Conservation of Energy: Free Fall, Springs, and Pendulums

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  • čas přidán 12. 03. 2017
  • The energy of a closed system is always conserved. This is an important law of physics! But energy does change forms. What are all the forms, how do they interchange, and how does this apply to things like free fall and pendulums? You gotta watch this clip to find out, buddy!
    Watch the whole Classical Physics playlist: bit.ly/ProfDavePhysics1
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Komentáře • 223

  • @nicolejaja270
    @nicolejaja270 Před 4 lety +293

    I have a hard time understanding physics when there's no too much theory, but your videos are the only ones who make me understand 100% everything in physics. I want to say that thanks to your videos I got the best score in physics of 100%

    • @pubgplayer1720
      @pubgplayer1720 Před 4 lety +3

      Yo this is literally primary school math drop out of high school if you don't understand any further...

    • @stop2759
      @stop2759 Před 4 lety +19

      Indian PUBG player Why so rude though?

    • @pubgplayer1720
      @pubgplayer1720 Před 4 lety +5

      @@stop2759 Sorry I was a bit rude; I was just trying to sound blunt to give this guy a reality check. If you can't understand the basic maths, then you're going to have trouble with all physics in later years.

    • @ohdeardeer804
      @ohdeardeer804 Před 3 lety +22

      @@pubgplayer1720 sometimes it's the teacher, the way it's explained, or it just isn't their passion. give it time and they'll be alright.

    • @josesolis642
      @josesolis642 Před 3 lety +11

      @@pubgplayer1720 physics needs to be explained with theory not just the use of equations, as that will help students broaden or lighten the topic they're dealing with.

  • @philipestrin4381
    @philipestrin4381 Před 2 lety +16

    For the past five decades, having flunked out of premed (remember, this was the '60s) I have still yearned to truly understand physics, chemistry, et al., simply for the sheer pleasure of understanding how the Universe works, what it is made of and its history. I've tried periodically many times over the years to initiate this understanding, since I have a large quantity of science textbooks I've purchased over the years (some applying calculus and some not). I start out full of resolve and optimism, I solve some of the problems. But soon enough I'm not able to solve them anymore and my energy (I'm using the term strictly in its colloquial metaphoric sense-- I understand its definition in physics) flags and I give up. I was always left with a feeling of frustration, because the yearning remained, despite the futility. Then, I discovered your tutorials and now I'm finally grokking (again with the '60s) these concepts and solving the problems. .And, at 75 years old, just in time. Grazia tanto, Signor Professore!

  • @kf5332
    @kf5332 Před 3 lety +26

    I love how simple and easy you make these concepts seem, my tutors over complicate EVERYTHING and their lectures leave me more confused than before I started! A class mate recommended your videos over the lectures and I'm so glad they did because I'm now understanding things in 5 minutes that before would of taken me weeks of sifting through my tutors overcomplicated jargon to reach the same understanding. I wish all professors were as clear cut and concise as you, keep up the good work educating the masses, love your content!

  • @pantheon.gamers
    @pantheon.gamers Před 4 měsíci +2

    I wish all classes and lectures were just like this. Straight to the point and effecient

  • @matiassolomon7198
    @matiassolomon7198 Před 2 lety +8

    i can't express how satisfying it is to try to solve the problem at the end of the video and then get it right first try.
    thanks prof dave!

  • @CODMReaper
    @CODMReaper Před 4 lety +9

    Thank you so much, I have been trying to figure this out for 2 days. The teachers lecture is very unhelpful in using the formula even though he took 2-3 hours to explain it, the textbook literally has only solutions for F=kx which made it impossible to even use the textbook. I can't believe how hard it was to even find a proper explanation on google, finding your videos is a godsend. I can finally answer the 4 questions the teacher has posted. I really really like physics and the idea but good explanations are so far and few.

  • @Finley2011PS3
    @Finley2011PS3 Před 2 lety +19

    So grateful that these videos exist! Unfortunately, professors can have a great understanding of physics but little ability to pass that understanding on. You, however, do have that ability!

