Using Vieta's Formulas | Math Competitions

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  • čas pƙidĂĄn 19. 06. 2024
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Komentáƙe • 3

  • @SidneiMV
    @SidneiMV Pƙed měsĂ­cem +1

    incredibly simple
    xÂČ - 5x + k = 0
    4a - b = 10 => b = 4a - 10
    a + b = a + 4a - 10 = 5 => a = 3
    a = 3 => b = 2
    ab = k => *k = 6*

  • @phill3986
    @phill3986 Pƙed měsĂ­cem +1

    👍👍👍😊😊😊

  • @Skank_and_Gutterboy
    @Skank_and_Gutterboy Pƙed měsĂ­cem

    For method #1, if you switch x1 and x2, attempting to solve for k yields no solution. Why? Because after simplification, you wind up with:
    sqrt(25-4k) = -1. No k will satisfy that equation. If 25-4k is positive, the square root will yield a positive number. If 25-4k is negative, the square root will yield a complex number. If 25-4k = 0, 0 cannot equal -1. There is no k that makes that equation work out, so x1 and x2 cannot be switched and k=6 is your only k-value.