Math Olympiad Problem | Nice Trigonometry Problem | Math Olympiad Training
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- čas přidán 25. 05. 2024
- In this Math Olympiad problem video, we'll tackle a nice Trigonometry Problem to help with your Math Olympiad training. Get ready to challenge your math skills!
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One other way to see it is to know that sin^4 -cos^4= sin^2-cos^2. Then everything cancels out and you get the result.
perfect
I did
f(x) = (cos²x + sin²x.sin²x)/(sin²x + cos²x.cos²x)
= (cos²x + sin²x.(1 - cos²x))/(sin²x + cos²x.(1 - sin²x))
= (cos²x + sin²x - sin²xcos²x))/(sin²x + cos²x - cos²xsin²x))
= (1 - sin²xcos²x)/(1 - sin²xcos²x)
= 1. Very easy.
Nice
writing z for sin^2 ( x) one gets
f ( x)
= (1 - z + z^2) /( z + ( 1 - z) ^2)
= (1 - z + z^2) /( 1 - z + z^2)
= 1
Nice
derivative of f(x) is 0. f(x) is constant and f(0)=1.
hence f (x)=1 for all x.
Ok thank you
@jwkim4428 how did you get thsi result? It is very tedious to calculate this derivative by the quotient rule, and there is no obvious term cancellation in the final result.
How do you pronounce x?
What are you hearing?
Bro.. Nice explanation
Thank you