    • @philipestrin4381
      @philipestrin4381 Před 2 lety

      And, of course, you amply have the great understanding, inasmuch as you know a lot about the science stuff.

  • @ghwoulspitt
    @ghwoulspitt Před 4 lety +52

    The intro felt like a fever dream ;-;

  • @kelvinthehuman
    @kelvinthehuman Před 2 lety +2

    Excelente, excelente, excelente, profesor Dave. ¡Saludos desde la República Dominicana!

  • @rashmikanojiya2578
    @rashmikanojiya2578 Před 2 lety +6

    sir ur physics videos are absolutely clear with the concepts ..thus help students to understand them easily

  • @playbuzz6301
    @playbuzz6301 Před 3 lety +1

    Thank you i really gained alot of value from this

  • @ygreaterr
    @ygreaterr Před 4 lety +24

    4:25 my heart is beating. im waiting for this moment! "did I calculate right?", "am i a loser?"! this is the most interesting moment

    • @Matt-sc6gg
      @Matt-sc6gg Před 3 lety +1

      omg, I have the exact same feeling when I get the results of a physics test! Dang!

    • @ygreaterr
      @ygreaterr Před 3 lety +1

      @@Matt-sc6gg same

  • @mrCetus
    @mrCetus Před 2 lety +1

    Very helpful! Tysm for making this video :)

  • @anirudhsarang2480
    @anirudhsarang2480 Před 4 lety

    Very nice explanation.thank you

  • @malebaruzani3650
    @malebaruzani3650 Před rokem

    Your videos has helped me to understand physics

  • @jonathansanchez8802
    @jonathansanchez8802 Před 4 lety

    Thanks for the videos!

  • @sharonsolana
    @sharonsolana Před 2 lety

    Thank you for the video!

  • @sashawarner
    @sashawarner Před 7 měsíci

    thank u professor Dave I rlly needed this

  • @avegarohanjaiswal
    @avegarohanjaiswal Před 7 lety +31

    hey its me again
    love your simplicity !!

  • @jenniferbello-ld3rp
    @jenniferbello-ld3rp Před 6 měsíci

    How can you find the maximum height of an object? I'm learning this unit in class and it was really confusing but your video explained it really well.

  • @brennanreedy3367
    @brennanreedy3367 Před 5 lety

    great video! thanks!

  • @destinityjae07
    @destinityjae07 Před 5 lety +2

    Helpful & to the point..thank you!!

  • @bluey_fan968
    @bluey_fan968 Před 3 lety +35

    Dang who else teacher told us to watch this video to compete the assignment

    • @05bahaafarah11
      @05bahaafarah11 Před 9 měsíci

      You in college?

    • @bluey_fan968
      @bluey_fan968 Před 9 měsíci +2

      @@05bahaafarah11 Nope I was in 9th grade when I made this comment I’m a senior now

    • @mustafafn5263
      @mustafafn5263 Před 8 měsíci

      Hahahah yep

  • @tenzintsepak3325
    @tenzintsepak3325 Před 2 lety +6

    The only non indian guy I can search up when I am in despair.

  • @lesliesamonte2213
    @lesliesamonte2213 Před 6 lety +17

    thanks Prof. Dave! This helped sooo much!!! All the love from the Philippines! :)))))))

  • @rajyasreeroychowdhury
    @rajyasreeroychowdhury Před 4 lety +1

    Good teaching sir 👍💞

  • @kurdos.1719
    @kurdos.1719 Před 3 lety

    The most useful video ever😍

  • @natashad8551
    @natashad8551 Před 3 lety

    eljko Milković, an academic and inventor from Novi Sad, has done something great that has not been done by any Serbian inventor before.
    Milković invention of the mechanical oscillator is widely used worldwide, a testament to the fact that over 500 foreign companies use, sell and manufacture pendulum-based machines used in the heavy industry.
    The purpose of the two-stage meganic oscillator is multifaceted, because the character of the machine (two-arm lever with pendulum) allows its use as a press, water pumps, compressor, crusher, power generator, mini power plants.

