It isn't often that I subscribe to a channel after watching one video but that's what I did. I'm a retired math teacher and i feel like I had a similar teaching style to you, sir.
The biggest takeway I get from your videos is a new perspective of algebra. I never thought about using formula manipulation with a term to make it fit within a problem's boundaries. Hence how you took Sqrt(x)/x is = to Sqrt(x)/Sqrt(x^2) and applied it to the problem. It was very abstract from what I'm accustomed to.
awesome, i smiled when i understood what you meant when you say dividing a sqroot by x is same as dividing by sqroot of x^2. i realised it after thinking about some basic surd rools.
6:49.. getting rid of as much as you can... Hmmm that's all I wanted to know 😁😁.. thank you. And if you can please make a video of rules that are applicable every time when solving limits
good day sir ..if you please just try to explain more on the part where you explained saying dividing a square root term by x is like diving that square root term by the square root of x^2
From inspection, something does not look right. Sqr(64*x2+X) at infinite will be 8x+ infinite; take off 8x, and you have infinite. Having said that I cannot see your maths is wrong.
Wow. Always like how you get behind the intuition of the topic first before solving.
It isn't often that I subscribe to a channel after watching one video but that's what I did. I'm a retired math teacher and i feel like I had a similar teaching style to you, sir.
Lots of Love and Respect from India... The energy and charisma you bring to your teaching is phenomenal..Keep Making such content..😀😀
Thank you for your kind words.
The process of finding the limit in this example is so interesting. It makes infinity more comes alive. Thank you
the way you solve problems makes it seem way easier to understand than the methods i have been taught. Thank you for the amazing teaching.
Well explained.. I couldn't find a better explaination than this.
You are a great teacher; you explain things very well. Thanks!
God bless u man! Ur such a good person it makes me wanna cry....
I love your teaching. I don,t have more words:)
Thank You a lot! I would like to meet teachers like you on my learning path... Keep it up!
I love this guy.....Thank you very much💚
You are amazing! Your way of teaching is very impressive I found your channel and from now on I am stuck on it all the time
What an amazing teacher!!!
Thank you! U just answered all my questions ❤️❤️❤️
My brother prime knows his shit keep up the good work my hero ur an inspiration to many of us
Thanks for the video! it really helped me to grasp this stuff
I love your mode of teaching sir.
My perfect math teacher
You're the best
Im still alive and still wanna learn more!
Appreciated. Thank you sir!
You made it look so simple thank you Boss 🙌🙌
Dear sir you are the best.
Simply Great!!!
Very good. Thanks!
You make everything easy kkk. love this
Thank you I was struggling with infinite limits
very well explained. very helpful
Simply great teacher , keep on please
Thanks so much. I'm in year 10 but still managed to understand this . Very good explanations.
I am glad I could help. Thanks for the comment too.
❤ cleared my thoughts 💭🎉🎉🎉tnx sir 😊😊
You are amazing like seriously thank you so much
This video is really helpful🔥
The biggest takeway I get from your videos is a new perspective of algebra. I never thought about using formula manipulation with a term to make it fit within a problem's boundaries. Hence how you took Sqrt(x)/x is = to Sqrt(x)/Sqrt(x^2) and applied it to the problem. It was very abstract from what I'm accustomed to.
That's a significant observation. I never thought that's what I was doing. I was just looking for a solution. Thank you.
@@PrimeNewtons I love you you made me ace my calc exam !
I'll
You are just too perfect sir any time when i find a challeng i will be running to you🏃♂️.sir you are a solution giver i love you explaination
awesome, i smiled when i understood what you meant when you say dividing a sqroot by x is same as dividing by sqroot of x^2. i realised it after thinking about some basic surd rools.
You have a smart mind ☺️
Love this 😍😍😍😍
Thank you so much!!!
It is how you make this easy for me❤😢, you just saved me days and days of headache...thank you Sir.❤❤ and I promise i won't stop learning ❤
YOU HELPED A LOT..
Thanks very much l have been trying limit for infinity
You really helping sir
Thank u 🙏🙏🙏🙏🙏
Thank you genius
wow! you make algebra become more livelyy niceeeee🤯
Finally... this makes sense
Thank you!
You're welcome!
Thanks, i was struggling with Limits during my uni 😂
متابع ايءما طريقة ممتازة
Thanks soo much
Very good in solving
متابع يشكرك من المغرب
GOATED!!!!!!!!!!!!!!
Where is that heart-shaped button "Love it"!!!? Thank you! Fantastic explanation!
best video I've seen for this concept
+1 subscriber
Well explained
Loves from Bangladesh❤❤❤
This helped me understand!
I'm glad you found it helpful.
thank you sir😁
you the best thanks for such a good content
Glad you enjoy it!
You're the best
That's nice
amazing video
Thanks!
6:49.. getting rid of as much as you can... Hmmm that's all I wanted to know 😁😁.. thank you. And if you can please make a video of rules that are applicable every time when solving limits
I didn't even need to know how to solve the problem in this video but you teach very well so I decided to watch anyways
Thanks Sir
lakas!!
best
good day sir ..if you please just try to explain more on the part where you explained saying dividing a square root term by x is like diving that square root term by the square root of x^2
🎉 making limit easy 😅
you look handsome young man = D
I find it interesting that in this case, subtracting one infinity from another infinity results in one sixteenth. 😅
From kenya❤I think know I can become professor😂
Please can u do the next one on the table of variation
I don't even know what that means. Updated. I googled it. Please email me a problem
What about the negative value if yo sqrt(64) in minute 9:44?
I think the answer is infinity. The square root of 64 is + or - 8. Taking -8 gives 1/0 = infinity. y= sq root 64. y^2 =64. (y-8)(y+8)=0.
Why you not substitute the infinity in the solution
Can you solve a limit on the cube root??
oral question pretty easy
Sir plz help me this question
Find the Limit of Lim tan7x/14x as x tends to 0
1/16
And when x goes to minus infinity what happens?! 😀😉
x= + inf
You teach well sir but I think you've gone wrong somewhere.You've divided the whole equation by X instead the X is under a square root.
Tried this, wamap said the answer was wrong. Granted this was 2 years ago
This calculation is correct. I'm sure wamap will fix that.
@@PrimeNewtons Considering the fact that the teacher requires us to use wamap, wamap is correct.
Lol. So, what was wamap's answer?
@@PrimeNewtons I don't know as it does not show the answer unless you get it right.
That's unfair to the student. I hope they've fixed it.
From inspection, something does not look right. Sqr(64*x2+X) at infinite will be 8x+ infinite; take off 8x, and you have infinite. Having said that I cannot see your maths is wrong.
That's why infinity is dangerous