Introduction to Momentum, Force, Newton's Second Law, Conservation of Linear Momentum, Physics
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- čas přidán 2. 10. 2017
- This physics video tutorial provides a basic introduction into momentum. It explains how to calculate the average force exerted on object using Newton's 2nd Law of motion. In addition, it explains why the conservation of linear momentum occurs for every collision using newton's laws of motion and action reaction forces. Momentum is the product of mass and velocity. It's a vector quantity that contains both magnitude and direction. Force is defined as the rate of change of momentum per unit time. This video also contains an example problem that asks you to calculate the force exerted by a water hose given the speed of the fluid and the mass flow rate. This video provides all of the equations and formulas needed to solve all of the practice problems presented in this video.
Conservation of Momentum:
• Conservation of Moment...
Rocket Propulsion:
• Rocket Propulsion Phys...
What Really Is a Force?
• Physics - What Really ...
Inelastic Collisions:
• Inelastic Collision Ph...
Impulse Momentum Theorem:
• Impulse Momentum Theor...
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Force-Time Graphs:
• Force Time Graphs & Im...
Ballistic Pendulum Problem:
• Ballistic Pendulum Phy...
Elastic Collisions:
• Elastic Collisions In ...
2D Collision Problems:
• Conservation of Moment...
Impulse & Momentum Test Review:
• Impulse and Momentum C...
_____________________________
Center of Mass Problems:
• Center of Mass Physics...
Center of Mass - Calculus:
• Center of Mass & Centr...
Intro to Rotational Motion:
• Rotational Motion Phys...
Full-Length Videos and Worksheets:
/ collections
Physics PDF Worksheets:
www.video-tutor.net/physics-b...
Physics PDF Worksheets: www.video-tutor.net/physics-basic-introduction.html
Full-Length Videos & Exams: www.patreon.com/MathScienceTutor/collections
Impulse & Momentum Practice Test - 47 Problems: bit.ly/3Qj9FjO
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Hi everyone. I just want to ask a question. It's about the example no. 4 (about the hose expelling water at the velocity of 30 m/s). Is there such thing ∆m/∆t ? Mass is constant. If there's a change of mass, therefore ∆m/∆t will be zero. Right?
nah its amount of mass at any interval per second e.g. that hose could fire 15kg of water in 3 seconds, but when being turned off its mass dwindles to 2kg/s
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The the initial mass of a body is = m1
The mass of the body changes to m2 At time t (the change occurs suddenly, as if m1 - m2 Was dropped on m1 at t )
V2 = m1V1 / m2
According to conservation of Linear momentum m1V1 = m2V2
But according to conservation of kinetic energy ½ m1V^21=½ m2V^22
V2 = V1_/m2 / m2
But velocity cannot be different.. So is one of the principals not applicable in here?
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For question 4 I used p=m.v then with the answer I used f= rate of change of momentum/rate of change of time
It gave me the same answer but I'm not sure if I was supposed to use that
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8:59 Simply using F=ma is so much easier to understand 😭
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I can see many comments under this video said that they are university students. I wonder what grades you are in when you guys from all over the world learn this physics lesson. I am a senior high student, but we have to learn this.
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What about centrifugal force, density and thermal dynamics?
Or are orbits still elliptical?
Maybe the wind threw that apple thought.
The wind has never been convinced.
Too many witnesses.
How did you convert the Si unit on the 2nd question?
He divided 1.5g by 1000 to convert it from grams to kilograms
no joke, my favorite part of this video is when momentum revealed it's true identity as Newton's definition of force after being divided by time.
for #3 wasn't the formula change in momentum over time=mass times acceleration? but when you answered part a, you didn't put the change in momentum over time even though the time was given in the formula? was this a mistake or does the formula without time also work, I got a different answer.
Are u trying to teach your teacher .
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I think you need to check the fourth scenario (the unit)
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9:06 The total kinetic energy of the first ball is10x6x6/2 =180J
The second ball will have 5x12x12/2=360J
Now I know how to get free energy !
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1. A 0.145-kg baseball is pitched horizontally at 37.0m/s. After it is hit by the bat, it moves at the same speed, but in the opposite direction.
a. What was the change in momentum of the ball?
send help i literally just multiplied but i feel like there's some secret answer i dont get bec. of the opposite direction part.
Since the baseball is now moving in the opposite direction, the final momentum of the baseball is (0.145)(-37.0)= -5.365. Change in momentum is final momentum minus initial momentum. The initial momentum is just (0.145)(37.0)= 5.365. so the difference between final and initial momentum would be -10.730.
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Hello there... help me out. You start saying to imagine what is momentum and started calculating it but never said what it is. ?.. what it is? Sorry I'm a musician looking for an answer through physics
for problem on 10kg and 5kg, is there a way to get 120N for force on 5kg ball with information given or do we just make it opposite due to Newton's 3rd Law
You make it opposite, I believe
you just use the law
I’m in thermodynamics 2 right now and this helped a lot
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Why it has to be delta m in no4
Why problem4 we have deltaM/delta t?I mean whats delta t
3:01 why would you divide? I thought the equation was multiplying velocity and mass-
I'm so stupid its asking for velocity not magnetum or whatever
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wtf did you do with time at 8:57.....
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Isn’t the final velocity is 6?🤔