How to design a steel column using an easy approach.

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  • čas přidán 26. 07. 2024
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    In this easy to follow tutorial, we will use a trail & error approach and show you how you can design a Universal Steel Column subjected to Axial force.
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Komentáře • 46

  • @andreipopovcean9494
    @andreipopovcean9494 Před 9 měsíci

    Thanks! This is one of the most understable and practical engineering channel on CZcams.

  • @emmadavies7434
    @emmadavies7434 Před 3 lety +1

    Great topic guys well done!.one of the most easiest ways I've ever come across cheers!.

  • @gulfadventurevlogs8054
    @gulfadventurevlogs8054 Před 6 měsíci

    Thanks. Great Explanation. easy to understand. great job.

  • @user-ov4dw3yr5d
    @user-ov4dw3yr5d Před rokem

    Thank you for all you very informative videos. 👍

  • @jacksonphillips6276
    @jacksonphillips6276 Před 2 lety +2

    Great Channel.

  • @dengineerslifevlog5534
    @dengineerslifevlog5534 Před 3 lety +2

    Thanks for this topic...

  • @vesaltorabi9
    @vesaltorabi9 Před 2 lety

    You are amazing!!

  • @zakwanabo9265
    @zakwanabo9265 Před rokem

    Thank you very much

  • @nirshunarayanyadav5297

    Very nice explanation

  • @nadinbu257
    @nadinbu257 Před měsícem

    thank you

  • @dopareel
    @dopareel Před 9 měsíci

    nice

  • @shahedsiddiki1165
    @shahedsiddiki1165 Před 2 lety +4

    It's a good video but we want more about column design

  • @ashutoshsuthar3753
    @ashutoshsuthar3753 Před rokem

    So core topics, please make video regarding design of crane grider on which the crab travels

  • @sakally6392
    @sakally6392 Před 4 měsíci

    cool

  • @goodmind6446
    @goodmind6446 Před rokem +1

    Thanks Sir ! want to see video on stability analysis and design of steel structure.

    • @cnjrq
      @cnjrq Před rokem

      I have lecture number 23 to 26 planned for stability analysis of steel buildings. I'm on lecture 10 at the moment and you'll see three vidoes per week uploaded. Please feel free to follow this playlist czcams.com/play/PLOQ_D0oq27oCKwuVHk-mgE0SRIGpOpSVu.html

  • @igirithankgod5395
    @igirithankgod5395 Před měsícem

    Thank you Sir for this easy approach.
    I have my actual stress as 157N/mm^2, is the column suitable?

  • @harigovind2968
    @harigovind2968 Před rokem

    can u make a video on design of inclined cantilever columns

  • @Beginner2Creator
    @Beginner2Creator Před 6 měsíci

    Great topic : let me ask you, what about slenderness more than 3 ?

  • @user-ov4dw3yr5d
    @user-ov4dw3yr5d Před rokem

    If I may request a vlog for alum. Curtain wall and steel brackets structural calcs.? Thanks in advance.

  • @ashleyrandall6582
    @ashleyrandall6582 Před rokem

    The 203 x 203 x 46 works. However can anyone tell me which codes this example is going according to ?

  • @boy-br2tr
    @boy-br2tr Před 2 lety +7

    Can you sample a building design from roof down to foundation structual analysis?..

    • @cnjrq
      @cnjrq Před rokem

      I have a complete tutorial on how loads are distributed from roof to foundation via columns. You can watch example 2 in my recent tutorial on steel columns czcams.com/video/XQipsi8Je2Q/video.html

  • @youubik
    @youubik Před rokem

    Just throw in that wacking great safety factor at the end and its doesn't matter what you calculate it to

  • @IvanIvanov-lo6lv
    @IvanIvanov-lo6lv Před 2 lety +2

    Please explain for 1.35 and 1.5 in design load. What do they mean, when to use them.

    • @sajadhussain6897
      @sajadhussain6897 Před 2 lety

      they are used to increase the load to induce factor of safety

    • @AS-tq2mn
      @AS-tq2mn Před rokem

      They're safety factors used to increase the load. You use 1.35 for permanent loads (which is the weight of the structure and anything else that's part of the build up) and 1.5 for variable loads (which is the load you consider from people using the structure, or any other load that comes and goes/isn't constant like snow).

  • @Kom-pks
    @Kom-pks Před 2 lety +1

    Hi,
    Anyone know the formula for calculating 'non-dimensional slenderness' for SS400 ?
    i seem to couldnt find it anywhere, or any keyword to search would be great too
    Thank you!

    • @cnjrq
      @cnjrq Před rokem

      Slenderness (Lambda) = (Lcr/iz)x(1/(93.9e), where e = SQRT(235/fy). Fy is yeild stress, Lcr is buckling lenggth, iz is radius of gyration in minor axix. You can follow the proceodure in my recent video, if it helps you czcams.com/video/udCnAM3RenQ/video.html

  • @maggysantana3878
    @maggysantana3878 Před 2 lety +3

    Just looking it few time and I don’t understand where you get the 350knm and the 300 Knm... from where you get the 4000mm ? Can you please do the example step by step... and show how you find those actor I mentioned to understand the math clear please.? Thanks.

    • @telestruct
      @telestruct Před rokem

      the design DL=350KN & LL=300KN are obtained from structural analysis. the selected column height of 4m is just an example.

  • @victorgetsbetter
    @victorgetsbetter Před rokem

    here right on time 😂

  • @suhaibkhan7356
    @suhaibkhan7356 Před 2 lety +3

    How 100 n/mmsq compressive stress assume

  • @vinothkumar-qq1gf
    @vinothkumar-qq1gf Před 2 lety

    As per 203 x 203 x 46Kg channel I got an actual stress value is 55.90 N/mm2. Is it correct?

  • @unitvector-dq1gb
    @unitvector-dq1gb Před rokem

    Trying 203×203×46 as you ask :
    This had properties,
    A = 58.8 cm
    i ( radius of gyration) = 5.11 cm
    The yield stress (fy) for this type of steel = 275 Mpa or N/mm² , it's the same.
    And the effective length is 4 m or *4000mm
    • Non-dimensional slenderness of the section is L/86i
    So 4000mm/86×5.11×10mm = 0.91
    • The reduction factor X from the curve is approximately 0.68
    • The buckling stress is : X × fy
    0.68×275= 187Mpa
    • Actual strees is :
    Design load/ Area of section
    922.5×10³ N / 58.8×10² mm
    = 156.9 Mpa < 187 Mpa ✓ok
    Susceptive to correct .

  • @saddammb5633
    @saddammb5633 Před 2 lety +5

    How did you consider 100 N/MM2 as compressive stress?

  • @bkingtz1
    @bkingtz1 Před rokem

    Who will help me calculate what type of columns and beams etc I need to make 7.5m L x 6m w and 4.5m H, cover/garage for my car lift?
    I live in country where there is snow, also no other weight on the roof except snow. I am just going to cover it with thermo panels.
    And what is necessary for column foundation (concrete and rebar etc type and spec)

    • @hudumasaud8295
      @hudumasaud8295 Před rokem

      As an engineer, do it first. Then submit for vetting

  • @bkingtz1
    @bkingtz1 Před rokem

    My 🧠 hurts 😵‍💫