  • @rainsmush
    @rainsmush Před 2 lety +1

    love the intro! iconic

  • @h35nilu87
    @h35nilu87 Před 5 lety

    Sirr you explain this topic in very easy manner thank you......

  • @zarzesratize1654
    @zarzesratize1654 Před 3 lety

    Thanks professor Dave, very informative. Pongan listo!

  • @barankiani450
    @barankiani450 Před 5 lety

    what an absolute saint. u are the best teacher!

  • @hariprasadprajapat3424

    Please give a video about simple harmonic motion for pendulum with examples

  • @adityaa8918
    @adityaa8918 Před 4 lety

    Thank you professor

  • @mariamasawaneh2260
    @mariamasawaneh2260 Před 4 lety

    This Man is really good

  • @moric4677
    @moric4677 Před 3 lety +4

    you can also get the answer of the last question by using
    v^2 = v0^2 + 2as formula

  • @niranjanwagh5767
    @niranjanwagh5767 Před 2 lety +1

    I always watch till the end just to listen the end music :)

  • @JihadJoe_FauziDiab
    @JihadJoe_FauziDiab Před 4 lety +2

    How did you get the initial velocity? Or the final velocity?

  • @rodelarana9759
    @rodelarana9759 Před 2 lety

    Thank you very much

  • @camofaluge7554
    @camofaluge7554 Před 2 lety

    how did you solve the problem in the checking comprehension?

  • @honeyb3603
    @honeyb3603 Před rokem

    what will be the mass of object at the start of swing, middle of swing and at the end of swing during one cycle.

  • @niceguy4801
    @niceguy4801 Před 3 lety

    Thankyou Sir!

  • @georgekashachila1725
    @georgekashachila1725 Před 5 lety

    This is great

  • @squid2400
    @squid2400 Před 2 lety

    dude, thank you.

  • @parmidaoffice6618
    @parmidaoffice6618 Před 3 lety +1

    very good

  • @benj.amin0s
    @benj.amin0s Před 3 lety +2

    dude your intro song is meme lol it is pretty funny to and like your content of teaching others like a teacher but in a short way

  • @lizrueda4910
    @lizrueda4910 Před 4 lety +3

    thanks! this video is really helpful especially during this time of pandemic where im not attending school. honestly this is better explained than my teacher! Keep up the good videos!! :)

    • @Fishylocker
      @Fishylocker Před rokem

      lol dis is 2 years ago

    • @Fishylocker
      @Fishylocker Před rokem

      @★SW4GGYP3NGU1N★ -OMG TYSM FOR 50 nah 10th or 11th maybe

  • @thegrayside7250
    @thegrayside7250 Před rokem

    when can i use g or -g? does velocity a vector?

  • @modojijindabad
    @modojijindabad Před 2 lety +1

    Nice lecture sir... Love from India ....🇮🇳🇮🇳🇮🇳

  • @user-ni6id3zy3r
    @user-ni6id3zy3r Před 5 lety

    1000000 thanks for you explanation

  • @dr.dineshseth9518
    @dr.dineshseth9518 Před 6 lety

    Hey prof could you pls release the vid of conservation of linear momentum asap

  • @alaamahmoud7708
    @alaamahmoud7708 Před 5 lety +1

    This video helps me a lot thank you!💙💙💙💙

  • @JohnJones-xx6tn
    @JohnJones-xx6tn Před 5 lety

    Hi, is there any formula for pendulum lever length periods for the free fall pendulum from 12 o`clock when potential energy on 12 clocks is zero?

    • @carultch
      @carultch Před 2 lety

      Free fall pendulum is an oxymoron. The bob is still supported by the constraint force in the rod and pivot.
      There is no closed form equation for high amplitude pendulums, where you can't approximate sin(theta) as theta. You can solve it with an infinite series if you need to model it, but you cannot get an exact equation in closed form for the period. It also no longer undergoes simple harmonic motion, when you can no longer take credit for the approximation.
      Hyperphysics has a large amplitude pendulum period calculator, that enables you to see this effect.

  • @tigonnikkoa.5730
    @tigonnikkoa.5730 Před 2 lety +4

    How you'd come up with the final velocity of 1,640?

