Thevenin's theorem with dependent source
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- čas přidán 4. 09. 2024
- This video is about Thevenin's theorem with dependent source. In finding Thevenin's equivalent circuit with parameters Vth and Rth, mesh analysis is used. Simple and easy explanation in Hindi along with English terminology is used to make it simple and easy to understand.
Mam the decoration done on board with different chalk colours is worth appreciating 💜
i know it's awesome awesome concept with awesome presentation but here is a better video on thevenin using dependent sources czcams.com/video/D1QxFA9_U5w/video.html
@@SupremeTuber bhai bada bakwas samjahaya tune kuch palle hi nahi pada pehle khud pad phir dusro ko pada
Bhai padne aata hai ya chalk ka colour dekhne aata hai
Thanks ma'am.I am from bits pilani,it really helped me.You are as good as our professors here
Life savior ❤🛐
Since the current flowing through the current controlled voltage source 2i is i it is just a 2 Ohm resistor. You have beautiful penmanship. Best.
That was just straight up awesome... That's more like it
Thank you.
Nice teaching mam👍👍🙂
thank you for clearing my doubt.
After finding current in closed loop u can also directly find Vth without writing another equation Its will consume less time.
Vth = voltage drop across 6ohm resistance (IR or 2x6)=12V
Yes, you can use that also.
More over I thin kvl is applied to a closed loop..
Awesome mam ... 🙏🙏😁
Thanks mam
I was solving JB Gupta book's questions, i knew only about simple independent source type questions of Vth & Rth
I easily solved all after watching your video☺️
Thank u.
Mam FABULOUS JOB..the way you teach is awesome..
Thank you. You can ask for more topics of EC.
I didn’t understand how we got Rth while in finding Rth we use short circuit current (isc) at AB...by ohms law Rth=Vth/isc
Draw a random thevenin's circuit and a Norton's circuit and observe both circuits...they are source transformations of each other by that observation we get Rth=Vth/isc
Best video mam
Very technically informative video, Mam.😊😊
Thank u so much.
Thanks alot...i didn't get anything our stupid college progessor say ....thank u maam ....😍😍🤗
awesome video maam! THank you!
Thank you very much mam....your video was so helpful to me....
thank u ma'am..keep doing the good work..
I don't understand what you are saying but I get it what you write Thanks 😀
very good explanation nd great teaching maam
Thanks. You need more videos on EC....
Very nicely explained ma'am.
Nice mam...apne khubsurat i k sath yeh chees samajh diya...thanks a lot mam...
👌👌Superb👌👌👌
Thanks mam for such helpful lecture.
Thank you mam nice explanation
Aapka video bahut acha laga
excellent mam jo doubt 1 hour se clr na hua 10 min me
ho gya
THANK YOU MAM.
Superb.. Keep it up mam
Nice explanation ....
Mam I think we needn't apply kvl to the outer loop because no current will flow through 10 ohm resistance .we need to apply kvl only in the inner loop and the voltage across 6 ohm resistance will be Vth.Correct me if I'm wrong.
Yes, its another way to find Vth .Here I tried to give a general method that suits to other problems also.
Good
the current way to find Rth is to take Isc ( short circuit current ) at terminal AB and then using mess analysis find the value of Isc and then Rth using formula Rth=Vth/Isc which is equal to 12.4 ohms
Thanks. Nice explanation.
Thank you.
Very nice ma'am.
Madam G, Aap ne Vth across terminal A-B 1v put kia, kaha se aa giya 1v???
This is part of the process to find Rth in dependent source ckts, since source is needed there: it may be a 1V source or a1Amp Current source.
Thankyou ma'am
very good
Thanks for your time
Thq so much mam
Very many thanks ma'am
Thank you.
great help for those who need help BUT too fast......... slow down a little bit; it's not a love story!
Slow your speed of video
Thanqu mam💕
Ma'am, could you solve this problem by using kcl method because there is a dependent voltage source in first loop ma'am what would we take as as a reference node. Can I take voltage source current dependant as a reference node kindly resolve my queries
First find I in loop ie (20+2i)volts/12 ohm=i.herewe got i= 2amp. Now get thevenin voltage Vth= VAB= 6* i= 12 volts.
Thanks mam
thank u mam. upload more
Thank you. I have uploaded some more videos,pls see those videos.
Thanks a lot.
Mam यदि किसी dependent circuit me Rth ki value negative में आता है तो उसका answer negative में देगे या फिर positive me
Mam
Why we ignore 10ohm and 6ohm resistors as 10ohm is in series with the circuit current also flow in 10 ohm
is Potential difference depends on it between a and b terminal
Waiting for your reply
The same i cudn't understand
entire current is flowing back from 6ohm resistance to source ..there is no return path from 10ohm resistance
bcuz its open while finding vth 1st case.
while finding VTh, open circuiied load terminal so no current across 10ohm for that case only. Next to find RTh, connect a test voltage at terminal AB, you have to consider 10ohm this time.
Only 10ohm resistor is not considered as there is no current flow when we open circuiied AB terminal..
THANKS Teacher
Nice job
Thank you.
Thank Teacher!
@6:58 we know value of "i" ..why you have not put directly
it's the value of i0 not i
👍🏼👍🏼👍🏼👍🏼👍🏼👍🏼
Thnks mam😇🙏
0:57 why 10 ohms is not consider while solving???? mam
In KVL we consider all voltage drops in the considering loop here outer loop. As no current in second loop so drop across 10 Ohm is 0.But drop across open terminals will be taken as Vth.
