Why was this visual proof missed for 400 years? (Fermat's two square theorem)

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  • čas přidán 13. 06. 2024
  • Today's video is about a new really wonderfully simple and visual proof of Fermat's famous two square theorem: An odd prime can be written as the sum of two integer squares iff it is of the form 4k+1. This proof is a visual incarnation of Zagier's (in)famous one-sentence proof.
    0:00 Intro
    2:20 Chapter 1: Discovering a theorem
    7:05 Chapter 2: 400 years worth of proofs
    9:59 Chapter 3: Zagier's one-sentence proof
    15:40 Chapter 4: The windmill trick
    22:12 Chapter 5: Windmill maths interlude
    25:08 Chapter 6: Uniqueness !!
    33:08 Credits
    The first ten minutes of the video are an introduction to the theorem and its history. The presentation of the new proof runs from 10:00 to 21:00. Later on I also present a proof that there is only one way to write 4k+1 primes as the sum of two squares of positive integers.
    I learned about the new visual proof from someone who goes by the CZcams name TheOneThreeSeven. What TheOneThreeSeven pointed out to me was a summary of the windmill proof by Moritz Firsching in this mathoverflow discussion: mathoverflow.net/questions/31...
    In turn Moritz Firsching mentions that he learned this proof from Günter Zieger and he links to a very nice survey of proofs of Fermat's theorem by Alexander Spivak that also contains the new proof (in Russian): Крылатые квадраты (Winged squares), Lecture notes for the mathematical circle at Moscow State University, 15th lecture 2007: mmmf.msu.ru/lect/spivak/summa_...
    Here is a link to JSTOR where you can read Zagier's paper for free:
    www.jstor.org/stable/2323918
    Here are the Numberphile videos on Zagier's proof that I mention in my video:
    • The Prime Problem with...
    • The One Sentence Proof...
    Finally here is a link to my summary of the different cases for the windmill pairing that need to be considered (don't read until you've given this a go yourself :)
    www.qedcat.com/misc/windmill_s...
    Today's t-shirt is one of my own: "To infinity and beyond"
    Enjoy!
    P.S.: Added a couple of hours after the video went live:
    One of the things that I find really rewarding about making these videos is all the great feedback here in the comments. Here are a few of the most noteworthy observations so far:
    - Based on feedback by one of you it looks like it was the Russian math teacher and math olympiad coach Alexander Spivak discovered the windmill interpretation of Zagier's proof; see also the link in the description of this video.
    - Challenge 1 at the very end should (of course :) be: an integer can be written as a difference of two squares if and only if it is odd or a multiple of 4.
    -one of you actually ran some primality testing to make sure that that 100 digit number is really a prime. Based on those tests it's looking good that this is indeed the case :)
    - one of you actually found this !!! 6513516734600035718300327211250928237178281758494417357560086828416863929270451437126021949850746381 = 16120430216983125661219096041413890639183535175875^2 + 79080013051462081144097259373611263341866969255266^2
    - a nice insight about the windmill proof for Pythagoras's theorem is that you can shift the two tilings with respect to each other and you get different dissection proofs this way. Particularly nice ones result when you place the vertices of the large square at the centres of the smaller squares :)
    - proving that there is only one straight square cross: observe that the five pieces of the cross can be lined up into a long rectangle with short side is x. Since the area of the rectangle is the prime p, x has to be 1. Very pretty :)
    - Mathologer videos covering the ticked beautiful proofs in the math beauty pageant:
    e^i pi=-1 : • e to the pi i for dummies (there are actually a couple of videos in which I talk about this but this is the main one)
    infinitely many primes: Mentioned a couple of times: This video has a really fun proof off the beaten track: • Euler’s Pi Prime Produ...
    pi^2/6: Again mentioned a couple of times but this one here is the main video: • Euler's real identity ...
    root 2 is irrational: one of the videos in which I present a proof: • Root 2 and the deadly ...
    pi is transcendental: • The dark side of the M...
    And actually there is one more on the list, Brouwer's fixed-point theorem that is a corollary of of what I do in this video: • NYT: Sperner's lemma d...
    - When you start with the 11k windmill and then alternate swapping yz and the footprint construction, you'll start cycling through different windmill solutions and will eventually reach one of the solutions we are really interested in. Zagier et al talk about this in an article in the American Mathematical Monthly "New Looks at Old Number Theory" www.jstor.org/stable/10.4169/...

Komentáře • 1,9K

  • @FourthDerivative
    @FourthDerivative Před 4 lety +762

    "The proof is left as an exercise for the reader" -Fermat

  • @caspermadlener4191
    @caspermadlener4191 Před rokem +67

    This proof is so beautiful that I wrote an entire essay about numbers as the sum of two squares. When the essay was "finished" (I admit that it wasn't), I sent it to the main competition for this type of math essays in the Netherlands, and it got third place.
    Also, because I heavily studied the subject in my spare time and Olympiad training, I got really good at this type of number theory.
    When I participated at the IMO in Oslo this year (second time), I solved question 3 with full points, which was about this type of number theory. I got a perfect score on the first day, and scored 7+5+4=16 points on the second day, for a total of 37 points! GOLD! 19th place worldwide! Relative best for my country ever!
    I really don't know if I would have gotten this score without this proof, so thank you so much for making this video. I hope that you are going to inspire lots of other people as well!

    • @PC_Simo
      @PC_Simo Před 7 měsíci +4

      *_WOW!_* That’s really impressive 😮👏🏻! *_CONGRATULATIONS!_* 🥳😃👍🏻

    • @Avighna
      @Avighna Před 5 měsíci +2

      You are a legend

    • @jannegrey593
      @jannegrey593 Před 3 měsíci +1

      This is great! Congratulations. And I hope that maybe you will be one inspiring people as well!

    • @gilberttheisen9270
      @gilberttheisen9270 Před 2 měsíci +1

      25/3/2024.
      La preuve se démontre en 4 lignes. Niveau: classe de 4e en France !
      Plus, revoir sa copie;
      Bon courage.

  • @mikemthify
    @mikemthify Před 4 lety +948

    This proof was discovered by Roger Heath-Brown in 1971, and was later condensed into the one sentence version by Don Zagier. It's one of two proofs of this theorem found in the wonderful book "Proofs from THE BOOK" 6th ed by Martin Aigner and Günter M. Ziegler in chapter 4.

    • @Mathologer
      @Mathologer  Před 4 lety +172

      Thanks for that. I bought the book when it came out (1ed.). Loved it then. Looks like I should have a look at the most recent edition. Who knows what other gems have found their way in there :)

    • @seanziewonzie
      @seanziewonzie Před 4 lety +46

      I love Zagier's sentence, even without the windmills. It serves as a great exercise in reading proofs. If I ever teach one of those "intro to proofs" class, I would assign the task of deciphering it as some sort of class discussion for the day.

    • @Macieks300
      @Macieks300 Před 4 lety +7

      @mikemthify
      Roger Heath-Brown was 19 in 1971. Could you post some sources?

