Calculus AB/BC - 1.12 Confirming Continuity Over an Interval

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[@sahibjamarai7400]

Why did you include 3 intervals on number 5

[@renztimog9308]

What if the function is √x³-1/x-1?

[@TheAlgebros]

That one definitely has discontinuity at x=1 because the denominator is not allowed to be x=1. If your question is whether or not it is a vertical asymptote, jump, or a hole, it might be easier to think of the limit as x -->1. If you check both the left side (an x value like 0.99999) and the right side (an x value like 1.00001), you would see that the answer is very close to the number 1. Therefore you have a hole at x=1.

[@stancix6080]

@@TheAlgebros is that mean that if the denominator is x-1 then its discontinuity?

[@darkrider7202]

@@stancix6080 late reply but yeah since 1-1 = 0 and 0 on the denominator is big indicator that the function has a discontinuity

[@TheLinposterIsSus]

If you from Mrs.K’s🎃 class u a real one