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I think confusion with the last example comes from not being sure how to deal with a ring. This would be one way to go about it: 1) Start at a particular carbon on a ring and follow a path (i.e. clockwise) all the way around that returns you to your starting point. 2) Begin at the same carbon and follow a path all the way around in the opposite direction (i.e. counterclockwise). 3) If the paths in both directions were the same, your starting carbon would NOT be a chiral center because the ring itself would be symmetrical (so therefore there aren't 4 different groups attached). If the paths differed at some point (for example, say that the ring has an OH group and you encounter that group sooner as you move clockwise around the ring than if you moved counterclockwise) then your starting carbon would be a chiral center. It's hard to explain it without a demonstration, but hopefully that helps anyone that was also confused!
@@catarinavagari8965 Thank you! So In the first chirality center on the left, the one attached to an isopropyl group, is it chiral because going clockwise a ring was found sooner than counterclockwise right?
My first year in college here. I could not afford the book i needed for this kind of stuff since it was criminally expensive. The book was would have contained a code which would grant me acces to an online portal where aditional information and practice exersices are located. I did not have any of this. Your videos are the sole reason im passing the year. Just wanted to let you know how thankfull i am.
Oh my God I've been trying to figure it out for hours... 4 different groups... DIFFERENT.... the book/cengage/professor/video no one put an emphasis on it!
cengage explanations are really bad for beginners. Dont know why the college make us pay hundreds of dollars on textbooks just to learn better explanation from our saviour, Julio, The Organic Chemistry Tutor.
@@Fraidoon seriously though, my teacher and textbook are absolutely useless. Idk why I'm even paying for the class and college when I can learn so much better right here.
i dont get how when i teach somebody shit ill explain every detail you need to know but when a professional professor teaches they dont explain important crucial shit to solve problems. Like i literally had no idea there was an invisible hydrogen atom which is why i kept thinking how is there four groups when i only see three and are given three. its not that hard for a teacher to mention something like that but they still seem to fail to do it. this dude is honestly my main professor this semester its sad
Bruh. For those people who keep saying how can he go this far on ochem without knowing how hydrogen work. My prof also say no shit about that until someone ask where is the hydrogen he’s talking about and he just say oh, you can just draw it in if you want to like wtf. I don’t understand why I can just draw it in until now after this video. Not everyone is lucky having a well explanation prof. That’s why we’re here for the video so stfu
I'm loving this content! I also really appreciate how you work through so many examples in each of your videos. Keep it up, you are doing CZcams and ochem students everywhere a great service!
My textbook did such a crap job explaining this. I'm sitting there seeing an indicated chiral center that's attached to a hydrogen, a ch2 a ch2 and an hydroxide trying to figure out how ch2 and ch2 are different groups. It failed to explain that everything else attached to each carbon constitutes as a group. Thank you so much!!!
Isn't that 5th one still a chiral center? Sure two of it's immediate connections are CH2, but aren't they technically different functional groups since they are attached to the ring section differently?
@@fable6506 fifth carbon is a chiral center because the carbon atom is connected to different functional groups, yeah sure it's directly attached to two ch2 groups but that's called a " tie " watch khan academy stereochemistry videos to understand.
Not sure if you still need an answer but the reason is that, if you were to follow both sides of the ring at the same time, you’d get through 2 and a half carbons on each side (meeting in the middle of the bond). Although he drew the lines to be different lengths, they each represent a bond of equal length. So, although it looks like there’s 3 bonds on one side and 2 bonds on the other of the pentagon, it’s actually 2.5 on each side.
Thanks for your video. I just have a question. Can molecules with benzene ring in them have chiral centres in the benzene ring? Like at the point where there is a branch coming off the ring?
For the second to last example you did in this video (one with cyclopentane, methyl, fluorine, and OH), how can you tell that the carbon in the cyclopentane attached to the OH has two of the same things around it? Is it because there are two carbons (from the cyclopentane) on one side of the carbon attached to -OH and then two other carbons (from the same cyclopentane) on the other side of the carbon attached to -OH?
