Converging and Diverging Sequences Using Limits - Practice Problems
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- čas přidán 25. 03. 2018
- This calculus video tutorial provides a basic introduction into converging and diverging sequences using limits. It explains how to write out the first four terms of a sequence and how to determine if a sequence converges or diverges by finding the limit of a sequence. If the limit exists and it equals to some constant L as n approaches infinity, then the sequence converges. If the limit does not exist or increases or decreases without bound, that is, to positive or negative infinity - then the sequence diverges. This video contains plenty of examples and practice problems of determining if a sequence is convergent or divergent using Lhopital's rule, the squeeze theorem, and properties of logarithms. It contains example problems with trigonometric functions such as sine and cosine, natural logarithms, square root functions, factorials, and exponential functions.
Improper Integrals: • Improper Integrals - C...
Converging & Diverging Sequences:
• Converging and Divergi...
Monotonic & Bounded Sequences:
• Monotonic Sequences an...
Absolute Value Theorem - Sequences:
• Absolute Value Theorem...
Squeeze Theorem - Sequences:
• Squeeze Theorem For Se...
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Geometric Series & Sequences:
• Geometric Series and G...
Introduction to Series - Convergence:
• Convergence and Diverg...
Divergence Test For Series:
• Divergence Test For Se...
Harmonic Series:
• Harmonic Series
Telescoping Series:
• Telescoping Series
__________________________________
Integral Test For Divergence:
• Calculus 2 - Integral ...
Remainder Estimate - Integral Test:
• Remainder Estimate For...
P-Series:
• P-series
Direct Comparison Test:
• Direct Comparison Test...
Limit Comparison Test:
• Limit Comparison Test
___________________________________
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Professor Organic Chemistry Tutor, thank you for using multiple well-known examples to explain/analyze Converging and Diverging Sequences in Calculus Two. In all Calculus textbooks, there is a whole chapter on Sequences and Series. This is an error free video/lecture on CZcams TV with the Organic Chemistry Tutor.
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Yes it is cause the lim as n>infinity of ln(1+(1/n))/(1/n) is ln(1+0)/(0) which is undefined.
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why do u use l'hopital rule insted of just substitute infinity in the equation lim n-> infinity n * sin(1/n)???
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for anyone else scratching there head at this!
plugging in inf into (1+1/n)^n = (1+1/inf)^inf = (1+0)^inf = (1)^inf = 1^inf = undefined
this is why we had to solve it
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At 4:30 why do you multiply the top and bottom by 1/n? How do I recognize when to use this?