polarizability is simply the ability of a molecule to have it's electron density deformed, an asymmetric stretch would not deform the density it would only shift it in one direction, changing the dipole, but not changing the polarizability too much
Thank you for the video, I needed just one more little clue to finally get it :) Keep up the good work, you explain pretty well and you have a nice voice to listen to :D
It's because the polarizability from the stretch on one side of CCl4 is "canceled out" by the compression of the other C-Cl bond in the asymmetric stretch, so there is little change in polarizability overall in that particular vibrational mode.
Confused on the Raman part. So change in polarisability needed for raman (due to change in shape/electron cloud position), would this not suggest that the asymmetric stretch would be more raman active as the shape change is more significant, as the structure is no longer a symmetrically linear geometry? This video did help clear up alot for me though thanks! Any response would be appreciated as i have my exams on this in a few weeks! :)
Hello mam! I am btech mechanical engineering student and I am working on a project related to raman spectroscope I had some doubts regarding that can you please help me with them?
11 years later, this very niche video is still helping people. Thank you, this video is wonderful!
polarizability is simply the ability of a molecule to have it's electron density deformed, an asymmetric stretch would not deform the density it would only shift it in one direction, changing the dipole, but not changing the polarizability too much
Holy shit, I didnt get why sometimes it's IR active and sometimes it isnt but i get it now. You're great, lady, omg I owe you my life I love u.
Just answered a 33% of my Analytical Techniques question, quite clearly in 8 minutes, owe you one
best video to understand the basics of IR and RAMAN, thanks a lot
Thank you for the video, I needed just one more little clue to finally get it :)
Keep up the good work, you explain pretty well and you have a nice voice to listen to :D
It's because the polarizability from the stretch on one side of CCl4 is "canceled out" by the compression of the other C-Cl bond in the asymmetric stretch, so there is little change in polarizability overall in that particular vibrational mode.
4:44 Yes, and this (CO2) mode is registered clearly by Raman Spectroscopy. Why isn't that stated?
5:11 sample irradiated, inelastic, 'transfer between molecule and photon 3:35 Beer's Law, concentration proportional to absorbance
This is clear and excellent. Many thanks!
as a physics student this saved my life , thanks a lot.
Nice video very useful, thanks
Would laser spectroscopy be a better way to determine information of a sample?
Tell the difference between Raman and FT-IR sepecrometer
awesome presentation, clear voice, to the point bravo
Can you add whole playlist of spectroscopic methods?
why is there a modern warfare 2 hit sound when slides change lol
Someone can tell me Wy we can determineded Cu with absorcion spectrofotometry
Confused on the Raman part. So change in polarisability needed for raman (due to change in shape/electron cloud position), would this not suggest that the asymmetric stretch would be more raman active as the shape change is more significant, as the structure is no longer a symmetrically linear geometry? This video did help clear up alot for me though thanks! Any response would be appreciated as i have my exams on this in a few weeks! :)
Very useful and understanding
Very useful, thank you!
energetic00cookie
Nice video, excellent!
Hello mam! I am btech mechanical engineering student and I am working on a project related to raman spectroscope I had some doubts regarding that can you please help me with them?
holy. this a great video. thank you
Whao! thank u so much
great video thanks girl
talk too much, maybe give some drawings