    • @mikemthify
      @mikemthify Před 4 lety +13

      @@Macieks300 page 21 of the book I mentioned.
      As a source it cites: D. R. Heath-Brown: Fermat's two squares theorem, Invariant (1984), 2-5. latex version, with appendix on history, January 2008, at eprints.maths.ox.ac.uk/677/1/invariant.pdf
      The URL is archived at: web.archive.org/web/20110606154228/eprints.maths.ox.ac.uk/677/1/invariant.pdf

    • @Macieks300
      @Macieks300 Před 4 lety +12

      @@mikemthify He said "My original
      notes date from 1971." I don't know if that means he came up with the proof then but if he did he really would've been 19 and that just blows my mind.

  • @scooldrood
    @scooldrood Před 4 lety +434

    "4k+1, now can you see the patter on the left?"
    "Yeah 😄, 4k-1!"
    "4k+3!
    "😑"

    • @McDaldo
      @McDaldo Před 4 lety +31

      Is there a reason that it is notated as 4k+3 in stead of 4k-1?

    • @MuffinsAPlenty
      @MuffinsAPlenty Před 4 lety +94

      @@McDaldo There is nothing wrong with using 4k-1 instead of 4k+3. An integer is 1 less than a multiple of 4 if and only if it is 3 more than a multiple of 4. So 4k-1 and 4k+3 describe the same sets of integers. The arguments/proofs in this video would work exactly as well using 4k-1 as it does using 4k+3.
      So why does Mathologer use 4k+3? Because of modular arithmetic! In modular arithmetic, we work with the _remainders._ So if you were asked, "what is 7 modulo 4; in other words, what is the remainder when you divide 7 by 4?" you would probably answer with "3", not with "-1".
      And Mathologer's next video (after this one), uses modular arithmetic, so feel free to check it out: watch?v=X63MWZIN3gM

    • @Alexgaby15Channel
      @Alexgaby15Channel Před 3 lety +19

      @@McDaldo it's because when you do modulo the remainder of 7 / 4 is 3 not -1. Because of this is more standardized to use 4k 4k+1 4k+2 4k+3 and not things like 4k-1 or 4k+4

    • @anniecenter
      @anniecenter Před 3 lety +10

      MuffinsAPlenty Thank you so much for answering this. This makes so much sense

    • @redpanda2961
      @redpanda2961 Před 3 lety +3

      @@MuffinsAPlenty Isn't it a trade-off of domain consistency for the consistency of modular arithmetic? For 4k+1 --> k>=1 but for 4k+3 --> k>=0.

  • @raynmanshorts9275
    @raynmanshorts9275 Před 4 lety +973

    Fermat: "Hey, here's this cool thing about numbers."
    Mathematicians: "Amazing! Can you prove it?"
    Fermat: "I already did."
    Mathematicians: "Wow! Can we see it?"
    Fermat: "Hmmm... nah."

    • @Fingerblasterstudios
      @Fingerblasterstudios Před 4 lety +105

      Fermat: *dies*

    • @archiebellega956
      @archiebellega956 Před 4 lety +116

      Fermat : I'm sorry but I run out of space to write the stuff anyway bye
      Everyone : ... you can just get another paper

    • @justpaulo
      @justpaulo Před 4 lety +19

      Fermat's👻: Aaaahh, now let's just sit and enjoy their struggle !

    • @gfhrtshergheghegewgewgew1730
      @gfhrtshergheghegewgewgew1730 Před 4 lety +28

      perhaps fermat chose to let other people work on the problem than to just spoonfeed the proofs for them, so as to not spoil the pursuit of mathematics for people. since he knew he was able to prove it he can reasonably assume that anyone else could be able to as well

    • @chickenduckhappy
      @chickenduckhappy Před 4 lety +6

      When it came to granting access to his proofs, he seems to have been slightly on the egg plant side of behaviors 🤔 On the other hand, he also was an extremely strict judge, so maybe he wanted people to demonstrate their ability to grok things on their own while watching with a frown 🙂

  • @ChrisSeltzer
    @ChrisSeltzer Před 4 lety +35

    Videos like this make me marvel at the internet. Growing up I could never have access to content like this but now I can watch a brilliant mathematical mind explain fascinating concepts to me. this channel is an example that should give everyone faith in the future of humanity.

  • @jakegerke7188
    @jakegerke7188 Před 4 lety +34

    I never made it past geometry in public school, and yet I was able to follow most of this well, and appreciate how beautiful this proof really is. I chalk that up not only to your ability to explain things in various ways, but also to just how clean and professionally edited this video was. Well done. You have yourself a new fan. (Or... a new windmill.)

    • @Mathologer
      @Mathologer  Před 4 lety +7

      That's great :)

    • @OKEKOBEB
      @OKEKOBEB Před 2 lety +1

      I don't know what I am doing on this video but that last bit of your comment is better than the proof

  • @vsevolodvoronov7526
    @vsevolodvoronov7526 Před 4 lety +35

    Thanks for the video! When I first heard about this proof, I asked Alexander Spivak who invented the visual version. And he said that there was no other source, it was his own idea. Because we don't know anybody who came up with this before 2007, it's almost certainly that he was the first. Unbelievable, but the Zagier's proof (and the previous proof by Heath-Brown) had appeared without any connection to geometry.

    • @Mathologer
      @Mathologer  Před 4 lety +9

      I actually had a link to a writeup by Spivak and I dug up an e-mail address. Sadly he never replied to my e-mail asking him whether he discovered the windmills (neither did Don Zagier) :(

    • @vsevolodvoronov7526
      @vsevolodvoronov7526 Před 4 lety +3

      @@Mathologer I have a few friends in common with him, and it was easier for me.

    • @rainjar
      @rainjar Před 2 lety

      @@vsevolodvoronov7526 No harm in him replying now?

