Titration of a strong acid with a strong base | Chemistry | Khan Academy

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  • čas přidán 30. 08. 2014
  • Calculating the pH before the equivalence point for titration of strong acid, hydrochloric acid, with strong base, NaOH. Created by Jay.
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Komentáře • 40

  • @user-fy9di3yo5y
    @user-fy9di3yo5y Před 7 lety +53

    i can pretend i understand it

  • @Hakseng127
    @Hakseng127 Před 7 lety +11

    plz mention end point, indicators, buffer region, nd equivalance point too

  • @mbtisocialclub
    @mbtisocialclub Před 6 lety +7

    This video is perfect . Very well explained and right to the point . Easy to understand compared to my chem prof ...

  • @b-b-ntheboy5613
    @b-b-ntheboy5613 Před 3 lety +1

    Thank you very much it was exactly what i was looking for

  • @zidamv1944
    @zidamv1944 Před 3 lety

    very well explained sir ! thank you

  • @icassipops
    @icassipops Před 6 lety +6

    that's the very first "not that helpful" "complex" khan academy video i've ever watched but anyway thanks for the effort

  • @ran9628
    @ran9628 Před 6 lety

    Thanks!

  • @khattakfarhan9854
    @khattakfarhan9854 Před 6 lety

    thank you so much sir

  • @pasha1339
    @pasha1339 Před 4 měsíci

    This man is the best. Thank youuuuuuuuuuuuuu

  • @terrencegreen755
    @terrencegreen755 Před 3 lety +1

    thank you!

  • @priyankapal5599
    @priyankapal5599 Před 3 lety

    Thank u so much sir

  • @OctobrTea
    @OctobrTea Před 3 lety +1

    thank you soooooooooooooooooooooooooooooooooooooooooooooooooo much

  • @chamyke
    @chamyke Před 7 lety +3

    Thanks for the video it is very useful:) I have an other (for me easier ) way to find the concentration of H3O+.
    You have all in all 20 ml of HCl , it will be added 10 ml of NaOH which is 1/2 of the whole amount.
    So you can say: [H3O+] = 0,5*1/2* 20ml/30ml = 0,167
    PH = -log (0,167)= 0,777

  • @kimmadarimot9868
    @kimmadarimot9868 Před 3 lety

    hello just want to ask. Is the hydronium ion concentration of a strong acid titrated with a strong base equal to the concentration of the strong base at the equivalent point?

    • @sabaakbar7427
      @sabaakbar7427 Před 3 lety +1

      At end point/ eq.point conecentration of hydronium ion is more than conetration of base in that case that is why solution is acidic in nature because all base moles have been neutralized with moles of acid but acid moles are more than base

  • @nurlybektoktarov469
    @nurlybektoktarov469 Před 2 lety +5

    Lifehack: put it at the speed 1.5 and Khan Academy will speak like normal human 😄

    • @Chirp-chirp
      @Chirp-chirp Před rokem

      Really? I feel like he speaks so much faster in the chem videos compared to the math ones

  • @emilys.8347
    @emilys.8347 Před 4 lety +1

    Is it possible to titrate a strong base (analyte) with a strong acid (titrant)??

    • @peybak
      @peybak Před 4 lety +2

      Yes, the curve will be the opposite of this one, meaning that the starting pH will be high.

  • @dayanacheong901
    @dayanacheong901 Před 7 lety

    can the calculation of the titration of strong base and strong acid use the handerson hasselbalch eqn?

    • @jakobj58
      @jakobj58 Před 7 lety +2

      no. you can only use the henderson.hasselbalch equation for weak acids because every molecule of the acid is deprotonated. the equation would then be: ph= pks - log(0/A-)
      -> ph = pks - log (0). log (0) is not defined

    • @KatherinePierce_81
      @KatherinePierce_81 Před 7 lety +1

      Artischoche k. Why did he use log to find pH? I can't understand how to find the pH. Could you please explain?

    • @atreyobhatta9919
      @atreyobhatta9919 Před 6 lety

      Nina Dobrev that's the formula for finding pH

    • @user-uh9uv2yw9h
      @user-uh9uv2yw9h Před 3 lety

      No. The Henderson eq is used ONLY for buffers

  • @laraibkhan9102
    @laraibkhan9102 Před 4 lety

    anybody help me in solving some chemistry problems ASAP ??

  • @kristinmcelroy5356
    @kristinmcelroy5356 Před 7 lety

    how do i find Ka from this

    • @benhardsim8629
      @benhardsim8629 Před 5 lety +3

      i know i am 2 years late , but maybe its gonna be useful for someone else .
      you cannot find the Ka because this is a strong acid and base solution .

    • @abdulmunimjundurahman7923
      @abdulmunimjundurahman7923 Před 3 lety

      @@benhardsim8629 After 1 years you helped someone with the same question.

  • @filipdepay4155
    @filipdepay4155 Před 4 lety

    pozdrawiam 8 grupe !

  • @esa2236
    @esa2236 Před 7 lety +5

    Thanks so much for the video, but I think all the extra explanation like converting ml to L is very excessive if this video was made for students in organic chemistry....

    • @TheRelentlessPPL
      @TheRelentlessPPL Před 7 lety +4

      Skid some do this in high school so let it be Mr. Chemistry

    • @brainphelps1994
      @brainphelps1994 Před 7 lety +3

      no skid is right if you're doing this in high school and don't know how to convert moles and mL and all that crap you are the anomaly. The conversions are tedious

    • @KatherinePierce_81
      @KatherinePierce_81 Před 7 lety

      Skid I'min high school too and I think it's unnecessary

  • @arbindapandey1711
    @arbindapandey1711 Před 5 lety

    I didn't understood why the concentration of H3O+ was also 0.500M.

    • @beneastman9244
      @beneastman9244 Před 5 lety

      Strong acids completely dissociate in aq solutions. So, the concentration of H3O+ is going to equal whatever the concentration of HCl is because there is no base added yet.

    • @beneastman9244
      @beneastman9244 Před 5 lety +1

      In other words, every single H+ that was once bound to Cl- is now bound to H2O.

  • @stoneluo8986
    @stoneluo8986 Před 4 lety

    why cant you just get khan to explain ...

  • @rustyshackelford3590
    @rustyshackelford3590 Před 3 měsíci

    The MCAT can go to hell for making us do this without a calculator.

  • @khattakfarhan9854
    @khattakfarhan9854 Před 6 lety

    thank you so much sir

  • @khattakfarhan9854
    @khattakfarhan9854 Před 6 lety

    thank you so much sir