  • @jakhammer4209
    @jakhammer4209 Před 3 lety

    If physics is the study of the natural physical world, mathematically observed, noted, studied, & expressed?
    What about the vibration behind the thermal energy output by our first, most important muscle, the brain, teacher?

  • @dhananjayyadavv
    @dhananjayyadavv Před 3 měsíci

    Pls explain mechanical energy is conserved for a system here only ball is there

  • @asthatiwari2648
    @asthatiwari2648 Před 4 lety +5

    Can u tell why does the speed (v) decreases on going upwards?

    • @ProfessorDaveExplains
      @ProfessorDaveExplains  Před 4 lety +14

      Because acceleration due to gravity is constant and points in the negative direction, acting on all projectiles and decreasing their vertical velocity all the time.

    • @saqlainmalik2392
      @saqlainmalik2392 Před 3 lety

      U are a good guy professor Dave luv u sir♥️♥️

  • @petermackinnon6546
    @petermackinnon6546 Před 3 lety

    what are the potential energies of a Blue Shell vs Red Shell vs Green Shell? If you're in 1st vs 2nd vs 3rd place?

  • @walitid8438
    @walitid8438 Před 2 lety

    good video

  • @GianlucaRoccaGian
    @GianlucaRoccaGian Před 4 lety

    bravo Dave. goo joob

  • @rakibsm3892
    @rakibsm3892 Před 5 lety

    Thanks

  • @merhawikahsay5022
    @merhawikahsay5022 Před 5 lety +1

    I love you, you are one of the best teachers 😍

  • @sergeyborodin9211
    @sergeyborodin9211 Před rokem

    hi! thanks for the video! a great one...one note though - we do not need to know the mass on the comprehension section to calculate the speed ta 20 meters as it is cancelled out for the equation

  • @cadenollom3224
    @cadenollom3224 Před 3 lety +1

    I’m confused on how you got velocity

  • @nasakbari9476
    @nasakbari9476 Před 2 lety

    thanks

  • @jamilandrew1821
    @jamilandrew1821 Před 5 lety +1

    In the comprehension test, the object falls toward the ground, isn't the g = (-9.8m/s^2)? Why it is positive?

    • @ProfessorDaveExplains
      @ProfessorDaveExplains  Před 5 lety +2

      good question, i think when it's g and not a, we just use the scalar value rather than the vector so we ignore direction. may want to double check but i think that's correct.

    • @jamilandrew1821
      @jamilandrew1821 Před 5 lety

      @@ProfessorDaveExplains Thanks for the respond :)

  • @tGoldenPhoenix
    @tGoldenPhoenix Před 2 lety

    Done.

  • @toinivelishavo695
    @toinivelishavo695 Před 4 lety +1

    Sir is both kinetic energy and potential energy are mechanical or thermal energy?

    • @carultch
      @carultch Před 2 lety

      They both are considered mechanical energy.
      Thermal energy ultimately is kinetic energy, except at the molecular level, instead of macroscopic.

  • @hasnaalmnsoori158
    @hasnaalmnsoori158 Před 4 lety

    Ty

  • @karlswanson95
    @karlswanson95 Před rokem

    Would this be the primary reason a magnetic motor can never provide more energy then is put into it?

  • @user-hv6ef9ie1g
    @user-hv6ef9ie1g Před 5 měsíci

    4:43 u can also do this with Vf^2 = Vi^2 = 2a(delta)x and get the same answer which proves these equations relates to one another :D

  • @lizicadumitru9683
    @lizicadumitru9683 Před 7 lety

    Is the conservation of the energy found in the way it is transformed? I'm trying to understand what you mean by conservation of energy...like it's saved? or more precisely not lost? because it goes from one form to another? Can the conservation be measured? Thank you for your videos, they're great ☺.

    • @ProfessorDaveExplains
      @ProfessorDaveExplains  Před 7 lety +1

      it means the total amount of energy remains constant for a closed system! the amount of energy can be measured, yes, we just have to account for all the different forms of energy. thanks for watching!