  • @Mathologer
    @Mathologer  Před 4 lety +247

    In his 1940 book “A Mathematician’s apology” the mathematical superstar G.H. Hardy writes: “Another famous and beautiful theorem is Fermat’s ‘two square’ theorem... All the primes of the first class” [i.e. 1 mod 4] ... “can be expressed as the sum of two integral squares... This is Fermat’s theorem, which is ranked, very justly, as one of the finest of arithmetic. Unfortunately, there is no proof within the comprehension of anybody but a fairly expert mathematician.”
    My mission in today’s video is to present to you a beautiful visual proof of Fermat’s theorem that hardly anybody seems to know about, a proof that I think just about anybody should be able to appreciate. Fingers crossed :) Please let me know how well this proof worked for you.
    And here is a very nice song that goes well with today’s video:
    czcams.com/video/qKV9bK-CBXo/video.html
    Added a couple of hours after the video went live:
    One of the things that I find really rewarding about making these videos is all the great feedback here in the comments. Here are a few of the most noteworthy observations so far:
    -Based on feedback by one of you it looks like it was the Russian math teacher and math olympiad coach Alexander Spivak discovered the windmill interpretation of Zagier's proof; see also the link in the description of this video.
    -Challenge 1 at the very end should be (of course :) be: an integer can be written as a difference of two squares if and only if it is odd or a multiple of 4.
    -one of you actually some primality testing to make sure that that 100 digit number is really a prime. Based on those tests it's looking good that this is indeed the case :)
    -one of you actually found this !!! 6513516734600035718300327211250928237178281758494417357560086828416863929270451437126021949850746381 = 16120430216983125661219096041413890639183535175875^2 + 79080013051462081144097259373611263341866969255266^2
    - a nice insight about the windmill proof for Pythagoras's theorem is that you can shift the two tilings with respect to each other and you get different dissection proofs this way. Particularly nice ones result when you place the vertices of the large square at the centres of the smaller squares :)
    -proving that there is only one straight square cross: observe that the five pieces of the cross can be lined up into a long rectangles one of whose short side is x. Since the area of the rectangle is the prime p, x has to be 1. Very pretty :)
    -Mathologer videos covering the various ticked beautiful theorems:
    e^i pi=-1 : czcams.com/video/-dhHrg-KbJ0/video.html (there are actually a couple of videos in which I talk about this but this is the main one)
    infinitely many primes was mentioned a couple of times already. This video has a really fun proof off the beaten track:czcams.com/video/LFwSIdLSosI/video.html
    pi^2/6: again mentioned a couple of times but this one here is the main video: czcams.com/video/yPl64xi_ZZA/video.html
    root 2 is irrational: one of the videos in which I present a proof: czcams.com/video/f1yDExNAEMg/video.html
    pi is transcendental: czcams.com/video/9gk_8mQuerg/video.html
    And actually there is one more on the list, Brower's fixed-point theorem that is a corollary of of what I do in this video: czcams.com/video/7s-YM-kcKME/video.html
    -When you start with the 11k windmill and then alternate swapping yz and the footprint construction, you'll start cycling through different windmill solutions and will eventually reach one of the solutions we are really interested in. Zagier et al talk about this in an article "New Looks at Old Number Theory" www.jstor.org/stable/10.4169/amer.math.monthly.120.03.243?seq=1

    • @EagerLearner23
      @EagerLearner23 Před 4 lety +13

      4k+1, 4k-1

    • @andlabs
      @andlabs Před 4 lety +3

      "Very nice song" is a link back to this video
      Prof. Hardy's life appears to be increasingly anticlimactic. Always overshadowed or outdone, it seems.

    • @madhuragrawal5685
      @madhuragrawal5685 Před 4 lety +1

      Windmill summary is 404ing

    • @kenhaley4
      @kenhaley4 Před 4 lety

      The link to the "very nice song" is incorrect. It simply links right back to this video.

    • @Mathologer
      @Mathologer  Před 4 lety +3

      @@kenhaley4 Fixed the link :)

  • @MrYAY100
    @MrYAY100 Před 4 lety +1008

    Shirt = To infinity and beyond?

    • @dimitrispapadakis2122
      @dimitrispapadakis2122 Před 4 lety +34

      why is > beyond?

    • @MrYAY100
      @MrYAY100 Před 4 lety +51

      @@dimitrispapadakis2122 Im thinking it refers to a number greater than infinity (>inf). In other words beyond infinity

    • @adama7752
      @adama7752 Před 4 lety +29

      @@dimitrispapadakis2122 because it's not >=

    • @livedandletdie
      @livedandletdie Před 4 lety +15

      2 Infinity or greater than. And is after all the multiplicative function.

    • @linyenchin6773
      @linyenchin6773 Před 4 lety +22

      There is no "beyond" the boundless aka infinite...Buzz Lightyear was stoned on "star command," a powerful strain of marijuana...

  • @serkanmuhcu1270
    @serkanmuhcu1270 Před 4 lety +337

    I like, that 3blue1brown is also a patron

    • @dikephobia
      @dikephobia Před 3 lety

      Yes. I love that "3lue1brown" is a "patreon."

  • @muskyoxes
    @muskyoxes Před 4 lety +41

    I kept hearing "a 4k+1 prime" and wondered how or if the primality mattered. It's amazing how late, and how crucially, it finally comes into play.

    • @programmer4047
      @programmer4047 Před rokem

      Where in the proof it mattered?
      Can you give me timestamp?
      I still don't understand why it has to be a 4k+1 prime.

    • @muskyoxes
      @muskyoxes Před rokem

      @@programmer4047 20:07 primality comes in

  • @chirayu_jain
    @chirayu_jain Před 4 lety +192

    So elegant. At 19:17, I understood where this proof is going, that is the happiest moment of your video when I understand where the proof is going 😃

    • @captainpints
      @captainpints Před 4 lety +2

      Chirayu Jain Nice!

    • @blackpenredpen
      @blackpenredpen Před 4 lety +9

      I agree! That kind of feeling is just amazing!

    • @nisargbhavsar25
      @nisargbhavsar25 Před 4 lety +1

      Hi Chairayu

    • @MrVerece
      @MrVerece Před 4 lety +1

      Jo didn't realize it was 19 minutes of Math already at that moment

    • @chirayu_jain
      @chirayu_jain Před 4 lety +2

      @@blackpenredpen you are too here!!!! 😮

  • @benjaminmiddaugh2729
    @benjaminmiddaugh2729 Před 4 lety +10

    I love the structure of this video. The moment when I understood how the visual proof would go (just before we moved to visual representations of it) is why I watch videos like this.

  • @leoneschle3112
    @leoneschle3112 Před 4 lety +418

    Minecraft villager be like: 5:30

    • @ploopybear
      @ploopybear Před 4 lety +36

      when the paper is worth 2 emeralds

    • @draketungsten74
      @draketungsten74 Před 4 lety +26

      Speaking of Minecraft... 33:13 first PayPal supporter 🤔

    • @SathvickSatish
      @SathvickSatish Před 4 lety +5

      Drake Tungsten notch agrees 😂

    • @Narinjas
      @Narinjas Před 4 lety

      I wonder if there is a villager sound expansion mod that includes this take of the sound in the variety or if it will have it included now.

    • @squibble311
      @squibble311 Před 3 lety +3

      mathologer is a gamer confirmed

  • @ghostrng
    @ghostrng Před 4 lety +166

    It is good to see that mathloger is back online...

  • @siradmiralbanana
    @siradmiralbanana Před 4 lety +31

    20:55 I had to immediately upvote here. I love when a proof concludes and it all comes together and makes sense. I wish that visuals were more commonplace in math papers (and in maths in general), because I feel like less people would feel like math is something they'll never be able to understand. Great video, very easy to follow, very enlightening!

