Piping 45 Degree Rolling Offset - How to Find 45 Degree Rolling Offset
Vložit
- čas přidán 22. 08. 2024
- Piping 45 Degree Rolling Offset - How to Find 45 Degree Rolling Offset.Piping,Welding,Non Destructive Examination-NDT
Common Piping Angles and their Solutions,Known and Unknown Angles and Angle Chart,Solving Rolling Offsets,mitered Pipe Cuts,Multipiece Mitered turns, "Y" Layout,90 deg. Saddle on (tees) Standard Weight Pipe,Pipe Circumference Divided into Equal Parts,90 deg.on (tees) extra Strong Pipe,90 deg. Eccentric Pipe Intersections, 45 deg. laterals,Concentric and Eccentric Supports on 90 deg. Long Radius Elbow,3 Types,Angle between Bolt Holes of Flanges, Pipe template layout,orange Peel head layout,Concentric Reducer Layout,Eccentric Reducer Layout,laying out Bolt Holes in Flanges,laying Out Ordinate Lines and lengths,Tank coil layout,Angle Iron Miter Cuts and Brackets,Special Offsets and Solutions,Slip or Spectacle Blind Data,Centers of Eccentric reducers and Eccentric Flanges,Centers of 15 deg.,221/2,30 & 60 deg. Butt Weld Elbows from 90 deg. Long Radius Elbows,Pipe Thread,Dimension of Weldolet on Pipe, Dimension of Socket Weld & Screwed Fittings, Dimension of Flanges Cast Steel Valves,Dimension of Flanges Cast Steel Fittings,Commercial Pipe Sizes & Welding Fittings,General Dimension of Welding Fittings,General Dimension of Forged Steel Flanges,Bolt,Gasket & Ring Joint Number Charts,Wrench Sizes,Drill Sizes for Pipe Taps,& Tap Drill Size Charts,Bolt Charts for Orifice Type Flange,Outside & Inside Diameter of Pipe& Flange Bores,Comparison Chart for Packing & gasket materials,Hand Signal for boom Operated Equipment,Hand Signal for Overhead & gantry Cranes,Useful Information,Pipe Expansion,Pipe Bends,Circle,Inches&Feet Converted to millimeters,Conversion Constant,Decimal Equivalents,Fractions& millimeters,Safe Loads,for Wire and Manila Rope Charts,Decimal of a Foot,minutes converted to Decimals of a Degree and trigonometric formulas,Pipe& Water Weight Per Line Foot &Feet head of Water to PSI,Wire bending,Symbols,Computation.Piping 45 Degree Rolling Offset - How to Find 45 Degree Rolling Offset
Good video thanks!!! but I think that run is the same as the set if you use 1.414
Sir, for rechecking of the results on your computation, divide your travel with 1.414 and if you have the correct run and A. I don't understand your calculation because for a 45 deg., wherever you roll or offset it, it will be the same as a normal vertical or horizontal run or travel. Try to analyze it... you just put it sideway, the run and travel should coincide. 20.52(run) x 1.414 = 29.015 and 26.8(TRAVEL) divided by 1.414=18.95. Either dimension you will use, the run or A, both should be equal. Even you will throw your pipe in the air and drop whatever it's position will be, the run and A should be the same, the roll dimension(coordinates of your line) and SET(elevation) may vary.... And being a 45 deg., your A and RUN should be equal, if not equal, then it is not on a 45 deg. anymore. Have you tried your theory in actual? Rolling or offsetting is only the position, the angle and the dimension should remain the same, Try rolling a simple 45 deg. right triangle (the one we use in drafting our drawing on paper, the plastic one, I'm sure you have one), place one side flat (one with 2 sides equal, not the travel) on the table and swing from side to side as you like, check if the before 2 equal sides differ after rolling. Only the coordinates and elevation changes or we call as ORIENTATION only changes. And where did you get your 1.08?
I’m lost, where did the 1.080 come from. Not saying I’m the best fitter with only 8.5 yrs experience but I like to watch free informative videos of my craft to not lost old info I barely or work on once or twice per 2years.
