Voltage Divider Circuit Explained!
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- čas přidán 11. 12. 2017
- This physics video tutorial provides a basic introduction into voltage divider circuits. It provides a simple formula to calculate the voltage across a resistor in a series circuit with two resistors in series with a battery. it contains plenty of examples and practice problems. It discusses the effect on the output voltage of a voltage divider circuit when a load resistor is placed in parallel with R2. It discusses how to design a voltage divider circuit to meet certain requirements.
Schematic Diagrams & Symbols:
• Schematic Diagrams & S...
Resistors In Series:
• Resistors In Series - ...
Resistors In Parallel:
• Resistors In Parallel ...
Series and Parallel Circuits - Light Bulb Brightness:
• Series and Parallel Ci...
Equivalent Resistance of Complex Circuits:
• Equivalent Resistance ...
How To Solve DC Circuits:
• How To Solve Any Resis...
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Current Dividers:
• Current Dividers Expla...
Parallel Circuit Challenge Problem:
• Finding The Current In...
Kirchhoff's Current Law:
• Kirchhoff's Current La...
Kirchhoff's Voltage Law:
• Kirchhoff's Voltage La...
DC Circuits Review:
• Series and Parallel Ci...
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KCL and KVL Circuit Analysis:
• Kirchhoff's Law, Junct...
Thevenin's Theorem - Circuit Analysis:
• Thevenin's Theorem - C...
Norton's Theorem - Circuit Analysis:
• Norton's Theorem and T...
Superposition Theorem:
• Superposition Theorem
Maximum Power Transfer:
• Maximum Power Transfer...
Physics PDF Worksheets:
www.video-tutor.net/physics-b...
Final Exams and Video Playlists: www.video-tutor.net/
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This video series is awesome! Very specific and helpful problems for real world examples. Thank you for sharing.
Really is it awesome? What resistors did he use in his first example? He just puts 10 and 20 are that doesn't tell anybody anything
Thank you so much for this class i got it now keep the good work teacher
YOU MADE THIS LOOK SO EASY TYSMM!
Wow! Before watching this video I watched and read many other tutorials on voltage dividers, but still was confused and had many question. Now I finally understand. Thanks.
Though you didn't mention practical examples of voltage divider usage
from confused to confident, I am grateful for your help!
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please also add something about Thevenin theorem
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At 17:53, does he know that the voltage around R2 is 3V due to the fact that the device needs a voltage of 3V and voltage is the same across parallel branches?
For #5 how does he know that R2 should be approx 100times less to get 3V?
The bigger the internal resistance, the closer it is to the original output voltage. The internal resistance, as he stated, is recommended to be at least a hundred times more than R2.
Universal Narcissist what about if the internal resistance wasn’t as big?
@@Imkicelee it wouldn't be as close to 3V. If R2 was 5000ohms the total R would be: (1/5000+1/5000)^-1 + 15000 = 17500ohms, wich means the voltage out is: V in * (R2/R1+R2) = 12 * (2500/2500+15000) = 1.71 V and not even close to the 3V we wanted.
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at 11:43 , the voltage calculated to be 9.52, that's across the two parallel resistors right? So the voltage drop across R1 is 11.48 since 20-9.52=11.48 right?
Thank u
I can u dis in my modification circuit
Really nice lessons.
When I have 20vt, and know vo is 12v that tells you to get r1 is 8v (20v-12v) x .05a is 160 ohms. r2 = 12v /.05a =240.
You seemed to do more work to get the same answer.
Thanks for this
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Thanks
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God of mathematics and science
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according to kvl, the voltage exiting the circuit should be 0 but at 4:08 you said that the voltage output is 6v. Should not 6v be between R1 and R2?
good video
Thankyou bro
@10:51 Why is the numerator Req? If we're finding the voltage across the device, shouldn't the numerator be just 1000 Ohms (resistance of the device)? Similarly, if we were to find the voltage across R2, shouldn't the equation be vout = vin ( R2/R1+R2+R3 ) and not vout = vin (Req/Req + R1)?
thanks for including CURRENT!!! i blew my fuse on my multimetre so i couldnt find out what it was...
Why didn't you use the 100 ohm from R1 when calculating Req, so that R1 @ 100 ohm will be in series with R2 + R Device to give 190.9 ohms? Was it Req of the entire circuit or just the part around R2 + R Device?
Please what app did u use in writing and drawing the circuits......it made explanations easier....let me know the name of the app please
If a ckt contains r1,r2,r3,r4,and ,r5 resistors then what resistor value we used as numanetor
Good video. I feel that the wording in the outputs voltage and amperage is deceiving. You can get a fixed voltage using this method but the amperage through the output of our new source will depend on the resistance of the load. I think the wording would be better if you stated that the circuit without the load connected in the voltage divider would be (blank)mA
I have a transformerless LED driver from a China LED Bulb but it's voltage output is more than 300V DC. Can I reduce the V-out to 45V DC using this Voltage Divider Method? Will it be safe to used to turn on several SMD LED in series??
The largest resistor in the voltage divider will drop More Voltage. That resistor can get very very hot! So watch your power rating of that resistor.
Are voltage divisor and current divisor concepts used in capacitors, batteries etc ? Just like in resistors
In question 5....how did you get R2 as 50 ohms
0. Construct a dual potential divider circuit with a common voltage source as supply. The
potential drop should produce an output which is 5 times greater than the cut in voltage of a
PN junction diode.