    • @johnnysparkleface3096
      @johnnysparkleface3096 Před 4 lety +1

      So far I'm utterly hopeless. Your eureka moment went right by me, I don't see how anything fits together. I was completely lost every inch of the way. I believe there are people who just CAN NOT understand math no matter how gifted the teacher. And I HATE that I am one of those people, because I think I'd really like math if I could just catch on.

    • @siradmiralbanana
      @siradmiralbanana Před 4 lety +4

      @@johnnysparkleface3096 That's ok! Even though this video is aimed at being a simple proof, it is still somewhat advanced to be able to grasp. Don't beat yourself up, there is always plenty of math for you to enjoy that you'd be able to digest, not matter your skill level.

    • @PC_Simo
      @PC_Simo Před 7 měsíci +1

      I love that eureka-moment, as well; and this proof and video certainly delivers. 👍🏻

  • @Saki630
    @Saki630 Před 4 lety +42

    It was me, I discovered this proof back in grade school when making arts & crafts. I wrote a note in my journal of discovering the proof, but I had to also go back and watch Power Rangers.

  • @bjdiament
    @bjdiament Před 4 lety +18

    Thank you, Mathologer for your wonderful videos! David Wells's survey sadly omits Cantor's diagonalization, which, in my opinion, belongs no lower than position 2 on his list of most beautiful proofs. Cantor's proof is also the granddaddy (through Goedel) of Turing's proof of the undecidability of the halting problem (which also sends chills down my spine whenever I read it), and which ushered in the field of computer science.

    • @Mathologer
      @Mathologer  Před 4 lety +6

      Speaking of omissions. What about Pythagoras's theorem ? :)

  • @luisbenites4825
    @luisbenites4825 Před 3 lety +1

    You guys really outdid yourselves with the presentation of this visual proof. Nice addition of the uniqueness proof. Spectacular job!

  • @TommasoGianiorio
    @TommasoGianiorio Před 4 lety +57

    Euler's formula for polyhedra can easily reach #1 if you realise it's actually d0-d1+d2-d3+d4...dn=1 where di is the number of i-dimensional objects that form an n-dimensional polyhedron

    • @csDiablo1
      @csDiablo1 Před 4 lety +1

      Out of curiosity: are you sure about the right side? I am certainly no expert in this particular subject, but having an odd number there seems....
      Well... Odd 😁😁
      Jokes aside though, this is kinda new form of knowledge for me and I want to see where you got this from :)

    • @rmsgrey
      @rmsgrey Před 4 lety +5

      @@csDiablo1 It checks out for the familiar 3D case - V-E+F-1=1 (the last 1 on the left is the body itself). In 2D, it can be rewritten as V=E (the shape and the constant 1 on the right cancel).

    • @zemoxian
      @zemoxian Před 4 lety +3

      I noticed that pattern in high school when playing with polytopes. Never tried to prove it though.
      I think I also noticed that the n-1 dimensional surface of an n-dimensional sphere is the derivative of its hyper-volume. I think that might have been an assumption on my part given that it’s true for the first couple of examples.
      I did integrate hyperspheres and derive a formula for n-dimensional spheres. It’s interesting that you get an extra factor of pi at every even dimension. I’ve wondered if that has anything to do with the number of independent axes of rotation you can have.
      I feel like I should study math again. Don’t think I could derive that formula now.

    • @TommasoGianiorio
      @TommasoGianiorio Před 4 lety +2

      @@zemoxian I think there is a recent video of 3B1B exactly on that extra Pi

    • @TommasoGianiorio
      @TommasoGianiorio Před 4 lety +2

      @@csDiablo1 yeah, absolutely sure! It's easy to see that that sum equals 1 in the case of a n-dimensional tetrahedron for example.
      If you didn't know, the n-th row of Pascal's triangle describes the number of i-dimensional objects that form an n-dimensional tetrahedron ( for example, a 3-dimensional pyramid has 4 V 6E 4 F and 1 Pyramid, 4-6-4-1) and the 1 left over in the equation is the first 1 in Pascal's rows (it is another well-known result that the alternating sums of the numbers in the rows equals zero)

  • @tejing2001
    @tejing2001 Před 4 lety +71

    I really love the graphical intuition added onto that one sentence proof. It makes it a lot clearer WHY that function is an involution and has exactly 1 fixed point.
    Also, you misspoke. At 28:54 you said "b squared" instead of "c squared." >.< Gotta be tough to get through that stuff without any mistakes. At least it's clear what you meant cause of the written equations.

    • @ThePharphis
      @ThePharphis Před rokem +2

      A great reason for redundancy in information given!

  • @15silverblade
    @15silverblade Před 4 lety +8

    Okay, this is actually one of the most beautiful things I've seen in math.

  • @AntonBourbon
    @AntonBourbon Před 2 lety +1

    I've seen many beautiful 4K videos on CZcams, but out of *4k+1* videos, this is definitely the best :)

  • @CC-hx8gj
    @CC-hx8gj Před 3 lety +14

    >One person assigned each theorem a score of 0, with the comment, “Maths is a tool. Art has beauty”; that response was excluded from the averages listed below, as was another that awarded very many zeros, four who left many blanks, and two who awarded numerous 10s.
    lol

  • @davidmeijer1645
    @davidmeijer1645 Před 4 lety +9

    "Step back and squint your eyes."
    Brilliant guide to this insight!

  • @jonsey3645
    @jonsey3645 Před 4 lety +2

    I am numerically challenged. I have a bachelor's degree in nursing and have never passed algebra...(please don't ask).
    I am addicted to your channel and genuinely understand the pleasure that you exhibit from elegant solutions.
    Thank you for this long undiscovered pleasure that you have introduced me to.

  • @TheOneThreeSeven
    @TheOneThreeSeven Před 4 lety +287

    A year ago I left a comment on one of these video's saying I was so inspired I was going to make my own math education you tube video's. I have something very special for everyone coming very soon, it's a free software project that I created while working on a tool to make animations for my video's and is almost ready to be released. I just published the first video on my channel, check it out!

    • @hassanakhtar7874
      @hassanakhtar7874 Před 4 lety +8

      Everyone like this comment lmao its TheOneThreeSeven :O

    • @MrAlRats
      @MrAlRats Před 4 lety +14

      You've got to learn to use apostrophes correctly!

    • @yt-sh
      @yt-sh Před 4 lety +1

      The numbers what do they mean?

    • @Machu_channel
      @Machu_channel Před 4 lety

      I wanna learn python. Make the UI of the software user friendly. I wanna try the software. I saw your video and that was great.

    • @elonmusk501
      @elonmusk501 Před 4 lety

      I had subscribe your channel

  •  Před 4 lety +6

    This is really beautiful. It's even more beautiful than the theorem itself, which was hard to beat.

  • @GreenMeansGOF
    @GreenMeansGOF Před 4 lety +69

    Mathologer’s Theorem: π is the sum of two squares. 21:19

    • @heliy_25
      @heliy_25 Před 4 lety

      Impossible. For a degree greater than 2 .

