but it'll be cool.

    • @a.fleischbender7681
      @a.fleischbender7681 Před 4 lety +1

      I'd buy it.

    • @Jared7873
      @Jared7873 Před 4 lety

      Buyer beware!

    • @cookie_n_Kurimu
      @cookie_n_Kurimu Před 4 lety +5

      yeah "WTF?" on the front and "What's the Function?" on the back!

    • @user-ss3oz7by1g
      @user-ss3oz7by1g Před 3 lety

      Should be something like this:
      WTF:
      What's the Function?

  • @Green_Eclipse
    @Green_Eclipse Před 4 lety +7

    Another great connection is that we can plug ix into exp and split that into the real and imaginary parts to get the Taylor polynomials for cos and sin.

  • @MichelleMaia
    @MichelleMaia Před 4 lety +4

    I just got my mind blown!! I'm engineer and it's the first time I've seen such explanation about exp(iθ)! Great lesson! Thank you Grant!!

  • @DanielMaidment
    @DanielMaidment Před 4 lety +1

    I'm watching this, and I think I know it well, but your videos are so good and insightful that it's probably worth watching anyway. I think you've shown me how to love math again, and how much insight can be gained with geometric interpretations.

  • @Jahus
    @Jahus Před 4 lety +5

    0:45 That animation says it all! And that's why 3Blue1Brown is the best! You taught me what 7 years of Calculus at University didn't. Thank you!

  • @user-on9rs3yx3s
    @user-on9rs3yx3s Před 4 lety +4

    I have an engineering degree and I genuinely thought that e^i.theta was referring to the exponential function, ie multiplying the number e by itself theta (or x) amount of times. Showing that it was the exp function (which is totally different) really opened it up for me.

    • @carultch
      @carultch Před 2 lety +2

      It ultimately is the same function. Just a different perspective of it.

  • @petarkasapinov7324
    @petarkasapinov7324 Před 4 lety +1

    You sir are a legendary wizard! I wish all of my math teachers taught like you do. Very insightful and satisfying. Keep up the good wizardry!

  • @alighasemian7118
    @alighasemian7118 Před 3 lety

    I really cannot show in words how much I enjoy your lectures. Whenever I see your videos I end up, "WOW, what an amazing way to look at this problem."

  • @uhgs
    @uhgs Před 4 lety +10

    OMG you just answered me a question wich confused me for 2 years now and I already gave up to understand why e^i*pi should make sense. It's because it's actually not e^i*pi but exp(i*pi) where exp(x) not necesseraly is equal to the thing we have in mind when we see e^x. THANK YOU!

    • @marcmengel1
      @marcmengel1 Před 4 lety +2

      See, *this* is the confusion caused by the presentation. exp(x) (the infinite one, not the python approximation) *is exactly* e^x ; the Taylor series *is exactly* equal to the function it's derived from, even in the complex plane... It ends up informing our understanding of what exponentiation to a complex value means.

  • @denny141196
    @denny141196 Před 4 lety +29

    37:30 Ah, you’ve stumbled across the fundamental theorem of engineering. pi=e=3=sqrt(g)

  • @1loshvitalik
    @1loshvitalik Před 4 lety +2

    Videos like these are useful not just for highschool students. For them, sure, they may be helpful in leaming these topics.
    For people like me, who has studied maths not that long ago and still remembers most of the ideas, watching these videos is very pleasing because I can focus specifically on logical, intuitive details of your explanations without having to struggle memorizing all of this new info from scratch.
    Yes, we've been taught all these topics, I know how to do all of that mathematically, but it is extremely satisfying to get an intuitive look on things that you already know in the form that is usually taught, re-think them, make the information in my head more organised and open possibilities to use this knowledge in real life.

