Maximum Consecutive Ones In An Array ( LeetCode

We have to write a program in java to count the maximum consecutive ones in an array. This is a Leetcode problem number 485.
So consider an array 0,1,1,0,0,1,1,1,0. The count of maximum consecutive ones will be 3.
For array 0,1,1,0. The count of consecutive ones will be 2.
For array 1,1,1,1,1. The count of consecutive ones will be 4 ie. the length of the array
For array 0,0. The count of consecutive ones will 0.
How do we solve this question?
The naive approach is simple. We can create a variable count to store the count of consecutive ones and another variable max count to store the maximum of all the counts.
We can run a loop to check the consecutive ones.
But this isn't the optimized approach.
Let's understand the optimized approach in this lecture.
Watch the complete lecture to know more.
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[@khusheeranjan7848]

sir your explanation for dsa is the best...there is something in your explanation which no one else can explain...

[@shaikshafiulla684]

SIR your explaination is just looking like woow
Sir,according to me NO OnE explains like you with animation
We cant forget logic even because you are using animation
we are watching like a movie, How can we forget sir
Superb sir

[@KRajesh-ej7dy]

Rohit sir u r my 1st fav on Utube

[@TAPACADEMY]

Thanks brother. Keep supporting Tap Academy

[@Sabh00]

Thank you so much Rohit sir
Waiting for maximum subarray

[@learn.-]

Sir we can also take 0 also

[@shitalshinde9387]

Sir program is not running,
Showing the error of "math.max"
What should I do sir , please reply sir

[@TAPACADEMY]

Please elaborate the problem

[@goutamraj8336]

Type maxcount= Math.max(count, maxcount);

[@MashoriMentors]

public static int countOnes(int num[]) {
int maxCount=0;
int count=0;
for(int i=0;i