    • @hugo3222
      @hugo3222 Před 4 lety +12

      It's actually a simple corollary of the theorem that a circle cannot be transformed into *one* square.

    • @federico6416
      @federico6416 Před 4 lety +9

      guys relax, he was referring to the fact that he pronounced "P" as π (pie)

    • @heliy_25
      @heliy_25 Před 4 lety +2

      @@federico6416 😜

  • @nilshoppenstedt6073
    @nilshoppenstedt6073 Před 4 lety +1

    WOW! Definitiv eines der besten Mathe-Videos auf CZcams! Und auch sehr schön aufbereitet und präsentiert!

  • @jezzag9739
    @jezzag9739 Před 3 lety +4

    This is great. You're a good teacher and I appreciate the time you spent making it

  • @koenth2359
    @koenth2359 Před 4 lety +26

    The simple part: any odd number n that can be written as the sum of two squares must be the sum of an even square a^2 and an odd square b^2. Now a^2=0 (mod 4) and b^2=1 (mod 4), so that n must be 1 (mod 4).

    • @Shadow81989
      @Shadow81989 Před 4 lety +1

      For an easier understanding I'd like to add that every odd b^2 can be expressed as (x+1)^2, with x being an even number.
      Now obviously that makes b^2 equal to x^2 + 2x + 1.
      As x is even, both x^2 and 2x are always divisible by 4, so any b^2 must be of the form 4k+1.
      (therefore obviously any a^2 + b^2 with a being even and b being odd has to be of the form 4k+1 as well...)

    • @Shadow81989
      @Shadow81989 Před 4 lety

      @Šimon Rada good point! I changed to the good old "x" to avoid confusion with the original "a".

    • @Shadow81989
      @Shadow81989 Před 4 lety

      @Šimon Rada yes, that was part of the first statement (not mine): "any odd number n *that can be written as the sum of two squares* [...must be of the form 4k+1]" :-)

  • @peterjamesfoote3964
    @peterjamesfoote3964 Před 3 lety +4

    Thank you for presenting this. Haven’t had a math class in more than 40 years but I did have formal logic which helped a bit when following this video. If I had seen this in high school I might have had a whole different career path.

  • @boringextrovert6719
    @boringextrovert6719 Před 4 lety +22

    7:02 yes it can. It's sufficient to look at the last two digits of a number to check if it's divisible by 4 since 4 divides 100. The last two digits were 81 which is one above a multiple of four.

    • @maulaucraw1209
      @maulaucraw1209 Před 4 lety +1

      Thank you kind sir

    • @Gulyus
      @Gulyus Před 4 lety +1

      Yes, but can you prove it is prime : P That would be the issue in this case.

    • @boringextrovert6719
      @boringextrovert6719 Před 4 lety

      @@maulaucraw1209 😆😆

  • @alexandersanchez9138
    @alexandersanchez9138 Před 4 lety +1

    Man, this channel is awesome. Keep up the great work!

  • @johnny_eth
    @johnny_eth Před 4 lety +44

    7:00 yes it can. The number ends in 81. That's a multiple of 4 + 1.

    • @keyboard_toucher
      @keyboard_toucher Před 4 lety +29

      To elaborate a bit, 6513...46381 = 6513...46300 + 81. The number on the left obviously has no remainder when divided by 4 (being a multiple of 100), leaving only 81 to be considered.

    • @incoralium9211
      @incoralium9211 Před 3 lety +3

      @@keyboard_toucher Thx captain abvious, but "multiple of 4 depends of last 2 digit " is a tool given at school before the age of ten, just like " sum up digits of a number to know if you can divide it by 3 "

  • @tamirerez2547
    @tamirerez2547 Před 4 lety +48

    2^2+ i^2=3

    • @Mathologer
      @Mathologer  Před 4 lety +18

      Veeery funny :)

    • @JMairboeck
      @JMairboeck Před 4 lety +9

      Wait a minute, does that mean that if we extend the domain of x and y into the complex numbers, it works for any (real) prime? 4^2+(3i)^2=7, for example

    • @willnewman9783
      @willnewman9783 Před 4 lety +14

      @@JMairboeck Yes. As he mentions at the end of the video, any odd number can be written as x^2-y^2. So any odd prime p has p=x^2-y^2=x^2+(iy)^2

    • @tamirerez2547
      @tamirerez2547 Před 4 lety +4

      Yes Joachim. looks like.
      And so 6^2 + 5i^2 = 11
      Or we can simply say that
      ANY PRIME NUMBER CAN BE WRITEN AS a^2 + b^2
      or a^2 - b^2 (and we dont need imaginary numbers) 10^2 - 9^2 = 19 12^2 - 11^2=23. 16^2 - 15^2=31
      Only now I notice:
      10+9=19
      12+11=23
      16+15=31

    • @jerberus5563
      @jerberus5563 Před 4 lety +3

      He says 4k+3, and that's equivalent to 4k-1.

  • @seiggrainhart4719
    @seiggrainhart4719 Před 4 lety +45

    I'm surprised there aren't more comments about how your shirt literally says "To infinity and beyond" in math geek. At least, I think it does?

  • @shoam2103
    @shoam2103 Před 4 lety +46

    Typical Fermat. Claiming he has proofs but not delivering. *Unlike* Mathologer of course 😜

  • @swingardium706
    @swingardium706 Před 4 lety +24

    The movie "Fermat's Room" is indeed excellent, I'm glad it's getting a bit of publicity!

    • @morphx666
      @morphx666 Před 4 lety +1

      Just finished watching it... thanks for the recommendation!

    • @guillermogil3391
      @guillermogil3391 Před 4 lety +1

      I see eye to eye with you! Totally!

    • @SimonBuchanNz
      @SimonBuchanNz Před 4 lety

      Huh, I vaguely remember watching it a while ago and sort of liking it, but not thinking it especially awesome? I should rewatch it I guess?

  • @user-jr4ih7zk6o
    @user-jr4ih7zk6o Před 4 lety +3

    I am very very fascinated by
    1) How hardworking you are with all these presentations
    2) How kind, positive and interested in math you are.
    It's perfect that you make these videos, it literally makes me much happier because i fall in love with math more and more.
    P. S. Sorry for my english, it's not my language.

    • @Mathologer
      @Mathologer  Před 4 lety +1

      Glad you like the videos. It's a lot of work but it's also very rewarding to then get comments like this that show people really appreciate what I am doing :)

  • @farofalo
    @farofalo Před 4 lety

    Omg. I wish more ppl were interested in math to appreciate things like this, and your vid itself. Great edit job too, congrats the team. Perfect job man. +1 sub for sure.