Simply check your math with Pythagorean Theorem and you'll see that your travel and run are conflicting. Please correct or take video down so you don't confuse people.
Really. This guy is terrible.
Your run and set should be the same if you are working off of a 45 degree angle.
I agree but I think it changes because of the roll so one's going to be greater correct
uh know. it doesn't change
rut and set is just equal only for the vertical triangle, but for the horizontal triangle, or for the roolling of the line, set and run the aswer shoud be the same or equal to the dimension of the vertical line
no no no 1.080 is where u went wrong mi amigo a and b have to be the same for a 45 degree angle
from mobile alabama Austal A class pipefitter
is it just 1.00 than? ( currently an apprentice in schooling)
@@-oscartrundle4829 Yes, for 45 degree angle the formula is Set X 1.00. Why by 1.00 because 1/tan 45 = 1
In my opinion to get 45° 📐 set and run must same length
WRONG, YOUR A AND RUN SHOULD BE THE SAME LENGTH SINCE ITS A 45° ROLLING OFFSET
Thank you sir
Thanks
I've done a lot of rolling offsets and the reason you can use 1.414 is because you intend to use a 45degree FITTING. The rise and run don't have to be the same.
How did you find 1.080?
this is wrong.if the run is 20.52 then it aint a 45° is a 40.03° fitting angle please correct
MrJj1620 the 45 is rolled
Sir good day ,,where did you get 1.080?
1.080?
please take this video down. Your calculations are wrong.
you cant connect the the bottom line to the upper line when your travel for the rolling offset line is not equal in the dimension of the height,
how can you calculate the " Travel" if there is no "RUN" ? based on 0:57, you cant use 1.414 , since its not same length .
this is very very wrong, when they draw an isometric drwg it is always required that the orientation is correct, second the detail dimension shown is incomplete, this what u said, the run is missing, i will explain to u, in 45 degre rolling offset set and run is always equal, now the height is 18, so the answer for the travel in the rolling offset triangle should be 18 to get that answer, set is 6, and run is 17.
thnk u
your welcome. more videos czcams.com/play/PLcAzKoCrAxLSlRMjDm3WinfWhmX0gAp6q.html
Is the run the same as a advance? Someone please help I have a test at the end of the month.
Can i use short method bro? √6squared+18squared=then press mixfraction its 18.9
where you get that 1.080
I keep on looking at the video and can't get the grasp of this equation..any other video out there that can be watched?
Centre elbow
25.4x1.5xtan(degree÷2)xsize pipe
Long radius=1.5
Short radius=1.0
5D=5
3D=3
4D=4
Pipe ODxpai÷360xdegree
Rolling offset
Nice! Thanks for sharing
you are both wrong, for the rolling offset, required degrew multiply by radius, of the pipe multiply by .0174
What is pai?
Sir, your video is incorrect in so many ways that I do not know where to begin.
In any right triangle with back to back 45 degree bends; both the set and the run MUST be the exact SAME length.
In the book: Tube Bending Simplified, on pages 44 and 45 trigonometry is explained in easy, crystal clear fashion for a right triangle with any degree bends at the 2 corners in any triangle which contains 1 each 90 degree corner.
where you have formula19x1080
im sorry but i dont quite understand how you got 1.080 can you please explain one more time
+alejandro garza A= multiply to 1.414 equals and also you must know the formula of How to find Angle if the 2 sides are given so to get 1.08 is Travel divided by Set = Cosecant.
The answer of that is 27.9 not.26.8
Please how did u get the 1.080 for run
Followed up until 1.080,some say it's wrong, some say it's correct, who is correct?
Where did you get 1.08?
I never hear 1,o80,pls explain
Thank you very much. Great video.:-)
welcome
May itatanong lang ako. Paano po ninyo nakuha yung 1.080?
I do not understand from where these numbers , you should subtitle them in Spanish , I checked with the results of the operation and do not match, there is no need to know English to realize that something does not fit the operation
1.080? Wer did you get that?
thanks for your video now i understand sir what about 90degree
Your Welcome
@@Mrjoelaguirre where did you get the 1.080?