  • @jsmunroe
    @jsmunroe Před 4 lety

    I love your normal videos, but I really love these as well. I hope you do more of this style in the future. I've been an amateur mathematician for along time, so this is just a refresher for me, but it is still fun as hell. I think that is what is key in becoming good at math or anything really. That is actually enjoying going over stuff you already know. ;)

  • @patinho5589
    @patinho5589 Před 4 lety +3

    I did A-level maths and and A-level further maths in 1996 at age 18 (high school).
    We did some complex numbers stuff in further maths.. but you know it’s all learnt to pas an exam then forgotten after the exam. I got an A grade in each.
    This series is giving me a proper understanding of trig, and the other topics that I never had so firmly ever before.
    And even little things I never got round to getting comfortable with (- simplifying square roots!)
    So this level is totally perfect for me !
    It’s like I’m taking off from where I was! I did economics at uni and didn’t really learn any maths so I’m loving taking my learning forwards from where I was 24 years ago.

  • @tkeooudom
    @tkeooudom Před 3 lety +3

    This video is simply beautiful. I am one those engineers who just accepted euler's formula and used it without ever deeply, intuitively understanding it. This is the best explanation of the formula. Thank you so much. Please keep making more of these videos.

  • @xkcd000
    @xkcd000 Před 4 lety +1

    I am loving these classes.
    Thanks for arranging them.

  • @SashaTownsendTulsa
    @SashaTownsendTulsa Před 3 lety

    Grant, this is wonderful. I’m preparing to teach synchronous online classes, and I wanted to see how you conducted a live class. I love this beautiful formula, and the way you shared it with the world in this wonderful, interactive way. Thank you for giving me some ideas, for your lovely personality, your musical taste, and the beautiful math!

  • @Gold161803
    @Gold161803 Před 4 lety +7

    My takeaway: exp(x) is very hard to introduce intuitively without the use of calculus. A valiant effort all the same, as always! Well done!

    • @ganondorfchampin
      @ganondorfchampin Před 3 lety +3

      The real significance of the function is that it's the function (well, it and any constant multiply of it, but it's the only of those that also has the algebraic property discussed in the video) whose derivative is itself, and the definition inherently entails calculus.

    • @Gold161803
      @Gold161803 Před 3 lety +2

      @@ganondorfchampin my point exactly!

    • @ganondorfchampin
      @ganondorfchampin Před 3 lety +1

      @@Gold161803 Slight correction to what I said, the constant function 0 ALSO has the algebraic property mentioned in the video AND is it's own derivative, but exp is more interesting for obvious reasons.

  • @surajvkothari
    @surajvkothari Před 4 lety +36

    ~~~ HOMEWORK ~~~
    Time-stamp: 45:56
    1. Fully expand exp(x) * exp(y).
    2. Expand exp(x + y). Hint: Binomial Formula.
    3. Compare the two expansions above.
    **4**. Show the properties for complex numbers and matrices.

  • @dustinsnodgress8026
    @dustinsnodgress8026 Před 2 lety +1

    Please do more of these live vids. They are awesome! No need for lockdown, just do it!

  • @leoyang1.618
    @leoyang1.618 Před 4 lety

    This channel is the best channel out here on mathematics. Although I still don't understand some of the harder content, it provides me with a deep intuition of various math topics. I feel like younger students like middle schoolers are also able to understand most of the content, since it is so well explained.

  • @noahtaul
    @noahtaul Před 4 lety +10

    The exponential formula only works if x and y multiplicatively commute. So for real and complex numbers it’s ok, but if x and y are matrices, if you try to expand out (x+y)^2 for example, you get x^2+xy+yx+y^2, which is not equal to x^2+2xy+y^2 which is what you need.

    • @EebstertheGreat
      @EebstertheGreat Před 4 lety +3

      Implicitly, the function f is from R to R. I guess he could have stated it explicitly, though. He also missed the special case of f(x) = 0, which satisfies the condition but does not satisfy property (3).

    • @Kaepsele337
      @Kaepsele337 Před 4 lety +1

      For anyone that wonders, if there is a corresponding equation for noncommuting matrices, it's called the Baker-Campbell-Hausdorff formula.

    • @noahtaul
      @noahtaul Před 4 lety +1

      EebstertheGreat oh I guess I should point out that I was answering the homework question number (4*). Sorry!

  • @lindap.5921
    @lindap.5921 Před 4 lety +6

    I'm 3 hours late due to a scheduled physics lab but I am very grateful for this 'Lockdown' series !!

  • @andrewalker3660
    @andrewalker3660 Před 2 lety

    By far one of the best videos in terms of giving a great intuition! Keep up the great work!