    • @Mathologer
      @Mathologer  Před 4 lety

      Well, 200k and counting, not bad I'd say :)

  • @dhritajitkalia2653
    @dhritajitkalia2653 Před 2 lety +1

    Beautiful beautiful explanations. Every student deserves a professor like you

  • @ciscoortega9789
    @ciscoortega9789 Před 4 lety +28

    I gasped out loud when he pointed out that the windmills pair up with each other. That was amazing

  • @michaelwoodhams7866
    @michaelwoodhams7866 Před 4 lety +6

    When you do Euler's polyhedron formula, here is an interesting bit you could include. For any polyhedron*, the angular deficits at the vertices sum to 720 degrees (4 pi steradians.) This can be very quickly proved via Euler's polyhedron formula, using for a polygon sum-of-angles = 180 x number-of-vertices - 360. The appeal is that this is about a 30 second proof.
    For example, consider a square pyramid with regular triangles. The 'top' vertex has 4 triangles, so the deficit is (360 - 4x60)=120 degrees. The other four vertices have a square and two triangles so the deficit is (360-90-2x60)=150. The sum of the deficits is 4x150+120=720.
    I expect (I haven't looked into it) that this is a special case of a theorem which says integrate-curvature-over-a-topologically-spherical-surface = 4 pi, and in turn gives surface area of a unit sphere = 4 pi. And probably integrate-curvature-over-any-surface = 4 pi (1 - number of holes in surface)
    * Not self-intersecting, topologically equivalent to a sphere.

  • @SoleaGalilei
    @SoleaGalilei Před 4 lety

    I remember the Numberphile video and I'm amazed that such a simpler proof is available now! Thanks for sharing it.

  • @AlabasterClay
    @AlabasterClay Před 4 lety

    Merry Christmas!!! What a beautiful proof. Amazing.

  • @Quwertyn007
    @Quwertyn007 Před 4 lety +39

    5:38
    All primes that can be written as a sum of two squares are primes

    • @Mathologer
      @Mathologer  Před 4 lety +12

      :)

    • @doctorwhouse3881
      @doctorwhouse3881 Před 4 lety

      I got that... and then remembered what I was watching and felt silly.

    • @FrankHarwald
      @FrankHarwald Před 4 lety

      @@Mathologer I mean, it's not wrong, is it? ;)

    • @mcris7727
      @mcris7727 Před 4 lety +2

      This reminds us of the old saying that mathematics is a giant truism (or tautology) that reduces to something like 1+1=2. In Physics, Dirac said: The world of elementary particles would be much more scarce if not for so many imaginative physicists.

    • @MrEvilNES
      @MrEvilNES Před 4 lety +1

      (p^q)->p , yes

  • @johnchessant3012
    @johnchessant3012 Před 4 lety +8

    This is the proof found in "Proofs from the Book"! Don Zagier condensed this into one (not easily understood) sentence.

    • @Mathologer
      @Mathologer  Před 4 lety +4

      Must be a more recent edition than the one on my bookshelf :) Maybe also have a look at the links in the description of this video :)

  • @iridium9512
    @iridium9512 Před 4 lety +1

    Wow. That's a lot to take in. I get the idea, but I feel like to truly get an intuitive grasp, I would need to take some time to think it all over.
    Amazingly well explained. Well done!

  • @Luxaray2000
    @Luxaray2000 Před 4 lety +2

    Great video. I actually had a project in my number theory class to verify the one sentence proof. Very fun, but this is way more enlightening.

  • @MK-13337
    @MK-13337 Před 4 lety +69

    21:15 "and therefore pi is a sum of two squares" 🤔 now that is some mathologer magic I missed in between the lines

    • @Mathologer
      @Mathologer  Před 4 lety +9

      Time to watch it one more time. Double the fun :)

    • @phiefer3
      @phiefer3 Před 4 lety +1

      The crux of it is that he had x^2 + 4y^2, and 4y^2 is the same as (2y)^2, so that's a square, and x^2 is obviously a square number, so that's the sum of two squares.
      In fact, this is how he started out this section of the video, go back to 10:38 and watch that bit. He starts out by defining p this way (since this is what he was trying to show), then he split the y^2 into y(y) and replaced one of the y with z to make a more general formula, and then from there he proved that there is always a case where y and z are equal.

    • @MK-13337
      @MK-13337 Před 4 lety +9

      I'm a mathematician myself so I know how the proof works. "pi" in my comment is not a typo since it *sounds* like he says that pi (3.1415....) is the sum of two squares 🤔
      Technically true if we don't consider integer squares

    • @davidr2421
      @davidr2421 Před 4 lety +3

      Yeah it does sound like he's saying "pi is the sum of two squares", but I assume he just mispronounced "p"?

    • @loganstrong5426
      @loganstrong5426 Před 4 lety

      I'm wondering if the original proof uses the function pi(n), referring to the nth prime number? He swapped out for p, but misspoke once after all his research.

  • @benjaminbrady2385
    @benjaminbrady2385 Před 4 lety +4

    6:59 the primes of the form 4k + 1 can be written as the sum of two integer squares. We only need to check the last two digits to determine a numbers modulo 4. This yields 81 which is 20*4 + 1 ⚀

    • @Sir_Isaac_Newton_
      @Sir_Isaac_Newton_ Před 2 lety

      This is wrong. Here's why:
      Although what you claim might be correct in most scenarios, it isn't in this one specifically; the fact that 4k is divisible by 2 and the 1 is prime* means that the aforementioned theorem cannot be extrapolated unto said value. In other words, the theorem doesn't "fit" for the equivallence we are trying to prove.

  • @kenhaley4
    @kenhaley4 Před 4 lety

    Brilliant! I admit I didn't follow every step of all this on first viewing, but I know there's nothing there beyond my ability to understand. I will watch it again (maybe several times), because it's easy to see that it's truly beautiful!

  • @ts4gv
    @ts4gv Před 4 lety +2

    THIS VIDEO IS FANTASTIC!!! THANK YOU

  • @ImranMoezKhan
    @ImranMoezKhan Před 4 lety +7

    Fermat was where "The proof is left as an exercise" started.

  • @eliyasne9695
    @eliyasne9695 Před 4 lety +14

    20:16
    This is brilliant!
    That's the very reason this theorem is about primes.

    • @ts4gv
      @ts4gv Před 4 lety +1

      eliya sne It's crazy to think about it that way, but you're totally right. The proof wasn't very "primey" until that key moment.

    • @sighthoundman
      @sighthoundman Před 4 lety

      But, because of the famous identity, known to the ancient Greeks, any number that is a product only of primes of the form 4k + 1 (and possibly including 2) will also be a sum of two squares.
      Things get more complicated if you allow primes of the form 4k + 3. The simplest way to describe it (YMMV) is that in the Gaussian integers (that's numbers that can be written in the form a + bi, where a and b are integers), primes are exactly the numbers that are either of the form a + bi where (a + bi)(a - bi) = a^2 + b^2 = p (prime in the [regular] integers) or p prime in the integers, with p = 4k + 3.
      That's one reason this theorem is important. It tells us how to factor complex integers.

  • @subhabratabasak5681
    @subhabratabasak5681 Před 4 lety

    hey!! your videos are really helpful ..please keep uploading such stuff. please do not stop.

