very informative, I am working on a similar problem for lakes in India. The lab test results reveal very interesting information. I have also taken part in a river hydrophone study to identify the mammals in water
Please let me know what device can we use to detect sound waves in utility pipeline 8 feet underground connected with an empty pipe at ground level 50 feet away?
Here it should been said to be half of the pressure not power, you're right: 10log10(((1/2)*p/preference)^2)= 20*log10(1/2) +....... = -20log10(2) + ..... = -6,... +......
very informative,
I am working on a similar problem for lakes in India. The lab test results reveal very interesting information. I have also taken part in a river hydrophone study to identify the mammals in water
Titanic sunk 1912...
Please let me know what device can we use to detect sound waves in utility pipeline 8 feet underground connected with an empty pipe at ground level 50 feet away?
hey! three db is twice power. or a factor of ten. its logarithmic. i dont get -6db being half power. ?????
Here it should been said to be half of the pressure not power, you're right:
10log10(((1/2)*p/preference)^2)= 20*log10(1/2) +....... = -20log10(2) + ..... = -6,... +......
Interesting subject on sound, that unfortunately was recorded with a potato.
speaking of sound.... ouch my ears