When the three blocks are released from rest, they accelerate with a magnitude of 0.500 m/s2. Block

When the three blocks are released from rest, they accelerate with a magnitude of 0.500 m/s2. Block 1 has mass M, block 2 has 2M, and block 3 has 2M. What is the coefficient of kinetic friction between block 2 and the table?

[@madamadadane7989]

You have saved my life and tears. Thank you

[@andrewslisher9059]

wow. I just found out about you. wish i found this sooner. please keep making videos.

[@SpaceDictator]

Thank you for doing this. Very helpful.

[@guggystyle]

Thank you for watching and for commenting!

[@beastzc7373]

Wonderful video!

[@MusicIsLifeSoLoveIt3]

I spent almost an hour and a half on this problem deciphering online notes, thank you so much for being so clear. It would be helpful if you slowed down a little bit, but it was clear.

[@guggystyle]

I'm so happy to hear that it helped!

[@michaelmassajr.9996]

Same here thanks a bunch friend!

[@CynthiaChiranian]

any idea which book was used?

[@hotarokun4428]

Thanks very much

[@TholangNtsere]

@WNY tutor please come back sir

[@exotictoast]

thanks

[@judithndangwa6804]

Why did you multiply 2 to the ma

[@aanishtanveer]

Why is T23 negative in the third block, and why isnt 2Mg negative?
Thanks

[@erikunixarias]

Yes, T23 should be positive because the tension vector is up in the positive y axis and 2Mg should be negative because the vector is going down in negative y axis. Correct me if I am wrong.

[@alexeyman7301]

@@erikunixarias I hope I am not too late on the reply but the reason that these forces are labeled as positive or negative seems to be, I believe, due to their relationship with the direction of motion and how that seems to relate to setting up the 3 equations later. It isn't that you are necessarily wrong but that we are changing our frame of reference for each equation, separately, to make it fit the motion we are trying to describe.
You arent wrong in your observation, and you can choose to do this in your calculations if you are more comfortable doing so, just ensure you include that it equals -2Ma across the equal sign to compensate. You should get the same answer either way because the values don't change, just the relative direction.

[@erikunixarias]

@@alexeyman7301 Yes, I see your point. If your frame of reference depends on the motion then your negative and positive sings in the equations make sense. Thank you clarifying this point for me.

[@enriquesoler3150]

So block 3 has a greater mass than block 1 so the system is moving to the right. As that happens in block 3, it moves downward making 2mg positive and T23 negative. Hope this makes sense

[@user-hm3ex4hw7i]

thanks