All of SHM & CIRCULAR MOTION in 10 minutes - A-level Physics Revision Mindmap
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- čas přidán 6. 08. 2024
- Download the pdf: scienceshorts.net/resources
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00:00 Circular motion
00:48 Angular velocity
01:34 Vertical loop & pendulum tension
02:26 Banked track & plane
03:48 SHM basics
06:50 Damping
08:09 Resonance
09:20 SHM energy changes
09:34 Pendulum & spring equations -
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Looking at this 2 hours before my 2022 A Level Physics Paper 1 exam. God I love youtube lol
Glad i’m not the only one lol
@@dustyyutes6972 u did AQA right how did u find it
Good grade?
@@aidankhan6194 A* :)
@@eron8044Woahhh!!!!!
You saved me! Love this video and summary of everything! Thanks man, I really appreciat it.
Wow! Your videos reeeeeeeeeeally helpful! I love you😍
here 2 hrs before my mock for last minute reviewing
It wouldn't be "last minute" if you were here "2 hrs before" :)
@@infinitespace1982 shush
Really helpful videos, thank you.
thanks this was a good overview
saving my physics grade
same
I hav a CIE in 2 hours IM SO THANKFUL FOR UR VIDS
i think for SHM its better to prove the equations with calculus for a thorough understanding so people know it from two points of view; the mathematical point of view and the physics point of view. I find it better since its harder to forget when it can be applied to two subjects
Sigh - good for you mate.
@@ScienceShorts bruh wtf did he do wrong? He's got a point.
tbh its in the formula book
@@saferehman8234 yeah but it's good practice to know where those formulas came from. And the exact formula changes depending on the starting position of the object (e.g. if the object starts from the equilibrium or the maximum), so being able to derive them is helpful.
@@jacobb7379 yeah it is helpful
Shouldn't the equation for Tension of a pendulum at the bottom be T=mv^2/r - mg ? Because mg acts downwards and the centripetal force acts upwards towards the pivot?
So you're saying a heavier weight means lower tension?!
@@ScienceShorts Ah I see. The Centripetal force should be the resultant force. So, mv^2/r= T - mg and by rearranging we get T=mv^2/r + mg
No. The mg in the equation refers to the tension needed to counteract the weight pulling down, creating the tension.
is the (cos) under the eqation for displacemnt in SHM for when it starts at the maximum?
Yep!
@@ScienceShorts Thank you
Is angular velocity constant in shm?
In theory yes, in practice not quite that simple due to approximations e.g. pendulum. But we have to assume it's constant, otherwise we can't do much.
@@ScienceShorts Ok thanks for the help!
Got a test on both of these topics at 10am today (it's 7.16am now) and done absolutely no revision.... I'll come back when I get my results.
any luck? i have a test in an hour
@@olliebhag yes I got an A by one mark haha the questions were mostly shm on my test
It’s funny how the course avoids calculus lmao, this makes a lot more sense with background knowledge on differential equations
Test is in 10 minutes wish me luck boys
noice
Anyone else doing last min rev w this
Did you delete your SHM video?
Reuploaded, forgot to fix link, sorry!
@@ScienceShorts Thanks man!
I thought there was 4 types of damping which were: Over damping, light damping, heavy damping and critical damping
It's a spectrum, so it depends what your board goes with.
who else noticed he uses "is'nt it" quite much
bro got me listening on 0.75x becase he knows too much
literally me before watching video :: oh god , this is soo hard I can't do this !☹☹
me after watching this video ::: so that's it??? okayy less goo😎😎😍😍
any sri lankans?