I couldn't decide which Integration Bee I was working on!

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[@waarschijn]

Nice but I'd just use the series for ln(1-x), no u sub necessary.

[@owl3math]

I think that was the other method but I don’t remember for sure

[@waarschijn]

@@owl3math Oh sorry forgot about that 😝

[@theupson]

the obvious approach, integration by parts, fails in a most delightful way

[@owl3math]

Ha! Yes I can imagine that would be trouble

[@GangulaArjunNarenReddy]

Awesome content

[@owl3math]

thanks!!

[@Chris_387]

Awesome substitution! Can I suggest an integral for future video? It is very difficult though

[@owl3math]

Hi Chris. And thanks! I usually don't do suggestions but I will always take a look.

[@Chris_387]

@@owl3math it's the integral of ln²(1-x)ln²(1+x) from 0 to 1

[@owl3math]

I don’t think I know how to do it

[@pantelostzimas7490]

Why?!?!? After the u dub -1/xdx=du so u are done its the integral of -u

[@owl3math]

At what time in the video? Du = -1/(1-x)

[@suryamgangwal8315]

How come it has a negative answer?

[@owl3math]

Hi. ln(1-x) is always negative between 0 and 1 making the whole thing negative within the bounds.

[@MackEven]

I have better way