  • @Lorendrawn
    @Lorendrawn Před 2 lety +2

    My University math professor had a genuine adoration of math. Failing his class is one of the few things I regret in college. His last gift to us on the last day of class was to show us Euler's formula. He talked about how it beautifully encapsulated everything we had studied up to this point and about how beautiful math is.

  • @sailor5853
    @sailor5853 Před 4 lety +8

    That was the first time I felt really confident to try and go for the question and I am really happy to see I could find the correct answer. (around min 20)
    That may be silly but I feel like that is my first step to really understand math.

  • @ethanfaust8513
    @ethanfaust8513 Před 3 lety +5

    43:05
    python has a built in round function, no need to import numpy.
    great video, thank a lot!!

  • @williamweatherall8333
    @williamweatherall8333 Před 2 lety +1

    this is incredible. One of the most worthwhile math videos I've ever seen.

  • @ryanmarshall2503
    @ryanmarshall2503 Před rokem

    I have been wondering this forever, and asked many math teachers to explain, to no avail. Thank you!

  • @ASLUHLUHCE
    @ASLUHLUHCE Před 4 lety +29

    So the main takeaway of this lecture is:
    "e" does not literally represent the number 2.71828, whereby e^x means 2.71828 being multiplied by itself x amount of times.
    Rather, *e^x = (1+x/n)^n as n approaches infinity*

    • @davidlixenberg5999
      @davidlixenberg5999 Před 2 lety

      I commented that at lecture close the WTF was completely unclear to me. I believe that you have helped me get to grips with this central point.
      Many, many thanks. David Lixenberg

  • @azpcox
    @azpcox Před 4 lety +11

    The beauty of seeing e^x written as exp(x) and the series expansion is that it becomes immediately obvious why the derivative of e^x is simply e^x. Thanks again for making these series! Pointing every high school kid I know this way to learn in maybe a different way to cement ideas and concepts in their heads.

    • @ster2600
      @ster2600 Před 4 lety +2

      This is not an obvious fact! It's pretty hard to prove that you can differentiate power series in a term by term fashion within their radius of convergence

    • @vincentandrieu5429
      @vincentandrieu5429 Před 4 lety +2

      @@ster2600 you're wrong. It does make it obvious. exp(x) is the sum of x^n/n! terms, plus a constant (1).
      So the derivative of exp(x) is the sum of the derivative of those terms.
      The derivative of x^n/n! is nx^(n-1)/n!
      which is x^(n-1)/(n-1)!
      Let's call N=n-1
      The derivative of
      x^n/n!
      is
      x^N/N!
      So basically the derivative of each term is the previous term in the series. As it's an infinite series, that makes no difference as n grows. And on the other side, the lower n side, you get the derivative of x which is 1, so you get all your terms back from the original.

    • @ster2600
      @ster2600 Před 4 lety +1

      @@vincentandrieu5429 that's only true for finitely many terms, while exp is an infinite series

    • @vincentandrieu5429
      @vincentandrieu5429 Před 4 lety +2

      @@ster2600 What I wrote is not valid for finite series. It's only valid for infinite series, and exp is an infinite series.

    • @Mathhead2000
      @Mathhead2000 Před 4 lety +1

      @@vincentandrieu5429 I think what Ster Chez was trying to say was that what's true in the finite world isn't always true in the infinite world. Just because the derivative of a finite sum is the sum of each terms' derivative (i.e. the additive property of derivatives), doesn't mean that the derivative of an infinite sum is also the sum of each of it's terms' derivatives.
      You would have to prove that this is a general property of derivatives (hint: it's not).

  • @locomate23
    @locomate23 Před 4 lety

    You are amazing Grant! Never stop doing this please!!

  • @henrybash2285
    @henrybash2285 Před rokem

    Great math lessons make me learn something new... but the greatest ones completely recontextualize things I thought I understood beforehand. This video was such an awesome walkthrough and, most importantly, made me understand WHY e^ipi works. Great job!

  • @AlexKing-tg9hl
    @AlexKing-tg9hl Před 4 lety +8

    0:35 it’s so satisfying that the 3b1b logo perfectly aligns right with the down count of the rhythm.