At 2:00 please do highlight OH group will bright colours...cuz while the question was being asked.. we could not see the dark blue/purple coloured OH.(unless u turn on ur screen brightness to full mode).. 😊
Not that he didn’t explain well on the last example. Watch it from the beginning to the end, he assumes that everyone should now know how to explain it by comparing your answer vs. his answer.
@Giorno Giovanna Actually, we won't call that as an invisible hydrogen. It's there because carbon always form 4 bonds and the structure that we're drawing is called bond line structure. It's the main purpose of drawing the structure as bond line so that we can reduce it and even after that we are able to represent the whole compound. That's why, hydrogen is present there so that we can satisfy the valency of carbon(having the tendency to form 4 bonds). I hope, this will help :)
That is for the chiral center connected to nh2. The one on the left and the right when looked at separately are chiral centers because they have 4 different groups attached to the carbon: one is the long chain, another is the hydrogen, the oh, and the ch3 group. The left and the right chiral centers are the same in this regard but are not associated with each other.
How many chiral centres r there in Ranitidine , Cimetidine,Bromopheniramine, Iproniazid, Phenelzine,Equanil ,Serotonin , Veronal , Valium , Tetracycline , Ofloxacin ..... If u know any of them plz and }:‑)🙏
We don't mention hydrogen when we write bond line structure of any organic compound but sometimes people overlook this "hydrogen atom" so it's named invisible as a joke it doesn't mean hydrogen atom doesn't exist we just don't show it
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I think confusion with the last example comes from not being sure how to deal with a ring. This would be one way to go about it:
1) Start at a particular carbon on a ring and follow a path (i.e. clockwise) all the way around that returns you to your starting point.
2) Begin at the same carbon and follow a path all the way around in the opposite direction (i.e. counterclockwise).
3) If the paths in both directions were the same, your starting carbon would NOT be a chiral center because the ring itself would be symmetrical (so therefore there aren't 4 different groups attached). If the paths differed at some point (for example, say that the ring has an OH group and you encounter that group sooner as you move clockwise around the ring than if you moved counterclockwise) then your starting carbon would be a chiral center.
It's hard to explain it without a demonstration, but hopefully that helps anyone that was also confused!
it helps, thanks
This honestly helped out a lot, thank you so much!
@@purplekyle0323 No problem, glad it helped!
i love you
@@catarinavagari8965
Thank you! So In the first chirality center on the left, the one attached to an isopropyl group, is it chiral because going clockwise a ring was found sooner than counterclockwise right?
My first year in college here. I could not afford the book i needed for this kind of stuff since it was criminally expensive. The book was would have contained a code which would grant me acces to an online portal where aditional information and practice exersices are located. I did not have any of this. Your videos are the sole reason im passing the year. Just wanted to let you know how thankfull i am.
Aww hope you did well
Oh my God I've been trying to figure it out for hours... 4 different groups... DIFFERENT.... the book/cengage/professor/video no one put an emphasis on it!
DUDE THANK U I'VE BEEN STUCK ON THIS FOR HOURS TOOO!!!! 4 D I F F E R E N T GROUPS DIFFERENT IS THE KEY WORD
Yeah I got confused with this I'm thankful to that person who saw me struggling here in yt and sent me this link. Thanks to you!
Bro I feel you on a different level haha
cengage explanations are really bad for beginners. Dont know why the college make us pay hundreds of dollars on textbooks just to learn better explanation from our saviour, Julio, The Organic Chemistry Tutor.
@@Fraidoon seriously though, my teacher and textbook are absolutely useless. Idk why I'm even paying for the class and college when I can learn so much better right here.
i dont get how when i teach somebody shit ill explain every detail you need to know but when a professional professor teaches they dont explain important crucial shit to solve problems. Like i literally had no idea there was an invisible hydrogen atom which is why i kept thinking how is there four groups when i only see three and are given three. its not that hard for a teacher to mention something like that but they still seem to fail to do it. this dude is honestly my main professor this semester its sad
A carbon does need to satisfy its valency, thus the hydrogens. In the bond line structures, h is usually omitted
Frank Franky stfu
@Wayne Smiles yeah honestly I wouldn’t doubt it. Luckily I passed with a C+ cuz I got an absolutely baller score on the final by studying my balls off
how the hell are you this far into ochem without knowing how hydrogens work in molecules?