Yes mam got your point.. Thank u mam.. And while considering signs it depends on us if we can take entering or leaving current sign,
By using 1v we can find Vth please exapian
To find Vth, no change in original ckt .Only open ckt the load terminals to find Vth there..Then apply KVL here in meahes.
Thanks you ma'am
Ma'am At 4:46 did we take any value of test voltage or test voltage is always 1V?
You can take any value but Calculationis for Rth with 1V are easy ie Rth= 1V / io.
@@rashmiagnihotritiwari8211 ok ma'am... thanku so much ma'am for these videos
Mam can't we do this problem using nodal analysis
Yes we can solve it using KCL.
[20+2i-Vth] /6i = Vth/6 ....( I )
Vth/6 = i.....( II )
@@rashmiagnihotritiwari8211 very much helpful mam. Thank you so much
Mam when to put 1volt or1 ampere
You can use any of them .When you take 1 volt then find current io in the branch we applied this 1volt. Then Rth= 1 volt/ io.
mam how you take only 'i' for outerloop and mesh1 ...i.e. i1 for outerloop and i2 for mesh1...
To find Vth, load resistance is removed in first step. So there is only one loop remaining in this ckt. In that loop one current I is flowing which is already given here .another mesh is not existing as it is opened at load.
Mam...when we apply kvl for outer loop then
10ohm resistance ke across me drop nahi hoga???
Yes,no drop.Reason: there is no current due to open circuit .
Thnq mam...
Mam we take test source when there is only dependent source but here we have both independent and dependent source ...... In spite of taking test source at ab terminal we will find the short circuit current at AB terminal and then find Rth using formula Rth=Vth/Isc (short circuit current)
do check this once again
Two equations are required as unknown variables are also two ie i and VTh.So apply KVL in outer and inner loops.
Yes,you can do like that also.
Okay mam thank you so much
Mom I thought we got Vth to help us in finding Rth bt I wonder where 12v has been used..help please!!!!
Maam please make a video on concept of capacitor and inductor charging and transient basics
I have uploaded videos on transient analysis. Pls see them.
BE LOVED VIDEO U DO
You are so cute mam 🥰
We need one more way to find rth
Mam
1:32 time
Vth concept not understand
Waiting for your reply
rj kumar ,Vth is voltage across open circuiied load terminal I.e.AB terminal and KVL is the method , used to find it.
Thankyou for reply
Mam is questions me kvl use kiye to usme 10ohm resistor use nahi ki app yaha pe doubt HH🙄🙄
No dropavross 10 Ohm resistor.Reason: there is no current due to open circuit .
thanku mamji
mam please provide +&- sign properly with direction of flow of current.
Take second (next) sign in voltage source in moving direction such as from voltage source [+ -] take - sign, which is second sign if we are moving rightward. In resistors take - sign , if moving in direction of current and vice-versa.
Thnx mam
nice madam
if you don't understand the concept while watching this video go check out this one
czcams.com/video/D1QxFA9_U5w/video.html
Ye outerloop kisi book me nhi dekha ma'am kaise ho rha h
In this ckt ,we have two unkowns (i and Vth). So we need two equations to solve them.
You can get second equation through other ways like Currrent i in loop I using ohm's law i.e. i= V/R =(20+2i)/12i.
Or use KCL at middle top node
For Both she didn't considered 10 ohms resistance.
For Vth, mesh II is an open Circuit. No current over there so need not to consider 10ohm as there is no voltage drop.
entire current from source is flowing through 6ohm resistance back to source ..there is no return path from 10ohm resistance bcuz its open while finding vth (1st case.)
Rth will be 13 Ohm?
12.4
Mam dependent current source hua to ka karenge
czcams.com/video/Oz7OMk_xy_0/video.html
czcams.com/video/btw6swstlk0/video.html
Pls see these videos.
Complete unit ki vidio bnao jis me sari theorm ho
I uploaded Reciprocity theorem. Millman and Resonant circuit in next few days. Any other topic...
Mam, how to know that when we should apply a test voltage source and when not to??
Waiting for ur reply
Manoj, when dependent source is present in circuit like 2i here as it is a voltage source that depends on current i in loop I ,then apply test voltage(1v) or test current (1amp) at load terminal while solving for Rth.
If u use test current (1amp) then apply KCL ie nodal analysis to find V0 across it.
Thanks for ur reply mam
@@manojchowdary662 u r welcome with some other topics of EC
Ap kiu 1v ka hi test voltage use Kiya ??? Dusra koi kiu nahi liya???
1V test voltage is used for simple calculations only. Other voltage ratings like 2V, 3V can also be used.
@@rashmiagnihotritiwari8211
Will I get same result?
Yes.
v.good explanation..... But your black board is too small
Abdullah Shah ,thanks ! your advice will be well considered.
yours diagrams are too easy but our paper is too tough
Abdullah Shah ,which university papers ? I would like solve those also.
Osmania university
I will definitely use a big board if needed. Thanks for suggestion.
Use big board maammmmmm
Galat Kiya he solve.
It is one of the simplest methods ie KVL. It can also be solved using Ohm's law or Nodal analysis.
keep it up madam
Pole zero pole
Poor sound
bekar lga bilkul...
thanks mam
Thanks ma'am
Thanku mam
Thanks mam