Finding current through Load resistor using Thevenin's theorem.

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  • čas přidán 3. 04. 2021

Komentáře • 11

  • @aldrinumali5675
    @aldrinumali5675 Před 6 měsíci +1

    sir what if there is a resistor right after the voltage source, 60V?

  • @rangarajan5866
    @rangarajan5866 Před 2 měsíci

    Sir why is 40 and 60 ohm resistors are in series when u calculate Vth but are in parallel when u calculate Rth

    • @VBDclasses
      @VBDclasses  Před 2 měsíci

      While calculating VTh, same current flows in 40 and 60 so they are in series

  • @pruthvimelagiri3856
    @pruthvimelagiri3856 Před 5 měsíci

    I have one doubt finding in Rth how right side 60 and 40 are in parallel

    • @VBDclasses
      @VBDclasses  Před 5 měsíci

      If 60v is shorted, then 60 and 40 will be in parallel

    • @pruthvimelagiri3856
      @pruthvimelagiri3856 Před 4 měsíci

      Sir we are asking the about the opposite resistance at B 60,40

  • @sharathshirwal4841
    @sharathshirwal4841 Před 2 lety

    Sir one mistake on VB 40*0.4=24

  • @sharathshirwal4841
    @sharathshirwal4841 Před 2 lety

    Sorrysir, When u are finding i1=60÷60+40,so for i2=40÷40+60 but u have written it i2=60÷60+40,but answer may come same as i1 u have mentioned it as 0.4 sir......

    • @VBDclasses
      @VBDclasses  Před 2 lety +2

      It is not like that. We know I=V/R. So V is 60 and total resistance is 100 . Therefore i2 is 0.6