Bruh. For those people who keep saying how can he go this far on ochem without knowing how hydrogen work. My prof also say no shit about that until someone ask where is the hydrogen he’s talking about and he just say oh, you can just draw it in if you want to like wtf. I don’t understand why I can just draw it in until now after this video. Not everyone is lucky having a well explanation prof. That’s why we’re here for the video so stfu
OMFG I finally understand! Thank you! I thought it had to be different ATOMS but it’s more like different GROUPS! Thank you 🙏🏼
You are saving lives your way. My goodness! Thank you
Thanks a lot!🌸However,the last example is a big challenge😩😭😭
Try the cholesterol molecule 😭
👌🏿sweet. My organic chemistry teacher teaches @ 60mph. Here I can learn everything with peace!!!
Explain last example properly
Zuko is teaching me Organic Chemistry!
LOOOL
The lightbulb above my head just turned on. Thank you.
I've been learning so so much with your videos! It really helps out more than many books! thanks loads
Seriously the best explantion ever heard about chirality and chiral molecules with such good explanation with examples
how is the left side and the right side of the cyclopentane the same??
omg wish you were my professor!! i would had failed chem without you in youtube
wow thanks for the explanation!! actually my finals in a few hours lol
Wow, you just saved one Korean student. So easy to understand!!!!!!
I'm loving this content! I also really appreciate how you work through so many examples in each of your videos. Keep it up, you are doing CZcams and ochem students everywhere a great service!
Finally, I can find how many chiral centers are in bond. Thanks for teaching us
explained the thing just in a moment. Thanks a lot sir.
Wow, this is very informational and easy to understand. Thank you!
Very useful for easy learning thank you so much
Are u from tamilnadu??
My textbook did such a crap job explaining this. I'm sitting there seeing an indicated chiral center that's attached to a hydrogen, a ch2 a ch2 and an hydroxide trying to figure out how ch2 and ch2 are different groups. It failed to explain that everything else attached to each carbon constitutes as a group. Thank you so much!!!
Keep making such great videos! Really helpful!
3:24 we can just say it's achiral by the plain of symmetry
Easy trick guys...first just look for carbons with three separate bonds
bro you just blew my mind thx so much!
This doesn't work all the time, but it is a quick trick.
@@TalhaFaisal1 ya it fails if there are identical compounds like the dimethly group up top, but still seems real neat
you've got a really nice voice mister. thanks for the vid
It became very easy after you explained🤩🤩 Thank you ✨💯
Thank you so much! This video is so explanatory. Absolutely Phenomenal :)
Great video! Helped to clear up the confusion I had before. You're the best!
did not teach well for the last example
@Chemist Me naw he was right it does have 7 chiral centers
Isn't that 5th one still a chiral center? Sure two of it's immediate connections are CH2, but aren't they technically different functional groups since they are attached to the ring section differently?
@@fable6506 fifth carbon is a chiral center because the carbon atom is connected to different functional groups, yeah sure it's directly attached to two ch2 groups but that's called a " tie " watch khan academy stereochemistry videos to understand.
@@OkaBridge Thanks for this I was almost confused when he said that the 5th carbon was not a chiral center. Greatly appreciate it!
@@dionel1388
What do you mean? I don't get where he did a mistake
I still don't get it
THE ORGANIC CHEMISTRY TUTOR ❤❤❤
Thank you!
Victor should’ve briefed up with this 😭
This was a lifesaver
It was really very helpful.
Oh so I was correct at the last part-
I'm learning
can u explain again the last example plz
Your explanation is nice
U ARE A GODSEND
At 4:22 How are they the same? Its not symmetric. So it has to be counted as 2 diff grps right?
Not sure if you still need an answer but the reason is that, if you were to follow both sides of the ring at the same time, you’d get through 2 and a half carbons on each side (meeting in the middle of the bond). Although he drew the lines to be different lengths, they each represent a bond of equal length. So, although it looks like there’s 3 bonds on one side and 2 bonds on the other of the pentagon, it’s actually 2.5 on each side.