    • @spb1179
      @spb1179 Před 4 lety

      Alex King this part got cut off :(

  • @NadellaVasishta
    @NadellaVasishta Před 4 lety +16

    Grant: WTF= what's the function?
    Dr.Peyam: WTF= want to find
    Us: WTF..
    = We're thy fans!

    • @davidliu323
      @davidliu323 Před 4 lety +2

      WOW I took Dr. Peyam's last class at UCI this past winter on multivariable calculus and "want to find" was the first thing that came to my mind too. I didn't think anybody else knew of him!

  • @astronomy-channel
    @astronomy-channel Před 10 měsíci

    Best lecture series on You Tube, period!
    I’m continually amazed…bravo

  • @hazelgalban3566
    @hazelgalban3566 Před 4 lety +1

    I think that watching videos of mathematics that are complex, I get brighter everyday :) Thanks Grant for the cool lectures!

  • @user-nf6jl9cg1t
    @user-nf6jl9cg1t Před 4 lety +40

    WTF LOL
    also I loved that you used python and showed it to us

    • @seheyt
      @seheyt Před 4 lety +2

      I had actually been pausing the video to do exactly the same thing. I was pretty pleased to find I had beaten him to showing me the exact same thing. I stumbled a bit more along the way, but (!!!) I realized that you do not have to clumsily type `complex(3,2)` - you can simply say 3+2j

    • @z.e....3175
      @z.e....3175 Před 3 lety

      WHAT'S THE FUNCTION LOL.

  • @ollerich32
    @ollerich32 Před 4 lety +10

    I hope that lockdown never ends. Learning so much these days!

    • @Ultiminati
      @Ultiminati Před 4 lety +2

      i enjoy that too but bruh, i don't want to stay at home forever. :D

    • @SoumilSahu
      @SoumilSahu Před 4 lety +1

      I understand your sentiment, but you do realise there are people starving to death because they have no jobs?

    • @Ultiminati
      @Ultiminati Před 4 lety +3

      @@SoumilSahu I think you get the point of the comment, he didn't mean that ofc

    • @Trucmuch
      @Trucmuch Před 4 lety

      You realize that you can watch educational YT videos even when there is no lockdown right?

    • @Ultiminati
      @Ultiminati Před 4 lety +1

      @@Trucmuch but there is no time to think through things

  • @parthibanpalani6490
    @parthibanpalani6490 Před 3 lety

    Thank you. Wonderful video, finally understood this important concept. We need more people like you with such a level of understanding and interest teaching in the schools and colleges. Thanks to CZcams, now every person can access such quality education.

  • @bellzgoose9040
    @bellzgoose9040 Před 4 lety

    thanks so much grant ! your lectures make math easy to fall in love with

  • @babycankles297
    @babycankles297 Před 4 lety +3

    I gotta start seeing these live, they are so well done and better then most actual math lectures

  • @cbrock21
    @cbrock21 Před 4 lety +4

    these lectures are just gems. thanks for what you do. and yeah-- not just high school students--- 39 year old physician with a part-time math interest here.

  • @jonathanclark5240
    @jonathanclark5240 Před 4 lety +1

    What a great class! Thank you for doing this! I love the positive energy and the love of learning that you bring to each video. =)

  • @72go5vq
    @72go5vq Před 2 lety

    this episode was a life-saver for me as i was stuck trying to understand the Quantum Fourier Transform (QFT) in my "Intro to quantum computation" course. It involved matrix-vector multiplication where the matrix's entries were n-th (complex) roots of unity & the vector's entries were complex numbers (i.e. qubits' superposition).
    Now i can finally go ahead & understand period finding & then after that: shor's algorithm!!
    Thank you Grant!!!!

