Simplification of Forces and Moments | Mechanics Statics | Solved examples

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  • čas přidán 7. 08. 2024
  • Learn to find a resultant force and a single couple moment that is equivalent to all the other forces and moments. We go through a few examples step by step and talk about different methods to get to an answer.
    🔹Fundamentals of moments: • Moment of a Force | Me...
    🔹How to express forces in cartesian form and find position vectors: • Force Vectors Along a ...
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    Intro (00:00)
    Replace the loading system acting on the beam by an equivalent resultant force and couple moment at point O. (01:51)
    Replace the force system by an equivalent resultant force (03:38)
    Replace the loading on the frame by a single resultant force. (04:58)
    Find more at www.questionsolutions.com
    Book used: R. C. Hibbeler and K. B. Yap, Engineering Mechanics Statics.
    Hoboken: Pearson, 2017.

Komentáře • 73

  • @TokolloMalatji-yl8xr
    @TokolloMalatji-yl8xr Před 11 měsíci +6

    Kudos to your great work. I managed to understand 4weeks of lecturer content in less than 2hours.

    • @QuestionSolutions
      @QuestionSolutions  Před 11 měsíci +1

      Glad it helped! Keep up the great work and best wishes with your studies!

    • @GurbetciAri
      @GurbetciAri Před 8 měsíci

      man, this comment won't be about video but your clothes are cool :)

  • @shubhankar3111
    @shubhankar3111 Před 3 lety +12

    Thanks for all the efforts you are taking to make the videos. Great work . Keep it up ❤️

  • @balubhaskar1915
    @balubhaskar1915 Před 2 lety +6

    excellent channel for Btech students thank you sir

  • @afnansaeed6697
    @afnansaeed6697 Před 3 lety +3

    This video helped me, thanks

  • @wanpanman5492
    @wanpanman5492 Před 2 lety +1

    oh man that was pretty good thank you Godbless you so much bro

  • @muhammadsaadkhan9701
    @muhammadsaadkhan9701 Před 3 lety +6

    God Bless U . Thank U So Much . 🙏❤️

  • @cemileceylan1017
    @cemileceylan1017 Před 2 lety

    Thank you great!!!!!!!!!!!!

  • @quanghungnguyen6630
    @quanghungnguyen6630 Před 2 lety +2

    amazing

  • @jaylut5931
    @jaylut5931 Před 2 lety +2

    Hey there, in the first example, at 2:54, for the M1x, how does the x component force create a counterclockwise movement, and at 3:09, how does the y component create a clockwise movement?

    • @QuestionSolutions
      @QuestionSolutions  Před 2 lety +4

      If you think of the beam able to turn freely about point point O, and we apply force Fx, which way will it spin? It will spin counter-clockwise. If we now look at the y-component force and apply it, which way would the beam spin about point O? That would be clockwise. If you have a hard time seeing thing, cut out a piece of paper that looks like the beam, and then use a needle or a pin to pin it at point O. Then with your finger, apply the forces and see how it spins. Also, if you haven't seen this video, please take a look: czcams.com/video/QNNnPZ68STI/video.html I show how things spin in the first example.

    • @hxshgodz9102
      @hxshgodz9102 Před 9 měsíci

      ​@QuestionSolutions but doesn't the line of action intersect point O for the x component, so wouldn't the x component not create movement?

  • @darrylcarter3691
    @darrylcarter3691 Před rokem

    The part at 1:00 where you discussed that you can place the resultant force anyway on the pole or any rigid body; can it also work when solving a problem for a 3 Dimensional body as well?

    • @QuestionSolutions
      @QuestionSolutions  Před rokem +2

      It can be a bit harder to do since finding the exact point to replace all the forces in a 3 Dimensional body can be difficult. But yes, you can.

    • @darrylcarter3691
      @darrylcarter3691 Před rokem

      @@QuestionSolutions I think best method is to use the right hand rule at least.

    • @QuestionSolutions
      @QuestionSolutions  Před rokem +2

      @@darrylcarter3691 The right hand rule gives you the direction of the moment vector. 👍

  • @tristandescamps8419
    @tristandescamps8419 Před rokem

    Do you have a step by step solving guide for type of exercises? Would be handy, like moments and couples or just forces on axis. It is easier to approach questions? How do you do this, i struggle with starting but when i am going i keep going.