    • @carultch
      @carultch Před 2 lety

      Conservation of energy means you cannot create or destroy energy. It only changes form, and changes what object contains it. The sum total energy in an isolated system will equal a constant value. Isolated system means no mass or energy crosses the boundaries of the system.

  • @BB-bc1xv
    @BB-bc1xv Před 4 lety

    How is the energy of a closed system conserved if ,according to the 1st law of thermodynamics, says that adding heat can cause a change in internal energy? Even though the system has no mass transfer the internal energy can still change. Maybe I just don’t have the right idea

    • @ProfessorDaveExplains
      @ProfessorDaveExplains  Před 4 lety +2

      Energy can be transferred in or out of a system. That's not a violation of the 1st law. The energy has to come from somewhere or go somewhere. It's conserved.

    • @BB-bc1xv
      @BB-bc1xv Před 4 lety

      Professor Dave Explains I was not taking the surrounding into consideration. Thank you

  • @Meliodas-os4dl
    @Meliodas-os4dl Před 6 lety

    Pls àdd a vedio on time period of pendulum

  • @cauilfiower
    @cauilfiower Před 4 lety

    I am stuck on a problem, this is because there is no velocity given at ALL. How could you find the velocity without having the initial information (No time, or acceleration of the object falling was given)? I did try using the conservation of energy formula yet the answer came out to be no solution!

    • @StanbyMode
      @StanbyMode Před 3 lety

      I guess you have to assume that the initial velocity is 0

  • @arctic215
    @arctic215 Před 4 lety +4

    Professor, I had a question. If you would answer this, I will be very grateful.The question is:
    An object is in free fall when the force acting on it is exclusively gravitational. But why then the moon is in free fall? Isn't there centrifugal force acting on it?
    Thanks professor.
    Lots of love.

    • @adithyank3773
      @adithyank3773 Před 3 lety

      I guess the gravitational force is contributing to the required centrifugal force.Feel free to correct me if I am wrong. :)

    • @lynxica2133
      @lynxica2133 Před 3 lety +1

      @@adithyank3773 Centrifugal force does not exist.

    • @thomasshreve8268
      @thomasshreve8268 Před 2 lety

      Lynxica is correct. It would be centripetal force acting on the moon' gravitational pull.

    • @carultch
      @carultch Před 2 lety +1

      The moon is in free fall around the Earth. However, due to the fact that the moon has sufficient tangential speed, the moon is continuing to overshoot its target, which is why it doesn't crash in to the Earth. If the orbit were a perfect circle, the force of gravity would directly match the net force needed to cause centripetal acceleration. The force of gravity would be entirely perpendicular to the moon's velocity, which means there is zero work done by the force of gravity on the moon, and zero change in speed.
      The orbit is not a perfect circle, so to a lesser extent, the moon does speed up slightly and slow down slightly. The path of the orbit is elliptical, with the Earth-Moon center of mass (which is inside of Earth) at one of the focus points. You can look up the apogee (farthest distance from Earth) and perigee (closest distance from Earth) of the moon to see how far it varies from a perfect circle. There is the parameter called eccentricity that is also a measure of how non-circular an orbital shape is. The moon does speed up as it approaches perigee and slow down as it approaches apogee, so gravity does do a little bit of work on the moon during this path, but not enough to put it on a crash trajectory with Earth.

  • @Aimenxo
    @Aimenxo Před 3 lety

    if the object is falling, that means g is negative and h is negative . Right? so that's why you got positive answer (the negative cancelled themselves) .. instead of negative ????????
    I always get confused with g. sometimes it be positive and sometimes it be negative. Please help!

    • @carultch
      @carultch Před 2 lety

      The reason its sign changes, is that you assign a sign convention and coordinate system as you see fit to solve the problem. In any event, the gravitational field g acts downward, and your assignment of signs needs to account for this, as the downward direction fits your coordinate system. Sometimes it is more convenient to assign positive to the downward direction, other times it is more convenient to assign positive to the upward direction.