  • @alexgan3219
    @alexgan3219 Před 4 lety +10

    Again, for the very last time
    Let's solve functional equation f(a+b)=f(a)f(b), which is valid for all reals.
    Let's plug b=0 into it. We get f(a)=f(a)f(0). We can put everything on the left handside and get f(a)-f(a)f(0)=f(a)(1-f(0))=0
    If the product is 0, then atleast one of the multiples is 0, so we need to consider 2 cases:
    1) f(a)=0 - well, this is the first solution of the equation. Due to it f(1)×f(-1)=0×0=0≠1
    2)1-f(0)=0 or f(0)=1. To answer the question, we don't really need to continue and find functions that satisfy this statement, cause we immediately get f(-1)f(1)=f(-1+1)=f(0)=1
    So
    20:00
    f(-1)=1/f(1) is true for all functions f(x)≠0. As there was no remark about that in the question, we need to agree that 3rd statement is NOT true for all such functions. Then answer E is wrong and C is true

    • @hexa3389
      @hexa3389 Před 4 lety

      Wouldn't b be true? I think the c was cases 1, and 3.

    • @alexgan3219
      @alexgan3219 Před 4 lety

      @@hexa3389 No, you missed "none of them".

    • @ster2600
      @ster2600 Před 4 lety +2

      @@duyaa9526 we have to assume the range of the function will be real as well, or the question is nonsensical

  • @mrpawcio3144
    @mrpawcio3144 Před 4 lety +52

    finally I understand WTF

  • @caspgin
    @caspgin Před 3 lety

    this lockdown math live series is awesome. The information, your presentation are all top notch. \you are a god send.

  • @dankazmarek1259
    @dankazmarek1259 Před 3 lety +2

    I was totally enthralled when I realized this is all about straightening out curves or patterns and get a convergence from them to define a coordinate.

  • @Noah-gy4wk
    @Noah-gy4wk Před 4 lety +50

    Why is it so weird to see this voice attached to a real living breathing person 😂

    • @SpartanFunnyProyect
      @SpartanFunnyProyect Před 4 lety +4

      It didn't match at all the first time I saw him in his Q&A, I always thought he was a muscular pi creature, but hey

    • @AkamiChannel
      @AkamiChannel Před 4 lety +11

      we all thought it was just the voice of math

  • @freddyt55555
    @freddyt55555 Před 4 lety +17

    2:51 - Your 8s look like 9s. How many points did you lose on high school math tests because of this?

    • @howardOKC
      @howardOKC Před 3 lety

      Haha, I had to go back and look. Yeah you are right!

  • @NotSexualAtAll
    @NotSexualAtAll Před 2 lety +1

    @38:00 the most useful visualization of this problem I've yet seen.

  • @OnamKingtheKing
    @OnamKingtheKing Před 4 lety

    I'm studying maths so I'm not actively following your videos because I'm too busy with lectures! But i wanted to thank you for your work, it's making more and more people interested in maths and I'm very happy to see it happen!

  • @stephenhousman6975
    @stephenhousman6975 Před 4 lety +14

    12:10 Mathologer video did a video on Euler's formula (e^(pi*i)+1=0) in Homer Simpson speak so the definition of e has to be used to make sense of it. Interesting take on the formula.
    I feel off you showing the Talor series of e^x and pulling out of nowhere.

    • @3blue1brown
      @3blue1brown  Před 4 lety +26

      That video is truly great.
      I hear you on the concern of pulling out the series "from nowhere". I suppose for many functions (e.g. sine) we start by seeing how they're defined, and slowly build up intuition from there. That's not a great answer, of course. As soon as you introduce a little calculus, one good motivation for this polynomial is that this is a function that is its own derivative, which you can see as soon as you learn the power rule, which in turn lets you describe lots of phenomena in nature where a rate of change depends on the value that's changing. The important point here is that we don't have to introduce it as a Taylor expansion (as it traditionally is), we could take it as the starting point from e and e^x pop out.

    • @xyz39808
      @xyz39808 Před 4 lety +2

      @@3blue1brown I first encounted e in this "function that is its own derivative" manner from my highschool calc1 class! I wasn't aware the tayler expansion that I learned in college calc2 was the traditional introduction of e.

  • @NoriMori1992
    @NoriMori1992 Před 4 lety +25

    2:33 Your 8s look like 9s! 😂

  • @jdmxxx38
    @jdmxxx38 Před 4 lety

    This video was very, very helpful to me. It lifted the veil of confusion from the meaning of e^x which plagued me forever. Thanks

  • @anvayjain4100
    @anvayjain4100 Před měsícem

    It's been more than 3 years but I guess it's never too late to appreciate art. Grant, Thank You for making me fall in love with mathematics gradually.