    • @QuestionSolutions
      @QuestionSolutions  Před rokem

      So everything is showed step by step but you have to watch the whole statics playlist from the beginning. Each video is about 10 mins long but covers everything step by step. It might be helpful to start with the video about moments or if you have the time, watch the whole playlist from the start. It will give you a really good foundation.

  • @user-bb6ys4rj5p
    @user-bb6ys4rj5p Před 9 měsíci

    During 2:50, should the Fx component be ignored since it's parallel to the line of action of the rotation about point O? It's parallel so how will the body move?

    • @QuestionSolutions
      @QuestionSolutions  Před 9 měsíci

      There is a 0.2m height difference as indicated on the diagram if you look carefully. This small height difference will create a moment. :)

  • @liamsebestyen4983
    @liamsebestyen4983 Před 5 měsíci

    Goat Teacher

  • @jesussaquin6266
    @jesussaquin6266 Před rokem

    Are moments different if we were to take them at different points?

    • @QuestionSolutions
      @QuestionSolutions  Před rokem

      In the most simplest sense, a moment is just force times perpendicular distance. So if the distance is shorter, you'd get a smaller moment and vice versa.

  • @fatimaphone1860
    @fatimaphone1860 Před 9 měsíci

    Cool!!! But i didn't get how you know the direction of moments (clockwise or anti

    • @QuestionSolutions
      @QuestionSolutions  Před 9 měsíci

      So you can pick the direction you want to be positive. Please see: czcams.com/users/shortsP029mqnp4XY

  • @nautahashimi6073
    @nautahashimi6073 Před 10 měsíci

    if i made clockwise positive and counterclockwise positive should my moment be different?

    • @koaw4792
      @koaw4792 Před 10 měsíci

      Should side set one negative, shouldn’t matter which side, just state the direction next to ur ans depending on the outcome

    • @QuestionSolutions
      @QuestionSolutions  Před 10 měsíci

      No, it makes no difference whatsoever. Please see: czcams.com/users/shortsP029mqnp4XY

  • @zwehtetnainai6618
    @zwehtetnainai6618 Před 5 měsíci

    In the last example, isn't the resultant moment supposed to be negative since it is turning clockwise? if it's negative, x is -2.16 which is way below.

    • @QuestionSolutions
      @QuestionSolutions  Před 5 měsíci

      If you use negative for clockwise, you will have to take the equation shown at 5:58 to be also negative (we chose clockwise to be positive). You can use either, you will end up with the same answer as long as you follow through the same direction you choose for positive.

  • @ugurakar9137
    @ugurakar9137 Před 8 měsíci

    at 4:48 m3's j component needs to be -450j or am I making a mistake

    • @QuestionSolutions
      @QuestionSolutions  Před 8 měsíci

      No, the value shown is correct. Please see: czcams.com/video/F8IHrg3pc7g/video.html
      If you want to verify your answers, use: onlinemschool.com/math/assistance/vector/multiply1/ and plug your two vectors in.

  • @k2___2
    @k2___2 Před 9 měsíci

    youre goated

    • @QuestionSolutions
      @QuestionSolutions  Před 9 měsíci

      Thank you very much!

    • @DirkdeZwijger
      @DirkdeZwijger Před 7 měsíci

      Genuinely if anyone asks me what statics/dynamics books they should go for, I'd recommend Hibbeler. Just because this channel's playlists are based on these books. Genuinely professional level videos

    • @QuestionSolutions
      @QuestionSolutions  Před 7 měsíci

      Thank you very much. Generally speaking, while there is a heavy emphasis on Hibbeler books, the concepts are the same for any other book used. The same methods are used for solving the same types of problems. I do think, however, Hibbeler books are easier to follow and understand. @@DirkdeZwijger

  • @davemichaelcalderon3454

    Is thus concept related to the topic of couple transfer?

    • @QuestionSolutions
      @QuestionSolutions  Před rokem

      I am not too sure, can you give me an example of what you mean by a couple transfer? Are you referring to mesh gears?