Can u please tell us the solution
hi thank you for the information you din't show us how you calculated Resistor equivalent on qsn 4
Thank u
I'm here again. Thanks for sharing it with us daddy
Is Vin referring to the total Voltage? I'm not entirely sure about this but otherwise it wouldn't make sense. Assuming that Vin doesn't refer to Vtotal, then I assume its the voltage "coming in" from the first point we measure it, right before Req. But after assuming this, Vin shouldnt be equal to 20V which is Vtotal since R1 should cause a voltage drop before the starting point that we're measuring. Can someone explain? I feel like I understood part of it but didn't get the main point. **If** my assumption is right, then shouldnt we say Vtotal instead of Vin?
im on reading week and totally forgot i had an assignment and had a massive brain fart, i could kiss you! thanks bro!
Thank you for all your content!
Thanks tomorrow is my exam😎
Just a Word of thank you for your efforts to make this simple, I came across a voltage divider problem in lab and saw the efficiency was terrible with parallel device to R2 , this video made my day thank you from all my heart.
Yes nice video but how can i make the transfer function of this ?
Thank u for the vedio, but i can't understand how we decide resistors for circuit with knowing Am .
You need to know more. For example: I build a circuit to turn on an appliance using an LDR (light dependent resistor). The specs said that it has a resistance between 5k and 500K (depending on amount of light). So I choose the minimum to work which is 5k. Next I looked at my relay. It said that it needs minimum 2V to turn on. So no I know that my Vout is 2V. I also know that my R1 the (LDR) is 5k. I also know my Vin because I used a 5V supply. With all this info I was able to build the circuit using this voltage divider here and I turned on the appliance with a flashlight over my LDR resistor. All I had to do was to find R2 to give me the 2V at Vout (which was the relay).
4:10 if u want to decrease the voltage why do the resistors have to be the same? thank you so much xx
thats to divide in half, they have to be the same to divide in half
Please how do you calculate for the input and outputt
shouldnt number 4 be R2/90.9+R2? if we want to solve the voltage across R2 specifically?
how should calculate input voltage
3 beers and a shot of whiskey, watching tube. You make more sense. Definitely better understanding for me , rather than by my highly qualified engineering mates in the pub. Ta.
On the 5th problem how did you know that R2 should be 100x less than the device resistor?
did you ever get an answer?
😂this guy is literally saving my electrical engineering degree
found kind of a hacky way to find the resistances.
If you divide 12v/20v you get 0.6
and 0.6x400Ω is 240Ω, so you get r2 from that equation.
no clue how that worked out but somehow it did.
I don't know if I can get clarification on how the external resistance across R2 is 50 ohms while the internal resistance across it is 5000 ohms.
Another easier way is that the voltage in series adds up so you can subract the given voltage against the total voltage to find the missing voltage across 1 resistor
If multimeter shows Vin with respect to Vout to be a lesser value than expected what could be the reason?
7:40 for this question i solved it slightly different but got the same answer. i did 12/20 times 100 which equals 3/5. i know that R2 must be 3/5 of 400 and that leaves R1 to be 2/5.
For the question at 4:23, it should be written as.
A voltage divider circuit, where R2 has an output of 12V, and the circuit has a current of 50mA, using a 20V battery. Find the resistance of R1, and R2.
You are required to design the circuit..
What if we had more resistances could we still do (r1/(r1+r2+r3)) or we’d need to do it two at a time
can just add more
For #5, I think the current that being delivered from the battery is not 60.2mA because in his calculation, he did not allow for the the current that being consumed by R1 = 150 ohm.
I know it’s been two years, but for anyone else wondering the same thing. No, he is correct. Current does not drop in a series circuit. So the current before resistor 1 is the same as current after resistor 1
2:11 BREAKING NEWS: THE LEGENDARY ORGANIC CHEMISTRY TUTOR HAS USED A CALCULATOR
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how can we maintain that voltage without changing the resistor value
At 06:00 Why u considered only 2 resistors to design vdr circuit..why not 3or4? and at 09:04 current must enter in to 100ohm coz..current always chooses low resistance path? If reply..very thankful...
1) VDR circuit only has 2 resistors. It is used to divide the output voltage in any desired ratio from the input voltage .
2) Higher resistance means lower current flow. Lower resistance means higher current flow. Current would still flow through both resistors. Just that there would be a high current flow through the 100ohm resistor.
@@samsungnote2683 thankyou
So where is the required voltage taken from? Across r2? Would you connect a component across it?
yes + across and - to negative
I hope I understand you correctly the voltage is what you select you choose a voltage and you choose the current then you figure out the resistor size
why did you place the internal resistor in parallel and not series @8:39? I mean what's the thought process behind it?
i think bcz it said across it
Why was question four raised to the -1 power?
How is Rout related to R when voltage output is zero
you lost me @ 17:40 ... Does anyone know the logic behind this other than looking at other examples?
♥️
tut on voltage divider on 3 resistor in series
pretty sure same principle. just modify the numerator and denominator according to question
why is the current in milliamps instead of just amps at 21:30
I saw this after my exam 😄
Wait hold up, what I learn for, it just do it with series circuit would be more efficiency? Why don't they just put it as series circuit?
Why did you divide r2 by a hundred in 18:02 ?
Is this For IGCSE or A-levels?