On a farm, the ratio to cows to goats is 1:3, pigs to goats 3:4. What is the ratio of cows to pigs?
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- čas přidán 10. 09. 2024
- How to solve a ratio math word problem - 3 ratios involved.
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At the title card, my answer is b) 4/9.
With 1 cow / 3 goats, and 3 pigs / 4 goats, find the LCD of 1/3 and 3/4, or 12.
4 cows per 12 goats vs 9 pigs per 12 goats = cows/pigs ratio of 4:9.
This one is very easy again:
C/G = 1/3 and P/G = 3/4
Now to find C/P we have to calculate C/G / P/G = C/G x G/P = C/P
So 1/3 x 4/3 = 4/9 cows over pigs.
That's exactly what I did, only I made the mistake that I often made while a math student. I wasn't careful enough. I did the ratio of pigs to cows. And 9:4 was one of the answer selections... just for people like me!
I solved it as follows: cows to goats = 1 : 3, which means that there are 3 times more goats than cows. Pigs to goats = 3 : 4, which means that the number of pigs is 3/4 x the number of goats. So cows to pigs = 1 : (3 x 3/4) = 1 : 2 1/4. Multiply both numbers by 4 and then you get 4 : 9. This means that the number of cows is 4/9 x the number of pigs and so the number of pigs is 9/4 x the number of cows.
. There are four other animals for every 4 goats. 1 is a cow and 3 are pigs. If we take the two whole groups to the power of 3, which is 24. (4 other + 4 goats =8 x 3 = 24) We can divide them up as 8 (8 x 1, in 1/3 (24)) to 18 (3/4 × 6 18/24) and halve that into 4 to 9.
This one I solved easily. I used the lowest common denominator, which is 12. From there, just filling in the correct numbers of cows, goats and pigs. Did it in my head. I’m 77 years old. I remembered this math from grammar school. However, I was a kid who loved math and science. As a girl, I wasn’t expected to like those subjects.
For this one you don't want to use a calculator.
You want to use a COWculator..
for me it was easier to cal algebraically: eq1: c/g=1/3 c=g/3; eq2: p/g=3/4 p=3/4g; sol: c/p=(g/3)/(3/4g)=4/9... was way easier calculating using x,y,z then c,g,p, because... math :) . Also simpler: if x/y=1/3 and z/y=4/3 and want x/z why not directly multiplyfirst fraction with the inverse of the second to get rid of y and get our desired fraction x/y: (x/y) * (y/z)=(1/3)*(4/3)=4/9
AGREE!! I did that in less than one minute
The second ratio suggests g = 4p/3. Why not substitute that for the value of g in the first ratio to get c/p = 4/9?
If one cow = 3 Pigs A can’t possibly be right. Other than answer B all of the other options can’t possible be correct as more cows than pigs. I didn’t know how to calculate the ratio, but I got the correct answer by eliminating all of the other answers. 3:38
got it... LCD of 12 4/9 thanks for the fun.
I totally missed this one, but loved the problem.
It took awhile, but i get it
Fun
Woohoo got it! Seems weird thinking these through after all this time!
I got 4/9 by inverting pigs/goats to get goats/pigs, and then multiplying cows/goats by goats/pigs. 1/3 * 4/3 = 4/9. I got the correct answer but I'm wondering whether it was a legitimate approach or if I just got lucky.
What you've done (likely without realizing) is called "dimensional analysis". It's a super easy method of problem solving that's used extensively in science and engineering. It involves multiplying a series of fractions together in such a way that units you don't need cancel and you're left with the units you're looking for.
In this example we started with *1 cow / 3 goats* and *3 pigs / 4 goats* . What we're looking for is *cows / pigs* and we don't need any *goats.* So by flipping that 2nd term and multiplying them together we get *1 cow / 3 goats X 4 goats / 3 pigs* . We have *goats* on top and *goats* on bottom, so we can cancel them out (just the units, not the numbers). Without those pesky goats, we can multiply across. This gives us *4 cows / 9 pigs* which is the correct answer.
It's easier to understand if you can actually write out the fractions instead of trying to type them in a comment. But dimensional analysis is a skill I'm very glad I learned in high school.
Before watching the clip, I determined that the solution was to set the goat herd up to a common denominator of 12, apply ratios to determine cows & pigs, then the answer jumps right out of the barn!
1/3•3/4=4/9=, 5 (x+5x-5)
4:9
b, 4/9
B roughly
B 4/9
there are only 2 possible right answers before you even do math because there has to be fewer cows than pigs and its not 1/4
4 to 9
I had to think about this one. Reading the question multiple times helped.
B- 4 to 9
Because cows to goats=4:12 and pigs to goats=9:12 therefore it implies cows to pigs=4:9
For every 1 COW there are 3 GOATS and for every 3 PIGS there are 4 GOATS
So .. let's get the number of GOATS to the same value.
For every 4 COWS there are 12 GOATS and for every 9 PIGS there are 12 GOATS
COWS to PIGS are therefore 4 to 9 answer b)
4/9
O.K. For now on, any title with" MANY WILL GET WRONG" gets a THUMBS DOWN!!
Not your "run of the mill" ratio problem indeed. :(
I always thought a 1:3 ration meant 1 item for every 3 of the other item for a total of 4 items thus being 25%.
A
OK
1:04 i worked out 4 cows to 9 pigs now lets see
B.
Cow's to pigs = 4/9
3 cows to 9 pigs
4/9
4/9
4/9