how to solve a factorial equation?
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- čas přidán 8. 09. 2024
- how to solve a factorial equation? This is a very interesting equation involving factorial. It may look hard, but it's actually not so bad.
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Maybe it will be "more interesting" to include 1! on the right hand side? (I don't know)
And why not use a pi function too?
1! = 1
Yeah
of course
Seeing no 11s, you know it is smaller than 11! (as 11 is prime). Seeing the 5! made me guess 10! because you need to use that extra 5 somewhere.
n!=3!5!7!
hence n>7,
(1x2x3)(1x2x3x4x5)=720
use division method (used in hcf calculation) start from 8 until the remainder is 1
n=10
kinda brutal way to solve the question 😂
i did this one on a math contest. it was my favourite problem on that contest :D
This is really really cool
Its easy, just dont solve the max factorial, solve the minors and try to see if a factorial can match, like n!=7!×6×120
n!=7!×720
n!=7!×8×9×10, so n=10
Cool solution
thanks mate
Divide the “!”, duh; n=(3)(5)(7)=105
if you divide the factorial symbol, there should be 2 factorial symbol on the right side
@@nick46285 n=3*5!*7! Easy, put it into your humongous calculator
Good Math Problem
Neat!
Well, a much more difficult question anyway is... HOW DO YOU CREATE A FACTORIAL EQUATION WITH AN INTEGER SOLUTION IN THE FIRST PLACE!!!???
1/2 + x = 3/2
x = 1
1 is an integer
with the power of a calculator I immediately found n to equal 10
Mesmorzing tutorial, just simplicity
Good for our bord exams...
Some trickey but easy
Are there any additional solutions to the equation x! = 10! if x can be any complex number and not necessarily a positive integer?
I guess write down all the complex factors and see if you can come up with something interesting. Make 10! a Gaussian Integer and look up an algorithm for extracting the complex factors from that.
Factorial function works with integer numbers larger than or equal to zero.
N=10...!!!
Why does he always repeat himself at the beginning of every video???
maybe he wants to do a retake but forgets to clip it out