  • @anishtiwari1121
    @anishtiwari1121 Před 7 lety +6

    If a ball is on the ground,its potential energy is 0, but if I dig a circle around the ball so that the ball looks like as if it's on top of a tower, it suddenly has potential energy. PLEASE EXPLAIN HOW Prof.

    • @ProfessorDaveExplains
      @ProfessorDaveExplains  Před 7 lety +7

      ooh good one! i think it would still have zero potential energy, it would only have potential energy if it were rolled off the edge such that it could fall. that may or may not be right!

    • @maryamabdullah7012
      @maryamabdullah7012 Před 6 lety +1

      so if I am on top of a mountain and its highest point is at sea level. does that means I don't have PE until I get rolled off the mountain?

    • @shannonbriscoe2460
      @shannonbriscoe2460 Před 6 lety +4

      Gravitational potential energy is relative to whatever you choose to be your datum. If you calculate total mechanical energy based on that datum, it will be conserved in a closed system either way. You just can't change the datum at any point during your evaluation.

    • @mississippimusic
      @mississippimusic Před 4 lety +1

      Was the potential created by removing the circle of dirt?

    • @carultch
      @carultch Před 2 lety

      Good question. It is arbitrary where we define GPE to equal zero. A ball sitting on the ground doesn't necessarily have truly zero GPE, we just define it to have zero GPE by convention. It is mathematically impractical to calculate how much GPE it truly has.
      We define its initial GPE to equal zero. We then dig a hole 1 meter deep. We let the 1kg ball roll toward the hole. The ball falls to the bottom of the hole, and its GPE becomes -9.8 Joules. The ball lost 9.8 Joules of GPE that became thermal energy, when it falls and comes to rest.
      When using the universal law of gravitation, we set GPE = 0 at r=infinity, but this is just for mathematical convenience. When we do this, all GPE's end up becoming negative. It is a simple consequence of picking r=infinity as our datum for GPE for mathematical convenience. There is no such thing as absolute GPE, the way we calculate it in Physics.

  • @abhinav5077
    @abhinav5077 Před 7 lety

    what happens if a glass ball and a metallic ball of same mass are dropped from same height? which will reach first? this question was on my test under electro mag.induction. i know its a bit out of context here but can you help plz?

    • @ProfessorDaveExplains
      @ProfessorDaveExplains  Před 7 lety +1

      ooohhh you mean like will the metal ball have its rate of free fall affected by the magnetic field of the earth? very interesting question. i would be confident that any impact would be negligible and we could not detect any difference. however the more fundamental question of whether there would be any difference whatsoever, even if not measurable, is pretty interesting, and i'm not sure of the answer.

    • @abhinav5077
      @abhinav5077 Před 7 lety

      my guess is that in order to stop the current from inducing there would be a decrease in its speed, so that energy remains conserved. im not that sure though since current itself gets induced in accordance with energy conservation (lenz's law).

  • @hajimajinja4941
    @hajimajinja4941 Před 5 lety

    wgt a pendelum does not hit a person's face without flinching. when released at the same point at a given distance?

    • @hajimajinja4941
      @hajimajinja4941 Před 5 lety

      why?

    • @carultch
      @carultch Před 2 lety

      @@hajimajinja4941 Because energy is conserved. There is no energy added to the swinging pendulum, when it fell from the person's face, to the opposite end of the room, and back to the person's face. The pendulum can go no higher, than the point at which it started.
      Time would need to run backwards, for the air drag and friction to do positive work on the swinging pendulum, which would speed it up. As crazy as this sounds, it is perfectly OK with the first law of thermodynamics. It is the second law of thermodynamics, that makes forces like friction and air drag slow objects down instead of speed them up.

  • @dejanjovic1430
    @dejanjovic1430 Před 4 lety

    how did you get 1,640 for Vf^2 ? I cant recognize the way of solution. All in all thumbs up for easy understanding

  • @xqzyt
    @xqzyt Před 2 lety

    So, which is correct? GPE > KE + SE + HE, or GPE > KE > SE + HE ?

  • @khayarulalam3596
    @khayarulalam3596 Před rokem +3

    Thank you PHYSICS JESUS!