  • @nboisen
    @nboisen Před 3 lety

    Brilliant. And explained with amazing clarity!

  • @mitjamastnak9206
    @mitjamastnak9206 Před 4 lety +3

    Awsome video! In the x^2-y^2 problem at the end, all solutions divisible by 4 are also possible (if you assume that x and y are coprime then you can get all odd numbers as well as numbers divisible by 8).

  • @myrthryn
    @myrthryn Před 4 lety +14

    I have the most excellent documentation of who came up with the windmill interpretation of this proof, but there isn't enough space to place it into this youtube comment.

  • @ArchimedesBC
    @ArchimedesBC Před 3 lety

    I love Professor Polster's geometric approach for this proof. It is genius! Great job, Mathologer!

  • @DarrelFrancis
    @DarrelFrancis Před 4 lety +2

    Beautiful proof, beautifully explained!

  • @alexanderboscan2087
    @alexanderboscan2087 Před 4 lety +18

    Videos are back :D

  • @georgm3257
    @georgm3257 Před 4 lety +6

    Thank you for this great video. A long time ago I heard that Zagier did a one-sentence-proof without knowing what it was until two weeks ago. I did a bit of thinking on my own and want to share what I found (probably not as the first one) because it might be interesting.
    In his original paper Zagier states that his proof is not constructive. In itself both involutions (the trivial t:(x,y,z) --> (x,z,y) and the zagier-involution z as discribed in the video) don't give many new solutions starting from a given one. But combined they lead from the trivial solution to the critical, from the fixpoint of the zagier-involution F := (1,1,k) to the fixpoint of the trivial involution t.
    Proof (sry no latex here): Let n be the smallest integer with (z*t)^n(F) = F. So t*(z*t)^(n-1)(F) = F (multiply by z on both sides). And therefore (t*z)^m * t * (z*t)^m (F) = F with m = (n-1)/2. Bringing (t*z)^m to the other side proofs that (z*t)^m (F) is a (the) fixpoint of the trivial involution, ie a critical solution.
    Note that n is always odd, assuming n is even results in a contradiction: If n is even we have t*(z*t)^k * z * (t*z)^k * t(F) = F with k=(n-2)/2. So again we see that (t*z)^k*t(F) is a fixpoint, this time of z, and therefore equals F. Multiplying by z gives us (z*t)^(k+1)(F) = F contradicting the choice of n.

  • @pengin6035
    @pengin6035 Před 4 lety +1

    You are a godsent angel, I've had my mouth open the whole video, I wish I could subscribe twice

  • @linuxgaminginfullhd60fps10

    I really appreciate the work you are doing. I wouldn't find(look for) this nice proof on my own and if you didn't post the video I would spent this limited time I had today on something useless... Your videos boost my inspiration and thus make me feel better. Keep going!

  • @randompuppy789
    @randompuppy789 Před 4 lety +3

    This man is straight up a beast.

  • @vj_henke
    @vj_henke Před 4 lety +8

    I have a question regarding 32:19, the challenge at the end.
    You claim that the existence of integers x,y with x^2 - y^2 = n (> 0, for simplicity) leads to n being odd.
    As i found the counter example x = 4, y=2 and therefore n=16 - 4 = 12 being not odd , I probably misunderstood you.
    Any help is kindly taken.
    Greetings from Germany.

    • @Mathologer
      @Mathologer  Před 4 lety +7

      Yes, well spotted, of course that statement is wrong. The correct statement is: an integer can be written as a difference of two squares if and only if it is odd or a multiple of 4 :)

  • @peterdriscoll4070
    @peterdriscoll4070 Před 4 lety +1

    I gotta admit, that was an awsome proof. Not long-winded, just windmilled.

  • @denisdaly1708
    @denisdaly1708 Před 4 lety +2

    I loved this video. I was able to follow it, and learned as well. Very interesting.

  • @_abdul
    @_abdul Před 4 lety +5

    21:20 And therefore pi is a Sum of Two Square. That Excitement Nearly Killed me.

  • @Jack-vm1fg
    @Jack-vm1fg Před 4 lety +7

    Makes me wonder just how much of mathematics can be reduced to stuff that's easier to understand.

  • @chayansarma4443
    @chayansarma4443 Před 4 lety

    Lovely explanation and illustrations.Really a nice proof.

  • @msgrtuning
    @msgrtuning Před 4 lety

    As always, thank you for your videos !

  • @chicohigs
    @chicohigs Před 4 lety +7

    p=x^2-y^2=(x+y)(x-y) => if p-prime, then x=y-1 => p=2x+1 (proof of the unique)

  • @spacemanspiff2137
    @spacemanspiff2137 Před 4 lety +14

    TheOneThreeSeven. I love the fine structure of his name

    • @LukeSumIpsePatremTe
      @LukeSumIpsePatremTe Před 4 lety +2

      I think that he's one 37 year old man who likes math. I know it goes deeper, but that's my impression.

    • @richardfarrer5616
      @richardfarrer5616 Před 4 lety +5

      That number is a constant surprise to me.

    • @TheOneThreeSeven
      @TheOneThreeSeven Před 4 lety +6

      HA!! You nailed it =) If I get enough subscribers on my new channel I just launched yesterday I will do a username backstory reveal

    • @dlevi67
      @dlevi67 Před 4 lety +2

      And he drives an Alfa?

    • @TheOneThreeSeven
      @TheOneThreeSeven Před 4 lety +1

      @@LukeSumIpsePatremTe lmao this is actually how old I am =)

  • @tbabubba32682
    @tbabubba32682 Před 3 lety

    I love the friendly rivalry between you and numberphile. I also love your visualizations.

  • @tonyschofield4489
    @tonyschofield4489 Před 2 lety

    Thankyou for reigniting my fascination with Maths.

  • @allmycircuits8850
    @allmycircuits8850 Před 4 lety +60

    behold: new Amazon Prime service translating in 4k+1 resolution :)

    • @ts4gv
      @ts4gv Před 4 lety +1

      AllMyCircuits Nice one dude

    • @danielwimmer4698
      @danielwimmer4698 Před 4 lety +1

      But you don't need prime to get 4k.

    • @danielwimmer4698
      @danielwimmer4698 Před 4 lety +1

      I guess, you can't get 4k with prime would have been better at least considering that it is more accurate and you don't need prime to get to 1 (mod 4) either. Oh, well I didn't think of it at the time.

  • @Censeo
    @Censeo Před 4 lety +16

    Mathologer making complicated math available for amateurs since 2016

  • @evanparsons123
    @evanparsons123 Před rokem

    I watched this video on Christmas morning 2020. At the risk of goading, this is a stunning video and I'm tremendously grateful for it.

  • @hippophile
    @hippophile Před 3 lety

    Great! Solved the two embedded problems which made me feel good! You are a clever youtuber as well as a good mathematicvian! :))

  • @nuzzleTOO
    @nuzzleTOO Před 4 lety +4

    I think i missunderstood the challenge in the end at 32:18.. because this would imply, that 12 = 4² - 2² would be an odd number (which is an odd statement), what do i missing here???

