Reverse Integer | LeetCode problem 7

Reverse Integer
Leetcode problem number 5
Solution in JAVA
JAVA interview programming playlist:
• Interview Programming ...
Linkedin: / amrita-bala-a2b79460
#java #interviewquestions #leetcode

[@gautamhelange2769]

Wow! You handled overflow condition greatly, Thank You!

[@faizuddin4032]

Great explanation, but it would be great if you use dark theme on leetcode

[@soullover8484]

Good explanation amrutha

[@ayomiposolaja2016]

Great explanation. Thank you.

[@dboss616]

Great explanation thank you😄👍

[@abhijitbiradar]

great explanation !!!

[@ssdnews2863]

very well explained ! tysm

[@niraj.suryavanshi_]

Great !!

[@Ganesh-mz1cd]

great Work !

[@sonammurarkar961]

Amazing explanation

[@ganeshjaggineni4097]

NICE SUPER EXCELLENT MOTIVATED

[@Sufferingitbastards369]

Amazing...keep up the good work. I like the way you break down the problem on white board but please slow it down a little bit when you code.

[@TechnosageLearning]

Sure

[@dushyant6229]

Really helpful

[@princeprasad973]

thankuu...😇

[@sujatamahata3128]

Thank you Di😊

[@kamleshlohani6149]

Amazing

[@mayanksinghal1400]

Hello.. Thankyou for this video.
Can you explain please why can't we use overflow condition like
if (rev*10 > Integer.MAX_VALUE || rev*10 < Integer.MIN_VALUE)

[@KRajesh-ej7dy]

Hello mam if rev>max or min we need to get output as 0 then y it is returning garbage value .Leet code is not accepting this code...

[@TechnosageLearning]

Hi .. It is giving 0 only when rev> max or min. .I have shown in the video ,when we don't consider that condition , it would give garbage value.. I think you missed the end part of video.. Please try the code from git repo.. Leetcode is accepting the code.. Thanks!

[@sanjaykumarpandey4325]

Why you are dividing by 10 to check overflow condition

[@prateekkumar299]

reversed * 10 > INT_MAX would mean performing the multiplication first which could already cause overflow

[@devendramishra5872]

ye gys kaha se aa gya ?
didi

[@TechnosageLearning]

gys?? Sorry..didn't get your question..Can you be more specific?

[@user-bl1gg1ff1q]

import java.util.*;
class Main {
public static void main (String [] args){
int nums=4567;
System.out.print(reverseInt(nums)) ;
}
public static int reverseInt(int n) {
int rev=0;
while(n>0){
int Lastdigit=n%10;
n=n/10;
rev=rev*10+Lastdigit;
}
return rev;
}
}