@@Majesticman47 thank you!
explanations weren’t great
Thanks a lot
Wow...thanks so much
Really do appreciate
Thanks this helped a lot👍🏼❤️
Superb explanation
Pls do a video on pseudo chiral carbon
Thank you ✨✨✨✨
THANKS 🥰🥰
what about the cyclopentane. I don’g agree that there are equals
THANK YOU!
Thank u so much 🙏💗
thank you
Thanks for your video. I just have a question. Can molecules with benzene ring in them have chiral centres in the benzene ring? Like at the point where there is a branch coming off the ring?
Thank you
Bro saved me from an extra mental breakdown
Would of loved to hear the explication of the last example but the video cuts off…
I thank Jesus for you bro
2:08 isnt the line on top of the 2nd carbon called a methyl group? why did he call it a hydroxyl group when thr is no OH present? plsss clarify
Thank you!🌟💥👍💫
bro i love you
if only u were my teacher
What about 1,2-chlorocyclohexane?
Nice
Thanks 😊🙏
For the second to last example you did in this video (one with cyclopentane, methyl, fluorine, and OH), how can you tell that the carbon in the cyclopentane attached to the OH has two of the same things around it? Is it because there are two carbons (from the cyclopentane) on one side of the carbon attached to -OH and then two other carbons (from the same cyclopentane) on the other side of the carbon attached to -OH?
yes
At 2:00 please do highlight OH group will bright colours...cuz while the question was being asked.. we could not see the dark blue/purple coloured OH.(unless u turn on ur screen brightness to full mode).. 😊
👍👍👍
Why are we finding chiral centers or r or s configs? I am missing the context of why.
To find the number of optical isomers
cause the fkin exam want us to do it
@@kejadianwahyu5826 LMAOOOOO
@@kejadianwahyu5826 IM DYING LMFAOOO
Not that he didn’t explain well on the last example. Watch it from the beginning to the end, he assumes that everyone should now know how to explain it by comparing your answer vs. his answer.
Thank you!
Why is there an invisible hydrogen in every chiral center?
@Giorno Giovanna Actually, we won't call that as an invisible hydrogen. It's there because carbon always form 4 bonds and the structure that we're drawing is called bond line structure.
It's the main purpose of drawing the structure as bond line so that we can reduce it and even after that we are able to represent the whole compound.
That's why, hydrogen is present there so that we can satisfy the valency of carbon(having the tendency to form 4 bonds).
I hope, this will help :)
Thanks girl
I owe you my degree man I swear
Thank you (Sun 20 Dec 2020, 6:03 PM)
Great
At 2:21 if the right and left are the same, then how are they both chiral centers?
That is for the chiral center connected to nh2. The one on the left and the right when looked at separately are chiral centers because they have 4 different groups attached to the carbon: one is the long chain, another is the hydrogen, the oh, and the ch3 group. The left and the right chiral centers are the same in this regard but are not associated with each other.
How many chiral centres r there in Ranitidine , Cimetidine,Bromopheniramine, Iproniazid, Phenelzine,Equanil ,Serotonin
, Veronal , Valium , Tetracycline , Ofloxacin .....
If u know any of them plz and }:‑)🙏
What is meant by invisible hydrogen? Where that comes from?
We don't mention hydrogen when we write bond line structure of any organic compound but sometimes people overlook this "hydrogen atom" so it's named invisible as a joke it doesn't mean hydrogen atom doesn't exist we just don't show it
can anybody help me out with the name of this compound at 5:16
wtf is the last one
No bad word is allowed
czcams.com/video/RRPCGr4b8KQ/video.html
i keep confusing element with groups 😭
What is the name of the molecule at 4:13 ?
1-(3-fluoro-1-methylbutyl)cyclopentanol
❤️
in this video ...
i still dont get it whatttttttttttttttt
Walter White brought me here
Not explained very well
fuck this class. thanks for the help but oh dear god this sucks
a center can't be chiral. dislike.