  • @RinaNewhouse
    @RinaNewhouse Před 5 lety +4

    Not sure how he got to v^2 = 1640. How did that work? I have a test on this sooooonnnn

    • @ProfessorDaveExplains
      @ProfessorDaveExplains  Před 5 lety +1

      all the arithmetic is there! don't forget to square that initial velocity.

    • @anirudhsubramanian7302
      @anirudhsubramanian7302 Před 4 lety

      @@ProfessorDaveExplains Could you please explain it briefly as a reply. I'm not able to understand how you got 1640. Would be appreciated.

    • @TheFacial83
      @TheFacial83 Před 4 lety

      Is it correlate with projectile motion. I use it and result is the same thanks

    • @user-mz7bh1eh9v
      @user-mz7bh1eh9v Před 4 lety

      @@lorihunter1429 Thanks for that tip, I actually struggled with this problem at first but your comment made me finally solve the equation right.

  • @tommypearl905
    @tommypearl905 Před 6 lety

    Legend.

  • @johannpaolog.operiano7684

    I have a question, how did you solve for its final velocity?

    • @fadihakim3112
      @fadihakim3112 Před 5 lety

      square root of 1,640 = 40.5

    • @modojijindabad
      @modojijindabad Před 2 lety

      Using v² = u² + 2gh formula you can solve= it.... Here I am explaining....
      v = ? , u = 40.5 m/s² , g = 9.8m/s²
      h = 20 m
      So, v² = (40.5)² + 2 × 9.8 × 20
      = 2032.25
      So, v = 45.08 m/s²
      So the final velocity is 45.08 m/s²

  • @shemelyazavrshemelikov5692

    Все понятно спасибо

  • @sirarnie9837
    @sirarnie9837 Před 5 lety

    How does energy conservation apply to a fulcrum?

    • @38Fanda
      @38Fanda Před 5 lety

      www.physicsforums.com/threads/law-of-the-lever-conservation-of-energy-or-angular-momentum.833317/

  • @Customlycool
    @Customlycool Před 5 lety +1

    Your theme song should be on the grammys.

  • @riel1674
    @riel1674 Před 3 lety +2

    3:46 who else decided to slap the table

  • @dazzle8351
    @dazzle8351 Před 3 lety

    I did not understand what 4:44, well the working out meant 😔😖

  • @AtypicalPaul
    @AtypicalPaul Před 5 lety

    If we are energy then once our bodies (matter) die, will our energy continue on? Since energy can not be destroyed then this kind of makes sense.
    This of course doesn't mean that energy of yours would have your consciousness nor memories.

    • @ProfessorDaveExplains
      @ProfessorDaveExplains  Před 5 lety

      Well as you say, we are energy in the sense that we are made of matter, and when we die, that matter persists. Our bodies decompose and the atoms go on to be part of other things, like the ground, and a tree, and the air, and so forth.

    • @ProfessorDaveExplains
      @ProfessorDaveExplains  Před 5 lety +1

      ​@@dixztube Sure, I suppose that's one way of putting it.

  • @johnpelsang9341
    @johnpelsang9341 Před 6 lety +1

    Huh, I thought it was 9.8 meters per second. Or is that terminal velocity?

    • @ProfessorDaveExplains
      @ProfessorDaveExplains  Před 6 lety +8

      9.8 meters per second per second is the acceleration due to gravity on earth

  • @sophiaalexis4229
    @sophiaalexis4229 Před 4 lety +1

    he is the only reason im halfway passing school 💀

  • @kevinsalaudeen2024
    @kevinsalaudeen2024 Před rokem

    The goat

  • @qaisarshehzad8360
    @qaisarshehzad8360 Před 4 lety

    Nice

  • @juancarlossanchez7256
    @juancarlossanchez7256 Před 4 lety

    Te rifaste gracias

  • @aashishgottumukkale3043

    2:32 What about air resistance?

  • @suzan3510
    @suzan3510 Před 4 lety +1

    Tysm 😭😭♥️♥️
    Love from India ❤️

  • @getmeoutofsanfrancisco9917

    Dave Grohl’s Cousin over here.