[ASMR] Can I Solve this Math Puzzle Before You Fall Asleep?
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- čas přidán 31. 05. 2024
- I was challenged to solve this fun MATHS PUZZLE! But can I solve it before you fall asleep? Watch and find out...
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My name is Duncan and I am a Maths Graduate in Scotland with a passion for maths and relaxation! I am an ASMR CZcamsr and plan to go on to teach maths at high school level in the coming years. I am very enthusiastic about teaching and to help me improve and get practice before entering the world of work I have created this channel to help people learn about mathematics at all levels all whilst having a good night's sleep.
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#ASMR #Maths #Relaxing - Zábava
My math teacher would say "well how do you know that its a square 🤓☝"
Well you see teach I actually used the "ligma equation"
Every triangle has a right angle so it has to be a square
@@emilstockmann5543how do you know 100% that those are right angles?
@@emilstockmann5543 eehm no?! Tf 😂
@@emilstockmann5543 First of all, that wasnt given. second of all, it could have been a rectangle.
Pretty cool puzzle
You don’t even need z. Since both the yellow and blue triangles have a height of x and the yellow triangles area is 1/2 that of the blue one. We can just put the base of the yellow triangle as y/2 and then instead of x-z we put x-y/2 and then it’s all in terms of x and y instead of another term z
True
That's very true! Love this alternative too. Depends what approach to take and how much you like fractions, I guess :)
Really creative idea
Thank you! 😊
My way:
Uhhh 4 seems to fit well
4² - all the areas = 7
How did u write the small 2?
Proof by inspection 🤓
²
Hold 2 on ur keyboard
you could have also looked at yellow triangle, 1/2ab=2 so ab=4 so the sides are either 2 and 2 or 1 and 4 but it cant be 2 and 2 as they arent equal so its 1 and 4, 4 squared is 16 and then take away the other areas
What about fractional values like 3 and 1.333?
@@naoxi1 i dont know or care really because they arent in this specific question
What Naoxi said is true, there are other values a and b could take in your explanation. But, given the simplicity of the numbers provided elsewhere it is a reasonable assumption to make of 1 and 4!
uhh 4 seems to work for x, so 4 * 4 = 16, 16 - 2 - 3 - 4 = 7
I overcomplicated this a lot but:
1/2 * sqrt17 * sqrt13 * sin(70.34617594) = 7cm^2
used pythagoras and simple trig rules for these values
coulda done 4^2 - the other areas, but we don't know it's a square
5cm 2
Is it?
Ooh, close but not quite!
i got it in like 10 seconds but i probably made some assumptions
Yeah I looked at yellow realized it could fit twice, with common knowledge. And I’m only a 5th grader (going into 6th)
Awesome!