  • @eyobderese5021
    @eyobderese5021 Před rokem

    at 6:34, can we put the force out of the body?

    • @QuestionSolutions
      @QuestionSolutions  Před rokem

      Yes, there is no other location. This is a theoretical question so that's the answer they are looking for.

  • @michaelokaysin4239
    @michaelokaysin4239 Před 2 lety +2

    Make more videos on this course

    • @QuestionSolutions
      @QuestionSolutions  Před 2 lety +1

      So far, I believe everything required for a 1st year statics course was covered. I will revisit in the future to do upper level topics :)

    • @michaelokaysin4239
      @michaelokaysin4239 Před 2 lety +1

      thanks man you are life saver

    • @QuestionSolutions
      @QuestionSolutions  Před 2 lety +1

      @@michaelokaysin4239 😃

    • @arjunrai8126
      @arjunrai8126 Před 2 lety

      @@QuestionSolutions hey I love your videos , they are very helpful . But have you covered topics like friction and dynamics . Thank you

    • @QuestionSolutions
      @QuestionSolutions  Před 2 lety

      @@arjunrai8126 yes, dynamics was covered, there is a playlist labeled dynamics A-Z

  • @paugust
    @paugust Před 9 měsíci

    Would you call any of these "reduction to wrench" problems?

    • @QuestionSolutions
      @QuestionSolutions  Před 9 měsíci

      I haven't really heard that term used, but from the looks of it, yes.

  • @rosiedianne1599
    @rosiedianne1599 Před rokem +1

  • @godzilla3572
    @godzilla3572 Před rokem

    2:50 how the M1x make a moment it's direction wont make a spin

    • @QuestionSolutions
      @QuestionSolutions  Před rokem +1

      Notice that there is a perpendicular distance of 0.2m, so yes, it will cause a moment. If that was 0, then no, but since there is that gap, it will lead to a moment being created.

    • @godzilla3572
      @godzilla3572 Před rokem

      @@QuestionSolutions thanks

  • @tristandescamps8419
    @tristandescamps8419 Před rokem

    Wouldn't the 200 N still have influenced the moment by enforcing the starting position and making it harder to start moment? Now when you put 20 kgs on a pole and it doesnt matter you could say that putting 20 tons on the pole doesnt matter either and doesn't affect the moment force, when in reality obviously it would? so why is this not taken into consideration? Is this because it wouldnt fit in the equation and propably has its own formula/rules and therefore, maybe is because this would be way to difficult and advanced for first year? Or i am wrong

    • @QuestionSolutions
      @QuestionSolutions  Před rokem

      Please give a timestamp so I know where you're referring to, that way I can answer you better. Thanks!

    • @tristandescamps8419
      @tristandescamps8419 Před rokem

      @@QuestionSolutions 5:00

    • @QuestionSolutions
      @QuestionSolutions  Před rokem +1

      @@tristandescamps8419 Okay, so you're actually thinking of this as a moving object. There is no "hard to start moment" because the item is stationary. It is a constant force that's applied. What you're actually thinking of is dynamics, not statics. Statics only covers objects that are in equilibrium, in other words, objects that don't move. So the pole at 5:00 is not moving, the 200N force was applied indefinitely, and we are just looking at a snapshot of things to see what moments or forces are effecting it. If you want to understand how a force applied for a certain time, and how a variable force would effect things, etc, you have to look at dynamics. Dynamics is usually taught after statics, which is still a first year course at most universities. So first semester would be statics, and dynamics would be second semester. Another thing to understand is that in statics, the moments caused does NOT make the object move in anyway. A counter moment is instantly created to keep the object in equilibrium. Say you have a pole buried in the ground. When you push against it, it doesn't move because the instant you push, a counter force is created, keeping the object still. When it starts to move, at a certain force, then we switch to dynamics. So in simple terms, you are one class ahead in your thinking. For now, keep in mind that every object you see in your statics class is not moving, every force added together must equal 0 for the object to be in equilibrium.

    • @tristandescamps8419
      @tristandescamps8419 Před rokem

      @@QuestionSolutions So just permanent third law of newton basically

    • @tristandescamps8419
      @tristandescamps8419 Před rokem

      @@QuestionSolutions I am having strength of materials also its weird