in this video I explain step by step procedure how to derive Relation Between Modulus of Elasticity and Modulus of Rigidity and Poisson's ratio.........
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can you please explain how teta on the one hand is equal to shear stress over 2 times of shear modules while the main low of shear modules implies that teta is equal to shear stress over shear modules.. this is contradict-able!
It is stated that' Shear stress tau causes tensile stress on BD and compressive stress on AC', a statement I agree with. These two linear stresses along BD and AC are, according to the notation established near the beginning of the lecture, each of magnitude sigma ( +sigma along BD and - sigma along AC) . However, at about 10:10 sigma is suddenly equated to the shear stress tau without explanation other than that the linear stress sigma is caused by the applied shear stress tau. Just because tensile stress sigma is caused by the applied shear stress tau does not mean sigma and tau are necessarily equal. I have noticed the same assumption slipped in during various other purported derivations on U tube of the relationship between Young's modulus, the shear modulus and Poisson's ratio. Actually, I reckon sigma and tau are equal but it was not demonstrated why they are. Sorry to be critical. I accept that the linear strain along BD and its relation to shear strain phi was shown in a very clear way.
Sir Incase of relationship between modulus of elasticity and bulk modulus we take compressive strain as negative, but here we took compressive strain as positive. Why we are taking there positive and here negative?
Because here we are finding lateral strain in diagonal BD due to linear compressive strain in diagonal AC and according to Poisson ratio lateral strain is always opposite in nature to linear strain so because diagonal AC has compressive strain it will induce tensile strain in diagonal BD.
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Please Donate some amount (Rs 10 to 500) to teach free on youtube.......
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Ok sir
Sir this is very helpful video 🙏
The way of explanation is nice 👌
thank you sir for your detailed explanation. 🙏
your videos are very good and have a wide message thank you
Great explanation 🙂
Thank you so much
A very helpful video sir
Very good, thank you
🤞🤞🤞☺nice explanation thnku sir
Thank you so much!
Superb 😍
Thank you sir 😊
Thank You Sir
Amazing sir
Gicchi guru...
Thanks🙏
❤️❤️❤️❤️❤️❤️❤️
establish relationship between young modulus rigidity modulus and poisson ratio
Sir is this answer for poisson ratio also?
Please reply 🙏🏻
can you please explain how teta on the one hand is equal to shear stress over 2 times of shear modules while the main low of shear modules implies that teta is equal to shear stress over shear modules.. this is contradict-able!
Please help the relationship between modulus of elasticity, modulus of rigidity and passion's ratio.
Thank you so much in answer keep safe ♥️
It is stated that' Shear stress tau causes tensile stress on BD and compressive stress on AC', a statement I agree with. These two linear stresses along BD and AC are, according to the notation established near the beginning of the lecture, each of magnitude sigma ( +sigma along BD and - sigma along AC) . However, at about 10:10 sigma is suddenly equated to the shear stress tau without explanation other than that the linear stress sigma is caused by the applied shear stress tau. Just because tensile stress sigma is caused by the applied shear stress tau does not mean sigma and tau are necessarily equal.
I have noticed the same assumption slipped in during various other purported derivations on U tube of the relationship between Young's modulus, the shear modulus and Poisson's ratio. Actually, I reckon sigma and tau are equal but it was not demonstrated why they are. Sorry to be critical. I accept that the linear strain along BD and its relation to shear strain phi was shown in a very clear way.
would you please explain to me why is sigma assumed to be equal to tau here this point puzzled me too.
Mast
When you put lateral stain =1/m and linear strain to tau/E , it must get reciprocated and you didn't done that , how can we conclude it as correct
Thanks sir
why is linear strain equal to the total strain??? and why is thou representing tensile stress??????
Thanks sir ji
Sir Incase of relationship between modulus of elasticity and bulk modulus we take compressive strain as negative, but here we took compressive strain as positive. Why we are taking there positive and here negative?
Because here we are finding lateral strain in diagonal BD due to linear compressive strain in diagonal AC and according to Poisson ratio lateral strain is always opposite in nature to linear strain so because diagonal AC has compressive strain it will induce tensile strain in diagonal BD.
Link pls
Why is BD1- BD2 = D1D2. ???
what is m?
Tomarow will my exam