Understanding Compact Sets

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  • čas přidán 20. 08. 2024

Komentáře • 20

  • @adeelakhtar3540
    @adeelakhtar3540 Před 3 lety +32

    Compactness has to to defined using open covers and subcovers. Of course, the characterization discussed in the video is true, but only valid for R^n, as stated by Heine-Borel theorem. Great video, thanks 😊

    • @hansbaeker9769
      @hansbaeker9769 Před rokem +2

      Exactly. Every open cover has a finite subcover.

    • @samtux762
      @samtux762 Před 9 měsíci

      I saw other videos. Those are more tecnical, talk about Hilbert spaces, show counterexamples. But for me this video is optimal: brings the point without extra details.
      Good news: I am not a mathematitian, airplane/powerplant designer, etc. So, even though my understanding of compactness is incomplete, this will not cause harm.

  • @markovchebyshev5376
    @markovchebyshev5376 Před 2 lety +3

    Really great video. It really explains with visual aid what finite subcover is

  • @PunmasterSTP
    @PunmasterSTP Před 2 lety

    Compact? More like "Completely where it's at!" This was a great video, and I'm really glad that you decided to make it.

  • @wuzhai2009
    @wuzhai2009 Před 2 lety +3

    Use a playback speed of 1.5x.

  • @rawiyahalraddadi7064
    @rawiyahalraddadi7064 Před 2 lety +1

    Thank you!

  • @david.2752
    @david.2752 Před rokem

    Thanks for this video 💥

  • @lckdai716
    @lckdai716 Před 3 lety +1

    Thank's very useful !!!

  • @xinyuewen3610
    @xinyuewen3610 Před 3 lety +1

    Thanks you !

  • @martinanthonyvargasalvines1681

    Thank you

  • @yassinesafraoui
    @yassinesafraoui Před 2 lety +2

    how can a set be closed and not bounded? does anyone have any example, because if there isn't any example, the condition of bounded would be useless then!

    • @mythicalbeast6585
      @mythicalbeast6585 Před 2 lety +4

      Closed means the complement is open, and open just means it's a neighbourhood for each of its points. For example, the integers as a subset of the reals. The complement of the integers (the reals excluding the integers) is open, because it consists of a union of open sets, and is thus a neighbourhood of each of its points. However the integers are clearly not bounded since they have no upper or lower bound.
      Likewise you could construct an uncountable number of closed but unbounded sets by simply centering the integers on any real number of your choosing - so there are at least as many closed but unbounded sets as there are reals. Of course there are many more closed but unbounded sets, but these are probably the easiest examples.

    • @tomtomtomtom691
      @tomtomtomtom691 Před 2 lety +1

      R^n is closed but not bounded.

  • @samtux762
    @samtux762 Před 9 měsíci

    I got the definition, but I have a question.
    "Most of the time" we deal with open set topology. It is "concidered nice and useful".
    Why do we suddnly switch to closed sets here?
    What are the benefits?

  • @letseconomics2938
    @letseconomics2938 Před rokem

    How can we prove an algebraically production set is a closed set?

  • @franciscoabusleme9085
    @franciscoabusleme9085 Před 3 lety +5

    This is not true in general, but it is true for Euclidean space...

  • @rajtilakpal5583
    @rajtilakpal5583 Před rokem +1

    Seriously, you need to speak at a lower voice😅

  • @wuwu365
    @wuwu365 Před 2 lety

    not good ,pls tell open and bound set is not compact.