Parabolic trajectories are actually elliptical orbits

Sdílet
Vložit
  • čas přidán 24. 09. 2023
  • Deriving the parameters of the elliptical orbit of a projectile, and showing that this orbit is equivalent to the well-known parabolic trajectory in the short-range limit.
    About me: I studied Physics at the University of Cambridge, then stayed on to get a PhD in Astronomy. During my PhD, I also spent four years teaching Physics undergraduates at the university. Now, I'm working as a private tutor, teaching Physics & Maths up to A Level standard.
    My website: benyelverton.com/
    #physics #mathematics #dynamics #projectile #mechanics #orbit #kepler #angularmomentum #energy #visviva #ellipse #parabola #trajectory #keplerslaws #taylorseries #calculus #differentiation #trigonometry #chainrule #physicsproblems #maths #math #science #education

Komentáře • 14

  • @Nxck2440
    @Nxck2440 Před 9 měsíci +10

    This is really cool, I knew that orbits are elliptical but never made the connection that projectile motion is mathematically identical to an orbit (just one that happens to hit the planet again!)

    • @DrBenYelverton
      @DrBenYelverton  Před 9 měsíci +3

      I'd been thinking for a while that they must be equivalent, but hadn't worked through all the details until I made this video. It was satisfying when that familiar parabolic expression appeared!

  • @cinephilia_3099
    @cinephilia_3099 Před 5 měsíci

    Very nicely done..Thanks!

  • @pjmoran42
    @pjmoran42 Před 9 měsíci +2

    Crap. So all these years I've been aiming my bombs at the wrong point.

  • @mxminecraft9410
    @mxminecraft9410 Před 9 měsíci +2

    Can you please make a video on projectile motion on inclined plane.

  • @MissPiggyM976
    @MissPiggyM976 Před 9 měsíci +1

    Very interesting, thanks !

  • @mxminecraft9410
    @mxminecraft9410 Před 9 měsíci +2

    Also in this situation what will be the trajectory of particle with escape velocity . Will there be some special feature for that

    • @DrBenYelverton
      @DrBenYelverton  Před 9 měsíci +1

      Great question! The escape velocity is such that u² = 2GM/R; from the vis-viva equation (at 4:12) this gives 1/a = 0, in other words the semi-major axis becomes infinite. This makes physical sense because at the escape velocity the projectile is no longer gravitationally bound to the Earth. The orbit is no longer closed and in fact becomes a parabola.

  • @singhvijay124
    @singhvijay124 Před 9 měsíci

    volume coming is little low.