Determine the horizontal and vertical components of reaction at the supports

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Determine the horizontal and vertical components
of reaction at the supports. Neglect the thickness of the
beam.

[@biscaynebuckets]

You're the best!

[@maxmahdy2]

very useful and clear

[@timothywayman1620]

You help me more than you may know :)

[@wirashahid1536]

Please do more of 3d rigid body equilibrium

[@ayusuryaningsih7680]

Thank you very much

[@inspecproinspectionsconsul901]

how did you come up with he 260? I can't seem to get that answer.

[@29nsa]

Yeah same goes to me. I dont know where he got 260 😅

[@omairkhan1999]

600+400(5) = 2600 , then By = 2600 / 10 = 260

[@tshepomashweu1730]

Please do the rest of the fundamental problems.

[@iqdzgaming2449]

It should be 600lb x 15 ft, correct for the moment by the 600lb at point A

[@jayyurong5311]

Im confused when the direction is positive or negative. please do provide explanation

[@brayanhernandez1548]

Since the body has to be in equilibrium, forces have to oppose others. In this case, the applied force determined the direction of Ax and Ay.

[@casseymaryparedes3791]

Why is 500lb multiplied by 4/5? What is the explanation to that?

[@dubamwansanyirenda6921]

What if there’s no 500lb diagonal force just 600 lb going downward

[@abdallahahmed2549]

Why does the x components doesn't create any moment

[@James-xt1ic]

You have to neglect the thickness of the beam, which means the perpendicular distance from your x-component of your force to the center will be 0.

[@aburvarajselvamselvam7571]

Since the support is hinged\pinned the moment about x is not restrained. Only x and y directions are restrained.

[@vinceianromo3876]

how to get 260?

[@user-vz4ju1mr4f]

كولشي مفهمت 😕😕

[@dalesteyn4526]

this quesion is wrong