It's not 1.080 ...it's 1.000..and your working off a 45 degree angle which means it doesn't matter what offset or roll you do the travel distance will be the same....I don't understand your calculations at all
No sir. i think it's the way he drew his rectangle, he made it a square so the angle looks like a 45°. But to find travel for a 45° you can multiply either rise or run with 1.414, they're the same length at 45°.
Saan Ng galing ang 1.080 sr
Sir I think ur run is wrong u using 1.414 meaning both 45 degree meaning set and run are same
please correct it. what your idea share it
Boss saan galing Yung 1.082
Creo que el run es 19
sir mali ka nmn, dapag ang trabel mo is 25 lng, ang run mo ay 17 lng, dapat ang magiging travel mo sa horizontal triangle mo, ay kaparehas ng elevation, dahil 45 degree sya, dapat laging equal ang set at run nya para magpanama, po.at ndi ganyan gumagawa ng iso dapat, may tamang orientation sya, kaya sya nilalagyan ng box para makita kung san sya nag roll po..
May tanong lang ako boss....parang may mali....diba pag gumamit tayo ng 45°elbow formula is...A=B ...dapat 19 yong seat mo....19 din ang run...bakit iba sayo....
uu kaya nga e.. :D mali ang nagtuturo
please correct it. what your idea share it
1.080 is incorrect it's
music in the beginning?
All
Pls explain about 1,080 where u got is.i has subriber your u tube.slaamat poo
Bakit mo e multiply sa 1.414 di naman pareho ang A at run?45 deg.yan bro
Kabayan San galing yong 1.080
I got 26.866 for the run..
Why the heck would you even BIM this job at 45 degree. You know 30 is a easy multiplier right (2)? Also why the heck would you even put that bend in a tight spot? Throw it in a can or a bust ducts. This foo never been on the field
Saan mo minagic ang 1.080?
please correct it. what your idea share it
Wrong r😎{run) 18,9
How did you get 1.414
Cosecant 45 degrees
What the hell!?! This is all kinds of wrong. If A=19 and Run=20.52 the angle is 42° not 45°! And where the hell did 1.080 come from? If this is a 45°, A and Run would be the same length!
Hello sir'tanung lng po San po nakuha ung 1.080.salamat po
sir mali po yan lahat unang una dapat pag gagawa ka ng iso drawung tama ang orientation nya, tapos may horizontal triangle shadow sya para sa rolling offset at vertical shadow para sa upper and bottom line connection, para madali po maintindihan ang 45 degree rolling offset ay lageng equal and set t at run, multiply lng nyo yong isa sa kanila 1.414, dahil pag ndi sila nag equal ndi sila magpapanma, padala ndi give ng run, na sana duon makikita na yong normal takbo, dapat may dimension, ngayon pinakita lng na nag iba sya ng direction yon 6, yong run na ndi nya nilagyan ng dimesion, yon po ay 17 gamitin nyon phytagorian theorym yan ang answer nyan is 18, pero ang pinaka importante yong travel duon vertical triangle na ang answer ay 25.4
How did you get 1.080 ?
+RJ Rainey A= multiply to 1.414 equals and also you must know the formula of How to find Angle if the 2 sides are given so to get 1.08 is Travel divided by Set = Cosecant.
Thank you very much
+RJ Rainey Your welcome!
💋💋💋💋
how do get the 1.080?
+Dexter Carbonero A= multiply to 1.414 equals and also you must know the formula of How to find Angle if the 2 sides are given so to get 1.08 is Travel divided by Set = Cosecant.
PipingWeldingNon Destructive Examination-NDT thank you
your answer is incorrect
Wrong cumputation
It's 1.000 check your ipt pipe trades book
Apply Pythagorean Theorem to get RUN
yes that is easy way...information other methods to find lenght of side. czcams.com/users/edit?o=U&video_id=8pQ4P4wIgkI
you sir are no fitter, lol
your calculation wrong & no understand
wrong!
Stop trying hard!
your explanation is no good