    • @Mathologer
      @Mathologer  Před 4 lety +4

      Very well spotted. Must have been getting tired at that point :) Challenge 1: Prove that every odd number can be written as a difference of two integer squares. Challenge 2: Prove that for odd primes this way of writing the number is unique.

    • @nuzzleTOO
      @nuzzleTOO Před 4 lety

      @@Mathologer Danke :)

    • @Demki
      @Demki Před 4 lety

      after this correction, the proof is pretty "trivial":
      for any odd integer x, both x+1 and x-1 are even, and we can check that indeed
      x=(x+1)^2/4-(x-1)^2/4
      for challenge 2:
      if p is an odd prime and a,b are positive integers such that p=a^2-b^2 (they can't be 0 and we can dismiss the negative solutions since they are essentially the same solution as the positive ones) then p=(a-b)(a+b), which implies that a-b=1 and a+b=p (p is prime so xy=p if and only if x=1, y=p or x=p, y=1, and we know a-b

  • @hugo3222
    @hugo3222 Před 4 lety +3

    At 24:37, instead of cutting the tiles, why not consider the whole plane, which is covered by "equally many" blue+green and red squares. Of course, one has to consider a proper limit, but it's still easier to see what's going on than with the cut-and-rearrange procedure.

  • @Dusk-MTG
    @Dusk-MTG Před 4 lety +1

    I'm studying mathematics right now nad I really love integer numbers, they have so many interesting properties and you really need to stretch your mind to find them. I find calculus, topology, geometry and all that stuff seemingly complicated, but actually easy (the proofs are very often similar), but number theory is always fascinating. At first glance it may seem the easiest part of mathematics, but it's probably the hardest one to understand deeply.

  • @bowtangey6830
    @bowtangey6830 Před 3 lety

    This is fabulous!! What a great video.

  • @denny141196
    @denny141196 Před 3 lety +4

    I’m pretty sure I got the 4k+3 proof. Might need corrections:
    1st claim: to get an odd number as the sum of two numbers, they must have opposite parity (one even one odd).
    Proof: by exhaustion. Even+even=even, odd+odd=even.
    2nd claim: The square of a number has the same parity as the number itself.
    Proof: (2k)^2 = 4k^2 = 2(2k^2). (2k+1)^2 = 4k^2 + 4k + 1 = 2(2k^2 + 2k) + 1.
    Therefore, for an odd number to be the sum of two squares, it must be an even number squared plus an odd number squared.
    Consider (2k)^2 + (2m+1)^2. Using previous working, this is equal to 4k^2 + 4m^2 + 4m + 1 = 4(k^2 + m^2 + m) + 1. Therefore, the sum of the squares of two numbers with opposite parity is always one more than a multiple of 4. There is no other way to get an odd number as the sum of two squares, so getting any number of the form 4k+3 is impossible.

    • @ViceroyoftheDiptera
      @ViceroyoftheDiptera Před 3 lety

      Yes, but you have not proved the hard part: that a number of the form 4K+1 can indeed be written as the of two squares.

  • @JERMAG07
    @JERMAG07 Před 4 lety +11

    I see Mathologer's new upload. I just literally drop anything else I do, and watch. Cat video after this, maybe? :)

  • @lukezeug3591
    @lukezeug3591 Před 4 lety

    Great visualization of the proof!!

  • @123mailashish
    @123mailashish Před 4 lety

    Marvellous!!!
    U r an excellent teacher. U know the nuances of voice modulation while teaching. Excellent write up.

  • @RCassinello
    @RCassinello Před 4 lety +25

    I have a simple solution to who found this proof: By the elimination of variables. As a variable, I eliminate myself. Good luck with the other 7 billion variables.

  • @hakeemnaa
    @hakeemnaa Před 4 lety +3

    7:05
    yes
    if a number has last two digits which can be divided by 4, the whole number can be
    because 100 can be divided by 4
    so any multiple of 100 can be, like 83500
    and you can check by delete all the other digits
    like 83516
    it will be 83500+16
    83500 can be divided and you have to check 16
    now with the prime number
    it end with 81 which is 80+1
    4(20)+1
    :)
    the rest don't not matter because they can be divided by 4 any way

    • @Mathologer
      @Mathologer  Před 4 lety +2

      That's it and that's the answer I was expecting :) I was actually quite surprised by this answer by ben1996123: 6513516734600035718300327211250928237178281758494417357560086828416863929270451437126021949850746381 = 16120430216983125661219096041413890639183535175875^2 + 79080013051462081144097259373611263341866969255266^2

  • @moonwatcher2001
    @moonwatcher2001 Před 4 lety

    Really interesting and entertaining at a time. Thanks. You're very good

  • @pierineri
    @pierineri Před 3 lety

    Thank you for this fantastic video!
    Note that the footprint-preserving involution defined in 18:01 does not need the special form of the prime p, and in fact the conclusion in 20:30 is: the footprint-preserving involution has exactly one fixed point if p=4k+1, and none if p=4k+3. Thus the number of windmills is odd if p=4k+1 and even if p=4k+3.
    The argument in Chapter 6 also still works if we do not assume the form of the prime p, but the conclusion reads: "there is at most one way of writing p as a sum of two squares".
    So if we like this video actually also includes the trivial case 4k+3:
    p=4k+1: odd number of windmills, exactly one fixed point of yz, p writes uniquely as a sum of two squares.
    p=4k+3: even number of windmills, no fixed points of yz, p is not a sum of two squares.

  • @tiziocaio101
    @tiziocaio101 Před 4 lety +7

    How do you prove ramanujan’s continued fraction for phi?
    Or formula for pi?

    • @Mathologer
      @Mathologer  Před 4 lety +6

      Actually, the superfact converging series for pi is on my to-do list :)

    • @tiziocaio101
      @tiziocaio101 Před 4 lety

      Mathologer super

    • @tiziocaio101
      @tiziocaio101 Před 4 lety

      Mathologer and for phi? I mean the one with e and pi in it. Where can I find proofs?

  • @saraswati_6171
    @saraswati_6171 Před 4 lety +44

    My wife called me a nerd when she caught me watching this! 🤓

  • @thomaschevrierlaliberte5884

    This is yet again a gem of a video and I hope I one day will be able to teach this to someone. It must be such a thrill to see people get it!
    Thanks an enormous lot for the time taken and it is so helpful for making maths fun for so many! (Well at least me!)
    To make the video more perfect I would like to point a possible mix up of words:
    28:53 : you said a2 = b2 but I think it's a2 = c2.
    I point it out for all those like me who must constantly rewind and listen to every single word many times to grasp it.
    Many thanks! 💛

  • @terenceshearer3276
    @terenceshearer3276 Před 4 lety

    Thank you for your explanation. Really enjoyed it.